68¡¢ÈçͼËùʾÉäÁ÷±Ã£¬Æä¹¤×÷ÔÀíÊǽ蹤×÷ÊÒÖйÜ×ì¸ßËÙÉäÁ÷²úÉúÕæ¿Õ£¬½«Íⲿˮ³ØÖеÄË®Îü½ø¹¤×÷ÊÒ£¬ È»ºóÔÙÓÉÉäÁ÷´ø½ø³ö¿Ú¹Ü¡£ÒÑÖª H=2 m£¬h=1 m£¬d1=10 cm£¬d2=7 cm£¬²»¼ÆË®Í·Ëðʧ£¬ÊÔÇó£º(1)ÉäÁ÷±ÃÌṩµÄÁ÷Á¿ qv£»(2)¹¤×÷ÊÒÖÐ3©¤3¶ÏÃæ´¦µÄÕæ¿Õ¶Èhv3¡£ £¨qV?49.2l/s£»hV3?5.33mH2O£©
69¡¢ÔÚÖ±¾¶ d=150 mm µÄÊäË®¹ÜÖУ¬×°ÖÃÒ»¸½ÓÐË®Òø²î¼ÆµÄ±ÏÍйܣ¬Ë®ÒøÃæ¸ß²î ¦¤h=20 mm£¬Éè¹ÜÖжÏÃæÆ½¾ù Á÷ËÙ v=0.8umax£¬ÊÔÇ󣺹ÜÖÐÁ÷Á¿ qv¡£ £¨31 l/s£©
70¡¢ÓúçÎü¹Ü´ÓË®¿âÖÐȡˮ£¬ÒÑÖª d=10 cm£¬ÆäÖÐÐÄÏßÉÏ×î¸ßµã3³¬³öË®¿âË®Ãæ2m£¬ÆäˮͷËðʧΪ£ºµã1µ½µã3 Ϊ 222
10v£¯2g£¬(ÆäÖÐ1ÖÁ2µãΪ 9v£¯2g)£¬Óɵã3µ½µã4Ϊ2v£¯2g£¬ÈôÕæ¿Õ¸ß¶ÈÏÞÖÆÔÚ 7 mÒÔÄÚ¡£ÎÊ£º(1)ÎüË®¹ÜµÄ×î´óÁ÷Á¿ÓÐÎÞÏÞÖÆ?ÈçÓÐӦΪ¶àÉÙ?³öË®¿ÚÖÁË®¿âË®ÃæµÄ¸ß²îhÓÐÎÞÏÞÖÆ?ÈçÓУ¬Ó¦Îª¶àÉÙ?(2) ÔÚͨ¹ý×î´óÁ÷Á¿Ê±2µãÔÚ
P23
??4.526mH2O£© ѹǿΪ¶àÉÙ? £¨qvmax?0.0234m£¯s?23.4 l£¯s£»hmax=5.9m£»
? 71¡¢ÈçͼËùʾ£¬Ë®ÔÚÎÞĦ²Á¹ÜµÀϵͳÖÐÁ÷¶¯£¬ÈôË®µÄÆû»¯Ñ¹Ç¿Îª7367 Pa£¬´óÆøÑ¹Á¦Îª99974 Pa£¬Ë®µÄÖØ¶È
3
¦Ñg=9730 N£¯m£¬ÊÔÇó±£Ö¤Ë®ÔÚ¹ÜÖв»·¢ÉúÆû»¯µÄ×î´ó¸ß¶È h¡£ £¨5.51m£©
1£¯7
72¡¢Ô²¹Ü¹ýË®¶ÏÃæÖ±¾¶ÉϵÄÁ÷ËÙ·Ö²¼¹æÂÉΪ u=u0 (1£r£¯r0)ʽÖÐ u Ϊ°ë¾¶ r ´¦µÄÁ÷ËÙ£¬u0ΪÖÐÐĵãµÄÁ÷ËÙ£¬r0ΪԲ¹Ü°ë¾¶¡£Éè r0=10 cm£¬²âµÃ u0=3 m£¯s£¬ÇóÁ÷Á¿¼°¶ÏÃæÆ½¾ùÁ÷ËÙ v0¡£ £¨qv ?0.0774m2/s; v0?2.46m/s£©
18
73¡¢Ä³ÒºÌåÔÚÁ½Æ½°åÖ®¼äÁ÷¶¯£¬Æä¶ÏÃæÁ÷ËÙ·Ö²¼Èçͼʾ¡£Çó¶ÏÃæÆ½¾ùÁ÷ËÙ vÓë×î´óÁ÷ËÙ umaxµÄ¹ØÏµ¡£ £¨v?1 umax£©
2 74¡¢Ä³ÇþµÀÔÚÒýˮ;ÖÐÒª´©¹ýÒ»ÌõÌú·£¬ÓÚ·»ùÏÂÃæÐÞ½¨Ô²ÐζÏÃæº¶´Ò»×ù£¬ÈçͼËùʾ¡£ÒÑÖªº¶´Éè¼ÆÁ÷Á¿
32
qv= 1m£¯s£¬º¶´ÉÏÏÂÓΠˮλ²î z=0.3 m£¬º¶´Ë®Í·Ëðʧ hw=1.47v£¯2g (vΪ¶´ÄÚÁ÷ËÙ)£¬º¶´ÉÏÏÂÓÎÇþµÀÁ÷ËÙºÜС£¬ËÙ¶Èˮͷ¿ÉºöÂÔ¡£Ç󺶴ֱ¾¶ d¡£ £¨0.80m£©
75¡¢¶¯Á¿ÊµÑé×°ÖÃΪһÅç×ìÏòÕý½»ÓÚÉäÁ÷·½ÏòµÄƽ°åÅçË®£¬ÒÑÖªÅç×ì³ö¿ÚÖ±¾¶Îª 10 mm£¬²âµÃƽ°åÊÜÁ¦Îª 100N£¬ÇóÉäÁ÷Á÷Á¿¡£ £¨2.8 l/s£©
76¡¢Ë®×ÔÃÜ·âÈÝÆ÷ÑØ¹Ü·Á÷³ö£¬ÈÝÆ÷ÒºÃæÉϵÄÕæ¿Õ¶ÈΪ 1kPa£¬²»¼ÆË®Í·Ëðʧ£¬Çó£º(1)Á÷Á¿£»(2)AµãÁ÷ËÙ£» (3)¹ÜÖÐѹǿ×îµÍµãµÄλÖü°Æä¸ºÑ¹Öµ¡£ £¨£¨1£©154 l/s£» £¨2£©19.67m/s£» £¨3£©135.45Kpa£© 77¡¢À¸ñÀÊÈÕ»ý·ÖÒªÇóÁ÷¶¯ÎªÎÞÐý£¬µ«¿ÉÒÔÊǷǺ㶨Á÷¶¯£»¶ø¿ÂÎ÷-²®Å¬Á¦»ý·Ö²»½öÒªÇóÁ÷¶¯ÎªÎÞÐý, ÇÒÒªÇóÊǺ㶨Á÷¶¯ ¡£ ( ) 78¡¢ÀíÏëÒºÌåÊôÓÚÓÐÊÆÁ÷,ʵ¼ÊÒºÌå¶¼ÊÇÓÐÎÐÁ÷. ( ) 79¡¢ÈôÒºÌåÖʵã×÷Ô²ÖÜÔ˶¯,Á÷ÏßΪͬÐÄÔ²,Ôò´ËÀàÁ÷¶¯Ò»¶¨ÎªÓÐÎÐÁ÷(ÓÐÎÐÐý)¡£ ( ) 80¡¢²»¿ÉѹËõÒºÌåµÄÆ½ÃæÁ÷¶¯ÖдæÔÚÁ÷º¯Êý£¬Ôò±Ø¶¨´æÔÚÊÆº¯Êý¡£ ( ) 81¡¢ÔÚÆ½ÃæÁ÷¶¯ÖÐ,Á½Á÷ÏßÖ®¼äͨ¹ýµÄµ¥¿íÁ÷Á¿µÈÓÚ¸ÃÁ½Á÷ÏßµÄÁ÷º¯ÊýÖµÖ®²î¡£ ( ) 82¡¢²»¿ÉѹËõÒºÌåÁ¬ÐøÐÔ΢·Ö·½³Ì
?ux?uy?uz???0Ö»ÊÊÓÃÓں㶨Á÷¡£ ( ) ?x?y?z83¡¢ÔÚÆ½ÃæÁ÷¶¯ÖУ¬Á½ÌõÁ÷ÏßµÄÁ÷º¯ÊýÖ®²îµÈÓÚ ( )
(1) Á½ÌõÁ÷Ïß¼äµÄÇÐÓ¦Á¦²î (2) Á½ÌõÁ÷Ïß¼äµÄѹǿ֮²î (3)Á½ÌõÁ÷Ïß¼äµÄÁ÷ËÙ²î (4) Á½ÌõÁ÷Ïߵĵ¥¿íÁ÷Á¿ 84¡¢ÒºÌå×÷ÓÐÊÆÔ˶¯Ê± ( ) (1) ×÷ÓÃÓÚÒºÌåµÄÁ¦£¬±ØÐëÊÇÓÐÊÆµÄ (2) ÒºÌåµÄ½Ç±äÐÎËÙ¶ÈΪÁã
(3) ÒºÌåµÄÐýת½ÇËÙ¶ÈΪÁã (4) ÒºÌåÑØÁ÷ÏòµÄѹǿÌݶÈΪÁã
19
85¡¢²®Å¬Á¦»ý·ÖµÄÓ¦ÓÃÌõ¼þΪ ( ) (1) ÀíÏëÕýѹÁ÷Ì壬ÖÊÁ¿Á¦ÓÐÊÆ£¬·Çºã¶¨ÎÞÐýÁ÷¶¯; (2) ²»¿ÉѹËõÁ÷Ì壬ÖÊÁ¿Á¦ÓÐÊÆ£¬·Çºã¶¨ÓÐÐýÁ÷¶¯
(3) ÀíÏëÕýѹÁ÷Ì壬ÖÊÁ¿Á¦ÓÐÊÆ£¬ºã¶¨Á÷¶¯£¬ÑØÍ¬Ò»Á÷Ïß
(4) ÀíÏëÕýѹÁ÷Ì壬ÖÊÁ¿Á¦ÓÐÊÆ£¬·Çºã¶¨Á÷¶¯ £¬ÑØÍ¬Ò»Á÷Ïß
86¡¢ÀíÏëÒºÌåºã¶¨ÓÐÊÆÁ÷¶¯£¬µ±ÖÊÁ¿Á¦½öÎªÖØÁ¦Ê±£¬ ( )
pu2?)ÏàµÈ£» (1) Õû¸öÁ÷³¡ÄÚ¸÷µãµÄ×Üˮͷ(z??g2gpu2?)ÏàµÈ£» (2) Ö»ÓÐλÓÚͬһÁ÷ÏßÉϵĵ㣬×Üˮͷ(z??g2g(3) ÑØÁ÷Ïß×ÜË®Í·ÑØ³Ì¼õС£»
pu2?)ÑØ³ÌÔö¼Ó£» (4) ÑØÁ÷Ïß×Üˮͷ(z??g2g_,uy____________.¡£ 87¡¢ÈôÒÑÖªÁ÷º¯Êý??a(x2?y2),aΪ³£Êý£¬Ôò ux?.__________88¡¢ºã¶¨Æ½ÃæÊÆÁ÷ÖУ¬×é³ÉÁ÷ÍøµÄÁ÷ÏßÓëµÈÊÆÏߵĹØÏµÊÇ_________________¡£
89¡¢ÒºÌåÖʵãµÄÔ˶¯ÐÎʽÓÐ________________________________________¡£
90¡¢ÀíÏëÒºÌåÔÚͬһµãÉϸ÷·½ÏòµÄ¶¯Ë®Ñ¹Ç¿ÊýÖµÊÇ___________µÄ¡£Êµ¼ÊÒºÌåÖеĶ¯Ë®Ñ¹Ç¿ÎªÔÚͬһµãÉÏÑØÈý¸öÕý½»·½ÏòµÄ¶¯Ë®Ñ¹Ç¿µÄ _________________________________________ £¬¶øpxx= __________ ____________£¬
pyy =________________________£¬pzz =____________________________¡£
91¡¢ÒºÌåÔ˶¯¿É¸ù¾Ý________________________________·ÖΪÓÐÎÐÁ÷ºÍÎÞÎÐÁ÷£¬ÎÞÎÐÁ÷ÊÇÖ¸ ________________________________£¬Ó¦Âú×ãµÄÅбðÌõ¼þÊÇ____________________________________¡£
92¡¢ÉèÒºÌåµÄÁ÷ËÙ³¡Îªux?6x,uy?6y,uz??7t,tΪʱ¼ä£¬Çó£º(1) µ±µØ¼ÓËÙ¶È£»(2) Ç¨ÒÆ¼ÓËÙ¶È£»(3) Öʵã¼ÓËÙ¶È¡£
93¡¢ÒÑÖªÆ½ÃæÎÞÐýÁ÷¶¯µÄËÙ¶È·ÖÁ¿ÓÉÏÂʽ¸ø³ö
ux?Ax?Byuy?Cx?Dy£»ÊÔÇó£º(1) A,B,C,DÖ®¼äµÄ¹ØÏµ£»(2) ËÙ¶ÈÊÆº¯Êý£»
(3)Á÷º¯Êý¡£ £¨(1) B=C ; A=£D ; (2) ??Bxy?A2B(x?y2)?c1£» (3) ? = Axy?(y2?x2)?c2£© 22
2294¡¢ÒÑÖª²»¿ÉѹËõÒºÌåÆ½ÃæÁ÷¶¯µÄÁ÷º¯Êý??(x?y)/2¡£ ÒªÇó£º
22(1) »³ö¸ÃÁ÷¶¯µÄÁ÷ÏßͼÐΣ¬²¢±êÃ÷Á÷Ïò£» £¨Á÷Ïß??(x?y)/2?Const.£©
(2) ÅбðÊÇÓÐÐýÁ÷¶¯»¹ÊÇÎÞÐýÁ÷¶¯£» £¨ÓÐÐý£©
(3) ÒÑÖªÁ÷³¡ÖÐÁ½¶¨µã×ø±ê·Ö±ðΪ A(1,0) Óë B(2,3),ͨ¹ý´ËÁ½µã¼äµÄµ¥¿íÁ÷Á¿ q£» £¨q??B??A?6£©
2(4) A¡¢BÁ½µãÊÇ·ñÂú×ã·½³Ìu/2g?p/?g?c£¿ £¨·ñ£©
20
95¡¢Ö¤Ã÷Á½¹Ì¶¨Æ½ÐÐÆ½°å¼ä·¢Éú²ãÁ÷Ô˶¯Ê±£¬ÆäÁ÷ËÙ·Ö²¼Îªux?um(1?y2H)£¬Ê½ÖÐumΪvmaxµÄ×î´óÖµ£¬2HΪƽ°å¼ä¾à¡£
2
ˮѹǿ¡£ £¨21.3KPa£©
96¡¢ÓÐÒ»Á÷ÏßÐÍÎïÌå˳Á÷·ÅÖÃÓÚˮϵã A¾àÀëË®Ãæ2m´¦£¬À´Á÷Á÷ËÙÑØË®Éî·Ö²¼Îªux?2(y/H)17£¬ ÊÔÇóµã AµÄ ¶¯
2297¡¢ÒÑ֪ijһ²»¿ÉѹËõÒºÌåÆ½ÃæÁ÷¶¯µÄËÙ¶È·Ö²¼Îª£ºux?x?y?x,uy??(2xy?y)£¬ÒªÇó£º (1) ÅбðÊÇ·ñÂú×ãËÙ¶ÈÊÆº¯Êý ? ºÍÁ÷º¯Êý ? µÄ´æÔÚÌõ¼þ£¬²¢Çó ? ºÍ ?£» (2) Çóͨ¹ý A(1,1) B(1,2) Á½µã¼äÁ÷Á¿£» £¨1/3£© (3) д³öÇÐÓ¦Á¦¼°¸½¼ÓѹǿµÄ±í´ïʽ£»
(4) AµãµÄѹǿˮͷ pA/?g=2 m Ë®Öù£¬ÊÔÇó BµãµÄѹǿˮͷ¡£ £¨0.47mH2O£©
98¡¢²»¿ÉѹËõ¶þάÁ÷¶¯µÄÁ÷ËÙ·ÖÁ¿Îª£ºux?x?4y,uy??y?4x £¬ÒªÇó£º
(1) ¸ÃÁ÷¶¯ÊǺ㶨Á÷»¹ÊǷǺ㶨Á÷£» (2) ¸ÃÁ÷¶¯ÊÇ·ñÁ¬Ðø£» (3) д³öÁ÷Ïß·½³Ìʽ£» (4) ÅбðÓÐÎÞÏß±äÐκͽDZäÐÎÔ˶¯£» (5) ÅбðÓÐÎÐÁ÷»¹ÊÇÎÞÎÐÁ÷£» (6) ÅбðÊÇ·ñÎªÊÆÁ÷£¬ÈôÁ÷¶¯ÓÐÊÆ£¬Ð´³öÁ÷ËÙÊÆº¯Êý±í´ïʽ¡£
99¡¢ÈçͼËùʾ£¬ÔÚÒ»³¤Îª l£¬¶¥½ÇΪ?µÄÔ²×¶ÐιÜ×ìÖУ¬×ìÖÐË®Á÷ÒÔÒ»¶¨µÄÁ÷Á¿ qv Á÷¶¯²¢ÔÚ¶¥µãÁ¬ÐøµØÅç³ö¡£°´Í¼Ê¾È¡×ø±êÖá x£¬ÊÔÇó£º×ø±êΪx ¶ÏÃæ´¦µÄ¼ÓËÙ¶È ax¡£ £¨ax?2q2v?(l?x)(?tan)2252£©
21