单层工业厂房排架结构设计复习习题库

q1k??s?z?0B?0.8?1.014?0.45?6?2.19kN/mq2k??s?z?0B?0.5?1.014?0.45?6?1.37kN/mq1?rQq1k?1.4?2.19?3.07kN/m(?)q2?rQq2k?1.4?1.37?1.92kN/m(?)风向

-0.6 W I1 q1 I2 +0.8

-0.5 I3 q2

I4 -0.5 10.5m 2.求W 高度取10.5+2.1=12.6m

?z?1?1.14?1.0(12.6?10)?1.07

15?10Wk?[(0.8?0.5)h1?(0.5?0.6)h2]?z?0B?[1.3?2.1?0.1?1.2]?1.07?0.45?6?7.54KN

W?rQWk?1.4?7.54?10.56kN 3.计算参数?,n

I3I12.13?1097.2?109n???0.37n???0.1599I214.38?10I419.5?10A柱: B柱:

HH33??u??0.29??u??0.29H10.5H10.54.在柱顶虚拟加不动铰支座

查表计算:

113[1??4(?1)]3?[1?0.294(?1)]n0.15A柱:C11???0.34 118[1??3(?1)]8?[1?0.293(?1)]n0.152.1m 1.2m 113[1??4(?1)]3?[1?0.294(?1)]n0.37B柱:C11???0.36 118[1??3(?1)]8?[1?0.293(?1)]n0.37

RA?q1HC11?3.07?10.5?0.34??11(?)RB?q2HC11?1.92?10.5?0.36??7.3(?)故:柱顶剪力

VA,1?RA??11(?)VB,1?RB??7.3(?)

5.撤消不动铰支座,反向施加支座反力。 A柱:C0?33??2.64 111??3(?1)1?0.293(?1)n0.1533??2.88 111??3(?1)1?0.293(?1)n0.37B柱:C0?于是:

H31.53?uA??EcIlC0Ec?1.3?10 9?24.6804H310.53 ?uB??EcIlC0Ec?19.5?109?2.882.64?14.38?0.42.64?14.38?2.88?19.5所以分配系数:

2.88?19.5?B??0.62.64?14.38?2.88?19.5?A?故,柱顶剪力:

VA,2??A(RA?RB?W)?0.4?(11?7.3?10.56)?11.54kN(?)VB,2??B(RA?RB?W)?0.6?(11?7.3?10.56)?17.32kN(?)6.叠加两个受力状态

VA?VA,1?VA,2?11.54?11?0.54(?)VB?VB,1?VB,2?17.32?7.3?10.02(?)

7.绘制弯矩图

0.54KN 10.02KN q1=3.07 KN/m 175 A柱

15.44 q1=1.92 KN/m 211.05 38.7 M图(KN·m) B柱 M图(KN·m)

49. 如图所示排架,在A,B牛腿顶面作用有力矩M1和M2。试求A,B柱的内

力,已知:M1=153.2KN.M,M2=131.0KN.M,柱截面惯性距同上习题13-2。

I1 M1 I2 I3 M2 I4 解:1.计算参数?,n

I3I12.13?1097.2?109n???0.37n???0.1599I214.38?10I419.5?10A柱: B柱:

HH33??u??0.29??u??0.29H10.5H10.52.在柱顶虚拟加不动铰支座

1??21?0.292?1.5??1.21 A柱:C3?1.5111??3(?1)1?0.293?(?1)n0.151??21?0.292?1.5??1.32 B柱:C3?1.513131??(?1)1?0.29?(?1)n0.37M1153.2C3??1.21??17.65kN(?)H10.5故:

M131.0RB?2C3??1.32?16.47kN(?)H10.5RA?3.撤消不动铰支座,反向施加支座反力

R?RA?RB?17.65?16.47?1.18kN(?)

?A?0.4,?B?0.6 所以:

VA?R?A?1.18?0.4?0.47kN(?)VB?R?B?1.18?0.6?0.71kN(?)

3.叠加内力

VA??17.65?0.47??17.18(?)VB?16.47?0.71?17.18(?)

4.弯矩图:

17.18KN 17.18KN 101.66 51.54 M=153.2KN.m M=131KN.m 51.54 79.46 27.19 A柱 M图(KN.M) B柱 49.39 M图(KN.M)

50. 如图所示柱牛腿,已知竖向力设计值Fv?324kN,水平拉力设计值

Fh?78kN,采用 C20(ftk?1.54N/mm2)混凝土和HRB335级钢筋,

试设计牛腿的纵向受力钢筋。

(截面宽度b=400mm(另加的条件))

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