1(H ) + CF (H ) . 1(H CF (H ) = 0.36 + 0.48 . 0.36 × 0.48 =
0.6672 CF ) CF 22 CF H 12 3 =
0.3672 () = CF (H ) + CF (H
) =
0.6672 . 0.3 CF (H)+ CF (H) 0.6672. 0.3 CF (H) = 12 3 == 0.5246 123 1. min{| CF 12 (H)|, |CF 3(H)|} 1.
min{0.6672,0.3} 5.15 p(E | LS) = 0.95 p(L | F) =
0 p(F) = 0.5 已知： pp ( ( EE | |. L. LS S ) ) = = 00. .89 pp ( ( SL | | F . ) F = ) = 0.19 求： p(F | E) p(E |.L.S) = 0.1
p(S |.F) = 0.1
1）求 p(E | F) p(E | F) = p(ELS | F)+ p(EL .S | F)+ p(E.LS | F)+ p(E.L.S | F) p(ELSF ) p(EL .SF) p(E.LSF )
p(E.L.SF) =+ + +
p(F) p(F) p(F)