Óлú»¯Ñ§Ï°Ìâ ÏÂÔر¾ÎÄ

£¨3£© ÒÒÈ©¡¢ÈýÂÈÒÒÈ©¡¢±ûͪ¡¢¼×È©

7. ÏÂÁл¯ºÏÎïÄÇЩÄÜ·¢Éúµâ·Â·´Ó¦£¿Ð´³öÆä·´Ó¦²úÎï¡£

£¨1£©¶¡Íª

£¨2£©Òì±û´¼

£¨3£©Õý¶¡´¼

£¨4£©3¡ªÎìͪ

O(5) C6H5CH2OH (6) CH3CH2CHCHO(7)CH3CHCH2CH3(8) CH3OH(9) (CH3)3COH(10)CH3CCH2CCH3(11) CCH3(12)OOO8£®ÊÔÎÊÏÂÁÐÖºÏÎï¿ÉÓɺÎÖÖȩͪת±äµÃÀ´£¿Ð´³öÆ䷴Ӧʽ¡£

CH3CHO

9£® ÇëÉè¼ÆÒ»¸ö·ÖÀëÎì´¼¡¢ÎìÈ©ºÍ3-ÎìͪµÄ»¯Ñ§·½·¨£¬²¢Ð´³öÓйصķ´Ó¦Ê½¡£

10£® Íê³ÉÏÂÁÐת»¯£¬²¢Ð´³ö·´Ó¦Ê½¡£

CH3CH2CHCH3(1)CH3CH2CHO OH

CH3COCH3 (2) CH3CH2OH

(3)ClCH2CH2CHOHOCH2CHOHCHO

(4) CH3COCH3CH2CCOOCH3

CH3

(5) CH3CHOCH3CH2CH2CHO CH3CH2COOCH2CH2CH3(6) CH3CH2CHO

11£®Ä³»¯ºÏÎï·Ö×ÓʽΪC5H12O(A)£¬Ñõ»¯ºóµÃ·Ö×ÓʽΪC5H10OµÄ»¯ºÏÎï(B)¡£BÄܺÍ2£¬4¡ª¶þÏõ»ù±½ë·´Ó¦

µÃ»ÆÉ«½á¾§£¬²¢ÄÜ·¢Éúµâ·Â·´Ó¦¡£(A)ºÍŨÁòËá¹²ÈȺó¾­ËáÐÔ¸ßÃÌËá¼ØÑõ»¯µÃµ½±ûͪºÍÒÒËá¡£ÊÔÍƳöAµÄ¹¹Ôìʽ£¬²¢Ó÷´Ó¦Ê½±íÃ÷ÍƵ¼¹ý³Ì¡£

12£®Ä³»¯ºÏÎïC8H14O(A)£¬¿ÉÒԺܿìµØʹäåË®ÍÊÉ«£¬¿ÉÒԺͱ½ë·¢Éú·´Ó¦£¬Ñõ»¯ºóµÃµ½Ò»·Ö×Ó±ûͪ¼°ÁíÒ»»¯

ºÏÎB£©¡£B¾ßÓÐËáÐÔ£¬ºÍ´ÎµâËáÄÆ·´Ó¦Éú²úµâ·ÂºÍÒ»·Ö×ÓôÈËᣬÆä½á¹¹ÊÇHOOCCH2CH2COOH¡£Ð´³ö(A)¡¢(B)µÄ½á¹¹Ê½¡£

13£®Ä³»¯ºÏÎï·Ö×ÓʽΪC6H12O£¬ÄÜÓëôÇ°·×÷ÓÃÉú³Éë¿£¬µ«²»ÆðÒø¾µ·´Ó¦£¬ÔÚ²¬µÄ´ß»¯Ï¼ÓÇâµÃµ½Ò»ÖÖ´¼¡£´Ë´¼¾­¹ýÍÑË®¡¢³ôÑõ»¯»¹Ô­Ë®½âµÈ·´Ó¦ºóµÃµ½Á½ÖÖÒºÌ壬ÆäÖÐÖ®Ò»ÄÜÆðÒø¾µ·´Ó¦µ«²»Æðµâ·Â·´Ó¦£¬ÁíÒ»ÖÖÄÜÆðµâ·Â·´Ó¦µ«²»ÄÜʹFehling ÊÔ¼Á»¹Ô­¡£ÊÔд³ö¸Ã»¯ºÏÎïµÄ½á¹¹Ê½¡£

14£®Ä³»¯ºÏÎïA·Ö×ÓʽΪC10H12O2£¬²»ÈÜÓÚÇâÑõ»¯ÄÆÈÜÒº£¬ÄÜÓëôÇ°±×÷ÓÃÉú³É°×É«³Áµí£¬µ«²»ÓëÍÐÂ×ÊÔ¼Á·´Ó¦¡£A¾­LiAlH4»¹Ô­µÃµ½B£¬·Ö×ÓʽΪC10H14O2¡£AÓëB¶¼ÄÜ·¢Éúµâ·Â·´Ó¦¡£AÓëŨHIËá¹²ÈÈÉú³ÉC£¬·Ö×ÓʽΪC9H10O2¡£CÄÜÈÜÓÚÇâÑõ»¯ÄÆ£¬¾­¿ËÀ³ÃÅÉ­»¹Ô­Éú³É»¯ºÏÎïD£¬·Ö×ÓʽΪC9H12O¡£ A¾­¸ßÃÌËá¼ØÑõ»¯Éú³É¶Ô¼×Ñõ»ù±½¼×Ëá¡£ÊÔд³öA¡¢B¡¢C¡¢DµÄ¹¹ÔìʽºÍÓйط´Ó¦Ê½¡£

µÚ°ËÕÂ

1£®ÃüÃûÏÂÁл¯ºÏÎï»òд³ö½á¹¹Ê½£º

ôÈËáºÍÈ¡´úËáÏ°Ìâ

ClOCH3OOCOCOH £¨1£© CH 3 CH 2 CH COOH £¨2£© CH C Cl £¨3£© H3

OO £¨4£© C O C H £¨5£© CH C CH C H C OOH £¨6£© E-2-¼×»ù-2-¶¡Ï©Ëá

253

£¨7£© ÒÒõ£ÒÒËá±ûõ¥ £¨8£© ¼×»ù¶¡¶þËáôû £¨9£© ¼×Ëá¼×õ¥ £¨10£© 2-Âȶ¡õ£äå

2£®½«ÏÂÁл¯ºÏÎï°´ËáÐÔÔöÇ¿µÄ˳ÐòÅÅÁУº £¨1£© ±½·Ó¡¢ÒÒËá¡¢±û¶þËá¡¢ÒÒ¶þËá

H2O¡¢CH3COOH¡¢C6H5OHH2CO3¡¢NH3¡¢ £¨2£© HCOOH¡¢

3£®Íê³ÉÏÂÁз´Ó¦£º

CH3OH¡¢CH2 £¨1£©

CH2HBr?NaCN?H3O+¡÷?PCl3??CHOH?25?OH+ £¨2£© CHCHCHCOOHK2Cr2O7/H32?H2SO4?3¨¢¨¬?¨º??¨¢? £¨3£© ±½¼×´¼ ? ÂÈ»¯ÜÐ ? ±½ÒÒëæ ? ±½ÒÒËá

£¨4£© CH(CH)OH323

4£®Íê³ÉÏÂÁкϳɣ¨ÎÞ»úÊÔ¼ÁÈÎÑ¡£©£º £¨1£©ÓÉÒÒÏ©ºÏ³É±ûͪËáºÍ¶¡¶þËá¶þÒÒõ¥

?CH3(CH2)3Br??CH3(CH2)3MgBr?CH3(CH2)3COOHNa?COOHHOHCH3(CH2)2CH O2Br £¨2£©ÓÉÒÒȲºÏ³É±ûÏ©ËáÒÒõ¥ £¨3£©Óɱ½ºÏ³É¶Ô-Ïõ»ù±½¼×õ£ÂÈ £¨4£©ÓÉ»·¼ºÍªºÏ³É¦Á-ôÇ»ù»·¼º»ù¼×Ëá 5£®Óüò±ãµÄ»¯Ñ§·½·¨¼ø±ðÏÂÁи÷×黯ºÏÎ £¨1£©¼×Ëá¡¢ÒÒËá¡¢ÒÒËá¼×õ¥

£¨2£©ÁÚ-ôÇ»ù±½¼×Ëá¡¢ÁÚ-ôÇ»ù±½¼×Ëá¼×õ¥¡¢ÁÚ-¼×Ñõ»ù±½¼×Ëá 6£® ÏÂÁл¯ºÏÎïÖУ¬ÄÇЩÄܲúÉú»¥±äÒì¹¹£¬Ð´³öÆäÒì¹¹ÌåµÄ½á¹¹Ê½£º

OOOHCH3COCOC2H5OCH COC2H5CH3CCH2CCH3OO

OHCH2CH3CH CH3CH2CHO 7£®ÍƵ¼½á¹¹Ê½£¬²¢Ð´³öÓйط´Ó¦Ê½¡£

£¨1£©·Ö×ÓʽΪC3H6O2µÄ»¯ºÏÎÓÐÈý¸öÒì¹¹ÌåA¡¢B¡¢C£¬ÆäÖÐA¿ÉºÍNaHCO3·´Ó¦·Å³öCO2£¬¶øBºÍC²»¿É£¬BºÍC¿ÉÔÚNaOHµÄË®ÈÜÒºÖÐË®½â£¬BµÄË®½â²úÎïµÄÁó³öÒº¿É·¢Éúµâ·Â·´Ó¦¡£ÍƲâA¡¢B¡¢CµÄ½á¹¹Ê½¡£

£¨2£©Ä³»¯ºÏÎïA£¬·Ö×ÓʽΪC5H6O3£¬¿ÉÓëÒÒ´¼×÷Óõõ½»¥ÎªÒì¹¹ÌåµÄ»¯ºÏÎïBºÍC£¬BºÍC·Ö±ðÓëÑÇÁòõ£ÂÈ£¨SOCl2£©×÷Óúó£¬ÔÙÓëÒÒ´¼·´Ó¦£¬µÃµ½ÏàͬµÄ»¯ºÏÎÍƲâA¡¢B¡¢CµÄ½á¹¹Ê½¡£

£¨3£©Ä³»¯ºÏÎïA£¬·Ö×ÓʽΪC6H8O2£¬ÄܺÍ2£¬4-Ïõ»ù±½ë·´Ó¦£¬ÄÜʹäåµÄËÄÂÈ»¯Ì¼ÈÜÒºÍÊÉ«£¬µ«A²»ÄܺÍNaHCO3·´Ó¦¡£AÓëµâµÄNaOHÈÜÒº·´Ó¦ºóÉú³ÉB£¬BµÄ·Ö×ÓʽΪC4H4O4£¬BÊÜÈȺó¿É·Ö×ÓÄÚʧˮÉú³É·Ö×ÓʽΪC4H2O3µÄËáôûC¡£ÍƲâA¡¢BµÄ¹¹ÐÍʽºÍCµÄ½á¹¹Ê½¡£

£¨4£©Ä³»¯ºÏÎïA£¬·Ö×ÓʽΪC7H6O3£¬ÄÜÈÜÓÚNaOHºÍNaHCO3£¬AÓëFeCl3×÷ÓÃÓÐÑÕÉ«·´Ó¦£¬Óë(CH3CO)2O×÷ÓúóÉú³É·Ö×ÓʽΪ C9H8O4µÄ»¯ºÏÎïB ¡£AÓë¼×´¼×÷ÓÃÉú³ÉÏãÁÏ»¯ºÏÎïC£¬CµÄ·Ö×ÓʽΪ C8H8O3£¬C¾­Ïõ»¯Ö÷ÒªµÃµ½Ò»ÖÖÒ»ÔªÏõ»ù»¯ºÏÎÍƲâA¡¢B¡¢CµÄ½á¹¹Ê½¡£

µÚ¾ÅÕ º¬µªºÍº¬Á×Óлú»¯ºÏÎïÏ°Ìâ

1£®ÃüÃûÏÂÁл¯ºÏÎï

£¨1£©CH3CH2NH2 £¨2£©CH3CH(NH2)CH3 £¨3£©(CH3)2NCH2CH3 £¨4£© £¨5£©[(CH3)3NC6H5] +OH

-

N(CH3)2

£¨6£©(CH3CH2)2N-NO

£¨7£©CH3CON(CH3)2 £¨8£© H2NCOOC2H5 £¨9£©H3CN2+Cl£­

(10)

N2N(CH3)2

2£®ÏÂÁи÷×黯ºÏÎï°´¼îÐÔÇ¿Èõ˳ÐòÅÅÁÐ £¨1£© ¶Ô¼×Ñõ»ù±½°·¡¢±½°·¡¢¶ÔÏõ»ù±½°· £¨2£© ±û°·¡¢¼×ÒÒ°·¡¢±½¼×õ£°·

£¨3£© ÇâÑõ»¯Ëļ×李¢ÁÚ±½¶þ¼×õ£ÑÇ°·¡¢ÄòËØ 3£®¼ø±ðÏÂÁи÷×黯ºÏÎï

£¨1£©Òì±û°·¡¢¶þÒÒ°·¡¢Èý¼×°·

£¨2£©±½°·¡¢Ïõ»ù±½¡¢Ïõ»ùÜÐ £¨3£©±½°·¡¢»·¼º°·¡¢N-¼×»ù±½°· 4£®Íê³ÉÏÂÁз´Ó¦Ê½

£¨1£©CH2=CHCH2Br +NaCN

£¨2£©£¨CH3£©3 N + CH3CH2I £¨3£©CH3CH2NH2 + CH3COCl (4) [(CH3)3N +CH2CH3]OH

£­

H+ £¿ £¿

HO2 £¿ £¿

AgOH|¡è|¡è (5)CH3CH£­CONH2 + HNO2

NH2

(6) CH3CH2NHCH2CH3 + (CH3CO)2O

£¨7£©COCl+NH3?Br2/NaOH¦¤?NaNO2/HCl0 5C¡£?OHÈõOH-?

£¨8£©HNO3H2SO4?Fe/HCl?SO2ClNaOH?

5£®ÓÉÖ¸¶¨Ô­ÁϺϳÉÏÂÁл¯ºÏÎÎÞ»úÊÔ¼Á¿ÉÈÎÈ¡£© £¨1£©Óɱ½ºÏ³É¼äÈýäå±½ £¨2£©Óɼױ½ºÏ³É¶Ô°±»ù±½¼×Ëá £¨3£©Óɱ½ºÏ³É4-ôÇ»ù-4-ÂÈżµª±½ £¨4£©Óɱ½°·ºÏ³É¶ÔÏõ»ù±½¼×õ£ÂÈ

6£®ÊÔ·ÖÀë±½°· ¡¢Ïõ»ù±½¡¢±½·Ó¡¢±½¼×ËáµÄ»ìºÏÎï¡£

7£®Ä³»¯ºÏÎA£©·Ö×ÓʽΪC7H7NO2 £¬ÎÞ¼îÐÔ£¬»¹Ô­ºóµÃµ½£¨B£©£¬½á¹¹Ãû³ÆΪ¶Ô¼×±½°·¡£µÍÎÂÏ£¨B£©ÓëÑÇÏõËáÄƵÄÑÎËáÈÜÒº×÷Óõõ½£¨C£©£¬·Ö×ÓʽΪC7H7N2Cl ¡££¨C£©ÔÚÈõ¼îÐÔÌõ¼þÏÂÓë±½·Ó×÷Óõõ½·Ö×ÓʽΪC13H12ON2µÄ»¯ºÏÎD£©¡£ÊÔÍƲ⣨A£©¡¢£¨C£©ºÍ£¨D£©µÄ½á¹¹¡£

8£®·Ö×ÓʽΪC7H7NO2µÄ»¯ºÏÎA£©¡¢£¨B£©¡¢£¨C£©¡¢£¨D£©£¬ËüÃǶ¼º¬Óб½»·£¬Îª1£¬4-ÑÜÉúÎï¡££¨A£©ÄÜÈÜÓÚËáºÍ¼î£»£¨B£©ÄÜÈÜÓÚËá¶ø²»ÈÜÓڼ£¨C£©ÄÜÈÜÓÚ¼î¶ø²»ÈÜÓÚË᣻£¨D£©²»ÈÜÓÚËáÒ²²»ÈÜÓڼÍƲ⣨A£©¡¢£¨B£©¡¢£¨C£©ºÍ£¨D£©µÄ¿ÉÄܽṹʽ¡£

9£®·Ö×ÓʽΪC6H13NµÄ»¯ºÏÎïA£¬ÄÜÈÜÓÚÑÎËáÈÜÒº£¬²¢¿ÉÓëHNO2·´Ó¦·Å³öN2£¬Éú³ÉÎïΪC6H12O£¨B£©¡£BÓëŨ H2SO4¹²ÈȵòúÎïC£¬C µÄ·Ö×ÓʽΪC6H10¡£CÄܱ»KMnO4ÈÜÒºÑõ»¯£¬Éú³É»¯ºÏÎïD£¨C6H10O3£©¡£DºÍNaOI×÷ÓÃÉú³Éµâ·ÂºÍÎì¶þËá¡£ÊÔÍƳöA¡¢B¡¢C¡¢DµÄ½á¹¹Ê½£¬²¢Ó÷´Ó¦Ê½±íʾÍƶϹý³Ì¡£

¡¯

µÚʮՠÓÍÖ¬ºÍÀàÖ¬»¯ºÏÎïÏ°Ìâ

1£®Ð´³öÏÂÁл¯ºÏÎïµÄ½á¹¹£º