·ÖÎö»¯Ñ§¸´Ï°Ìâ(youdaan)

A.ÉÕ±­ B.Á¿Í² C.×¶ÐÎÆ¿ D.ÈÝÁ¿Æ¿ E.ÊÔ¼ÁÆ¿

B3¡¢µÎ¶¨·ÖÎö·¨ÊÇÊôÓÚ

A.΢Á¿·ÖÎö B.³£Á¿·ÖÎö C.°ë΢Á¿·ÖÎö D.ºÛÁ¿·ÖÎö E.¶¨ÐÔ·ÖÎö

B4¡¢µÎ¶¨·ÖÎöµÄÏà¶ÔÎó²îÒ»°ãÇé¿öÏÂÔÚ

A.0.02%ÒÔÏ B.0.2%ÒÔÏ C.0.3%ÒÔÏ D.0.2-0.3%Ö®¼ä E.1%ÒÔÏÂ

A5¡¢TT/A±íʾµÄÒâÒåÊÇ

A.1mlµÎ¶¨ÒºÏ൱ÓÚ±»²âÎïÖʵÄÖÊÁ¿ B.1mlµÎ¶¨ÒºÖÐËùº¬ÈÜÖʵÄÖÊÁ¿ C.1LµÎ¶¨ÒºÏ൱ÓÚ±»²âÎïÖʵÄÖÊÁ¿ D.1LµÎ¶¨ÒºËùº¬ÈÜÖʵÄÖÊÁ¿

E.100mlµÎ¶¨ÒºÖÐËùº¬ÈÜÖʵÄÖÊÁ¿

B6¡¢³£ÓõÄ50mlµÎ¶¨¹ÜÆä×îС¿Ì¶ÈΪ

A.0.01ml B.0.1ml C.0.02ml D.0.2ml E.1ml

B7¡¢Ôڵζ¨¹ÜÉ϶ÁÈ¡ÏûºÄµÎ¶¨ÒºµÄÌå»ý£¬ÏÂÁмǼÕýÈ·µÄÊÇ

A.20.1ml B.20.10ml C.20ml D.20.100ml E.20.1000ml

D8¡¢Ôڵζ¨·ÖÎöÖУ¬»¯Ñ§¼ÆÁ¿µãÓëµÎ¶¨ÖÕµãÖ®¼äµÄ¹ØÏµÎª

A.Á½µãº¬ÒåÏàͬ B.Á½µã±ØÐëÎÇºÏ C.Á½Õß»¥²»Ïà¸É

D.Á½ÕßÔ½½Ó½ü£¬µÎ¶¨Îó²îԽС E.Á½ÕßµÄÎǺϳ̶ÈÓëµÎ¶¨Îó²îÎÞ¹Ø

C9¡¢ÒÑ֪׼ȷŨ¶ÈµÄÊÔ¼ÁÈÜÒº³ÆÎª

A.·ÖÎö´¿ÊÔ¼Á B.±ê¶¨ÈÜÒº C.µÎ¶¨Òº D.»ù×¼ÊÔ¼Á E.ÓÅÖÊÊÔ¼Á

B10¡¢Èç¹û»ù×¼ÎïÖÊH2C2O3¡¤2H2O±£´æ²»µ±£¬²¿·Ö·ç»¯£¬ÓÃËüÀ´±ê¶¨NaOHÈÜÒºµÄŨ¶Èʱ

A.½á¹ûÆ«¸ß B.½á¹ûÆ«µÍ C.׼ȷ D.ÎÞ·¨È·¶¨ E.¶Ô½á¹ûÎÞÓ°Ïì

C11¡¢Ôڵζ¨·ÖÎöÖУ¬ËùʹÓõĵζ¨¹ÜÖÐÕ´ÓÐÉÙÁ¿´¿»¯Ë®£¬Ê¹ÓÃǰ

A.±ØÐëÔÚµç¯ÉϼÓÈȳýȥˮ B.²»±Ø½øÐÐÈκδ¦Àí C.±ØÐëÓÃÉÙÁ¿´ýÊ¢×°ÈÜÒºµ´Ï´2-3´Î D.ÓÃÏ´Òº½þÅÝ´¦Àí E.±ØÐëÓÃHClÈÜÒºµ´Ï´2-3´Î

D17¡¢ÏÂÁд¿ÎïÖÊ¿ÉÓÃÓڱ궨HClÈÜÒºµÄÊÇ

A.H2C2O4 B.ZnO C.As2O3 D.Na2CO3 E.KClO3

B12¡¢ÓÃTHCl/NaOH=0.004000g/mlHClÈÜÒºµÎ¶¨NaOHÈÜÒº£¬ÖÕµãʱÏûºÄHCl20.00ml£¬ÊÔÑùÖк¬NaOHµÄÖÊÁ¿ÎªA.0.8000g B.0.08000g C.0.004000g D.0.008000g E.0.04g

ABD13¡¢µÎ¶¨·´Ó¦Ö÷ÒªÓÐ

A.È·¶¨µÄ¼ÆÁ¿¹ØÏµ B.·´Ó¦ËٶȽϿì C.ÎÞ³ÁµíÉú³É D.·´Ó¦½øÐÐÍêÈ« E.Ã÷ÏԵĿɾõ²ìµÄÍâ¹Û±ä»¯

ACDE14¡¢ÏÂÁÐÊôÓÚ»ù×¼ÎïÖÊËùÓ¦¾ß±¸µÄÌõ¼þÊÇ

A.Ó뻯ѧʽÏà·ûµÄÎïÖÊ×é³É B.²»Ó¦º¬Óнᾧˮ C.´¿¶ÈÓ¦´ï99.9%ÒÔÉÏ D.ÔÚͨ³£Ìõ¼þÏÂÏ൱Îȶ¨ E.×îºÃ¾ßÓнϴóµÄĦ¶ûÖÊÁ¿

ACDE15¡¢ËáʽµÎ¶¨¹Ü¿ÉװʲôÈÜÒº

A.ËáÐÔ B.¼îÐÔ C.ÖÐÐÔ D.Ñõ»¯ÐÔ E.»¹Ô­ÐÔ

AE16¡¢²»ÄÜÓüîʽµÎ¶¨¹ÜÊ¢×°µÄÈÜÒº

A.KMnO4 B.KOH C.NaOH D.Na2SO4 E.I2

BC17¡¢Óûù×¼ÎïÖʱ궨µÎ¶¨Òº¿É²ÉÓÃ

A.±È½Ï·¨ B.¶à´Î³ÆÁ¿·¨ C.ÒÆÒº¹Ü·¨ D.¼õÖØ·¨ E.Á¿Æ¿·¨

BD18¡¢µÎ¶¨ÒºµÄÅäÖÆ·½·¨ÓÐ

A.ÒÆÒº¹Ü·¨ B.Ö±½Ó·¨ C.±È½Ï·¨ D.¼ä½Ó·¨ E.»ù×¼ÎïÖÊ·¨

BE19¡¢±ê¶¨µÎ¶¨ÒºµÄ·½·¨ÓÐ

A.Öû»·¨ B.»ù×¼ÎïÖʱ궨·¨ C.Ö±½Ó·¨ D.¼ä½Ó·¨ E.µÎ¶¨Òº±È½Ï·¨

AE20¡¢ÏÂÁÐÒÇÆ÷Óô¿»¯Ë®Ï´µÓ¸É¾»ºó£¬±ØÐëÓôý×°ÈÜҺϴµÓµÄÊÇ

A.ÒÆÒº¹Ü B.×¶ÐÎÆ¿ C.ÈÝÁ¿Æ¿ D.µâÁ¿Æ¿ E.µÎ¶¨¹Ü

5

ABCD21¡¢µÎ¶¨·ÖÎö·¨µÄµÎ¶¨·½Ê½ÓÐ

A.Ö±½ÓµÎ¶¨·¨ B.¼ä½ÓµÎ¶¨·¨ C.Öû»µÎ¶¨·¨ D.·µµÎ¶¨·¨ E.·ÇË®µÎ¶¨·¨

BC22¡¢ÏÂÁÐÎïÖÊ¿É×÷Ϊ»ù×¼ÎïÖʵÄÊÇ

A.NaCl(C.P) B.NaCl(A.P) C.NaCl(G.R) D.NaOH E.HCl

¶þ¡¢ÊÇ·ÇÌâ

¡Ì1¡¢µÎ¶¨ÖÕµãÓ뻯ѧ¼ÆÁ¿µã²»ÍêÈ«·ûºÏ¶øÒýÆðµÄÎó²îÊÇÖÕµãÎó²î¡£ ¡Ì2¡¢µÎ¶¨·´Ó¦¾ù¾ßÓÐÈ·¶¨µÄ¼ÆÁ¿¹ØÏµ¡£

x 3¡¢ÒªÖªµÀÈÜÒºµÄ׼ȷŨ¶È£¬±ØÐë½øÐб궨¡£ ¡Ì4¡¢´øÓв£Á§÷á¿Ú»îÈûµÄµÎ¶¨¹ÜÊÇËáʽµÎ¶¨¹Ü¡£ x 5¡¢¼îʽµÎ¶¨¹Ü¿ÉÊ¢·ÅÑõ»¯ÐÔÈÜÒº¡£ x 6¡¢µÎ¶¨ÖÕµãÒ»¶¨ºÍ¼ÆÁ¿µãÏàÎǺϡ£ x 7¡¢´¿¾»ÎïÖʾù¿ÉÓÃÖ±½Ó·¨ÅäÖÆÈÜÒº¡£ x 8¡¢NaOHºÍHClµÎ¶¨Òº¶¼¿ÉÓÃÑÎËáÅäÖÆ¡£ x 9¡¢ËùÓд¿¶È¸ßµÄÎïÖʶ¼ÊÇ»ù×¼ÎïÖÊ¡£ ¡Ì10¡¢¶ÁÊýʱµÎ¶¨¹ÜÓ¦±£³Ö´¹Ö±¡£

x 11¡¢Ôڵζ¨¹ÜÉ϶ÁÊýʱ£¬¶ÔÓÚ½ÏÄÑ¿´ÇåÇеãµÄÉîÉ«ÈÜÒº£¬¿É¶ÁÈ¡ÒºÃæµÄ×îÏÂÑØ¡£ ¡Ì12¡¢»ù×¼ÎïÖʼ´¿ÉÓÃÖ±½Ó·¨ÓÖ¿ÉÓüä½Ó·¨ÅäÖÆÈÜÒº¡£ x 13¡¢³£Á¿µÎ¶¨¹ÜµÄ×îС¿Ì¶ÈΪ0.01ml¡£ x 14¡¢¶ÔÈÎÒ»µÎ¶¨·´Ó¦´ï¼ÆÁ¿µãʱ£¬nA=nB¡£

Ëá¼îµÎ¶¨·¨

Ò»¡¢Ñ¡ÔñÌâ £¨Ò»£©AÐÍÌâ

C1¡¢Ç¿¼îµÎ¶¨ÈõËáʱ£¬Ö»ÓÐÔÚÏÂÁÐÄÄÖÖÇé¿öÏ£¬¿ÉÒÔÖ±½ÓµÎ¶¨

A.C=0.1mol/L B.Ka=10-7 C.CKa¡Ý10-8 D¡£CKa¡Ü10-8 E.Ka£¼10

-7

C2¡¢NaOHµÎ¶¨HAcʱ£¬Ó¦Ñ¡ÓÃÏÂÁÐÄÄÖÖָʾ¼Á

A¡¢¼×»ù³È B¡¢¼×»ùºì C¡¢·Ó̪ D¡¢°ÙÀï·ÓÀ¶ E¡¢Ç°ÃæËÄÖÖ¾ù¿É

D3¡¢¶ÔÓÚËá¼îָʾ¼ÁÏÂÁÐÄÄÖÖ˵·¨ÊDz»Ç¡µ±µÄ

A¡¢Ö¸Ê¾¼Á±¾ÉíÊÇÒ»ÖÖÈõËá B¡¢Ö¸Ê¾¼Á±¾ÉíÊÇÒ»ÖÖÈõ¼î C¡¢Ö¸Ê¾¼ÁµÄÑÕÉ«±ä»¯ÓëÈÜÒºµÄPHÓÐ¹Ø D¡¢Ö¸Ê¾¼ÁµÄ±äÉ«ÓëÆäKHInÓйØ

E¡¢Ö¸Ê¾¼ÁµÄ±äÉ«·¶Î§Óëָʾ¼ÁµÄÓÃÁ¿ÓйØ

C4¡¢ÓÃHClµÎ¶¨Na2CO3½Ó½üÖÕµãʱ£¬ÐèÒªÖó·ÐÈÜÒº£¬ÆäÄ¿µÄÊÇ

A¡¢Çý¸ÏO2 B¡¢ÎªÁ˼ӿ췴ӦËÙ¶È C¡¢Çý¸ÏCO2 D¡¢ÒòΪָʾ¼ÁÔÚÈȵÄÈÜÒºÖÐÈÝÒ×±äÉ« E¡¢ÒòΪNa2CO3ÖÐÓÐÉÙÁ¿Î¢ÈÜÐÔÔÓÖÊ

B5¡¢ÏÂÁÐÄÄÒ»ÖÖËá²»ÄÜÓÃNaOHÈÜÒºÖ±½ÓµÎ¶¨

A¡¢HCOOH £¨Ka=1.77¡Á10-4

£©

B¡¢H¡Á10-10

3BO3 (Ka=7.3)

C¡¢HAc £¨Ka=1.76¡Á10-5

£©

D¡¢H-5-6

2C4H4O4 (Ka1=6.4¡Á10, Ka2=2.7¡Á10)

E¡¢CH-5

65COOH £¨Ka=6.46¡Á10£©

B6¡¢ÓÐÒ»ÖÖδ֪ÈÜÒº¼Ó¼×»ùºìָʾ¼ÁÏÔ»ÆÉ«£¬¼Ó·Óָ̪ʾ¼ÁÎÞÉ«£¬¸Ãδ֪ÈÜÒºµÄPHԼΪ

A¡¢6.2 B¡¢6.2¡«8.0 C¡¢8.0 D¡¢8.0¡«10.0 E¡¢4.4¡«6.2

E7¡¢ÄÜÓÃNaOHÈÜÒºÖ±½ÓµÎ¶¨£¬²¢ÇÒÓÐÁ½¸öµÎ¶¨Í»Ô¾µÄËáΪ

A¡¢H-2-5

2C2O4 (Ka1=6.5¡Á10, Ka2=6.1¡Á10)

B¡¢ÈéËá £¨Ka=1.4¡Á10-4

£©

C¡¢ÁÚ±½¶þ¼×Ëá (Ka-3-14

1=1.3¡Á10, Ka2=4¡Á10)

6

D¡¢Ë®ÑîËá (Ka1=1.07¡Á10, Ka2=4¡Á10)

-2-7

E¡¢Ë³¶¡Ï©¶þËá (Ka1=1.42¡Á10, Ka2=8.57¡Á10)

B8¡¢±ê¶¨NaOHµÎ¶¨ÒºÊ±³£ÓÃ×î¼ÑµÄ»ù×¼ÎïÖÊÊÇ

A¡¢ÎÞˮ̼ËáÄÆ B¡¢ÁÚ±½¶þ¼×ËáÇâ¼Ø C¡¢Åðɰ D¡¢²ÝËáÄÆ E¡¢±½¼×Ëá

A9¡¢ÓÃÎÞË®Na2CO3±ê¶¨HClŨ¶Èʱ£¬Î´¾­ÔÚ270-300¡æºæ¿¾£¬Æä±ê¶¨µÄŨ¶È

A¡¢Æ«¸ß B¡¢Æ«µÍ C¡¢ÕýÈ· D¡¢ÎÞÓ°Ïì E¡¢ÒÔÉ϶¼²»ÊÇ

C10¡¢ÏÂÁйØÓÚָʾ¼ÁµÄÂÛÊö´íÎóµÄÊÇ

A¡¢Ö¸Ê¾¼ÁµÄ±äÉ«·¶Î§Ô½Õ­Ô½ºÃ B¡¢Ö¸Ê¾¼ÁµÄÓÃÁ¿Ó¦Êʵ± C¡¢Ö»ÄÜÓûìºÏָʾ¼Á

D¡¢Ö¸Ê¾¼ÁµÄ±äÉ«·¶Î§Ó¦Ç¡ºÃÔÚͻԽ·¶Î§ÄÚ E¡¢Ö¸Ê¾¼ÁµÄÀíÂÛ±äÉ«µãPH=PKHin

E11¡¢Ëá¼îµÎ¶¨ÖÐÐèÒªÓÃÈÜÒºÈóÏ´µÄÆ÷ÃóÊÇ

A¡¢×¶ÐÎÆ¿ B¡¢ÒÆÒº¹Ü C¡¢µÎ¶¨¹Ü D¡¢Á¿Í² E¡¢ÒÔÉÏBºÍC

BE12¡¢ÏÂÁÐÄܲúÉúÁ½¸öµÎ¶¨Í»Ô¾µÄËáÊÇ

-5-6

A¡¢çúçêËá £¨Ka1=6.89¡Á10,Ka2=2.74¡Á10£©

-2-7

B¡¢Ë³¶¡Ï©¶þËá £¨Ka1=1.42¡Á10,Ka2=8.57¡Á10£©

-2-5

C¡¢²ÝËá £¨Ka1=6.5¡Á10,Ka2=6.1¡Á10£©

-3-6

D¡¢±û¶þËá £¨Ka1=1.49¡Á10,Ka2=2.03¡Á10£©

-2-7

E¡¢¸ÊÓÍÁ×Ëá £¨Ka1=3.4¡Á10,Ka2=6.4¡Á10£©

ACE13¡¢Ó°ÏìËá¼îָʾ¼Á±äÉ«·¶Î§µÄÒòËØÓÐ

A¡¢ÈÜÒºÎÂ¶È B¡¢ÈÜҺŨ¶È C¡¢Ö¸Ê¾¼ÁµÄÓÃÁ¿ D¡¢ÈÜÒºµÄËá¶È E¡¢µÎ¶¨³ÌÐò

AC14¡¢Åж϶àÔªËáÖ±½Ó±»µÎ¶¨ÇÒÓÐÁ½¸öµÎ¶¨Í»Ô¾µÄÔ­ÔòÊÇ

-7-8

A¡¢Ã¿¼¶H+µçÀëµÄKa¡Ý10 B¡¢Ö»ÒªÆäcKa¡Ý10

-8

C¡¢Kan/Kan-1¡Ý4 D¡¢cKa¡Ü10 E¡¢ÒÔÉϾùÊÇ

BC15¡¢¿ÉÓÃÀ´±ê¶¨NaOHµÎ¶¨ÒºµÄ»ù×¼ÎïÖÊÊÇ

A¡¢ÎÞˮ̼ËáÄÆ B¡¢ÁÚ±½¶þ¼×ËáÇâ¼Ø C¡¢²ÝËá D¡¢Åðɰ E¡¢¼×Ëá

¶þ¡¢ÊÇ·ÇÌâ

x¡Ì1¡¢Ëá¼îµÎ¶¨µÄÖÕµãÒ»¶¨ÊǼÆÁ¿µã¡£ x 2¡¢ÈýÔªËá±»µÎ¶¨£¬¾ÍÓ¦¸ÃÓÐÈý¸öͻԾ¡£

x 3¡¢Ëá¼îµÎ¶¨ÇúÏßÉÏ£¬Í»Ô¾·¶Î§µÄ´óС£¬Ö»ÓëËáµÄÇ¿ÈõÓйء£ ¡Ì4¡¢Ö¸Ê¾¼ÁµÄ±äÉ«·¶Î§Ô½Õ­Ô½ºÃ£¬Ö¸Ê¾¼Á±äɫԽÃôÈñ¡£ ¡Ì5¡¢µÎ¶¨Í»Ô¾·¶Î§Ô½´ó£¬¿É¹©Ñ¡ÔñµÄָʾ¼ÁÔ½¶à¡£ ¡Ì6¡¢µÎ¶¨ÒºµÄŨ¶ÈÔ½´ó£¬Í»Ô¾·¶Î§Ô½´ó¡£

x 7¡¢Çãµ¹ÑùƷǰ£¬×¶ÐÎÆ¿ÖÐÈôÓÐÉÙÁ¿Ë®£¬»áʹ²â¶¨½á¹ûÆ«µÍ¡£

-¡Ì8¡¢µ±[HIn]/[In]¡Ý10ʱ£¬ÈÜÒº³ÊÏÖµÄÊÇָʾ¼ÁµÄËáʽɫ¡£

x 9¡¢ÓÉÓÚHAc¿ÉÒÔÓÃNaOHµÎ¶¨ÒºÖ±½ÓµÎ¶¨£¬Òò´ËNaAc¾Í¿ÉÒÔÓÃHClµÎ¶¨ÒºÖ±½ÓµÎ¶¨¡£ x 10¡¢ÅäÖÆÑÎËáµÎ¶¨Òº£¬Ö»ÒªÓÃÒÆÒº¹ÜÎüȡһ¶¨Á¿µÄŨÑÎËᣬÔÙ׼ȷ¼ÓˮϡÊÍÖÁÒ»¶¨Ìå»ý£¬ËùµÃµÄŨ¶ÈÊÇ׼ȷµÄ¡£ x 11¡¢0.1mol/LHClºÍ0.1mol/LHAcÈÜÒºµÄPH¶¼ÊÇ1.0¡£

x 12¡¢·²ÊÇËá¡¢ËáÐÔÎïÖÊ£¬¼îºÍ¼îÐÔÎïÖʶ¼¿ÉÒÔÓÃËá¼îµÎ¶¨·¨²â¶¨¡£

³ÁµíµÎ¶¨·¨

C1¡¢ÓøõËá¼ØÖ¸Ê¾¼Á·¨²â¶¨KBrº¬Á¿Ê±£¬K2CrO4ָʾ¼ÁÓÃÁ¿¹ý¶à½«²úÉú

7

-3-14

A¡¢ÕýÎó²î B¡¢Æ½Ðнá¹û»ìÂÒ C¡¢¸ºÎó²î D¡¢Ê¹ÖÕµã±äÉ«¸üÃôÈñ E¡¢ÎÞÓ°Ïì

D2¡¢¸õËá¼ØÖ¸Ê¾¼Á·¨²â¶¨Cl-º¬Á¿Ê±£¬ÒªÇóÈÜÒºµÄPHÖµÔÚ6.5-10.5·¶Î§ÄÚ£¬ÈçËá¶È¹ý¸ßÔò

A¡¢AgCl³Áµí²»ÍêÈ« B¡¢AgClÒ×Ðγɽº×´³Áµí

C¡¢AgCl³Áµí¶ÔCl-µÄÎü¸½Á¦ÔöÇ¿ D¡¢Ag2CrO4³Áµí²»Ò×ÐγÉ

E¡¢AgCl³Áµí¶ÔAg+

µÄÎü¸½Á¦ÔöÇ¿

A3¡¢ÏÂÁÐÀë×ÓÄÜÓøõËá¼ØÖ¸Ê¾¼Á·¨²â¶¨µÄÊÇ

A¡¢Cl- B¡¢Ag+ C¡¢Ba2+ D¡¢SCN- E¡¢I-

B4¡¢ÓÃÌúï§·°Ö¸Ê¾¼Á·¨²â¶¨ÂÈ»¯Îïʱ£¬Îª·ÀÖ¹³ÁµíµÄת»¯£¬ÔÚ¼ÓÈë¹ýÁ¿µÄAgNO3µÎ¶¨Òººó£¬Ó¦¼ÓÈëÒ»¶¨Á¿µÄ

A¡¢NaHCO3 B¡¢Ïõ»ù±½ C¡¢ÏõËá D¡¢Åðɰ E¡¢CaCO3

C5¡¢AgNO3µÎ¶¨ÒºÓ¦´¢´æÓÚ

A¡¢°×É«ÈÝÁ¿Æ¿ B¡¢×ØÉ«ÈÝÁ¿Æ¿ C¡¢×ØÉ«ÊÔ¼ÁÆ¿ D¡¢°×É«ÊÔ¼ÁÆ¿ E¡¢×ØÉ«µÎ¶¨¹Ü

D6¡¢¸õËá¼ØÖ¸Ê¾¼Á·¨²â¶¨NaClº¬Á¿Ê±£¬ÆäµÎ¶¨ÖÕµãµÄÑÕÉ«ÊÇ

A¡¢»ÆÉ« B¡¢°×É« C¡¢µ­×ÏÉ« D¡¢µ­ºìÉ« E¡¢»ÆÂÌÉ«

C7¡¢AgCl±ÈAg2CrO4ÏȳÁµíµÄÔ­ÒòÊÇ

A¡¢AgCl±ÈAg2CrO4¿ÅÁ£Ð¡ B¡¢AgCl±ÈAg2CrO4¿ÅÁ£´ó C¡¢AgCl±ÈAg2CrO4Èܽâ¶ÈС D¡¢AgCl±ÈAg2CrO4Èܽâ¶È´ó E¡¢AgCl±ÈAg2CrO4ÈܶȻýС

B8¡¢ÔÚ³ÁµíµÎ¶¨·¨ÖУ¬Í¬Ê±¶¼ÒªÓõ½AgNO3ºÍNH4SCNÁ½Öֵζ¨ÒºµÄ·½·¨ÊÇ

A¡¢¸õËá¼ØÖ¸Ê¾¼Á·¨ B¡¢Ìúï§·°Ö¸Ê¾¼Á·¨ C¡¢Îü¸½Ö¸Ê¾¼Á·¨ D¡¢NaOHË®½â·¨ E¡¢Na2CO3ÈÛÈÚ·¨

C9¡¢ÔÚÒøÁ¿·¨ÖÐÒªÓõ½µÄ»ù×¼ÎïÖÊÊÇ

A¡¢Na2CO3 B¡¢ÁÚ±½¶þ¼×ËáÇâ¼Ø C¡¢NaCl D¡¢Åðɰ E¡¢ZnO

ABD10¡¢Äܹ»ÓÃÓÚ³ÁµíµÎ¶¨·´Ó¦±ØÐë·ûºÏµÄÌõ¼þÊÇ

A¡¢³Áµí·´Ó¦±ØÐëÄÜѸËÙ¶¨Á¿Íê³É

B¡¢Éú³ÉµÄ³ÁµíÈܽâ¶È±ØÐë×㹻С£¨S£¼10-6

g/ml£© C¡¢±ØÐëÓÐÆøÌåÉú³É

D¡¢±ØÐëÓÐÊʵ±µÄָʾ»¯Ñ§¼ÆÁ¿µãµÄ·½·¨ E¡¢±ØÐëÓÃAgNO3×÷µÎ¶¨Òº

BC11¡¢ÔÚ³ÁµíµÎ¶¨ÖУ¬Ó°ÏìµÎ¶¨ÇúÏßͻԾ·¶Î§µÄÒòËØÊÇ

A¡¢ÈÜÒºµÄPHÖµ B¡¢ÈÜÒºµÄŨ¶È C¡¢³ÁµíµÄÈܽâ¶È D¡¢µÎ¶¨ÒºµÄÀàÐÍ E¡¢³ÁµíµÄ¿ÅÁ£¶È

ABC12¡¢¸ù¾Ýָʾ¼Á²»Í¬£¬ÒøÁ¿·¨¿É·ÖΪ

A¡¢¸õËá¼ØÖ¸Ê¾¼Á·¨ B¡¢Ìúï§·°Ö¸Ê¾¼Á·¨ C¡¢Îü¸½Ö¸Ê¾¼Á·¨ D¡¢Ö±½ÓÒøÁ¿·¨ E¡¢»ØµÎÒøÁ¿·¨

AB13¡¢ÓÃÌúï§·°Ö¸Ê¾¼Á·¨²â¶¨ÂÈ»¯ÎïµÄº¬Á¿Ê±£¬ÎªÁ˱ÜÃâAg³Áµí·¢Éúת»¯£¬¿É²ÉÓõĴëÊ©ÓÐ

A¡¢½«Éú³ÉµÄAgCl³ÁµíÂËÈ¥£¬ÔÙÓÃNH4SCNµÎ¶¨

B¡¢ÔÚÓÃNH4SCNµÎ¶¨Ç°£¬ÏòÈÜÒºÖмÓÈëÏõ»ù±½±£»¤AgCl³Áµí C¡¢Ìá¸ßÌúï§·°Ö¸Ê¾¼ÁµÄŨ¶È D¡¢¿ØÖÆÈÜÒºµÄËá¶È E¡¢¿ØÖƺõζ¨ËÙ¶È

ABCD14¡¢ÒøÁ¿·¨²â¶¨µÄ¶ÔÏóÊÇ

A¡¢ÎÞ»ú±»¯Îï B¡¢Óлú±»¯Îï C¡¢ÁòÇèËáÑÛ D¡¢Óлú¼îÇâ±ËáÑÎ E¡¢ÉúÎï¼îµÄÓлúËáÑÎ

¶þ¡¢ÅжÏÌâ

8

ÁªÏµ¿Í·þ£º779662525#qq.com(#Ìæ»»Îª@)