工程化学基础(第二?浙江大学完美答案 - 百度文库 ر

2.4 ͵ 1. A 2. A

O2,N2CO2ʵֱΪ0.213. 25ʱ1dmijУ

3dm0.780.01ѹΪ100kPa¸ʵķѹ2CO23ķѹΪ٣

⣺pCO2=100*0.01=1kPa

pO2=21 kPa

pN2=78 kPa p?CO2=0.5 kPa

4.20ʱijˮʵѹΪ1.001 kPaʱԿʪȣ

¶Ƚ͵10棬ʪΪ٣ ⣺ã

1.001 2.339?100%?42.8% 1.001 1.228?100%?81.5%

5. <5.6 CO2SO2NO , H2SO4H2SO3HNO3HNO2H2CO3 6. 塱Щ𡰳նЩ 𣺢CO2CH4O3N2OCFC

NOxCFC

2.4 ͵ ˼

1.

2.ȫůն⻯ѧԭʲôԻкΣΪʲôH2O(g)Ϊ壿

ЧӦ̫͸һֱգ󲿷ֵ棬رԺʽ䣬CO2գӶֹ˵յɢʹ¡

ն⻯ѧNOXCFCԼһЩҵüȣڴܷһϵеĹ⻯ѧӦƻ㡣Σƻʹ䵽棬ֲಡӣٸ߷Ӳϵϻӳй⻯ѧӾ绷Ⱦɸ߿ƽ͵ů ΪH2O(g)ڿ۷ȡ

3.ߴһ֧Լ20 mg ΢Щ΢ֱΪ400 nm ܶΪ1.0 gcm3 壬ôЩ΢ܱǶ٣Ƕȷ̵Σ ã

A4?r233 Ai = =1.5105M-1 ????5V4?r3r2.0?10320?10?3g A = Ai V = Ai ?1.5?10?= 3000 M3

3?1.0g?cmm5

4.

5.ȫůն⻯ѧԭʲôԻкΣΪʲôH2O(g)Ϊ壿

ЧӦ̫͸һֱգ󲿷ֵ棬رԺʽ䣬CO2գӶֹ˵յɢʹ¡

ն⻯ѧNOXCFCԼһЩҵüȣڴܷһϵеĹ⻯ѧӦƻ㡣Σƻʹ䵽棬ֲಡӣٸ߷Ӳϵϻӳй⻯ѧӾ绷Ⱦɸ߿ƽ͵ů ΪH2O(g)ڿ۷ȡ

6.ߴһ֧Լ20 mg ΢Щ΢ֱΪ400 nm ܶΪ1.0 gcm3 壬ôЩ΢ܱǶ٣Ƕȷ̵Σ ã

A4?r233??? Ai = =1.5105M-1 ?5V4?r3r2.0?10320?10?3g3

A = Ai V = Ai ?1.5?10?= 3000 M

?1.0g?cm3m5

ʵĽṹͲϵ

3.1 ԭӺ˶״̬

1.бжԭӺ˶˵ЩȷģЩǴģ

a) b) c) 2.λ

3.n 0,1,2,34 4f 7 4.桢䣩

5.Ԫػ̬ԭӵйд±

̬ Ƿ ɵ

6.蘆ĵݳΪ3.0410-19 J

1ʹ爐ЧӦĹСƵʼ䲨Ƕ٣

2ҪﵽΪ2.410-19J,ʹòΪ׵Ĺ䣿 ⣺ã

1 p 2s 2 0 1 2 2d 3p 3 1 3 6 5f 5 3 7 14 6s 6 0 1 2 ??3.04?10?19J? (1) ??=4.591014 s-1 ?34h6.63?10J?s3.0?108m?s?1????6.54?10?7m 14?1?4.59?10schc3.0?108m?s?1?6.63?10?34J?s??8.3?10?7m (2) ????19???2.4?10Jc