¡¶¹¤³ÌÁ¦Ñ§¡·Ìâ¿â(º¬´ð°¸)

¡¶¹¤³ÌÁ¦Ñ§¡·ÐǼ¶¿Î³ÌÊÔÌâ¿â´ð°¸

F

M=Fa

A

1 2 1 2

a

a

B

½â£ºÒÔÕûÌåΪÑо¿¶ÔÏó

Fx

0 £¬ FAx 0

M FBy 2a 0 £¬µÃ FBy

(2 ·Ö)

F ( £©

(2 ·Ö) (2 ·Ö)

M A 0 £¬ F a Fy

0 £¬ FAy FBy F 0 ,µÃ FAy 0

ÒÔ 1-1 ½ØÃæ×ó²à²¿·ÖΪÑо¿¶ÔÏó

M 1 1 0 £¬ FAy a M 1 1

0£¬µÃM11 0

(2 ·Ö)

ÒÔ 2-2 ½ØÃæÓҲಿ·ÖΪÑо¿¶ÔÏó

M 2 2 0 £¬ FBy a M 2 2 0 £¬µÃ M 2 2 Fa(ϲ¿ÊÜÀ­£©

(2 ·Ö)

10¡¢ÇóÏÂͼËùʾÁºµÄÖ§×ù·´Á¦¼° C ½ØÃæµÄÍ侨ºÍ 1-1 ½ØÃæµÄ¼ôÁ¦¡££¨10 ·Ö£©

M=Fa

F

1 1

A

a

½â£ºÒÔÕûÌåΪÑо¿¶ÔÏó

C

Ba

Fx Fy

0 £¬ FBx 0

0 £¬ FBy F 0 ,µÃ FBy

F a M

(2 ·Ö) (2 ·Ö)

2Fa(Éϲ¿ÊÜÀ­£©

F ( )

0£¬µÃ MB

M B 0£¬MB (2 ·Ö)

-44-

¡¶¹¤³ÌÁ¦Ñ§¡·ÐǼ¶¿Î³ÌÊÔÌâ¿â´ð°¸

ÒÔ AC ¶ÎΪÑо¿¶ÔÏó

M C 0 £¬ M C M 0 £¬µÃ M C Fa (Éϲ¿ÊÜÀ­£©

(2 ·Ö )

ÒÔ 1-1 ½ØÃæ×ó²à²¿·ÖΪÑо¿¶ÔÏó

y

Q1 1

Q1 1

F

0 £¬ F 0 0,µÃF

£¨ kN£© 0

(2 ·Ö)

11¡¢ÇóÏÂͼËùʾÁºµÄÖ§×ù·´Á¦¼° A ½ØÃæºÍ D ½ØÃæµÄÍ侨¡££¨10 ·Ö£©

10KN/m

C

A

3m

D

B

3m

3m

½â£ºÒÔÕûÌåΪÑо¿¶ÔÏó

Fx

0 £¬ FAx

0

(2 ·Ö)

M B 0 £¬10 9 4.5

FAy

6 0 £¬µÃ FAy 67.£¨5kN£©£¨ £© (2 ·Ö) (2 ·Ö)

Fy

0 £¬ FAy

FBy 10

9 0, µÃ FBy 22.£¨5 kN£©£¨ £©

ÒÔ DB ¶ÎΪÑо¿¶ÔÏó

M D 0 £¬ M D 10 3 1.5 FBy 3 0 £¬µÃ M D

22.£¨5 kN m£©(Éϲ¿ÊÜÀ­£©

(2 ·Ö)

ÒÔ AC ¶ÎΪÑо¿¶ÔÏó

M A 0 £¬ M A 10 3 1.5 0 £¬µÃ M A 45£¨ kN m£©(Éϲ¿ÊÜÀ­£© (2 ·Ö)

12¡¢ÇóÏÂͼËùʾÁºµÄÖ§×ù·´Á¦¼° B ½ØÃæºÍ C ½ØÃæµÄÍ侨¡££¨10 ·Ö£©

-45-

¡¶¹¤³ÌÁ¦Ñ§¡·ÐǼ¶¿Î³ÌÊÔÌâ¿â´ð°¸

F=qa

q

q

A

C

a

B

a

a

½â£ºÒÔÕûÌåΪÑо¿¶ÔÏó

Fx

0 £¬ FAx 0

(2 ·Ö) (2 ·Ö)

M A 0 £¬ qa a F a qa 5 a FBy 2a

1

0 £¬µÃ FBy 2qa£¨ £©

2

0 £¬ FAy

By

2

Fy

F

F qa qa 0 ,µÃ FAy qa£¨kN£©£¨ £© (2 ·Ö)

ÒÔ B ½ØÃæÓҲಿ·ÖΪÑо¿¶ÔÏó

qa a 0£¬µÃ MB M B 0£¬MB

2

ÒÔ AC ¶ÎΪÑо¿¶ÔÏó

M C 0 £¬ FAy a

1

1

qa2 (Éϲ¿ÊÜÀ­£©

(2 ·Ö)

2

qa 1 a M C 0£¬µÃ MC 1 qa2 (ϲ¿ÊÜÀ­£©

2 2

13¡¢ÇóÏÂͼËùʾÁºµÄÖ§×ù·´Á¦¼° B ½ØÃæºÍ C ½ØÃæµÄÍ侨¡££¨10 ·Ö£©

(2 ·Ö)

20KN

10KN/m

A

C

1m

½â£ºÒÔÕûÌåΪÑо¿¶ÔÏó

B

1m

D

1m

Fx

0 £¬ FAx

0

(2 ·Ö) (2 ·Ö)

M B 0 £¬ FAy 2 20 1 10 1 0.5 0 £¬µÃ FAy 7.£¨5kN£©£¨ £©

-46-

¡¶¹¤³ÌÁ¦Ñ§¡·ÐǼ¶¿Î³ÌÊÔÌâ¿â´ð°¸

Fy 0 £¬ FAy FBy 10 1 20 0 ,µÃ FBy 22.£¨5kN£©£¨ £©

(2 ·Ö )

ÒÔ DB ¶ÎΪÑо¿¶ÔÏó

M B 0 £¬ M B 10 1 0.5 0 £¬µÃ M B £¨5 kN m£©(Éϲ¿ÊÜÀ­£©

(2 ·Ö)

ÒÔ AC ¶ÎΪÑо¿¶ÔÏó

M C 0 £¬ M C FAy 1 0 £¬µÃ M C 7.£¨5 kN m£©(ϲ¿ÊÜÀ­£© (2 ·Ö)

14¡¢ÇóÏÂͼËùʾÁºµÄÖ§×ù·´Á¦¼° D ½ØÃæµÄÍ侨¡££¨ 10 ·Ö£©

M=

¡¤

15KN m

10KN/m

20KN

A

D

3m

3m

B

1.5m

E

1m

F

2m

C

½â£ºÒÔ EC ¶ÎΪÑо¿¶ÔÏó

M E 0 £¬ 20 1 FCy 3 Fy

0 £¬µÃ FC y 6.67£¨kN£©( £© (2 ·Ö)

0 £¬ FEy FCy 20 0 ,µÃ FEy 13.33£¨kN£©£¨ £© ,Ôò F 'Ey 13.33£¨kN£©£¨ £©

ÒÔ EA ¶ÎΪÑо¿¶ÔÏó

M A 0 £¬ 15 10 3 4.5 FBy 6 F 'Ey 7.5 0 £¬µÃ FB y 36.6625£¨kN£©( £©

(2 ·Ö) (2 ·Ö) (2 ·Ö)

Fy Fx

0 £¬ FAy FBy 10 3 F ' Ey 0 ,µÃ FAy 0 £¬ FAx 0

6.6675£¨kN£©£¨ £©

ÒÔ AD ¶ÎΪÑо¿¶ÔÏó

M D 0 £¬ FAy 3 15 M D 0 £¬µÃ M D 5.0025£¨ kN m£©(ϲ¿ÊÜÀ­£© (2 ·Ö)

15¡¢ÇóÏÂͼËùʾ¸Õ¼ÜµÄÖ§×ù·´Á¦¼° 1-1 ½ØÃæµÄµÄÍ侨ºÍ¼ôÁ¦¡££¨10 ·Ö£©

-47-

ÁªÏµ¿Í·þ£º779662525#qq.com(#Ìæ»»Îª@)