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(2) break (3) s!=a[k] (4) k

(2) printf(¡°\\n¡±) (3) a[i][0] (4) a[k][j]

µÚÁùµ¥Ôª º¯Êý Ò»¡¢ Ñ¡ÔñÌâ

1. A 2. A 3. A 4. B 5. D 6. B 7. B 8.C 9.B 10.C 11.B ¶þ¡¢ ¶Á³ÌÐòд½á¹û

1£® The final result is:4 2£® 125 3£® 9 4£® 0,0 0,2 5£® 8, 17 6£® 5 6 7£® 31 8£® 57 9£® 2 6 10£® 15 11.4 Èý¡¢ Ìî¿Õ

1£® (1) i

(2) pp=0;

(3) sum+prime(a[i]); 2£® (1) strlen(str);

(2) str[i]>=?A? && str[i]<=?Z? || str[i]>=?a? && str[i]<=?z? (3) str[i]>=?0? && str[i]<=?9? (4) str[i]= =? ? 3£® (1) pn(x,n);

(2) 1; (3) x;

(4) ((2*n-1)*x*pn(x,n-1)-(n-1)*pn(x,n-2))/n;

4. x

6¡¢ÏÂÁгÌÐòµÄÖ´Ðнá¹ûÊÇ main()

{ int A, B, C, T;

12.B 13 .A 40

A=3; B=2; C=1; T=B; A=B; B=C; C=A; A=T;

printf(\} }

printf(\ }

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