C. D.
Na(s) NaCl(s) CaCl2(s) O3(g) O2(g) O(g)
36¡¢±½µÄÈÛµãΪ5.0oC, ÈÛ»¯ÈÈΪ10.7 KJ¡¤mol-1£¬ÄÇô±½µÄÈÛ»¯¹ý³Ì¦¤SµÈÓÚ£¨ £© A. 2.1 KJ¡¤mol-1¡¤K B. 10.7KJ¡¤mol-1
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C. 38.5 KJ¡¤mol-1¡¤K D. 38.5 J¡¤mol-1¡¤K
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37¡¢ÒÑÖªB2H6(g)ºÍH2O(l)µÄ?fH?·Ö±ðΪ+31.4 KJ¡¤mol-1ºÍ¨C286 KJ¡¤mol-1,ÓÖÒÑÖªB2H6(g)µÄȼÉÕm(298.15K)ֵΪ¨C2153 KJ¡¤mol-1£¬Ôò¿ÉÇóµÃB2O3(g)µÄ?fH?Ϊ£¨ £© m(298.15K)A. -1836 KJ¡¤mol-1 B.-1264 KJ¡¤mol-1 C . +2153 KJ¡¤mol-1 D.+1264 KJ¡¤mol-1
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1£® Ìåϵ¶Ô»·¾³×öÁË200JµÄ¹¦£¬ÌåϵÐë´Ó»·¾³____ ÈÈ______ J£¬²ÅÄÜʹÌåϵÈÈÁ¦Ñ§ÄÜÔö¼Ó50J¡£ 2£®ÒÑÖª·´Ó¦ 4NH3(g) + 5O2(g) = 4NO(g) + 6H2O(l)
¦¤rH?m = £1170KJ.mol-1
4NH3(g) + 3O2(g) = 2N2(g) + 6H2O(l)
¦¤rH?m = £1530KJ.mol-1
ÔòNO(g) µÄ±ê׼Ħ¶ûÉú³Éìʦ¤fH?mΪ_______
3£® ÔÚ373KºÍ101.325Kpaʱ£¬ÒºÌ¬H2O±ä³ÉË®ÕôÆûµÄ¹ý³ÌÖÐ
¦¤rG?m___________£»¦¤rH?m_________£»¦¤rS?m______(Ìî>0 =0 <0)
4£® ·´Ó¦2N2(g) + O2(g) = 2N2O(g)ÔÚ298KʱµÄ¦¤rH?m = 164.0KJ.mol-1,Ôò´Ë·´Ó¦µÄ¦¤rU?mΪ_________KJ.mol-1 5£®ÔÚ298KºÍ101.325Kpaʱ£¬ÒÑÖªÏÂÁз´Ó¦
C(s) + H2O(g) = CO(g) + H2(g)
¦¤fH?m/KJ.mol-1 £241.8 £110.5
?.-1 ¦¤fGm /KJmol
£228.6 £137.2
Ôò¦¤rS?mΪ__________J.mol-1.K-1
6. Èç¹ûÒ»¸ö·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬¶ø·´Ó¦µÄìØ±äСÓÚÁ㣬Ôò¸Ã·´Ó¦ÔÚ__________ÊÇ¿ÉÒÔ×Ô·¢µÄ£¬__________ϾͲ»
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7. ·´Ó¦N2(g) + 3H2(g) = 2NH3(g) µÄ¦¤rH?m,298 = £92.2KJ.mol-1£¬ ÈôÉý¸ßζȣ¬Ôò¦¤rH?m,T_______________£»¦¤rS?m,T______________£»¦¤rG?m,T_________£¨ÒªÇó¶¨ÐԻشð£©
8. »¯Ñ§·´Ó¦A(g) + B(g) = 2C(g)£¬ A¡¢B¡¢C¾ùΪÀíÏëÆøÌ壬ÔÚ250C±ê׼״̬Ï£¬¸Ã¹ý³Ì·Ö±ðÒÀÁ½¸ö²»Í¬Í¾¾¶Íê³É£º£¨1£©²»×ö¹¦£¬·ÅÈÈ40KJ£»£¨2£©×ö×î´ó¹¦£¬·ÅÈÈ2KJ¡£ÔòÔÚ£¨1£©¡¢£¨2£©Á½Çé¿öÏ£¬¦¤H?·Ö±ðΪ__________£¬__________£»¦¤G?·Ö±ðΪ__________£¬__________£» ¦¤S?·Ö±ðΪ__________£¬__________¡£ ËÄ¡¢ ¼ÆËãÌâ
1¡¢ÀûÓÃÏÂÁз´Ó¦µÄ¦¤rG?m£¬¼ÆËãFe3O4(s)ÔÚ298KʱµÄ±ê׼Ħ¶ûÉú³É¼ª²¼Ë¹×ÔÓÉÄܦ¤fG?m.
(1) 2Fe(s) + 3/2O2(g) = Fe2O3(s) ¦¤rG?m = £742KJ.mol-1 (2) 4 Fe2O3(s) + Fe(s) = 3 Fe3O4(s) ¦¤rG?m = £78 KJ.mol-1
2¡¢ÉèÏÂÁз´Ó¦
(1) A + B = C + D ¦¤rH?m = £40 KJ.mol-1 (2) C +D = E ¦¤rH?m = 60 KJ.mol-1
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A. B. C.
C + D = A + B 2C +2D = 2A + 2B A + B = E
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CO(g) = C(ʯī) + O2(g)
¦¤fH?m /(KJ.mol-1) £110.53 0 0 S?m/(J.mol-1.K-1) 197.56 5.74 205.03
4¡¢ÒÑÖªµ¥Ð±ÁòµÄS?= 32.6 J.mol-1.K-1,¦¤Hc? = £297.19KJ.mol-1£¬Õý½»ÁòµÄ S?= 31.8 J.mol-1.K-1£¬¦¤Hc? =
-296.90KJ.mol-1£» ÔÚ101Kpa¼°95.50CʱÕý½»Áòת»¯Îªµ¥Ð±Áò£¬¼ÆËã˵Ã÷ÔÚ¸ÃѹÁ¦Ï£¬Î¶ȷֱðΪ250CºÍ95.50C£¬ÁòµÄÄÄÖÖ¾§ÐÍÎȶ¨¡£
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ÒÑÖª298Kʱ: W(s) I2(g) WI2(g) ¦¤fH?m /(KJ.mol-1) 0 62.24 £8.37 S?m/(J.mol-1.K-1) 33.5 260 250.4
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