C£®ÎÞÂÛN¼«ÏòϲåÈ뻹ÊÇS¼«ÏòϲåÈ룬´ÅÌú¶¼Êܵ½ÏòϵÄÒýÁ¦ D£®ÎÞÂÛN¼«ÏòϲåÈ뻹ÊÇS¼«ÏòϲåÈ룬´ÅÌú¶¼Êܵ½ÏòÉϵijâÁ¦
11.ÈçͼËùʾ£¬a¡¢b¡¢cÊÇÒ»¸ºµãµçºÉ²úÉúµÄµç³¡ÖеÄÒ»Ìõµç³¡ÏßÉϵÄÈý¸öµã£¬µç³¡Ïߵķ½ÏòÓÉaµ½c£¬a¡¢b¼ä¾àÀëµÈÓÚb¡¢c¼ä¾àÀ룬ÓÃUa¡¢Ub¡¢UcºÍEa¡¢Eb¡¢Ec·Ö±ð±íʾa¡¢b¡¢³¡Ç¿¶È£¬¿ÉÒÔÅжÏ( ) A.Ea£¼Eb£¼Ec B.Ua£¾Ub£¾Uc C.Ua=Ub=Uc D.Ea=Eb=Ec
12.A¡¢BÁ½¸öÎïÌåÔÚͬһֱÏßÉÏ×öÔȱäËÙÖ±ÏßÔ˶¯£¬ËüÃǵÄËÙ¶ÈͼÏñÈçͼËùʾ£¬Ôò£¨ £© A£®A¡¢BÁ½ÎïÌåÔ˶¯·½ÏòÒ»¶¨Ïà·´£» B£®4sÄÚA¡¢BÁ½ÎïÌåµÄÎ»ÒÆÏàͬ£» C£®t=4sʱ£¬A¡¢BÁ½ÎïÌåµÄËÙ¶ÈÏàͬ£» D£®AÎïÌåµÄ¼ÓËٶȱÈBÎïÌåµÄ¼ÓËÙ¶È´ó£»
¶þ¡¢ÊµÑéÌ⣨¹²12·Ö£©
13£®(6·Ö)һСÇòÔÚ×ÀÃæÉÏ´Ó¾²Ö¹¿ªÊ¼×öÔȼÓËÙÔ˶¯£¬ÏÖÓøßËÙÉãÓ°»úÔÚͬһµ×ƬÉ϶à´ÎÆØ¹â£¬¼Ç¼ÏÂСÇòÿ´ÎÆØ¹âµÄλÖ㬲¢½«Ð¡ÇòµÄλÖñàºÅ¡£ÈçͼËùʾ£¬1λÖÃǡΪСÇò¸Õ¿ªÊ¼Ô˶¯µÄ˲¼ä£¬ÉãÓ°»úÁ¬ÐøÁ½´ÎÆØ¹âµÄʱ¼ä¼ä¸ô¾ùΪ1s£¬ÔòСÇòÔÚ4λÖÃʱµÄ˲ʱËÙ¶ÈԼΪ______________m/s£¬Ð¡Çò´Ó1λÖõ½6λÖõÄÔ˶¯¹ý³ÌÖÐµÄÆ½¾ùËÙ¶ÈΪ___________________m/s£¬Ôڸùý³ÌÖеļÓËÙ¶È´óԼΪ_____________________m/s¡£
2
a b c cÈýµãµÄµçÊÆºÍµç
E
14.(6·Ö)ijͬѧÓÃÒ»¸ö¶¨Öµµç×èR¡¢Á½¸ö¿ª¹Ø¡¢Ò»¸öµçѹ±íºÍÈô¸Éµ¼ÏßÁ¬³ÉÒ»¸ö²âÁ¿µçÔ´ÄÚ×èµÄʵÑéµç·£¬Èç
ͼËùʾ£¬ÒÑÖªµçѹ±íµÄÄÚ×èÔ¶´óÓÚµçÔ´µÄÄÚµç×èºÍR£¬ÆäÁ¿³Ì´óÓÚµçÔ´µç¶¯ÊÆ£¬±íÅÌÉϿ̶ÈÇåÎú£¬µ«Êý×Ö²»Ç壬µçÔ´ÄÚ×èԼΪ¼¸Å·¡£ £¨1£©ÔÚ·½¿òÄÚ»³öʵÑéµç·ͼ¡£
£¨2£©ÊµÑéÖÐʼÖձպϿª¹ØS1£¬µ±¿ª¹ØS2´¦ÓÚ¶Ï¿ªºÍ±ÕºÏÁ½ÖÖ״̬ʱ£¬µçѹ±íÖ¸ÕëÆ«×ª¸ñÊý·Ö±ðΪn1¡¢n2£¬Ôò
¼ÆËãµçÔ´ÄÚ×èµÄ±í´ïʽÊÇr= ¡£
Èý£®¼ÆËãÌ⣨¹²40·Ö£©
15£®(6·Ö) ÖÊÁ¿Îª5.0kgµÄÎïÌ壬´ÓÀëµØÃæ36m¸ß´¦£¬Óɾ²Ö¹¿ªÊ¼¼ÓËÙÏÂÂ䣬¾3sÂ䵨£¬ÊÔÇó£º
¢ÙÎïÌåÏÂÂäµÄ¼ÓËٶȵĴóС£»
¢ÚÏÂÂä¹ý³ÌÖÐÎïÌåËùÊÜ×èÁ¦µÄ´óС¡££¨gÈ¡10m/s£©
2
16.£¨8·Ö£©³¤ÎªLµÄÉþÒ»¶ËϵÓÚOµã,ÁíÒ»¶ËϵһÖÊÁ¿Îª3mµÄСÇò,ÈçͼËùʾ,ÖÊÁ¿ÎªmµÄ×Óµ¯Ë®Æ½ÉäÈëСÇò²¢
ÁôÔÚÆäÄÚ,СÇòÇ¡ºÃÄܹý×î¸ß´¦(OµãÉÏ·½L´¦),Çó×Óµ¯µÄ³õËÙ¶ÈΪv0.
BOv0A17.(10·Ö)ÈçͼËùʾ£¬Á½Æ½ÐнðÊô°å¼ä¾àΪd£¬µçÊÆ²îΪU£¬°å¼äµç³¡¿ÉÊÓΪÔÈÇ¿µç³¡£»½ðÊô°å Ï·½ÓÐÒ»´Å¸ÐӦǿ¶ÈΪBµÄÔÈÇ¿´Å³¡¡£´øµçÁ¿Îª+q¡¢ÖÊÁ¿ÎªmµÄÁ£×Ó£¬Óɾ²Ö¹¿ªÊ¼´ÓÕý ¼«°å³ö·¢£¬¾µç³¡¼ÓËÙºóÉä³ö£¬²¢½øÈë´Å³¡×öÔÈËÙÔ²ÖÜÔ˶¯¡£ºöÂÔÖØÁ¦µÄÓ°Ï죬Çó£º £¨1£© ÔÈÇ¿µç³¡³¡Ç¿EµÄ´óС£» £¨2£© Á£×Ӵӵ糡Éä³öʱËٶȦ͵ĴóС£» £¨3£© Á£×ÓÔڴų¡ÖÐ×öÔÈËÙÔ²ÖÜÔ˶¯µÄ°ë¾¶R¡£
18.£¨16·Ö£©½»Á÷·¢µç»úµÄ¶ËµçѹÊÇ220·ü£¬Êä³ö¹¦ÂÊΪ2018Íߣ¬Êäµçµ¼Ïß×ܵç×èΪ2Å·¡£ÊÔÇ󣺢ÙÓû§µÃµ½µÄµçѹºÍ¹¦Âʸ÷¶à´ó£¿ÊäµçËðʧ¹¦Âʶà´ó£¿¢ÚÈô·¢µç»úÊä³ö¶ËÓÃ1£º10µÄÉýѹ±äѹÆ÷Éýѹºó£¬¾Í¬ÑùÊäµçµ¼ÏßÊäËÍ£¬ÔÙÓÃ10£º1µÄ½µÑ¹±äѹÆ÷½µÑ¹ºó¹©¸øÓû§£¬ÔòÓû§µÃµ½µÄµçѹºÍ¹¦ÂÊÓÖ¶à´ó£¿ ²Î¿¼´ð°¸
Ò»¡¢Ñ¡ÔñÌ⣨±¾Ìâ12СÌâ¡£¹²48·Ö£¬Ã¿Ð¡Ìâ¸ø³öµÄËĸöÑ¡ÏîÖУ¬ÓеÄÖ»ÓÐÒ»¸öÑ¡ÏîÕýÈ·£¬ÓеÄÓжà¸öÑ¡ÏîÕýÈ·£¬È«²¿Ñ¡¶ÔµÄµÃ4·Ö£¬Ñ¡¶Ôµ«²»È«µÄµÃ2·Ö£¬ÓÐÑ¡´íµÄµÃ0·Ö£© ÌâºÅ 1 ´ð°¸ ¶þ¡¢ ʵÑéÌ⣨ÿ¿Õ2·Ö£¬¹²12·Ö£©
13£®0.09£¨2·Ö£© 0.075£¨2·Ö£© 0.030£¨2·Ö£© 14£®£®£¨1£©£¨3·Ö£©
v BCD 2 B 3 D 4 A 5 B 6 D 7 C 8 C 9 ABC 10 BD 11 AB 12 AC
£¨2£©£¨3·Ö£©µçÔ´ÄÚ×èµÄ±í´ïʽÊÇr=
Èý£®¼ÆËãÌ⣨¹²40·Ö£© 15£®£¨6·Ö£©½â´ð£º £¨1£©n1?n2R n2h?12at2 £¨2·Ö£© a=8m/s £¨1·Ö£© 2(2)mg-f=ma £¨2·Ö£© f=10N£¨1·Ö£©
16£®£¨8·Ö£©½â´ð£º
2vB mv0=(m+3m)v £¨2·Ö£© mg?m£¨2·Ö£©
L112(m?3m)v2?(m?3m)vB?(m?3m)g?2L£¨3·Ö£© 22v0?45gL£¨1·Ö£©
17£®£¨10·Ö£©½â´ð£º£¨1£©U £¨2·Ö£© E?d
£¨2£©qU?12mv £¨2·Ö£© µÃv?22qU£¨2·Ö£© m2qU£¨2·Ö£© m1v2£¨3£©qvB?m £¨2·Ö£© µÃR?BR
18£®£¨16·Ö£©£¨1£©I?P?20A £¨2·Ö£© UUÓÃ=UÊä-IR=220-20¡Á2=180V £¨2·Ö£© PÓÃ=PÊä-IR=2018-20¡Á2=2018W £¨2·Ö£© £¨2£©
2
2
U2n2P??2A £¨2·Ö£© U2=2018V £¨2·Ö£© I2?U1n1U2U3=U2-IR=2018-2¡Á2=2018V£¨2·Ö£©