2010数学建模竞赛才C题

ans =

18/5/(x4^2+(y4-5)^2)^(1/2)*(2*y4-10)+36/5+18/5/((x4-15)^2+(y4-8)^2)^(1/2)*(2*y4-16) >>

[x4,y4]=solve('36/5/(x4^2+(y4-5)^2)^(1/2)*x4+18/5/((x4-15)^2+(y4-8)^2)^(1/2)*(2*x4-30)=0','18/5/(x4^2+(y4-5)^2)^(1/2)*(2*y4-10)+36/5+18/5/((x4-15)^2+(y4-8)^2)^(1/2)*(2*y4-16)=0') x4 =

15/2-3/2*3^(1/2) y4 =

13/2-5/2*3^(1/2)

>> x4=15/2-3/2*3^(1/2) x4 =

4.9019

>> y4=13/2-5/2*3^(1/2) y4 =

2.1699 >>

7.2*(x4^2+(y4-5)^2)^0.5+7.2*y4+7.2*((x4-15)^2+(y4-8)^2)^0.5+5*(21+7.2)

ans =

281.3307 %公司一的管线建设费用 >>

7.2*(x4^2+(y4-5)^2)^0.5+7.2*y4+7.2*((x4-15)^2+(y4-8)^2)^0.5+5*(24+7.2)

- 29 -

ans =

296.3307 %公司二的管线建设费用 >>

7.2*(x4^2+(y4-5)^2)^0.5+7.2*y4+7.2*((x4-15)^2+(y4-8)^2)^0.5+5*(20+7.2)

ans =

276.3307 %公司三的管线建设费用

问题三 方案三 公司一(21)

>> syms x y z f >>

f=5.6*(x^2+(y-5)^2)^0.5+7.2*y+6*((x-15)^2+(y-z)^2)^0.5+27*(25+(8-z)^2)^0.5 f =

28/5*(x^2+(y-5)^2)^(1/2)+36/5*y+6*((x-15)^2+(y-z)^2)^(1/2)+27*(25+(8-z)^2)^(1/2)

>> diff(f,'x') ans =

28/5/(x^2+(y-5)^2)^(1/2)*x+3/((x-15)^2+(y-z)^2)^(1/2)*(2*x-30)

>> diff(f,'y') ans =

14/5/(x^2+(y-5)^2)^(1/2)*(2*y-10)+36/5+3/((x-15)^2+(y-z)^2)^(1/2)*(2*y-2*z)

>> diff(f,'z') ans =

- 30 -

3/((x-15)^2+(y-z)^2)^(1/2)*(-2*y+2*z)+27/2/(25+(8-z)^2)^(1/2)*(-16+2*z) >>

[x,y,z]=solve('28/5/(x^2+(y-5)^2)^(1/2)*x+3/((x-15)^2+(y-z)^2)^(1/2)*(2*x-30)=0','14/5/(x^2+(y-5)^2)^(1/2)*(2*y-1

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