printf(\结果为%.4f\\n\ return 0;

}

6.7

# include int main(void) { int i,n; float s;

printf(\请输入变量n: \

scanf(\ s = 0;

for( i=1; i <= n; i++) { s += 1 / ( (i + 1) * (float)i ); // }

printf(\结果为%f\\n\ return 0;

} 6.8

# include double fun(int);

int main(void)

强制转换 { }

double fun(int n) { } 6.9

#include #define N 17 int main() {int a[N],i,j,t,k;

printf(\请输入原始数据:\\n\ for(i=0;i

{printf(\ printf(\排序前的数据如下所示:\\n\ for(i=0;i

double s; int i; s=0.0;

for(i=1; i<=n; i++) { } return s;

s +=1.0 /(2*i-1) - 1.0 /(2*i) ;

int n; double sum;

printf(\请输入变量n: \scanf(\sum = fun(n);

printf(\结果为: %f\

for(i=0;i

for(j=i+1;j

}

printf(\排序后的数据如下所示:\\n\ for(i=0;i

10.编程序，应用冒泡法对通过键盘输入17个整数 按照从大到小的顺序排序，并输出排序前后的数据 */

# include # define N 17

void maxtomin(int [], int n);

int main(void) {

int a[N]; int i,j,temp;

printf(\输入%d个整数,空格隔开:\\n\ return 0;

}

for( i=0; i

scanf(\

for( i=0; i

for( j=0; j

if( a[j] < a[j+1] ) { }

temp=a[j]; a[j]=a[j+1]; a[j+1]=temp;

printf(\结果为:\\n\for(i=0; i

printf(\

return 0;

6.11

# include

int fun(int);

int main(void) { }

int fun(int x)

int x;

printf(\输入x的值: \scanf(\

printf(\结果为: %d\\n\