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1ln(l2?h2) 2dDldl?hdh?2 ΢·ÖºóµÃ£º 2Dl?hlh222 תΪÖÐÎó²îµÃ£ºmD?(ml)?(mh)

DD302.30?0.005)2?(?0.04)2 =(29.91229.912 lnD=

=0.000025+0.000009=0.000034

mD =¡À0.0058m

µÚ 49 Ò³ ¹² 123 Ò³

(17)½â: m×Ü=¡À934=¡À12(mm) Éèˮ׼·ÏßÏß³¤D km

12D¡Ü24 ¡à D¡Ü(

242

)=4(km) 12

VV 9mm 25 4 25 9 4 [VV]=76 (18)

Ðò ºÅ 1 2 3 4 5 6 ¹Û ²â ÖµL 256.565 256.563 256.570 256.573 256.571 256.566 L=256.568 V -3mm -5 +2 +5 +3 -2 [V]=0 ¾«¶ÈÆÀ¶¨£º¹Û²âÖµÖÐÎó²î£º£í=¡À3.9mm ËãÊõƽ¾ùÖµÖÐÎó²î£ºM=¡À1.6mm (19)½â: (a) m§¡/DA=1/3521 mB/DB=1/4010

(b)¡ÆD= DA + DB ¦¤D= DA - DB

m¡Æ2=m§¡2+ m¦¢2 m¡Æ =¡À0.05m m¦¤D =¡À0.05m

Á½¶Î¾àÀëÖ®ºÍÓëÖ®²îÖÐÎó²îµÄÏà¶ÔÖÐÎó²î¾ùΪ m¡Æ/(D§¡+ DB)=1/5223

£¨20£© mÖÕ=83m¦Â=835=¡À14.1¡å

n¡Ü(mÖÕ/m¦Â)2=(18/5) 2 =12.9 ×î¶àÉè13¸öתÕÛ½Ç

(21)M=

mn=

95=¡À4.0¡å n¡Ý(

m29)=()2 =6.6 M3.5n=7²â»Ø

(22)h=100.08tg15¡ã30¡ä00¡å+1.48-1.00=28.23Ã× mh2=(tg¦Á3mD)2+(D3sec2¦Á3m¦Á/¦Ñ¡å) 2+mi2+mv2 =(tg15¡ã30¡ä00¡å30.05) 2+

(100.083sec215¡ã30¡ä00¡å320/206265) 2+(0.01) 2 +(0.01) 2

=0.000192+0.0001092+0.0001+0.0001=0.000501m 2

mh =¡À0.022m (23) (a)f¦Â=¦²¦Â-540¡ã

µÚ 50 Ò³ ¹² 123 Ò³

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