22¡¢Ö¸³ö?fH?mµÈÓÚÁãµÄµ¥ÖÊ£¨ £©
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A ¡÷H3
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C
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¡÷H ¡÷H ¡÷H
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B ¡÷H2 D
A¡¢¡÷H1+ ¡÷H2+¡÷H3 =¡÷H4 B¡¢¡÷H1+ ¡÷H2 = ¡÷H3 +¡÷H4
C¡¢£¨¡÷H1+ ¡÷H2 £©££¨¡÷H3 +¡÷H4£©= ¡÷H5 D¡¢¡÷H1£«¡÷H2£«¡÷H3£«¡÷H4 =¡÷H5
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C(s) + O2(g) = CO(g) ¡÷H1
122C(s) + O2(g) =2 CO(g) ¡÷H?2
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28¡¢ÏÂÁÐÄÄÒ»·´Ó¦£¨»ò¹ý³Ì£©µÄìØÖµÊǼõСµÄ£¨ £© A¡¢NaCl¾§Ìå´ÓÈÜÒºÖÐÎö³ö B¡¢·´Ó¦C(s) + 1/2 O2(g) = CO(g) C¡¢CuSO4¡¤5H2O¾§ÌåÈÜÓÚË® D¡¢¹Ì̬I2µÄÉý»ª 29¡¢ÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ£¨ £©
A. Òò¦¤H=QP£¬¹ÊQÊÇ״̬º¯Êý B. ÔÚµÈѹÌõ¼þÏ£¬¦¤H=QP
C. µÈѹ²¢ÇÒÖ»×öÌå»ýÅòÕ͹¦µÄ¹ý³Ì¦¤H=QP D. QP×ÜÊÇ´óÓÚQV
30¡¢ÔÚ298KºÍ100KpaÌõ¼þÏ£¬N2ºÍH2»¯ºÏÉú³É1g NH3ʱ·ÅÈÈ27KJ£¬
ÄÇôNH3µÄ?fH?ÊÇ ( ) m(298.15K)A. ¨C 46KJ?mol-1 B. ¨C 46KJ C. + 46KJ?mol-1 D. ¨C ?g-1
31¡¢ÌìÈ»ÆøµÄÖ÷Òª³É·ÖÊÇCH4, ÒÑÖªCH4£¨g£©,CO2(g)¼°H2O(l)µÄ
?fH?ol?1)·Ö±ðΪ ¨C75£¬¨C394ÒÔ¼°¨C286£¬ÄÇôm(kJ?m1m3(273K,101Kpa) CH4ÍêȫȼÉÕʱ£¬Ó¦·ÅÈÈ£º( ) A. 2.7¡Á104KJ B. 891KJ¡¤mol-1 C. ¡Á104KJ D. ÎÞ·¨¼ÆËã
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32¡¢ÒÑÖªN2(g)+3H2(g)=2NH3(g), ?rH?= ¨C¡¤mol£¬ÆäÖÐmolÊÇÖ¸£¨ £© m A. ÿmol NH3 B. ÿmol H2 C. ÿmol H2 D. ÿmol ÉÏÊö·´Ó¦ 33¡¢Ê¯Ä«ºÍ½ð¸ÕʯµÄȼÉÕÈÈ·Ö±ðÊÇ394ºÍ396KJ¡¤mol-1, ÄÇô½ð¸Õʯ
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A. ¨C790 KJ¡¤mol-1 B. 2KJ¡¤mol-1 C. +790 KJ¡¤mol-1 D. ¨C2 KJ¡¤mol-1 34¡¢ÒÑÖªÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ
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£¨1£©C(g) + O2(g) = CO2(g) ?rH?= ¨C394KJ¡¤mol m-1£¨2£©H2 (g) + 1/2O2(g) = H2O(l) ?rH?= ¨C286KJ¡¤mol m£¨3£©C2H6(g) + 7/2O2(g) = 2CO2(g) +3H2O(l) ?rH?= ¨C286KJ¡¤mol-1 mÓɴ˿ɵÃC2H6 (g)µÄ?fH?µÈÓÚ ( ) m(298.15K)A. ¨C1560KJ¡¤mol-1 B. ¨C86KJ¡¤mol-1
C. +86 KJ¡¤mol-1 D. ÎÞ·¨¼ÆËã 35¡¢Í¬ÎÂͬѹÌõ¼þÏ£¬°´ìØÖµµÝÔö´ÎÐòÅÅÁÐÕýÈ·µÄ£¨ £©
A. H2O(l) H2O(g) H2O(s) B. Cl2(l) Br2 (l) I2(s) C. Na(s) NaCl(s) CaCl2(s) D. O3(g) O2(g) O(g)
36¡¢±½µÄÈÛµãΪoC, ÈÛ»¯ÈÈΪ KJ¡¤mol-1£¬ÄÇô±½µÄÈÛ»¯¹ý³Ì¦¤SµÈ
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A. 2.1 KJ¡¤mol-1¡¤K-1 B. ¡¤mol-1 C. KJ¡¤mol-1¡¤K-1 D. J¡¤mol-1¡¤K-1
37¡¢ÒÑÖªB2H6(g)ºÍH2O(l)µÄ?fH?·Ö±ðΪ+ KJ¡¤mol-1ºÍ¨C286 m(298.15K)KJ¡¤mol-1,ÓÖÒÑÖªB2H6(g)µÄȼÉÕֵΪ¨C2153 KJ¡¤mol-1£¬Ôò¿ÉÇóµÃB2O3(g)µÄ?fH?Ϊ£¨ £© m(298.15K)A. -1836 KJ¡¤mol-1 KJ¡¤mol-1 C . +2153 KJ¡¤mol-1 D.+1264 KJ¡¤mol-1
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2£®ÒÑÖª·´Ó¦ 4NH3(g) + 5O2(g) = 4NO(g) + 6H2O(l)
¦¤rH?m = £
4NH3(g) + 3O2(g) = 2N2(g) + 6H2O(l)
¦¤rH?m = £