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11. ÔÚpH=10°±ÐÔÈÜÒºÖÐÒÔ¸õºÚTΪָʾ¼Á,ÓÃEDTAµÎ¶¨Ca2+ʱÐè¼ÓÈëMgY¡£Çë»Ø´ðÏÂÊöÎÊÌâ: (1) MgY¼ÓÈëÁ¿ÊÇ·ñÐèҪ׼ȷ? (2) MgºÍYµÄÁ¿ÊÇ·ñ±ØÐë±£³Ö׼ȷµÄ1:1¹Øϵ?Ϊʲô?
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12. Éè¼ÆÁ½ÖֲⶨHCl-MgCl2 »ìºÏÒºÖÐÁ½×é·ÖŨ¶ÈµÄ·ÖÎö·½°¸, Ö¸³öµÎ¶¨¼Á¡¢ËùÐèÊÔ¼ÁÓëÌõ¼þ¡¢Ö¸Ê¾¼ÁÒÔ¼°Å¨¶È¼ÆËãʽ¡£
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1.ÔÚFe3+,Al3+,Ca2+,Mg2+»ìºÏÒºÖÐ, ÓÃEDTA·¨²â¶¨Fe3+,Al3+º¬Á¿Ê±, ΪÁËÏû³ýCa2+,Mg2+µÄ¸ÉÈÅ, ×î¼ò±ãµÄ·½·¨ÊÇ---( )
(A) ³Áµí·ÖÀë·¨ (B) ¿ØÖÆËá¶È·¨ (C) ÂçºÏÑڱη¨ (D) ÈܼÁÝÍÈ¡·¨ 2.ÓÃEDTAµÎ¶¨Bi3+ʱ, Ïû³ýFe3+¸ÉÈÅÒ˲ÉÓÃ----------------( )
(A) ¼ÓNaOH (B) ¼Ó¿¹»µÑªËá (C) ¼ÓÈýÒÒ´¼°· (D) ¼ÓÇ軯¼Ø
3.ÈôÒÔ¼×»ù³ÈΪָʾ¼Á, ÓÃNaOH±ê×¼ÈÜÒºµÎ¶¨FeCl3ÈÜÒºÖеÄHClʱ,Fe3+½«²úÉú¸ÉÈÅ¡£ÎªÏû³ýFe3+µÄ¸ÉÈÅ, Ö±½Ó²â¶¨HCl, Ó¦¼ÓÈëµÄÊÔ¼ÁÊÇ------------------------------------------( )
(A) KCN (B) ÈýÒÒ´¼°· (C) EDTA¶þÄÆÑÎ(Ô¤Ïȵ÷½ÚpH=4.0) (D) Zn2+-EDTA(Ô¤Ïȵ÷½Ú
32
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4.ijÈÜÒºº¬Ca2+¡¢Mg2+¼°ÉÙÁ¿Al3+¡¢Fe3+,½ñ¼ÓÈëÈýÒÒ´¼°·, µ÷ÖÁpH=10, ÒÔ¸õºÚTΪָʾ¼Á, ÓÃEDTAµÎ¶¨, ´Ëʱ²â¶¨µÄÊÇ---------------------------------( )
(A) Mg2+Á¿ (B) Ca2+Á¿ (C) Ca2+, Mg2+×ÜÁ¿ (D) Ca2+,Mg2+,Al3+,Fe3+×ÜÁ¿ 5.ÔÚ·Ç»º³åÈÜÒºÖÐÓÃEDTAµÎ¶¨½ðÊôÀë×Óʱ, ÈÜÒºµÄpH½«---------------------------( ) (A) Éý¸ß (B) ½µµÍ (C) ²»±ä (D) Óë½ðÊôÀë×Ó¼Û̬ÓйØ
6.ÂçºÏµÎ¶¨ÖÐ,µ±±»²âÀë×ÓMŨ¶ÈΪ¸ÉÈÅÀë×ÓNŨ¶È10±¶Ê±,ÓûÓÿØÖÆËá¶È·½·¨µÎ¶¨M,ÒªÇóEt¡Ü¡À0.1£¥¡¢?pM=¡À0.2,ÔòlgK(MY)?lgK(NY)Ó¦´óÓÚ--------------------------------( ) (A) 5 (B) 6 (C) 7 (D) 8
7.ÔÚpH=5.0ʱ, ÓÃEDTAÈÜÒºµÎ¶¨º¬ÓÐAl3+,Zn2+,Mg2+ºÍ´óÁ¿F-µÈÀë×ÓµÄÈÜÒº, ÒÑÖªlgK(AlY)=16.3, lgK(ZnY)=16.5, lgK(MgY)=8.7, lg?Y(H)=6.5, Ôò²âµÃµÄÊÇ---------------( )
(A) Al,Zn,Mg×ÜÁ¿ (B) ZnºÍMgµÄ×ÜÁ¿ (C) ZnµÄº¬Á¿ (D) MgµÄº¬Á¿ 8. Fe3+,Al3+¶Ô¸õºÚTÓÐ-------------( )
(A) ½©»¯×÷Óà (B) Ñõ»¯×÷Óà (C) ³Áµí×÷Óà (D) ·â±Õ×÷ÓÃ
9. ÓÃEDTAµÎ¶¨Mg2+,²ÉÓøõºÚTΪָʾ¼Á,ÉÙÁ¿Fe3+µÄ´æÔÚ½«µ¼ÖÂ------------( )
(A) ÖÕµãÑÕÉ«±ä»¯²»Ã÷ÏÔÒÔÖÂÎÞ·¨È·¶¨ÖÕµã (B) ÔÚ»¯Ñ§¼ÆÁ¿µãǰָʾ¼Á¼´¿ªÊ¼ÓÎÀë³öÀ´,ʹÖÕµãÌáÇ°
(C) ʹEDTAÓëָʾ¼Á×÷ÓûºÂý,ÖÕµãÑÓ³¤ (D) Óëָʾ¼ÁÐγɳÁµí,ʹÆäʧȥ×÷ÓÃ
10.ÔÚÂçºÏµÎ¶¨ÖÐ, Óûصη¨²â¶¨Al3+ʱ, ÈôÔÚpH=5~6ʱÒÔij½ðÊôÀë×Ó±ê×¼ÈÜÒº»ØµÎ¹ýÁ¿µÄEDTA, ½ðÊôÀë×Ó±ê×¼ÈÜҺӦѡ---( )
(A) Mg2+ (B) Zn2+ (C) Ag+ (D) Bi3+ 11. EDTAµÄËáЧӦÇúÏßÊÇÖ¸-----------------------------( )
(A) ?Y(H)-pH ÇúÏß (B) pM-pH ÇúÏß (C) lgK'(MY)-pH ÇúÏß (D) lg?Y(H)-pH ÇúÏß 12.Ö¸³öÏÂÁÐÐðÊöÖдíÎóµÄ½áÂÛ----------------------------------( )
(A) ÂçºÏ¼ÁµÄËáЧӦʹÂçºÏÎïµÄÎȶ¨ÐÔ½µµÍ (B) ½ðÊôÀë×ÓµÄË®½âЧӦʹÂçºÏÎïµÄÎȶ¨ÐÔ½µµÍ (C) ¸¨ÖúÂçºÏЧӦʹÂçºÏÎïµÄÎȶ¨ÐÔ½µµÍ (D) ¸÷ÖÖ¸±·´Ó¦¾ùʹÂçºÏÎïµÄÎȶ¨ÐÔ½µµÍ 13.ÔÚ°±ÐÔ»º³åÒºÖÐÓÃEDTAµÎ¶¨Zn2+ÖÁ»¯Ñ§¼ÆÁ¿µãʱ,ÒÔϹØϵÕýÈ·µÄÊÇ-( )
(A) [Zn2+] = [Y4-] (B) c(Zn2+) = c(Y) (C) [Zn2+]2= [ZnY]/K(ZnY) (D) [Zn2+]2= [ZnY]/K'(ZnY) 14.ÒÑÖª lgK(ZnY)=16.5ºÍ pH lg ?Y(H) 4 8.44 5 6.45 6 4.65 7 3.32 ÈôÓÃ0.02 mol/L EDTAµÎ¶¨0.02mol/L Zn2+ÈÜÒº,(ÒªÇó?pM=0.2,Et=0.1%)µÎ¶¨Ê±×î¸ßÔÊÐíËá¶ÈÊÇ--( ) (A) pH¡Ö4 (B) pH¡Ö5 (C) pH¡Ö6 (D) pH¡Ö7 15. ÔÚpHΪ10.0µÄ°±ÐÔ»º³åÒºÖÐ, ÒÔ0.01 mol/L EDTA µÎ¶¨Í¬Å¨¶ÈZn2+ÈÜÒºÁ½·Ý¡£ÆäÖÐÒ»·Ýº¬ÓÐ0.2 mol/L ÓÎÀëNH3; ÁíÒ»·Ýº¬ÓÐ0.5 mol/L ÓÎÀëNH3¡£ÔÚÉÏÊöÁ½ÖÖÇé¿öÏÂ,¶ÔpZn'ÐðÊöÕýÈ·µÄÊÇ-( )
(A) ÔÚ»¯Ñ§¼ÆÁ¿µãÇ°pZn'ÏàµÈ (B) ÔÚ»¯Ñ§¼ÆÁ¿µãʱpZn'ÏàµÈ (C) ÔÚ»¯Ñ§¼ÆÁ¿µãºópZn'ÏàµÈ (D) ÔÚÉÏÊöÈýÖÖÇé¿öÏÂpZn'¶¼²»ÏàµÈ
16.ÔÚpH=5.0µÄ´×ËỺ³åÒºÖÐÓÃ0.002 mol/LµÄ EDTA µÎ¶¨Í¬Å¨¶ÈµÄPb2+¡£ÒÑÖª: lgK(PbY)=18.0, lg?Y(H)=6.6, lg?Pb(Ac)=2.0, »¯Ñ§¼ÆÁ¿µãʱÈÜÒºÖÐpPbӦΪ ( )
(A) 8.2 (B) 6.2 (C) 5.2 (D) 3.2 17.ÔÚpH=10µÄ°±ÐÔ»º³åÒºÖÐÓÃEDTAµÎ¶¨Zn2+ÖÁ50%´¦Ê±---( )
(A) pZn'ÖµÖ»Óë[NH3]ÓÐ¹Ø (B) pZn'ÖµÖ»ÓëlgK'ÓÐ¹Ø (C) pZn'ÖµÖ»Óëc(Zn)ÓÐ¹Ø (D) pZn'ÖµÓëÒÔÉÏÈýÕß¾ùÓйØ
18.ÔÚpH=5µÄÁù´Î¼×»ùËÄ°·»º³åÈÜÒºÖÐÒÔEDTAµÎ¶¨Pb2+,ÔÚ»¯Ñ§¼ÆÁ¿µãºóµÄpPbÖµ--( )
(A) Ö»ÓëlgK'(PbY)ÓйØ(B) Ö»Óëlgc(Pb)ÓÐ¹Ø (C) ÓëlgK'(PbY)ºÍc(Pb)¾ùÓÐ¹Ø (D) ÉÏÊö˵·¨¾ù²»
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19.EDTAµÎ¶¨Al3+,Zn2+,Pb2+»ìºÏÒºÖеÄAl3+Ó¦²ÉÓÃ-------------( )
(A) Ö±½ÓµÎ¶¨·¨ (B) »ØµÎ·¨ (C) Öû»µÎ¶¨·¨ (D) ¼ä½Ó·¨
20.ÓÃNaOH±ê×¼ÈÜÒº²â¶¨FeCl3ÈÜÒºÖеÄÓÎÀëHClʱ,Fe3+½«²úÉú³Áµí¶øÒýÆð¸ÉÈÅ,¿ÉÏû³ýÆä¸ÉÈŵÄÎïÖÊÊÇ-( )
(A) Na2H2Y (B) CaY2- (C) ÄûÃÊËáÈýÄÆ (D)ÈýÒÒ´¼°·
21.»Ç»ùË®ÑîËá(L)ÓëCu2+ÂçºÏÎïµÄlg?1Ϊ9.5,lg?2Ϊ16.5,[CuL]´ï×î´óµÄpLΪ-( ) (A) 9.5 (B) 16.5 (C) 7.0 (D) 8.3
22.ÒÑÖªÒÒ¶þ°·(L)ÓëAg+ÂçºÏÎïµÄlg?1,lg?2·Ö±ðÊÇ4.7Óë7.7,Ôòµ±[AgL]= [AgL2]ʱµÄpLÊÇ--( ) (A) 4.7 (B) 7.7 (C) 6.2 (D) 3.0
23.ÒÒõ£±ûͪ(L)ÓëAl3+ÂçºÏÎïµÄlgK1~lgK3·Ö±ðÊÇ8.6,6.9,5.8,Ôò[Al]=[AlL2] ʱµÄpLԼΪ--( ) (A) 8.6 (B) 6.9 (C) 7.8 (D) 6.4
24.ÐðÊöNa2H2YÈÜÒºÒÔY4-ÐÎʽ´æÔڵķֲ¼ÏµÊý[x(Y4-)]ʱ,˵·¨ÕýÈ·µÄÊÇ-( ) (A) x(Y4-)ËæËá¶ÈµÄÔö´ó¶øÔö´ó (B) x(Y4-)ËæpHµÄÔö´ó¶ø¼õС (C) x(Y4-)ËæpHµÄÔö´ó¶øÔö´ó (D) x(Y4-)ÓëpHµÄ´óСÎÞ¹Ø
25.»Ç»ùË®ÑîËá(H2L)ÓëÍÐγÉÂçºÏÎïµÄlg?1,lg?2·Ö±ðΪ9.5ºÍ16.5,µ±CuL2ÂçºÏÎïΪÖ÷Òª´æÔÚÐÎʽʱ,ÈÜÒºÖÐÓÎÀëLµÄŨ¶È£¨mol/L£©·¶Î§ÊÇ----------------------------( )
(A) [L]>10-9.5 (B) [L]<10-7.0 (C) [L]=10-7.0 (D) [L]>10-7.0
26.½«2¡Á10-2mol/L NaFÈÜÒºÓë2¡Á10-4mol/L Fe3+µÄÇ¿ËáÐÔÈÜÒºµÈÌå»ý»ìºÏºó,ÈÜÒºµÄpH=1.0¡£´ËʱÌúÂçºÏÎïµÄÖ÷Òª´æÔÚÐÎʽÊÇ--------( ) (ÒÑÖª HFµÄpKa=3.2, Fe3+-F- ÂçºÏÎïµÄlg?1~lg?3·Ö±ðΪ5.3,9.3, 12.1) (A) FeF2+ (B) FeF3 (C) FeF2+ºÍFeF3 (D) FeF2+
27.ÔÚpH=5µÄÁù´Î¼×»ùËÄ°·»º³åÈÜÒºÖÐ,ÓÃ0.02000 mol/LµÄEDTAµÎ¶¨Í¬Å¨¶ÈµÄPb2+, »¯Ñ§¼ÆÁ¿µãʱ,pYÊÇ--( ) [pH 5ʱ, lg?Y(H)=6.4, lgK(PbY)=18.0] (A) 6.8 (B) 7.2 (C) 10.0 (D) 13.2
28.ÔÚpH=5.0µÄÁù´Î¼×»ùËÄ°·»º³åÈÜÒºÖÐ,ÓÃEDTAµÎ¶¨Pb2+,»¯Ñ§¼ÆÁ¿µãºópPbµÄÐðÊöÖÐ,ÕýÈ·µÄ( ) (A) ÓëlgK'(PbY)ºÍc(Pb2+)ÓÐ¹Ø (B) Ö»ÓëlgK'(PbY)ÓÐ¹Ø (C) Ö»Óëc(Y)ÓÐ¹Ø (D) Ö»Óëc(Pb2+)ÓÐ¹Ø 29.ÔÚÏÂÁÐÈÜÒºÖÐ,ÓÃ1.0¡Á10-2mol/L EDTA µÎ¶¨1.0¡Á10-2mol/L Zn2+ ÖÁ»¯Ñ§¼ÆÁ¿µãʱ, pZn'×îСµÄÊÇ-----( )
(A) pH=9.0, [NH3]=0.01mol/L (B) pH=10.0, [NH3]=0.01mol/L (C) pH=9.0, [NH3]=0.05mol/L (D) pH=10.0, [NH3]=0.15mol/L
30.ÔÚÏÂÁÐÁ½ÖÖÇé¿öÏ£¬ÒÔEDTAµÎ¶¨ÏàͬŨ¶ÈµÄZn2+£»Ò»ÊÇÔÚpH = 10.0µÄ°±ÐÔ»º³åÈÜÒºÖУ¬¶þÊÇÔÚpH=5.5µÄÁù´Î¼×»ùËÄ°·»º³åÈÜÒºÖС£ÐðÊöµÎ¶¨ÇúÏßpZnͻԾ·¶Î§´óСÕýÈ·µÄÊÇ???( ) ( A )ͻԾ·¶Î§´óСÏàͬ ( B )Ç°ÕßpZnµÄͻԾ·¶Î§±ÈºóÕß´ó ( C )Ç°ÕßpZnµÄͻԾ·¶Î§±ÈºóÕßС ( D )ÉÏÊöÈýÖÖÇé¿ö¶¼ÓпÉÄÜ
31.º¬ÓÐͬŨ¶ÈµÄMg2+ÈÜÒºA¡¢BÁ½·Ý¡£AÈÜÒºµÄpH = 10.0£¬ÆäÖÐÓÎÀë°±µÄŨ¶ÈΪ0.1 mol /L£»BÈÜÒºµÄpH = 9.5£¬ÆäÖÐÓÎÀë°±µÄŨ¶ÈΪ0.02 mol / L¡£½ñÒÔµÈŨ¶ÈµÄEDTAÈÜÒºµÎ¶¨ÉÏÊöÈÜÒºÖÁ»¯Ñ§¼ÆÁ¿µãʱ¡£¶ÔpY?¼Æ µÄ´óСÐðÊöÕýÈ·µÄÊÇ???( )
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32.½ñÓÐA¡¢BŨ¶ÈÏàͬµÄZn2+-EDTAÈÜÒºÁ½·Ý£ºAΪpH = 10.0µÄNaOHÈÜÒº£»BΪpH = 10.0µÄ°±ÐÔ»º³åÈÜÒº¡£ÔòÔÚA¡¢BÈÜÒºÖÐZn2+-EDTAµÄK?(ZnY)ÖµµÄ´óСÊÇ??? ( )
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(A) ·ÖÎö´¿µÄAgNO3 (B) ·ÖÎö´¿µÄCaCO3 (C) ·ÖÎö´¿µÄFeSO4¡¤7H2O (D) ¹âÆ×´¿µÄCaO ¶þ¡¢Ìî¿ÕÌâ
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Zn2+ΪÖ÷ [Zn2+]=[ZnL] [ZnL]×î´ó ZnL2ΪÖ÷ 2.ÒÑÖªÒÒõ£±ûͪ(L)ÓëAl3+ÂçºÏÎïµÄlg?1-lg?3·Ö±ðÊÇ8.6¡¢15.5ºÍ21.3,ÔòAlL3ΪÖ÷ÒªÐÎʽʱµÄpL·¶Î§ÊÇ____________ ¡£pLΪ10.0ʱÂÁµÄÖ÷ÒªÐÎʽÊÇ_____ ¡£
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8.½ðÊôָʾ¼Á PAN ÔÚÈÜÒºÖÐÓÐÈçÏÂƽºâ: pK a1=1.9 pK a2=12.2 H2In+
HIn
In-
»ÆÂÌ »Æ ·Ûºì
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9.ÊÔ¸ø³ö¸õºÚTÓÃÓÚEDTAµÎ¶¨Mg2+µÄÌõ¼þºÍÏÖÏó -H+ -H+ H2In- HIn2-
In3-
pKa1 =6.3 pKa2 =11.6
ºìÉ« ( ___É« ) ³ÈÉ« + Mg2+
|| pH=_______ MgIn+Mg2+(_____É«) || +Y
MgY+HIn (ÖÕµã______É«)
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