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D 4. A 5. C 6. D 7. A ¶þ¡¢ ¶Á³ÌÐòд½á¹û 1£® 1 0 2 2 5 7 13 2£® 2.20 3.30 4.40 5.50 6.60 1.10 3£® k=24 4£® sum=6 5£® 0 1 0 2 1 0 3 2 1 0 6£® -5 7£® ¡°BBB¡± 8£® ûÓÐÊäÈëÊý¾Ý Èý¡¢ Ìî¿Õ 1£® ÀàÐÍ 2£® (1) int i,p (2) p=i (3) printf(¡°%d\\n¡±,p); 3£® (1) #include ¡°math.h¡± (2) a[i]/20 (3) s=fabs(a[i]-pjz); (4) printf(¡°%f,%f\\n¡±,pjz,t); 4£® (1) x<4 (2) y<3 (3) z==3 5£® (1) N/2 (2) a[N-1-k] (3) a[N-1-k] (4) k 6£® (1) str[i]!=?\\0? (2) k (3) k 7£® (1) s[i] (2) strcmp(s[i],str) 8£® (1) i*3+j*5 20 39 (2) break (3) s!=a[k] (4) k (2) printf(¡°\\n¡±) (3) a[i][0] (4) a[k][j] µÚÁùµ¥Ôª º¯Êý Ò»¡¢ Ñ¡ÔñÌâ 1. A 2. A 3. A 4. B 5. D 6. B 7. B 8.C 9.B 10.C 11.B ¶þ¡¢ ¶Á³ÌÐòд½á¹û 1£® The final result is:4 2£® 125 3£® 9 4£® 0,0 0,2 5£® 8, 17 6£® 5 6 7£® 31 8£® 57 9£® 2 6 10£® 15 11.4 Èý¡¢ Ìî¿Õ 1£® (1) i (2) pp=0; (3) sum+prime(a[i]); 2£® (1) strlen(str); (2) str[i]>=?A? && str[i]<=?Z? || str[i]>=?a? && str[i]<=?z? (3) str[i]>=?0? && str[i]<=?9? 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