Ìì½òÀí¹¤´óѧ¡¶²ÄÁÏÎïÀí»¯Ñ§¡·¸´Ï°Ì⣨Ð޸ģ© ÏÂÔØ±¾ÎÄ

¡¶²ÄÁÏÎïÀí»¯Ñ§¡·¸´Ï°Ìâ

Ò»¡¢ÅжÏÌâ

1. ƫĦ¶ûÁ¿¾ÍÊÇ»¯Ñ§ÊÆ¡££¨ £Ø £©

2£®·â±ÕϵͳºÍ»·¾³¼äûÓÐζȲî¾ÍÎÞÈÈ´«µÝ¡££¨ £©

3£®ÀíÏëÆøÌåÏòÕæ¿ÕÅòÕÍ£¬Ìå»ýÔö¼ÓÒ»±¶£¬Ôò W = nRTln(V2/V1) = nRTln2¡£( ) 4£®×Ô·¢¹ý³ÌÒ»¶¨ÊDz»¿ÉÄæµÄ¡££¨ ¡Ì £©

5. ÏàÊÇָϵͳ´¦ÓÚÆ½ºâʱ£¬ÏµÍ³Öл¯Ñ§ÐÔÖʾùÔȵIJ¿·Ö¡££¨ ¡Á £©

6. ÔÚζȡ¢ÈܼÁÖÖÀàÒ»¶¨Ìõ¼þÏ£¬Ä³Ç¿µç½âÖÊÏ¡ÈÜÒºËæµç½âÖÊŨ¶ÈÔö¼Ó£¬µçµ¼Âʦʱä´ó£¬¶øÄ¦¶ûµçµ¼Âʦ«m±äС¡££¨ ¡Ì £©

7£®±íÃæÕÅÁ¦µÄ´æÔÚÊÇÍäÇúÒºÃæ²úÉú¸½¼ÓѹÁ¦µÄÔ­Òò¡£( ) 8£®¶ÔÓÚij¸ö·´Ó¦À´Ëµ£¬Æä·´Ó¦ËÙÂÊÔ½¿ì£¬Ôòת»¯ÂÊÔ½¸ß¡££¨ £© 9£®Ï¡ÈÜÒºµÄ·ÐµãÒ»¶¨¸ßÓÚ´¿ÈܼÁµÄ·Ðµã¡££¨ £Ø £©

10. ÀÊçѶûÎü¸½µÈÎÂʽֻÊÊÓÃÓÚµ¥·Ö×Ó²ãÎü¸½¡££¨ ¡Ì £©

11£®·´Ó¦N2(g)£«O2(g) ? 2NO µÄÈÈЧӦΪ?rHm£¬Õâ¾ÍÊÇN2(g)µÄȼÉÕÈÈ£¬Ò²ÊÇNO(g)Éú³ÉÈȵÄ2 ±¶¡£( ) 12£®¸ôÀëϵͳµÄÈÈÁ¦Ñ§ÄÜÊÇÊØºãµÄ¡££¨ ¡Ì £© 13£®¸ôÀëϵͳµÄìØÊÇÊØºãµÄ¡££¨ £Ø £©

14£®Ö»Óйã¶ÈÁ¿²ÅÓÐÆ«Ä¦¶ûÁ¿£¬Ç¿¶ÈÁ¿ÊDz»´æÔÚÆ«Ä¦¶ûÁ¿µÄ¡££¨ £©

15. ¶ÔÀíÏëÆøÌå·´Ó¦£¬ºãκãÈÝÏÂÌí¼Ó¶èÐÔÆøÌå×é·Ö£¬Æ½ºâ²»Òƶ¯¡££¨ ¡Ì £© 16£®·²ÊÇ¡÷S > 0µÄ¹ý³Ì¶¼ÊDz»¿ÉÄæ¹ý³Ì¡££¨ £Ø £©

17£®¾øÈȹý³ÌQ£½0£¬ÓÉÓÚQ£½¦¤H£¬ËùÒÔ¦¤H£½0¡££¨ £Ø £© 18£®ÈÎÒâÌåϵ¾­Ò»Ñ­»·¹ý³ÌÔòÆäU£¬H£¬S£¬G£¬¾ùΪÁã¡£ ( )

19£®ÔÚºãκãѹÏÂÈôÈÎÒ»ÎïÖÊB ÔÚÁ½ÏàÖеĻ¯Ñ§ÊƲ»ÏàµÈ£¬Ôò¸Ã×é·Ö±ØÈ»´Ó»¯Ñ§ÊƵ͵ÄÄÇÒ»ÏàÏò»¯Ñ§ÊƸߵÄÄÇÒ»Ïà×ªÒÆ¡££¨ £©

20. ¼ª²¼Ë¹Ëù¶¨ÒåµÄ±íÃæ¹ýÊ£¦£BÖ»ÄÜÊÇÕýÖµ£¬²»ÄÜÊǸºÖµ¡££¨ ¡Á £© 21. ÀÊçѶûÎü¸½µÈÎÂʽֻÊÊÓÃÓÚµ¥·Ö×Ó²ãÎü¸½¡££¨ ¡Ì £©

22. ÔÚºãΡ¢ºãѹ¡¢·ÇÌå»ý¹¦ÎªÁãµÄÌõ¼þÏ£¬Ä³·´Ó¦µÄ¡÷rGm<£°£¬Ôò·´Ó¦ÎïÈ«²¿±ä³É²úÎ·´Ó¦½«½øÐе½µ×¡££¨ ¡Á £© 23£®¶ÔÀíÏëÆøÌå·´Ó¦£¬ºãκãѹÏÂÌí¼Ó¶èÐÔÆøÌå×é·Ö£¬Æ½ºâ²»Òƶ¯¡££¨ £©

24£®ÎÞÂÛÊÇÇ¿µç½âÖÊ»¹ÊÇÈõµç½âÖÊ£¬ÆäĦ¶ûµçµ¼ÂʾùËæÈÜÒºµÄÏ¡ÊͶøÔö´ó ¡££¨ ¡Ì £©

25£®ÏòÈܼÁÖмÓÈëÉÙÁ¿ÈÜÖÊÒ»¶¨»áµ¼Ö¸ÃÈܼÁ·ÐµãÉÏÉý¡£( )

26. ÈôÒ»¸ö¹ý³ÌÊÇ¿ÉÄæ¹ý³Ì£¬Ôò¸Ã¹ý³ÌµÄÿһ²½¶¼ÊÇ¿ÉÄæ¹ý³Ì¡££¨ ¡Ì £©

27. ÔÚÒ»¶¨Î¶ÈÏ£¬p*B>p*A£¬ÓÉ´¿ÒºÌ¬ÎïÖÊAºÍBÐγÉÀíÏëҺ̬»ìºÏÎµ±Æø¡ªÒºÁ½Ïà´ïµ½Æ½ºâʱ£¬ÆøÏà×é³ÉyB×ÜÊÇ´óÓÚÒºÏà×é³ÉxB¡££¨ ¡Ì £© 28£®µ¥×é·ÖϵͳµÄÏàÊý×î¶àΪ3¡££¨¡Ì £©

29£®Î¶ȡ¢Ìå»ýÒ»¶¨µÄÇé¿öÏ£¬Ôö¼Ó¶èÐÔÆøÌåµÄÓ°ÏìÏ൱ÓÚ¼õѹ¶ÔƽºâµÄÓ°Ïì¡£( )

30£®ÔÚºãΡ¢ºãѹ¡¢·ÇÌå»ý¹¦ÎªÁãµÄÌõ¼þÏ£¬Ä³·´Ó¦µÄ¡÷rGm<0£¬Ôò·´Ó¦ÎïÈ«²¿±ä³É²úÎ·´Ó¦½«½øÐе½µ×¡££¨ £©

31. Ò»¶¨Á¿ÀíÏëÆøÌåµÄìØÖ»ÊÇζȵĺ¯Êý¡££¨ ¡Á £©

32. ÔÚºãΡ¢ºãѹ¡¢·ÇÌå»ý¹¦ÎªÁãµÄÌõ¼þÏ£¬Ä³·´Ó¦µÄ¡÷r£Çm<£°£¬Ôò·´Ó¦ÎïÈ«²¿±ä³É²úÎ·´Ó¦½«½øÐе½µ×¡££¨ ¡Á £©

33£®ºãÎÂÏ£¬Ï¡µç½âÖÊÈÜÒºµÄŨ¶ÈÔö´óʱ£¬Ä¦¶ûµçµ¼ÂÊÔö´ó¡££¨£Ø £© 34£®ÀÊçѶû¼Ù¶¨¹ÌÌå±íÃæ¶Ô·Ö×ÓÖ»ÄÜ·¢Éúµ¥·Ö×Ó²ãÎü¸½¡££¨¡Ì £©

35£®ÀíÏëÆøÌå¾øÈȹý³Ì¹¦µÄ¼ÆËãʽΪW=nCv£¬m(T2-T1)£¬´ËʽÎÞÂÛ¾øÈȹý³ÌÊÇ·ñ¿ÉÄæ¾ùÊÊÓᣣ¨ £© 36£®ÏàÂÊÖ»ÊÊÓÃÓÚÆ½ºâϵͳ¡£( )

37. ¡÷fH¦¨m£¨C£¬½ð¸Õʯ£¬298.15K£©=0£¨ ¡Á £© 38£®µ¥×é·Öϵͳ×ÔÓɶÈ×î´óΪ3¡£( )

39£®ÀíÏëÆøÌå¾øÈȹý³Ì¹¦µÄ¼ÆËãʽΪW=nCv£¬m(T2-T1)£¬´ËʽÎÞÂÛ¾øÈȹý³ÌÊÇ·ñ¿ÉÄæ¾ùÊÊÓᣣ¨ ¡Ì £© 40£®ÌåϵÓÉÆ½ºâ̬A±äµ½Æ½ºâ̬B£¬²»¿ÉÄæ¹ý³ÌµÄìØ±äÒ»¶¨´óÓÚ¿ÉÄæ¹ý³ÌµÄìØ±ä¡£(¡Á )¡£

41£®ÔÚÒ»¶¨Î¶ÈÏ£¬p*B>p*A£¬ÓÉ´¿ÒºÌ¬ÎïÖÊAºÍBÐγÉÀíÏëҺ̬»ìºÏÎµ±Æø¡ªÒºÁ½Ïà´ïµ½Æ½ºâʱ£¬ÆøÏà×é³ÉyB×ÜÊÇ´óÓÚÒºÏà×é³ÉxB¡££¨ £©

42. ¾øÈȹý³ÌQ£½0£¬ÓÉÓÚQ£½¦¤H£¬ËùÒÔ¦¤H£½0¡££¨ £Ø £©

43. ÔÚÒ»Ìå»ýºã¶¨µÄ¾øÈÈÏäÖÐÖÃÒ»¾øÈȸô°å£¬½«Æä·ÖΪ×óÓÒÁ½²¿·Ö¡£ÔÚÁ½²à·Ö±ð·ÅÈëT¡¢p½Ô²»ÏàͬµÄͬÖÖÆøÌå¡£ÏÖ½«¸ô°å³éÈ¥²¢´ïµ½Æ½ºâ£¬ÈôÒÔÏäÄÚÈ«²¿ÆøÌåΪϵͳ£¬Ôò´Ë»ìºÏ¹ý³ÌµÄQ¡¢W¡¢¡÷U¶¼ÎªÁã¡££¨ ¡Ì £© 44£®µç½âÖÊÈܶÈÔ½¸ß£¬Æäµçµ¼ÂÊÔ½´ó¡£( )

45£®·´Ó¦ C(s)+H2O(g)=CO(g)+H2(g)£¬ºãÎÂÏÂÈôÔö´óÌåϵµÄ×Üѹ£¬·´Ó¦ÕýÏò½øÐС££¨£Ø £© 46£®ÍäÇúÒºÃæ²úÉú¸½¼ÓѹÁ¦µÄ¸ù±¾Ô­ÒòÊÇ´æÔÚ±íÃæÕÅÁ¦¡££¨ £©

47. ¸ôÀëϵͳµÄÈÈÁ¦Ñ§ÄÜÊÇÊØºãµÄ¡££¨ ¡Ì £©

48. ÔÚ¸ôÀëϵͳÖз¢Éúij»¯Ñ§·´Ó¦£¬Ê¹ÏµÍ³µÄζÈÃ÷ÏÔÉý¸ß£¬Ôò¸ÃϵͳµÄ¡÷U>0£¨ £Ø £© 49£®298.15Kʱ£¬ÇâÆøµÄ±ê׼Ħ¶ûȼÉÕìÊÓëH2O£¨l£©µÄ±ê׼Ħ¶ûÉú³ÉìÊÁ¿ÖµÉÏÏàµÈ¡£( ¡Ì ) 50£®¿ÕÆøÖеÄÐ¡ÆøÅÝ£¨Èç·ÊÔíÅÝ£©£¬ÓÐÄÚÍâÁ½¸öÆø¡ª¡ªÒº½çÃæ¡£( ) 51£®¿ÕÆøÖÐСˮµÎµÄ±¥ºÍÕôÆûѹҪСÓÚÆ½ÃæË®µÄ±¥ºÍÕôÆûѹ¡££¨ £© 52£®ÈôÒ»¸ö¹ý³ÌÊÇ¿ÉÄæ¹ý³Ì£¬Ôò¸Ã¹ý³ÌµÄÿһ²½¶¼ÊÇ¿ÉÄæ¹ý³Ì¡££¨ ¡Ì £©

¶þ¡¢Ìî¿ÕÌâ

1. ÔÚU¡¢H¡¢S¡¢GËĸöÈÈÁ¦Ñ§Á¿ÖУ¬ÏµÍ³·¢Éúºãκãѹ¿ÉÄæÏà±ä£¬²»±äµÄÁ¿ÊÇ G £¬¶ø¾øÈÈ¿ÉÄæ

¹ý³ÌÖв»±äµÄÁ¿ÊÇ S ¡£ 2. ÒÑÖª E¦¨Cu2+/Cu = 0.337V£¬ E¦¨Cu+/Cu = 0.521V£¬ ÓÉ´Ë¿ÉÇó³öE¦¨Cu2+/Cu+ =

V¡£

3. ÔÚÒ»³é¿ÕµÄÈÝÆ÷ÖзÅÓйýÁ¿µÄNH4HS£¨s£©·¢Éú·Ö½â·´Ó¦£¬NH4HS£¨s£©ÓëÆä·Ö½â²úÎïNH3£¨g£©ºÍ

H2S£¨g£©³Éƽºâ£¬´ËƽºâϵͳµÄÏàÊýP¡¢×é·ÖÊýC¡¢×ÔÓɶÈÊýF·Ö±ðΪ£º2¡¢ 1¡¢ 1 ¡£ 4. 1molÀíÏëÆøÌåÔÚ298KÏ£¬´Ó2¡Á10-3m3µÈοÉÄæÅòÕ͵½20¡Á10-3m3£¬´Ë¹ý³ÌÖÐϵͳµÄìØ±ä¡÷SΪ 19.15

£­£­

J¡¤K-1¡££¨RΪ8.315 J¡¤mol1¡¤K1£©¡£

5. Ò»¶¨Á¿µÄÀíÏëÆøÌå´Óͬһʼ̬³ö·¢£¬·Ö±ð¾­¾øÈÈ¿ÉÄæÑ¹ËõºÍºãοÉÄæÑ¹Ëõµ½ÏàͬµÄÖÕ̬Ìå»ýV2£¬Ôò

ÖÕ̬µÄѹÁ¦p2£¨ºãΣ© < p2£¨¾øÈÈ£©¡££¨Ñ¡Ìî¡°>¡±¡¢¡°<¡±¡°=¡±£© 6. ·´Ó¦2O3 = 3O2 µÄËÙÂÊ·½³Ì¿É±íʾΪ?dc(O3)?kc(O3)2c(O2)?1 »ò dc(O2)?k?c(O3)2c(O2)?1ÔòËٶȳ£Êý

dtdtk ºÍ k¨@ µÄ¹ØÏµÎª 3k = 2 k¨@ ¡£

7.1000C¡¢1.5p¦¨µÄË®ÕôÆû±äΪ1000C£¬p¦¨µÄÒºÌåË®£¬Ôò´Ë¹ý³ÌµÄ¡÷S ___ 0£¬¡÷G _ _0¡£

8. ij·´Ó¦2A£«B

P ½øÐÐÒ»¶Îʱ¼äºó£¬ÏûºÄAÎïÖÊ1mol£¬Æä¦¤H£½200kJ£¬´Ëʱ·´Ó¦½ø¶ÈΪ 0.5

mol£¬·´Ó¦µÄ¡÷rHm£½ 400 kJ?mol-1¡£

9. ϵͳÓÉÏàͬµÄʼ̬¾­¹ý²»Í¬Í¾¾¶´ïµ½Ïàͬĩ̬¡£Èô;¾¶aµÄQa=2078J£¬Wa=-4157J£¬¶øÍ¾

¾¶bµÄQb=-692J£¬ÔòWb= 10. ÒÑÖª250CÏ£¬·´Ó¦C£¨Ê¯Ä«£©£«2H2£¨g£©£«0.5O2£¨g£©¡úCH3OH£¨l£©µÄC£¨Ê¯Ä«£©¡¢H2

£¨g£©ºÍCH3OH£¨l£©µÄ±ê׼Ħ¶ûȼÉÕìʦ¤CHm¦¨·Ö±ðΪ-393.51kJ?mol£­1£¬-285.85kJ?mol£­1ºÍ-726.51kJ?mol£­1£¬ÔòCH3OH£¨l£©µÄ±ê׼Ħ¶ûÉú³Éìʦ¤fHm¦¨Îª £­238.7 kJ?mol£­1¡£ 11. 400KÊ±ÆøÏà·´Ó¦N2(g)+3H2(g)2NH3(g)µÄ¦¤rGm¦¨£½£­3.0kJ?mol-1 £¬Ôò·´Ó¦NH3(g)1/2N2(g)+3/2 H2(g) ÔÚ400KʱµÄK¦¨Îª 0.638 ¡££¨RΪ8.315J¡¤mol£­1¡¤K£­1£©

12. Ũ¶ÈΪ b µÄ Al2(SO4)3 ÈÜÒº£¬Õý¸ºÀë×ӵĻî¶ÈϵÊý·Ö±ðÓæÃ+ºÍ¦Ã£­±íʾ£¬ ÔòÆä¦Ã ¡À

= £»a¡À = ¡£

13. ÔÚU¡¢H¡¢S¡¢GËĸöÈÈÁ¦Ñ§Á¿ÖУ¬ÏµÍ³·¢Éúºãκãѹ¿ÉÄæÏà±ä£¬²»±äµÄÁ¿ÊÇ G £¬¶ø¾øÈÈ¿ÉÄæ¹ý³ÌÖв»±äµÄÁ¿ÊÇ S ¡£

14. ÔÚÒ»¶¨µÄT¡¢pÏ£¬ÈôÎïÖÊAÔÚ?ÏàºÍ?ÏàÖеĻ¯Ñ§ÊÆÂú×ã?A(?)??A(?)£¬ÔòAÔÚÁ½ÏàÖеÄÇ¨ÒÆ

·½ÏòÊÇ ¦Á¡ú¦Â £»ÈôAÔÚÁ½ÏàÖдﵽƽºâ£¬Ôò?A(?) = ?A(?)¡£

15. ÒÑÖª E¦¨Cu2+/Cu = 0.337V£¬ E¦¨Cu+/Cu = 0.521V£¬ ÓÉ´Ë¿ÉÇó³öE¦¨Cu2+/Cu+ = 0.153 V¡£

16. ÒÑÖª250CÏ£¬·´Ó¦C£¨Ê¯Ä«£©£«2H2£¨g£©£«0.5O2£¨g£©¡úCH3OH£¨l£©ÖеÄC£¨Ê¯Ä«£©¡¢

H2£¨g£©ºÍCH3OH£¨l£©µÄ±ê׼Ħ¶ûȼÉÕìʦ¤CHm¦¨·Ö±ðΪ-393.51kJ?mol£­1£¬-285.85kJ?mol£­1

ºÍ-726.51kJ?mol£­1£¬ÔòCH3OH£¨l£©µÄ±ê׼Ħ¶ûÉú³Éìʦ¤fHm¦¨Îª £­238.7 kJ?mol£­1¡£ 17. ij·´Ó¦ÔÚ20oCʱµÄËÙÂʳ£ÊýΪ0.01s£­1£¬¸Ã·´Ó¦µÄ¼¶ÊýΪ Ò»¼¶ £¬20oCʱ·´Ó¦µÄ°ë

Ë¥ÆÚΪ 69.31S ¡£

18. ·ÓÓëË®»ìºÏÐγÉÏ໥±¥ºÍµÄÁ½¸öÒº²ã£¬¸ÃƽºâϵͳµÄ¶ÀÁ¢×é·ÖÊý C = £¬ÏàÊý P = £¬×ÔÓɶÈÊý F = ¡£ 19. 400KÊ±ÆøÏà·´Ó¦N2(g)+3H2(g)

NH3(g)

?2NH3(g)µÄ?rGm£½£­3.0kJ?mol-1 £¬Ôò·´Ó¦

13N2(g)+H2(g) ÔÚ400KʱµÄK¦¨Îª 0.637 ¡££¨RΪ8.315 J¡¤mol£­1¡¤K£­1£© 2220. ÒÑÖª E¦¨Cu2+/Cu = 0.337V£¬ E¦¨Cu+/Cu = 0.521V£¬ÓÉ´Ë¿ÉÇó³öE¦¨Cu2+/Cu+ = 0.153 V¡£

21. ÔÚÒ»³é¿ÕµÄÈÝÆ÷ÖзÅÓйýÁ¿µÄNH4HS£¨s£©·¢Éú·Ö½â·´Ó¦£¬NH4HS£¨s£©ÓëÆä·Ö½â²úÎïNH3

£¨g£©ºÍH2S£¨g£©³Éƽºâ£¬´ËƽºâϵͳµÄÏàÊýP¡¢×é·ÖÊýC¡¢×ÔÓɶÈÊýF·Ö±ðΪ£º 2£¬1£¬1 ¡£

22. 100?C¡¢1.5p? µÄË®ÕôÆû±äΪ100?C£¬p? µÄÒºÌåË®£¬Ôò´Ë¹ý³ÌµÄ?S _ 0, ?G _ __ 0¡£ 23. ÔÚÒ»¶¨µÄT¡¢pÏ£¬ÈôÎïÖÊAÔÚ?ÏàºÍ?ÏàÖеĻ¯Ñ§ÊÆÂú×ã?A(?)??A(?)£¬ÔòAÔÚÁ½ÏàÖÐ

µÄÇ¨ÒÆ·½ÏòÊÇ ¦Á¡ú¦Â £»ÈôAÔÚÁ½ÏàÖдﵽƽºâ£¬Ôò?A(?) = ?A(?)£¨Ñ¡Ìî¡°>¡±£¬¡°<¡±£¬¡°=¡±£©¡£

24. n mol ijÀíÏëÆøÌåÔÚºãÈÝÏÂÓÉT1¼ÓÈȵ½T2£¬ÆäìØ±äΪ¦¤S1£¬ÏàͬÁ¿µÄ¸ÃÆøÌåÔÚºãѹÏÂÓÉ

T1¼ÓÈȵ½T2£¬ÆäìØ±äΪ¦¤S2£¬Ôò¦¤S1Ó릤S2µÄ´óС¹ØÏµÎª ¦¤S1<¦¤S2 25. ij»¯ºÏÎï·Ö½â·´Ó¦Ê±£¬³õʼŨ¶ÈΪ1.0 mol¡¤dm£¬1СʱºóŨ¶ÈΪ0.5 mol¡Ádm£¬2Сʱ

ºóŨ¶ÈΪ0.25 mol¡¤dm£¬ ÕâÊÇ ¼¶·´Ó¦£¬ Æä·´Ó¦ËÙÂʳ£Êý k = ¡£ 26. ÔÚ300Kʱ£¬48.98dm3µÄÀíÏëÆøÌå´Ó100kPa±äµ½500kPa£¬¡÷GΪ 7.88 kJ¡£ 27. ÀíÏëÆøÌå·´¿¹ºãÍâѹ¾øÈÈÅòÕÍʱ, ?U < 0 £¬?T < 0£¨Ñ¡Ìî¡°>¡±£¬¡°<¡±£¬¡°=¡±£© 28. ´¿ÎïÖÊÍêÃÀ¾§Ì壬 0K ʱìØÖµÎªÁã¡£

29. ij·´Ó¦µÄ·´Ó¦ÎïÏûºÄµô3/4µÄʱ¼äÊÇÆä°ëË¥ÆÚµÄ2±¶£¬Ôò¸Ã·´Ó¦¼¶ÊýΪ ¡£ 30. Ò»¶¨Á¿µÄÀíÏëÆøÌå´Óͬһʼ̬³ö·¢£¬·Ö±ð¾­¾øÈÈ¿ÉÄæÑ¹ËõºÍºãοÉÄæÑ¹Ëõµ½ÏàͬµÄÖÕ̬

£­3

£­3

£­3

Ìå»ýV2£¬ÔòÖÕ̬µÄѹÁ¦p2£¨ºãΣ© < p2£¨¾øÈÈ£©¡££¨Ñ¡Ìî¡°>¡±¡¢¡°<¡±¡°=¡±£© 31. ·´Ó¦2A?3B£¬Ôò?dcA/dtÓëdcB/dtÖ®±ÈΪ 2:3 ¡£

32. »¯Ñ§·´Ó¦µÄ±ê׼ƽºâ³£ÊýK¦¨Ö»ÊÇ ÎÂ¶È µÄº¯Êý¡£

33. ¶þ×é·Ö¹Ì̬²»»¥ÈÜϵͳҺ¡ª¹ÌƽºâÏàͼÈýÏàµã´¦£¬×ÔÓɶÈF= ¡£

34. 1molÀíÏëÆøÌåÔÚ298KÏ£¬´Ó2¡Á10-3m3µÈοÉÄæÅòÕ͵½20¡Á10-3m3£¬´Ë¹ý³ÌÖÐϵͳµÄ

ìØ±ä¡÷SΪ 19.15 J¡¤K-1¡££¨RΪ8.315 J¡¤mol£­1¡¤K£­1£©¡£

35. ϵͳÓÉÏàͬµÄʼ̬¾­¹ý²»Í¬Í¾¾¶´ïµ½Ïàͬĩ̬¡£Èô;¾¶aµÄQa=2078J£¬Wa=-4157J£¬¶ø

;¾¶bµÄQb=-692J£¬ÔòWb= -1387J 36. ÔÚÒ»¶¨µÄT¡¢pÏ£¬ÈôÎïÖÊAÔÚ?ÏàºÍ?ÏàÖеĻ¯Ñ§ÊÆÂú×ã?A(?)??A(?)£¬ÔòAÔÚÁ½Ïà

ÖеÄÇ¨ÒÆ·½ÏòÊÇ ¦Á¡ú¦Â £»ÈôAÔÚÁ½ÏàÖдﵽƽºâ£¬Ôò?A(?) = ?A(?)¡£

37. ÒÑÖª E¦¨Cu2+/Cu = 0.337V£¬ E¦¨Cu+/Cu = 0.521V£¬ ÓÉ´Ë¿ÉÇó³öE¦¨Cu2+/Cu+ = 0.153 V¡£

38. ÔÚÒ»³é¿ÕµÄÈÝÆ÷ÖзÅÓйýÁ¿µÄNH4HS£¨s£©·¢Éú·Ö½â·´Ó¦£¬NH4HS£¨s£©ÓëÆä·Ö½â²úÎï

NH3£¨g£©ºÍH2S£¨g£©³Éƽºâ£¬´ËƽºâϵͳµÄÏàÊýP¡¢×é·ÖÊýC¡¢×ÔÓɶÈÊýF·Ö±ðΪ£º2¡¢ 1¡¢ 1 ¡£ 39. ·´Ó¦5A?3B£¬Ôò?dcA/dtÓëdcB/dtÖ®±ÈΪ ¡£

40. ÀíÏëÆøÌå¾­ÀúÒ»¸öÑ­»·¹ý³Ì£¬¶Ô»·¾³×÷¹¦100 J£¬ÔòÑ­»·¹ý³ÌµÄÈÈQµÈÓÚ 100 J ¡£ 41. ·ÓÓëË®»ìºÏÐγÉÏ໥±¥ºÍµÄÁ½¸öÒº²ã, ¸ÃƽºâϵͳµÄ¶ÀÁ¢×é·ÖÊý C¡¢ÏàÊý P¡¢×ÔÓɶÈÊý F

·Ö±ðΪ£º ¡£

42. ÒÑÖª250CÏ£¬·´Ó¦C£¨Ê¯Ä«£©£«2H2£¨g£©£«0.5O2£¨g£©¡úCH3OH£¨l£©ÖеÄC£¨Ê¯Ä«£©¡¢

¦¨£­1

H2£¨g£©ºÍCH3OH£¨l£©µÄ±ê׼Ħ¶ûȼÉÕìʦ¤CHm·Ö±ðΪ-393.51kJ?mol£¬-285.85kJ?mol£­1

ºÍ-726.51kJ?mol£­1£¬ÔòCH3OH£¨l£©µÄ±ê׼Ħ¶ûÉú³Éìʦ¤fHm¦¨Îª £­238.7 kJ?mol£­1¡£ 43. ÒÑÖª250CÏ£¬·´Ó¦C£¨Ê¯Ä«£©£«2H2£¨g£©£«0.5O2£¨g£©¡úCH3OH£¨l£©µÄC£¨Ê¯Ä«£©¡¢H2

£¨g£©ºÍCH3OH£¨l£©µÄ±ê׼Ħ¶ûȼÉÕìʦ¤CHm¦¨·Ö±ðΪ-393.51kJ?mol£­1£¬-285.85kJ?mol£­1ºÍ-726.51kJ?mol£­1£¬ÔòCH3OH£¨l£©µÄ±ê׼Ħ¶ûÉú³Éìʦ¤fHm¦¨Îª kJ?mol£­1¡£ 44. ij·´Ó¦ÔÚ20oCʱµÄËÙÂʳ£ÊýΪ0.01s£­1£¬¸Ã·´Ó¦µÄ¼¶ÊýΪ Ò»¼¶ £¬20oCʱ·´Ó¦µÄ°ë

Ë¥ÆÚΪ 69.31S ¡£

45. ÀÊçѶûµ¥·Ö×Ó²ãÎü¸½ÀíÂ۵Ļù±¾¼ÙÉè

ÊÇ£º £¬ £¬ £¬ ¡£ 46. ÀíÏëҺ̬»ìºÏÎïµÄ¦¤V = 0£¬¦¤H = 0£¬¦¤S > 0£¬¦¤G < 0 £¨Ñ¡Ìî¡°>, <, =¡± £© 47. ÓÉÓÚÐÂÏàÄÑÒÔÐγɶø³öÏÖµÄËÄÖÖ³£¼ûµÄÑÇÎÈ̬ÊÇ ¹ý±¥ºÍÕôÆû£¬¹ýÈÈÒºÌ壬¹ýÀäÒºÌ壬¹ý±¥ºÍÈÜÒº ¡£

48. ÔÚÒ»³é¿ÕµÄÈÝÆ÷ÖзÅÓйýÁ¿µÄNH4HS£¨s£©·¢Éú·Ö½â·´Ó¦£¬NH4HS£¨s£©ÓëÆä·Ö½â²úÎïNH3

£¨g£©ºÍH2S£¨g£©³Éƽºâ£¬´ËƽºâϵͳµÄÏàÊýP¡¢×é·ÖÊýC¡¢×ÔÓɶÈÊýF·Ö±ðΪ£º 2£¬1£¬1 ¡£ 49. ÔÚÒ»¶¨µÄT¡¢pÏ£¬ÈôÎïÖÊAÔÚ?ÏàºÍ?ÏàÖеĻ¯Ñ§ÊÆÂú×ã?A(?)??A(?)£¬ÔòAÔÚÁ½ÏàÖÐ

µÄÇ¨ÒÆ·½ÏòÊÇ ¦Á¡ú¦Â £»ÈôAÔÚÁ½ÏàÖдﵽƽºâ£¬Ôò?A(?) = ?A(?)£¨Ñ¡Ìî¡°>¡±£¬¡°<¡±£¬¡°=¡±£©¡£

50. n mol ijÀíÏëÆøÌåÔÚºãÈÝÏÂÓÉT1¼ÓÈȵ½T2£¬ÆäìØ±äΪ¦¤S1£¬ÏàͬÁ¿µÄ¸ÃÆøÌåÔÚºãѹÏÂÓÉ

T1¼ÓÈȵ½T2£¬ÆäìØ±äΪ¦¤S2£¬Ôò¦¤S1Ó릤S2µÄ´óС¹ØÏµÎª ¦¤S1<¦¤S2 ¡£

51. ÔÚ300Kʱ£¬48.98dm3µÄÀíÏëÆøÌå´Ó100kPa±äµ½500kPa£¬¡÷GΪ 7.88 kJ¡£ 52. 1molÀíÏëÆøÌå¾øÈÈÏòÕæ¿ÕÅòÕÍ£¬ÈôÆäÌå»ýÔö¼Óµ½Ô­À´µÄ10±¶£¬ÔòÌåϵºÍ»·¾³µÄìØ±ä·Ö±ð

Ϊ£º 19.14 J¡¤K-1 ºÍ 0 J¡¤K-1

53. ÔÚU¡¢H¡¢S¡¢GËĸöÈÈÁ¦Ñ§Á¿ÖУ¬ÏµÍ³·¢Éúºãκãѹ¿ÉÄæÏà±ä£¬²»±äµÄÁ¿ÊÇ G £¬¶ø¾øÈÈ¿ÉÄæ¹ý³ÌÖв»±äµÄÁ¿ÊÇ S ¡£

54. Ï¡ÈÜÒºµÄÒÀÊýÐÔÊÇ £¬ £¬ £¬ ¡£

55. ÀíÏëÆøÌå¾­ÀúÒ»¸öÑ­»·¹ý³Ì£¬¶Ô»·¾³×÷¹¦100 J£¬ÔòÑ­»·¹ý³ÌµÄÈÈQµÈÓÚ 100 J ¡£¡£ 56. ij·´Ó¦ÔÚ20oCʱµÄËÙÂʳ£ÊýΪ0.01s£­1£¬¸Ã·´Ó¦µÄ¼¶ÊýΪ Ò»¼¶ £¬20oCʱ·´Ó¦µÄ°ë

Ë¥ÆÚΪ 69.31S ¡£

57. ÀíÏëҺ̬»ìºÏÎïµÄ¦¤V = 0£¬¦¤H = 0£¬¦¤S > 0£¬¦¤G < 0 £¨Ñ¡Ìî¡°>, <, =¡± £© 58. Ó°ÏìK´óСµÄÒòËØÓÐ _£» Ó°Ï컯ѧƽºâ״̬µÄÒòËØÓÐ 59. ÒÑÖª E¦¨Cu2+/Cu = 0.337V£¬ E¦¨Cu+/Cu = 0.521V£¬ ÓÉ´Ë¿ÉÇó³öE¦¨Cu2+/Cu+ = 0.153 V¡£

60. ÔÚÒ»³é¿ÕµÄÈÝÆ÷ÖзÅÓйýÁ¿µÄNH4HS£¨s£©·¢Éú·Ö½â·´Ó¦£¬NH4HS£¨s£©ÓëÆä·Ö½â²úÎïNH3

£¨g£©ºÍH2S£¨g£©³Éƽºâ£¬´ËƽºâϵͳµÄÏàÊýP¡¢×é·ÖÊýC¡¢×ÔÓɶÈÊýF·Ö±ðΪ£º 2£¬1£¬1 ¡£

61. µäÐ͵ĸ´ºÏ·´Ó¦·½Ê½ÓÐ £¬ £¬ ¡£

62. ÔÚÒ»¶¨µÄT¡¢pÏ£¬ÈôÎïÖÊAÔÚ?ÏàºÍ?ÏàÖеĻ¯Ñ§ÊÆÂú×ã?A(?)??A(?)£¬ÔòAÔÚÁ½ÏàÖÐ

µÄÇ¨ÒÆ·½ÏòÊÇ ¦Á¡ú¦Â £»ÈôAÔÚÁ½ÏàÖдﵽƽºâ£¬Ôò?A(?) = ?A(?)£¨Ñ¡Ìî¡°>¡±£¬¡°<¡±£¬¡°=¡±£©¡£

63. ÔÚÒ»¶¨Î¶ȺͽÏСµÄŨ¶ÈµÄÇé¿öÏ£¬ Ôö´óÈõµç½âÖÊÈÜÒºµÄŨ¶È£¬ Ôò¸ÃÈõµç½âÖʵĵ絼

ÂÊ £¨ÌîÔö´ó»ò¼õС»ò²»±ä£©£¬ Ħ¶ûµçµ¼ÂÊ £¨ÌîÔö´ó»ò¼õС»ò²»±ä£©£¬ µçÀëÆ½ºâ³£Êý £¨ÌîÔö´ó»ò¼õС»ò²»±ä£©¡£

64. 1molÀíÏëÆøÌå¾øÈÈÏòÕæ¿ÕÅòÕÍ£¬ÈôÆäÌå»ýÔö¼Óµ½Ô­À´µÄ10±¶£¬ÔòìØ±äΪ£º 19.14

J¡¤K-1 ¡£

65. ÔÚ300Kʱ£¬48.98dm3µÄÀíÏëÆøÌå´Ó100kPa±äµ½500kPa£¬¡÷GΪ 7.88 kJ¡£ 66. ÀíÏëÆøÌå·´¿¹ºãÍâѹ¾øÈÈÅòÕÍʱ, ?U < 0 £¬?T < 0£¨Ñ¡Ìî¡°>¡±£¬¡°<¡±£¬¡°=¡±£©

-33-33

67. 1molÀíÏëÆøÌåÔÚ298KÏ£¬´Ó2¡Á10mµÈοÉÄæÅòÕ͵½20¡Á10m£¬´Ë¹ý³ÌÖÐϵͳµÄìØ

±ä¡÷SΪ J¡¤K-1¡££¨RΪ8.315 J¡¤mol£­1¡¤K£­1£©¡£

68. ÀÊçѶûµ¥·Ö×Ó²ãÎü¸½ÀíÂ۵Ļù±¾¼ÙÉ裺 £¬ £¬

¡£ 70. ʯīºÍ½ð¸Õʯ(C)ÔÚ25¡æ£¬101325Paϵıê׼ȼÉÕÈÈ·Ö±ðΪ-393.4kJ¡¤mol-1ºÍ-395.3kJ¡¤mol-1£¬

Ôò½ð¸ÕʯµÄ±ê×¼Éú³ÉÈÈ ?fH?m (298K)Ϊ ______ kJ¡¤mol-1¡£

¦¨

Èý¡¢Ñ¡ÔñÌâ

1. 1molµ¥Ô­×ÓÀíÏëÆøÌå´Ó273K¼°202.6kPaµÄ³õ̬¾­PT£½³£ÊýµÄ¿ÉÄæÍ¾¾¶Ñ¹ËõÖÁ409.4kPaµÄÖÕ̬£¬Ôò

£­£­

´Ë¹ý³ÌµÄ¡÷UΪ£¨ D £©¡££¨RΪ8.315J¡¤mol1¡¤K1£© A. 1720J B £­406.8J C. 406.8J D. £­1720J

2. ÒÑÖª·´Ó¦ 2NO£¨g£©+O2£¨g£©=2NO2£¨g£© µÄ¡÷r£È¦¨m£¨T£©£¼0£¬µ±ÉÏÊö·´Ó¦´ïµ½Æ½ºâ

ºó£¬ÈôҪƽºâÏò²úÎï·½ÏòÒÆ¶¯£¬¿ÉÒÔ²ÉÈ¡£¨ D £©µÄ´ëÊ©¡£

A. Éý¸ßζȣ¬¼õСѹÁ¦ B. Éý¸ßζȣ¬Ôö´óѹÁ¦ C. ½µµÍζȣ¬¼õСѹÁ¦ D. ½µµÍζȣ¬Ôö´óѹÁ¦

3. ¶ÔÀíÏëÆøÌ壬ÏÂÁйØÏµÊ½²»ÕýÈ·µÄÊÇ£¨ A £©¡£

A£®???U???0 B. ??T?p??H???H??0 C£®?????0 D. ?V??p?T??T??U????0 ??V?T4. ²»ÂÛÊǵç½â³Ø»¹ÊÇÔ­µç³Ø£¬¼«»¯µÄ½á¹û¶¼½«Ê¹£¨ C £©¡£

A. Òõ¡¢Ñô¼«µçÊÆÍ¬Ê±Ôö¼Ó B. Òõ¡¢Ñô¼«µçÊÆÍ¬Ê±¼õÉÙ

C. Ñô¼«µçÊÆ±ä´ó£¬Òõ¼«µçÊÆ±äС D. Ñô¼«µçÊÆ±äС£¬Òõ¼«µçÊÆ±ä´ó

++2+2+2++2+

5. µç³ØCu | Cu || Cu£¬Cu|Pt ºÍ Cu | Cu || Cu£¬Cu|Pt µÄ·´Ó¦¾ù¿Éд×÷ Cu + Cu = 2Cu+£¬ ´Ë¶þµç

³ØµÄ ____¡£

A. ¦¤rG¦¨mºÍ E¦¨¾ùÏàͬ B. ¦¤rG¦¨mÏàͬ£¬ E¦¨²»Í¬ C. ¦¤rG¦¨m²»Í¬£¬ E¦¨Ïàͬ D. ¦¤rG¦¨mºÍ E¦¨¾ù²»Í¬

6. ¹ÌÌå±íÃæÉ϶ÔijÖÖÆøÌå·¢Éúµ¥·Ö×Ó²ãÎü¸½£¬ Îü¸½Á¿½«ËæÆøÌåѹÁ¦Ôö´ó¶ø ¡£

A. ³É±ÈÀýÔö¼Ó B. ³É±¶Ôö¼Ó C. Öð½¥Ç÷ÓÚ±¥ºÍ D. ºã¶¨²»±ä 7. ij·´Ó¦µÄËÙÂʳ£Êý k = 0.214 min£¬·´Ó¦ÎïŨ¶È´Ó0.21 mol¡¤dm

¼äΪ t1£¬´Ó 0.12 mol¡¤dm

£­3

£­3

£­1

£­3

±äÖÁ0.14mol¡¤dm

£­3

µÄʱ

±äµ½0.08 mol¡¤dmµÄʱ¼äΪt2£¬Ôòt2 £ºt1 = ¡£

A. 0.57 B. 0.75 C. 1 D. 1.25

8. ÔÚijһζÈTÏ£¬ÓÉ´¿ÒºÌ¬µÄAÓëBÐγÉÀíÏëҺ̬»ìºÏÎï¡£ÒÑÖªpA*

A£®Ð¡ÓÚ B. ´óÓÚ C£®µÈÓÚ D. ²»ÄÜÈ·¶¨

8. 100¡æ£¬101.325kPaϵÄË®ÏòÕæ¿ÕÆø»¯ÎªÍ¬ÎÂͬѹϵÄË®ÕôÆø£¬Æä¡÷U£¨ C £©¡£

A.=0 B.£¼0 C.£¾0 D.ÎÞ·¨È·¶¨

*9. ÔÚijһζÈTÏ£¬ÓÉ´¿ÒºÌ¬µÄAÓëBÐγÉÀíÏëҺ̬»ìºÏÎï¡£ÒÑÖªp*A?pB£¬µ±Æø£­ÒºÁ½

Ïà´ïµ½Æ½ºâʱ£¬ÆøÏà×é³ÉyB×ÜÊÇ£¨ B £©ÒºÏà×é³ÉxB¡£

A£® СÓÚ B. ´óÓÚ C£®µÈÓÚ D. ²»ÄÜÈ·¶¨

10. ÔÚÈܼÁÖмÓÈë·Ç»Ó·¢ÐÔÈÜÖʺó·ÐµãÉý¸ß£¬±íÃ÷Óëδ¼ÓÈÜÖÊʱÏà±È£¬¸ÃÈܼÁµÄ»¯Ñ§ÊÆ

£¨ B £©¡£

A£® Ôö¼Ó B. ¼õС C£®²»±ä D. ²»ÄÜÈ·¶¨

11. ijÀíÏëÆøÌå´Óͬһʼ̬³ö·¢£¬·Ö±ð¾­¹ýºãοÉÄæÑ¹ËõºÍ¾øÈÈ¿ÉÄæÑ¹ËõÖÁͬһÌå»ý£¬Èô»·

¾³Ëù×÷µÄ¹¦µÄ¾ø¶ÔÖµ·Ö±ðΪWTºÍWA£¬ÎÊWTºÍWAµÄ´óС¹ØÏµÈçºÎ£¿£¨ B £©

A£®WT>WA B. WT

12. ·¢ÉúÏÂÊö±ä»¯Ê±, £¨ A £©ÏµÍ³µÄìØÖµ¿ÉÄܱ仯¡£

A. ¿ÉÄæ¹ý³Ì B. ¿ÉÄæÑ­»· C. ²»¿ÉÄæÑ­»· D. ¾øÈÈ¿ÉÄæ

13. ¶ÔÀíÏëÆøÌ壬ÏÂÁйØÏµÊ½²»ÕýÈ·µÄÊÇ£¨ A £©¡£

??H???H???U??0?0A£®? B. C£®?????0 D. ???T?p??p?T??V?T

??U????0 ??V?T14. ¸ß·ÖÉ¢¶È¹ÌÌå±íÃæÎü¸½ÆøÌåºó£¬¿Éʹ¹ÌÌå±íÃæµÄ¼ª²¼Ë¹º¯Êý£¨ A £©¡£

A.¼õС B.Ôö´ó C. ²»¸Ä±ä D. ÎÞ·¨È·¶¨

15. µç½âÖÊÈÜÒºµÄĦ¶ûµçµ¼ÂÊ¿ÉÒÔ¿´³ÉÊÇÕý¸ºÀë×ÓµÄĦ¶ûµçµ¼ÂÊÖ®ºÍ£¬ÕâÒ»¹æÂÉÊÊÓÃÓÚ

£¨ B £©¡£

A£®Ç¿µç½âÖÊÈÜÒº B. ÎÞÏÞÏ¡Ê͵ç½âÖÊÈÜÒº C. Èõµç½âÖÊÈÜÒº D. ÎïÖʵÄÁ¿Å¨¶ÈΪ1µÄÈÜÒº 16. »¯Ñ§·´Ó¦µÄ¼¶ÊýÊǸöºê¹ÛµÄ¸ÅÄÊÇʵÑéµÄ½á¹û£¬ÆäÖµ£¨ D £©¡£

A. Ö»ÄÜÊÇÕýÕûÊý B. Ö»ÄÜÊÇÕûÊý C. Ö»ÄÜÊÇÕýÊý D. ÒÔÉ϶¼²»¶Ô

17. 0.1mol¡¤kg-1µÄLaCl3ÈÜÒºµÄÀë×ÓÇ¿¶ÈIΪ£¨ B £©¡£

A. 1.2 mol¡¤kg-1 B. 0.6mol¡¤kg-1 C. 0.3mol¡¤kg-1 D. 0.2mol¡¤kg-1

18. ¶Ô·´Ó¦Ê½(1) A + B = 2C ºÍ (2) (1/2)A + (1/2)B = C, ÔÚÏàͬÌõ¼þÏ´æÔÚ¹ØÏµ£¨ B £©¡£

??(1)?2?rGm(2),K?(1)??K?(2)? A.?rG(1)?2?rG(2),K(1)?K(2)£¬B.?rGm?m?m??2????(1)??rGm(2),K?(1)??K?(2)?£¬D.?rGmC.?rGm(1)??rGm(2),K?(1)?K?(2)

219. ²»ÂÛÊǵç½â³Ø»¹ÊÇÔ­µç³Ø£¬¼«»¯µÄ½á¹û¶¼½«Ê¹£¨ C £©¡£

A£®Òõ¡¢Ñô¼«µçÊÆÍ¬Ê±Ôö¼Ó B. Òõ¡¢Ñô¼«µçÊÆÍ¬Ê±¼õС C£®Ñô¼«µçÊÆ±ä´ó£¬Òõ¼«µçÊÆ±äС D. Ñô¼«µçÊÆ±äС£¬Òõ¼«µçÊÆ±ä´ó

20. ÔÚ298.15KºÍ100kPaÏÂË®Æû»¯ÎªÍ¬ÎÂͬѹµÄË®ÕôÆø£¬ÔòϵͳÓë»·¾³µÄìØ±ä£¨ C £©

A. ¦¤S£¨Ïµ£©< 0£¬¦¤S£¨»·£©<0 B. ¦¤S£¨Ïµ£©< 0£¬¦¤S£¨»·£©>0 C. ¦¤S£¨Ïµ£©>0£¬¦¤S£¨»·£©<0 D. ¦¤S£¨Ïµ£©>0£¬¦¤S£¨»·£©>0

21. ÀíÏëÆøÌå¾øÈÈÏòÕæ¿Õ×ÔÓÉÅòÕ͹ý³ÌÖУ¨ D £©

A£®W = 0£¬Q > 0£¬¦¤U > 0£¬¦¤H = 0 B. W = 0£¬Q£½0£¬ ¦¤U = 0£¬¦¤H > 0 C£®W< 0£¬Q > 0£¬¦¤U = 0£¬¦¤H = 0 D. W£½0£¬Q = 0£¬ ¦¤U = 0£¬¦¤H = 0

22. Àë×Ó¶ÀÁ¢Ô˶¯¶¨ÂÉ£¨C £©¡£

A£®Ö»ÊÊÓÃÓÚÎÞÏÞϡǿµç½âÖÊÈÜÒº B.Ö»ÊÊÓÃÓÚÎÞÏÞÏ¡Èõµç½âÖÊÈÜÒº C. ¼ÈÊÊÓÃÓÚÎÞÏÞϡǿµç½âÖÊÈÜÒºÒ²ÊÊÓÃÓÚÎÞÏÞÏ¡Èõµç½âÖÊÈÜÒº

23. ÒÑÖª·´Ó¦ 2NO£¨g£©+O2£¨g£©=2NO2£¨g£© µÄ¡÷rH¦¨m£¨T£©£¼0£¬µ±ÉÏÊö·´Ó¦´ïµ½Æ½ºâºó£¬

ÈôҪƽºâÏò²úÎï·½ÏòÒÆ¶¯£¬¿ÉÒÔ²ÉÈ¡£¨ D £©µÄ´ëÊ©¡£

A. Éý¸ßζȣ¬¼õСѹÁ¦ B. Éý¸ßζȣ¬Ôö´óѹÁ¦ C. ½µµÍζȣ¬¼õСѹÁ¦ D. ½µµÍζȣ¬Ôö´óѹÁ¦

24. ¸ß·ÖÉ¢¶È¹ÌÌå±íÃæÎü¸½ÆøÌåºó£¬¿Éʹ¹ÌÌå±íÃæµÄ¼ª²¼Ë¹º¯Êý£¨ A £©¡£

A.¼õС B.Ôö´ó C.²»¸Ä±ä D.ÎÞ·¨È·¶¨

25. ²»ÂÛÊǵç½â³Ø»¹ÊÇÔ­µç³Ø£¬¼«»¯µÄ½á¹û¶¼½«Ê¹£¨ C £©¡£

A. Òõ¡¢Ñô¼«µçÊÆÍ¬Ê±Ôö¼Ó B.Òõ¡¢Ñô¼«µçÊÆÍ¬Ê±¼õÉÙ

C. Ñô¼«µçÊÆ±ä´ó£¬Òõ¼«µçÊÆ±äС D. Ñô¼«µçÊÆ±äС£¬Òõ¼«µçÊÆ±ä´ó

26. ÓÐÒ»ÇòÐηÊÔíÅÝ£¬°ë¾¶Îªr£¬·ÊÔíË®ÈÜÒºµÄ±íÃæÕÅÁ¦Îª¦Ã£¬Ôò·ÊÔíÅÝÄÚ¸½¼ÓѹÁ¦ÊÇ£¨ C £©

A. ¡÷p=2¦Ã/r B.¡÷p=¦Ã/r C. ¡÷p=4¦Ã/r

27. ÀíÏëÆøÌå¾øÈÈÏòÕæ¿Õ×ÔÓÉÅòÕ͹ý³ÌÖУ¨ D £©

A£®W = 0£¬Q > 0£¬¦¤U > 0£¬¦¤H = 0 B. W = 0£¬Q£½0£¬ ¦¤U = 0£¬¦¤H > 0

C£®W< 0£¬Q > 0£¬¦¤U = 0£¬¦¤H = 0 D. W£½0£¬Q = 0£¬ ¦¤U = 0£¬¦¤H = 0

28. 0.1mol¡¤kg-1µÄLaCl3ÈÜÒºµÄÀë×ÓÇ¿¶ÈIΪ£¨ B £©¡£

A. 1.2 mol¡¤kg-1 B. 0.6mol¡¤kg-1 C. 0.3mol¡¤kg-1 D. 0.2mol¡¤kg-1

29. ¡÷H £½Qp´ËʽÊÊÓÃÓÚÄÄÒ»¸ö¹ý³Ì: ( B )

A. ÀíÏëÆøÌå´Ó101325 Pa·´¿¹ºã¶¨µÄ10132.5 PaÅòÕ͵½10132.5 Pa B. ÔÚ0¡æ¡¢101325 PaÏ£¬±ùÈÚ»¯³ÉË® C. µç½âCuSO4µÄË®ÈÜÒº

D. ÆøÌå´Ó( 298K£¬101325 Pa )¿ÉÄæ±ä»¯µ½( 373K£¬10132.5 Pa )

30. ²»ÂÛÊǵç½â³Ø»¹ÊÇÔ­µç³Ø£¬¼«»¯µÄ½á¹û¶¼½«Ê¹£¨ C £©¡£

A£®Òõ¡¢Ñô¼«µçÊÆÍ¬Ê±Ôö¼Ó B. Òõ¡¢Ñô¼«µçÊÆÍ¬Ê±¼õС

C£®Ñô¼«µçÊÆ±ä´ó£¬Òõ¼«µçÊÆ±äС D. Ñô¼«µçÊÆ±äС£¬Òõ¼«µçÊÆ±ä´ó

31. ÔÚ298.15KºÍ100KPaÏÂË®Æû»¯ÎªÍ¬ÎÂͬѹµÄË®ÕôÆø£¬ÔòϵͳÓë»·¾³µÄìØ±ä£¨ C £©

A. ¦¤Ssys< 0£¬¦¤Samb<0 B. ¦¤Ssys < 0£¬¦¤Samb >0 C. ¦¤Ssys >0£¬¦¤Samb <0 D. ¦¤Ssys >0£¬¦¤Samb >0

32. Èôϵͳ¾­ÀúÈÎÒâµÄ²»¿ÉÄæ¹ý³Ì£¬¸ÃϵͳµÄìØ±ä£¨ C £©¡£

A.Ò»¶¨´óÓÚÁã B. Ò»¶¨Ð¡ÓÚÁã C. ¿ÉÄÜ´óÓÚÁ㣬Ҳ¿ÉÄÜСÓÚÁã

33. ¶Ô·´Ó¦Ê½(1) A + B = 2C ºÍ (2) (1/2)A + (1/2)B = C, ÔÚÏàͬÌõ¼þÏ´æÔÚ¹ØÏµ£¨ B £©¡£

????(1)?2?rGm(2),K?(1)??K?(2)? A.?rGm(1)?2?rGm(2),K?(1)?K?(2)£¬B.?rGm2???rGm(1)??rGm(2),K?(1)??K?(2)?2??£¬D.?rGm(1)??rGm(2),K?(1)?K?(2)

C.

34. ¶ÔÀíÏëÆøÌ壬ÏÂÁйØÏµÊ½²»ÕýÈ·µÄÊÇ£¨ A £©¡£

??H???H???U??0?0A£®? B. C£®?????0 D. ??V?T?p??p??T??T??U????0 ?V??T35. ¸ß·ÖÉ¢¶È¹ÌÌå±íÃæÎü¸½ÆøÌåºó£¬¿Éʹ¹ÌÌå±íÃæµÄ¼ª²¼Ë¹º¯Êý£¨ A £©¡£

A. ¼õС B. Ôö´ó C. ²»¸Ä±ä D. ÎÞ·¨È·¶¨

36. ijÌåϵ¾­²»¿ÉÄæÑ­»·ºó£¬ÏÂÁдð°¸Öв»ÕýÈ·µÄÊÇ£¨ A £©

A Q=0 B ¡÷U=0 C ¡÷H=0 D ¡÷CP=0

37. ×é·ÖAºÍBÄÜÐγÉÀíÏëҺ̬»ìºÏÎï¡£ÒÑÖªÔÚ1000Cʱ£¬´¿ÒºÌåAºÍBµÄ±¥ºÍÕôÆûѹ·Ö±ð

133.32ºÍ66.66KPa£¬µ±AºÍBµÄҺ̬»ìºÏÎïÖÐAµÄĦ¶û·ÖÊýxAΪ0.5ʱ£¬ÓëҺ̬»ìºÏÎï³ÉƽºâµÄÕôÆûÖÐ×é·ÖAµÄĦ¶û·ÖÊýyAÊÇ( C )

A 1 B 3/4 C 2/3 D 1/2

38. ÀíÏëÆøÌå¾­ÀúµÈοÉÄæ¹ý³Ì£¬ÆäìØ±äµÄ¼ÆË㹫ʽÊÇ£º ___¡£

A.??S =nRTln(p1/p2) B. ?S =nRTln(V2/V1) C.??S =nRln(p2/p1) D.??S =nRln(V2/V1)

39. ÔÚ±ê׼ѹÁ¦p? ºÍ268.15Kʱ£¬±ù±äΪˮ£¬ÌåϵµÄìØ±ä?S ÌåÓ¦£º ___¡£

A. ´óÓÚÁã B. СÓÚÁã C. µÈÓÚÁã D. ÎÞ·¨È·¶¨

40. ÔÚ00C£¬101.325kPaµÄѹÁ¦Ï£¬H2O£¨s£©¡úH2O£¨l£©£¬´Ë¹ý³Ì£¨ D £©¡£

A. W<0, ¦¤U<0, ¦¤G<0 B. W>0, ¦¤U>0, ¦¤G<0 C. W<0, ¦¤U>0, ¦¤G=0 D. W>0, ¦¤U>0, ¦¤G=0 41. ij»ùÔª·´Ó¦ÎªË«·Ö×Ó·´Ó¦£¬¸Ã·´Ó¦µÄ·´Ó¦¼¶Êý£¨ A £©¡£

A. µÈÓÚ£² B. ´óÓÚ£² C. СÓÚ£² D. ÎÞ·¨È·¶¨

?42. ·´Ó¦ 2NO(g) + O2(g) = 2NO2(g)µÄ?rHm< 0£¬µ±´Ë·´Ó¦´ïƽºâºó, ÈôҪʹƽºâÏò²úÎï·½Ïò

ÒÆ¶¯£¬¿ÉÒÔ ___¡£

A. ÉýÎÂÉýѹ B. ÉýνµÑ¹ C. ½µÎÂÉýѹ D. ½µÎ½µÑ¹

43. ÔÚijζÈÏ£¬Ò»ÃܱոÕÐÔÈÝÆ÷ÄÚPCl5 (g)´ïµ½·Ö½âƽºâ£¬ÈôÍù´ËÈÝÆ÷ÖгäÈëµªÆøÊ¹ÏµÍ³Ñ¹

Á¦Ôö´óÒ»±¶(´ËÊ±ÆøÌåÈԿɰ´ÀíÏëÆøÌå´¦Àí)£¬ÔòPCl5(g)µÄÀë½â¶È½«____¡£

A. Ôö´ó B. ¼õС C. ²»±ä D. ÊÓζȶø¶¨

44. Èôϵͳ¾­ÀúÈÎÒâµÄ²»¿ÉÄæ¹ý³Ì£¬¸ÃϵͳµÄìØ±ä£¨ C £©¡£

A Ò»¶¨´óÓÚÁã B.Ò»¶¨Ð¡ÓÚÁã C.¿ÉÄÜ´óÓÚÁ㣬Ҳ¿ÉÄÜСÓÚÁã

45. ·´Ó¦2A?3B£¬Ôò-dCA / dtÓëdCB / dtÖ®±ÈΪ £¨ A £©¡£

A 2:3 B 1:1 C 3:2 D 2:2

46. ÀíÏëÆøÌå¾øÈÈÏòÕæ¿Õ×ÔÓÉÅòÕ͹ý³ÌÖУ¨ D £©

A£®W = 0£¬Q > 0£¬¦¤U > 0£¬¦¤H = 0 B. W = 0£¬Q£½0£¬ ¦¤U = 0£¬¦¤H > 0 C£®W< 0£¬Q > 0£¬¦¤U = 0£¬¦¤H = 0 D. W£½0£¬Q = 0£¬ ¦¤U = 0£¬¦¤H = 0

47. ijÀíÏëÆøÌå´Óͬһʼ̬³ö·¢£¬·Ö±ð¾­¹ýºãοÉÄæÑ¹ËõºÍ¾øÈÈ¿ÉÄæÑ¹ËõÖÁͬһÌå»ý£¬Èô»·

¾³Ëù×÷µÄ¹¦µÄ¾ø¶ÔÖµ·Ö±ðΪWTºÍWA£¬ÎÊWTºÍWAµÄ´óС¹ØÏµÈçºÎ£¿£¨ B £©

A£®WT>WA B. WT

48. ¶ÔÀíÏëÆøÌ壬ÏÂÁйØÏµÊ½²»ÕýÈ·µÄÊÇ£¨ A £©¡£

??H???H???U??0?0A£®? B. C£®?????0 D. ???T?p??p?T??V?T??U????0 ??V?T49. ÒÑÖª E¦¨Cu2+/Cu = 0.337V£¬ E¦¨Cu+/Cu = 0.521V£¬ ÓÉ´Ë¿ÉÇó³öE¦¨Cu2+/Cu+ = V¡£

A. 0.184 B. £­0.184 C. 0.352 D. 0.153

50. ¸ß·ÖÉ¢¶È¹ÌÌå±íÃæÎü¸½ÆøÌåºó£¬¿Éʹ¹ÌÌå±íÃæµÄ¼ª²¼Ë¹º¯Êý£¨ A £©¡£

A.¼õС B.Ôö´ó C. ²»¸Ä±ä D. ÎÞ·¨È·¶¨

51. µç½âÖÊÈÜÒºµÄĦ¶ûµçµ¼ÂÊ¿ÉÒÔ¿´³ÉÊÇÕý¸ºÀë×ÓµÄĦ¶ûµçµ¼ÂÊÖ®ºÍ£¬ÕâÒ»¹æÂÉÊÊÓÃÓÚ

£¨ B £©¡£

A£®Ç¿µç½âÖÊÈÜÒº B. ÎÞÏÞÏ¡Ê͵ç½âÖÊÈÜÒº C. Èõµç½âÖÊÈÜÒº D. ÎïÖʵÄÁ¿Å¨¶ÈΪ1µÄÈÜÒº

*52. ÔÚijһζÈTÏ£¬ÓÉ´¿ÒºÌ¬µÄAÓëBÐγÉÀíÏëҺ̬»ìºÏÎï¡£ÒÑÖªp*A?pB£¬µ±Æø£­ÒºÁ½

Ïà´ïµ½Æ½ºâʱ£¬ÆøÏà×é³ÉyB×ÜÊÇ£¨ B £©ÒºÏà×é³ÉxB¡£

A£® СÓÚ B. ´óÓÚ C£®µÈÓÚ D. ²»ÄÜÈ·¶¨ 53. ijÌåϵ¾­²»¿ÉÄæÑ­»·ºó£¬ÏÂÁдð°¸Öв»ÕýÈ·µÄÊÇ£¨ A £©

A Q=0 B ¡÷U=0 C ¡÷H=0 D ¡÷CP=0

54. ijÀíÏëÆøÌå´Óͬһʼ̬³ö·¢£¬·Ö±ð¾­¹ýºãοÉÄæÑ¹ËõºÍ¾øÈÈ¿ÉÄæÑ¹ËõÖÁͬһÌå»ý£¬Èô»·

¾³Ëù×÷µÄ¹¦µÄ¾ø¶ÔÖµ·Ö±ðΪWTºÍWA£¬ÎÊWTºÍWAµÄ´óС¹ØÏµÈçºÎ£¿£¨ B £©

A£®WT>WA B. WT

55. ijÌåϵÔڷǵÈѹ¹ý³ÌÖмÓÈÈ£¬ÎüÈÈs£¬Ê¹Î¶ȴÓT1Éýµ½T2£¬Ôò´Ë¹ý³ÌµÄìÊÔöÁ¿?H£º£¨ £©

A.?H = Q B.?H = 0 C.?H = U +(pV) D.?H µÈÓÚ±ðµÄÖµ¡£

56. ¶ÔÀíÏëÆøÌ壬ÏÂÁйØÏµÊ½²»ÕýÈ·µÄÊÇ£¨ £©¡£

??H???H???U???U??0?0?0A£®? B. C£® D. ????????0

??T?p??V?T??p?T??V?T57. 0.1mol¡¤kg-1µÄLaCl3ÈÜÒºµÄÀë×ÓÇ¿¶ÈIΪ£¨ £©¡£

-1-1-1

A. 1.2 mol¡¤kg B. 0.6mol¡¤kg C. 0.3mol¡¤kg D. 0.2mol¡¤kg-1

58. ÓÐÒ»ÇòÐηÊÔíÅÝ£¬°ë¾¶Îªr£¬·ÊÔíË®ÈÜÒºµÄ±íÃæÕÅÁ¦Îª¦Ã£¬Ôò·ÊÔíÅÝÄÚ¸½¼ÓѹÁ¦ÊÇ£¨ £©

A. ¡÷p=2¦Ã/r B.¡÷p=¦Ã/r C. ¡÷p=4¦Ã/r D. ¡÷p=3¦Ã/r

59. ²»ÂÛÊǵç½â³Ø»¹ÊÇÔ­µç³Ø£¬¼«»¯µÄ½á¹û¶¼½«Ê¹£¨ C £©¡£

A£®Òõ¡¢Ñô¼«µçÊÆÍ¬Ê±Ôö¼Ó B. Òõ¡¢Ñô¼«µçÊÆÍ¬Ê±¼õС

C£®Ñô¼«µçÊÆ±ä´ó£¬Òõ¼«µçÊÆ±äС D. Ñô¼«µçÊÆ±äС£¬Òõ¼«µçÊÆ±ä´ó

60. ÔÚ298.15KºÍ100kPaÏÂË®Æû»¯ÎªÍ¬ÎÂͬѹµÄË®ÕôÆø£¬ÔòϵͳÓë»·¾³µÄìØ±ä£¨ C £©

A. ¦¤S£¨Ïµ£©< 0£¬¦¤S£¨»·£©<0 B. ¦¤S£¨Ïµ£©< 0£¬¦¤S£¨»·£©>0 C. ¦¤S£¨Ïµ£©>0£¬¦¤S£¨»·£©<0 D. ¦¤S£¨Ïµ£©>0£¬¦¤S£¨»·£©>0

61. ÏÂÊö˵·¨ºÎÕßÕýÈ·£º£¨ £©

A. Ë®µÄÉú³ÉÈȼ´ÊÇÑõÆøµÄȼÉÕÈÈ B.Ë®ÕôÆûµÄÉú³ÉÈȼ´ÊÇÑõÆøµÄȼÉÕÈÈ B. Ë®µÄÉú³ÉÈȼ´ÊÇÇâÆøµÄȼÉÕÈÈ D.Ë®ÕôÆûµÄÉú³ÉÈȼ´ÊÇÇâÆøµÄȼÉÕÈÈ

62. ÒÑÖª373KʱҺÌåAµÄ±¥ºÍÕôÆøÑ¹Îª133.24kPa£¬ÒºÌåBµÄ±¥ºÍÕôÆøÑ¹Îª66.62kPa¡£ÉèA

ºÍBÐγÉÀíÏëÈÜÒº£¬µ±ÈÜÒºÖÐAµÄÎïÖʵÄÁ¿·ÖÊýΪ0.5ʱ£¬ÔÚÆøÏàÖÐAµÄÎïÖʵķÖÊýΪ£º£¨ £©

A. 1 B. 1/2 C. 2/3 D. 1/3

63. ÔÚ-100C, p¦¨Ê±£¬1mol ¹ýÀäË®½á³É±ùʱ£¬ÏÂÊö±íÊöÕýÈ·µÄÊÇ£¨ A £©

A. ¦¤G< 0£¬¦¤Ssys <0 B. ¦¤G < 0£¬¦¤Ssys >0 C. ¦¤G >0£¬¦¤Ssys <0 D. ¦¤G >0£¬¦¤Ssys >0

64. ¶Ô·´Ó¦Ê½(1) A + B = 2C ºÍ (2) (1/2)A + (1/2)B = C, ÔÚÏàͬÌõ¼þÏ´æÔÚ¹ØÏµ£¨ B £©¡£

????(1)?2?rGm(2),K?(1)??K?(2)? A.?rGm(1)?2?rGm(2),K?(1)?K?(2)£¬B.?rGm2???rGm(1)??rGm(2),K?(1)??K?(2)?2??£¬D.?rGm(1)??rGm(2),K?(1)?K?(2)

C.

65. ¶Ô·´Ó¦Ê½(1) A + B = 2C ºÍ (2) (1/2)A + (1/2)B = C, ÔÚÏàͬÌõ¼þÏ´æÔÚ¹ØÏµ£¨ £©¡£

????(1)?2?rGm(2),K?(1)??K?(2)? A.?rGm(1)?2?rGm(2),K?(1)?K?(2)£¬B.?rGm2????C.?rGm(1)??rGm(2),K?(1)??K?(2)?£¬D.?rGm(1)??rGm(2),K?(1)?K?(2)

266. ÔÚµç½âAgNO3ʱ£¬µç¼«·¢Éú¼«»¯£¬£¨ £©¡£

A. Òõ¼«µÄ»¹Ô­µç¼«µçÊÆÔö´ó B. Òõ¼«¸½½üAg+Ũ¶ÈÔö¼Ó

C µç½â³Øµç×è¼õС D Á½¼«Ö®¼äµçÊÆ²îÔö´ó

67. ¹ÌÌå±íÃæÉ϶ÔijÖÖÆøÌå·¢Éúµ¥·Ö×Ó²ãÎü¸½£¬ Îü¸½Á¿½«ËæÆøÌåѹÁ¦Ôö´ó¶ø£¨ £©¡£

A. ³É±ÈÀýÔö¼Ó B. ³É±¶Ôö¼Ó C. Öð½¥Ç÷ÓÚ±¥ºÍ D. ºã¶¨²»±ä

68. »¯Ñ§·´Ó¦µÄ¼¶ÊýÊǸöºê¹ÛµÄ¸ÅÄÊÇʵÑéµÄ½á¹û£¬ÆäÖµ£¨ D £©¡£

A. Ö»ÄÜÊÇÕýÕûÊý B. Ö»ÄÜÊÇÕûÊý C. Ö»ÄÜÊÇÕýÊý D. ÒÔÉ϶¼²»¶Ô

69. ÔÚ¸ôÀëϵͳÖз¢Éúij»¯Ñ§·´Ó¦£¬Ê¹ÏµÍ³µÄζÈÃ÷ÏÔÉý¸ß£¬Ôò¸ÃϵͳµÄ¡÷U

£¨ B £©¡£

A. £¾0 B. =0 C. £¼0 D.ÎÞ·¨È·¶¨

70. ij»ùÔª·´Ó¦ÎªË«·Ö×Ó·´Ó¦£¬¸Ã·´Ó¦µÄ·´Ó¦¼¶Êý£¨ A £©¡£

A. µÈÓÚ2 B. ´óÓÚ2 C. СÓÚ2 D. ÎÞ·¨È·¶¨

71. 0.1mol¡¤kg-1µÄLaCl3ÈÜÒºµÄÀë×ÓÇ¿¶ÈIΪ£¨ B £©¡£

A. 1.2 mol¡¤kg-1 B. 0.6mol¡¤kg-1 C. 0.3mol¡¤kg-1 D. 0.2mol¡¤kg-1

72. ij·´Ó¦µÄ·´Ó¦ÎïÏûºÄµô3/4µÄʱ¼äÊÇÆä°ëË¥ÆÚµÄ2±¶£¬Ôò¸Ã·´Ó¦¼¶ÊýΪ £¨ £©¡£

A. Áã¼¶ B. Ò»¼¶ C. ¶þ¼¶ D. Èý¼¶

73. Èçͼ£¬Óøô°å½«¸ÕÐÔ¾øÈȱÚÈÝÆ÷·Ö³ÉÁ½°ë£¬Á½±ß³äÈëѹÁ¦²»µÈµÄ¿ÕÆø(ÊÓΪÀíÏëÆøÌå)£¬ÒÑ

ÖªpÓÒ> p×󣬽«¸ô°å³éÈ¥ºó£º ___¡£

a) A. Q £½0£¬W £½0£¬U £½0 B. Q£½0£¬W <0£¬U >0 b) C. Q >0£¬W <0£¬U >0 D. U £½0£¬Q£½W?0

74.ijÀíÏëÆøÌåµÄ¦Ã=Cp/CV=1.4£¬Ôò¸ÃÆøÌåΪ¼¸Ô­×Ó·Ö×ÓÆøÌ壿 ___¡£

A. µ¥Ô­×Ó·Ö×ÓÆøÌå B.˫ԭ×Ó·Ö×ÓÆøÌå C.ÈýÔ­×Ó·Ö×ÓÆøÌå D.ËÄÔ­×Ó·Ö×ÓÆøÌå

74. ÔÚ¦Á£¬¦ÂÁ½ÖÖÏàÖоùº¬ÓÐAºÍBÁ½ÖÖÎïÖÊ£¬µ±´ïµ½Æ½ºâʱ£¬ÏÂÁÐÖÖÄÄÇé¿öÊÇÕýÈ·µÄ£º ___.

A.¦ÌA¦Á = ¦ÌB¦Á B.¦ÌA¦Á = ¦ÌA¦Â C.¦ÌA¦Á =¦ÌB¦Â D. ¦ÌA¦Â = ¦ÌB¦Â

75. µ±ÀíÏëÆøÌå·´¿¹Ò»¶¨µÄѹÁ¦×÷¾øÈÈÅòÕÍʱ£¬Ôò£¨ D £©

A£®ìÊ×ÜÊDz»±ä B. ÈÈÁ¦Ñ§ÄÜ×ÜÊÇÔö¼Ó C£®ìÊ×ÜÊÇÔö¼Ó D. ÈÈÁ¦Ñ§ÄÜ×ÜÊǼõÉÙ 76. ÀíÏëÆøÌå¾øÈÈÏòÕæ¿Õ×ÔÓÉÅòÕ͹ý³ÌÖУ¨ D £©

A£®W = 0£¬Q > 0£¬¦¤U > 0£¬¦¤H = 0 B. W = 0£¬Q£½0£¬ ¦¤U = 0£¬¦¤H > 0 C£®W< 0£¬Q > 0£¬¦¤U = 0£¬¦¤H = 0 D. W£½0£¬Q = 0£¬ ¦¤U = 0£¬¦¤H = 0

77. Á½ÒºÌåµÄ±¥ºÍÕôÆûѹ·Ö±ðΪp*A£¬p*B £¬ËüÃÇ»ìºÏÐγÉÀíÏëÈÜÒº£¬ÒºÏà×é³ÉΪx£¬ÆøÏà×é

³ÉΪy£¬Èô p*A > p*B £¬ Ôò£º ___.

A. yA > xA B. yA > yB C. xA > yA D. yB > yA

ËÄ¡¢¼ò´ðÌâ

1£®ÀíÏëÆøÌåµÈÎÂÅòÕͺó£¬ÓÉÓÚ¡÷U=0£¬ËùÒÔÎüµÄÈÈÈ«²¿×ª»¯Îª¹¦£¬ÕâÓëÈÈÁ¦Ñ§µÚ¶þ¶¨ÂÉì¶ÜÂð£¿ÎªÊ²Ã´£¿ 2. ÒÔÁ½ÖÖŨ¶È²»Í¬µÄHClÈÜÒºµÄ½çÃæÎªÀý£¬ËµÃ÷ÒºÌå½Ó½çµçÊÆ²úÉúµÄÔ­Òò¼°Ïû³ý·½Ê½¡£

3. ÔÚζÈÒ»¶¨µÄÇé¿öÏ£¬Ïò·´Ó¦Æ½ºâÌåϵÖгäÈë¶èÐÔÆøÌåÓë¼õµÍÌåϵµÄѹÁ¦µÈЧ£¬ÕâÖÖ˵·¨¶ÔÂð£¿

4. ÔÚºãΡ¢ºãѹ¡¢·ÇÌå»ý¹¦ÎªÁãµÄÌõ¼þÏ£¬Ä³·´Ó¦µÄ¡÷rGm<£°£¬Ôò·´Ó¦ÎïÈ«²¿±ä³É²úÎ·´Ó¦½«½øÐе½µ×£¬ÕâÖÖ˵·¨¶ÔÂ𣿼òÊöÆäÀíÓÉ¡£

5. ÏÂͼΪˮµÄÏàͼ£¬Çë¼òÒª½âÊͱùˮƽºâÏßOBбÂÊΪ¸ºÖµµÄÔ­Òò

BA

P / KPals0.61C273.16T/KOg6. д³öÓ¦ÓÃS¡¢A¡¢GÈý¸ö״̬º¯Êý×÷Ϊ¹ý³Ì·½ÏòµÄÅоݼ°ÆäÓ¦ÓÃÌõ¼þ£¿

7. ÔÚºãΡ¢ºãѹ¡¢·ÇÌå»ý¹¦ÎªÁãµÄÌõ¼þÏ£¬Ä³·´Ó¦µÄ¡÷rGm<£°£¬Ôò·´Ó¦ÎïÈ«²¿±ä³É²úÎ·´Ó¦½«½øÐе½µ×£¬ÕâÖÖ˵·¨¶ÔÂ𣿼òÊöÆäÀíÓÉ¡£

8£®ÀíÏëҺ̬»ìºÏÎïµÄ¶¨ÒåÊÇʲô? ˵Ã÷ÀíÏëҺ̬»ìºÏÎïµÄ»ìºÏÐÔÖÊ¡£ 9. д³öÓ¦ÓÃS¡¢A¡¢GÈý¸ö״̬º¯Êý×÷Ϊ¹ý³Ì·½ÏòµÄÅоݼ°ÆäÓ¦ÓÃÌõ¼þ£¿

10. AºÍB¹Ì̬ʱÍêÈ«²»»¥ÈÜ£¬101 325 Pa ʱA(s)µÄÈÛµãΪ30?C£¬B(s)µÄÈÛµãΪ50?C£¬AºÍBÔÚ10?C¾ßÓÐ×îµÍ¹²È۵㣬Æä×é³ÉΪxB?E=0.4£¬ÉèAºÍBµÄÈܽâ¶ÈÇúÏß¾ùΪֱÏß¡£½ñÓÉ2 mol A ºÍ8 mol B ×é³Éϵͳ£¬¸ù¾Ý»­³öµÄt-xBͼ£¬ÁÐ±í»Ø´ðϵͳÔÚ5?C£¬30?C£¬50?CʱµÄÏàÊý¡¢ÏàµÄ¾Û¼¯Ì¬¼°³É·Ö¡¢ÏµÍ³ËùÔÚÏàÇøµÄ×ÔÓɶÈÊý¡£

ÎÂ¶È ÏàÊý t / ?C 5 30 50 ÏàµÄ¾Û¼¯Ì¬¼°³É·Ö ×ÔÓɶÈF

11. ¡°ÔÚµÈΣ¬µÈѹÌõ¼þÏ£¬?rGm?0µÄ·´Ó¦Ò»¶¨²»ÄܽøÐС±ÕâÖÖ˵·¨¶ÔÂð£¬ÎªÊ²Ã´£¿

12 д³öÓ¦ÓÃS¡¢A¡¢GÈý¸ö״̬º¯Êý×÷Ϊ¹ý³Ì·½ÏòµÄÅоݼ°ÆäÓ¦ÓÃÌõ¼þ£¿ 13. ÔÚÒ»¶¨Î¶ÈѹÁ¦ÏÂ,ΪʲôÎïÀíÎü¸½ÊÇ·ÅÈÈ·´Ó¦?

14. ¾ßÓÐÒ»¶¨×ª±äζȵĶþ×é·Ö¹Ì̬²¿·Ö»¥ÈÜϵͳÏàͼÈ總ͼ,»æ³ö״̬µãΪaÑùÆ·µÄÀäÈ´ÇúÏß¡£

t t 0

L a b l+ ¦Â S 1 c S 2 d ¦Á£«¦Â ¦Â l+ ¦Á ¦Á

15. £¨9·Ö£©¾ßÓе͹²ÈÛµãµÄ¶þ×é·Ö¹Ì̬²¿·Ö»¥ÈÜϵͳÏàͼÈ總ͼ,»æ³ö״̬µãΪa£¬eÑùÆ·µÄÀäÈ´ÇúÏß¡£

A M P S 1 a b L c d f e S 2

t/?C

Q w B

N B

Îå¡¢¼ÆËãÌâ

*1. ÒÑÖªÒºÌå¼×±½£¨A£©ºÍÒºÌå±½£¨B£©ÔÚ 900CʱµÄ±¥ºÍÕôÆûѹ·Ö±ðΪp*A£½54.22kPaºÍpB£½136.12kPa¡£

Á½Õß¿ÉÐγÉÀíÏëҺ̬»ìºÏÎï¡£½ñÓÐϵͳ×é³ÉΪxB,0£½0.3µÄ¼×±½£­±½»ìºÏÎï5mol£¬ÔÚ900CÏÂ³ÉÆø£­ÒºÁ½ÏàÆ½ºâ£¬ÈôÆøÏà×é³ÉΪyB=0.4556£¬Çó

£¨1£©Æ½ºâʱҺÏà×é³ÉxB¼°ÏµÍ³µÄѹÁ¦p£» £¨2£©Æ½ºâÊ±Æø¡¢ÒºÁ½ÏàµÄÎïÖʵÄÁ¿n£¨g£©£¬n£¨l£©¡£

2£®ÒÑÖªÏÂÁÐµç³ØPt|H2(100kPa)|HBr£¨¦Á¡À£½1£©|AgBr£¨s£©| Ag£¨s£©ÔÚ25oCʱµÄµç¶¯ÊÆE£½0.0713V£¬

??E?-4-1µç¶¯ÊƵÄζÈϵÊý?£½£­5.0¡Á10V¡¤K¡£ ???T?pÇó£¨1£©Ð´³öµç¼«·´Ó¦ºÍµç³Ø·´Ó¦¡£

£¨2£©¼ÆËã¸Ãµç³Ø·´Ó¦ÔÚ25oC ʱµÄ?rHm¡¢?rSm¡¢?rGm

£¨3£©ÈôÉÏÊöµç³ØµÄHBrÈÜÒºµÄŨ¶Èb£½2.0mol¡¤kg£­1£¬ÔÚ25oC²âµÃµç³ØµÄµç¶¯ÊÆE£½0.0815V£¬ÇóÈÜÒºÖÐHBrµÄ»î¶È?HBr¡£

3£® A£¬BÁ½ÒºÌåÄÜÐγÉÀíÏëҺ̬»ìºÏÎï¡£ÒÑÖªÔÚζÈtʱ´¿AµÄ±¥ºÍÕôÆøÑ¹´¿BµÄ±¥ºÍÕôÆøÑ¹

¡£

µÄA£¬B»ìºÏÆøÌåºãλºÂýѹËõ£¬ÇóÄý½á³ö

£¬

£¨1£©ÔÚζÈtÏ£¬ÓÚÆø¸×Öн«×é³ÉΪ

µÚÒ»µÎ΢СҺµÎʱϵͳµÄ×Üѹ¼°¸ÃÒºµÎµÄ×é³É£¨ÒÔĦ¶û·ÖÊý±íʾ£©Îª¶àÉÙ£¿

£¨2£©Èô½«A£¬BÁ½ÒºÌå»ìºÏ£¬²¢Ê¹´Ë»ìºÏÎïÔÚ100 kPa£¬Î¶ÈtÏ¿ªÊ¼·ÐÌÚ£¬Çó¸ÃҺ̬»ìºÏÎïµÄ×é³É¼°·ÐÌÚʱ±¥ºÍÕôÆøµÄ×é³É£¨Ä¦¶û·ÖÊý£©

4£®¼×´¼ÔÚ337.65 KµÄ±¥ºÍÕôÆøÑ¹p*=101.325 kPa£¬ÔÚ´ËζÈѹÁ¦Ï£¬¼×´¼µÄĦ¶ûÕô·¢ìÊ¡÷vapHm = 35.32 kJ¡¤mol-1¡£ÇóÔÚ337.65 K¡¢101.325 kPaÏ£¬2molÆøÌ¬¼×´¼È«²¿Äý½á³ÉҺ̬¼×´¼Ê±µÄQ¡¢W¡¢¡÷U¡¢¡÷H¡¢¡÷S¡¢¡÷AºÍ¡÷G 5£®Ê¼Ì¬Îª

£¬

£¨1£© ºãοÉÄæÅòÕÍ£»

£¨2£© ÏȺãÈÝÀäÈ´ÖÁʹѹÁ¦½µÖÁ100 kPa£¬ÔÙºãѹ¼ÓÈÈÖÁ

£»

¡£

£¬

µÄij˫ԭ×ÓÀíÏëÆøÌå1 mol£¬¾­ÏÂÁв»Í¬Í¾¾¶±ä»¯µ½

µÄĩ̬¡£Çó¸÷²½Ö輰;¾¶µÄ

¡£

£¨3£© ÏȾøÈÈ¿ÉÄæÅòÕ͵½Ê¹Ñ¹Á¦½µÖÁ100 kPa£¬ÔÙºãѹ¼ÓÈÈÖÁ

6£®250Cʱ£¬µç³ØAg|AgCl(s)|HCl(b)| Cl2 (g,100kPa) |PtµÄµç¶¯ÊÆE£½1.136V£¬µç¶¯ÊƵÄζÈϵ

1??E?-4-1Êý?= -5.95¡Á10V¡¤K¡£µç³Ø·´Ó¦ÎªAg?Cl2(g,100kPa)?AgCl(s)¡£ÊÔ¹ÀËã¸Ã·´Ó¦µÄ?2??T?p¦¤G¡¢¦¤S¡¢¦¤H¼°µç³ØºãοÉÄæ·Åµçʱ¹ý³ÌµÄ¿ÉÄæÈÈQr¡£

7. ÒÑÖª373.15K¡¢101.325kPaÏÂË®µÄĦ¶ûÕô·¢ìÊ¡÷vapHmΪ40.63 kJ¡¤mol1£¬Ë®ÕôÆûÓëÒºÌåË®µÄĦ¶ûÌå»ý·Ö

£­£­£­£­

±ðΪV£¨£½3.019¡Á102 m3¡¤mol1£¬V£¨£½1.800¡Á105 m3¡¤mol1¡£¼ÆËã1molÒºÌåË®ÓÚ373.15K¡¢101.325kPa mg£©ml£©

ÏÂÏòÕæ¿ÕÕô·¢ÎªÍ¬ÎÂͬѹϵÄË®ÕôÆûµÄQ¡¢W¡¢¡÷U¡¢¡÷H¡¢¡÷G£¨ÉèË®ÕôÆûΪÀíÏëÆøÌ壬RΪ8.315J¡¤mol£­1£­

¡¤K1£©¡£

£­

8£® ÔÚÒ»¸ö³é¿ÕµÄºãÈÝÈÝÆ÷ÖÐÒýÈëÂȺͶþÑõ»¯Áò£¬ÈôËüÃÇÖ®¼äûÓз¢Éú·´Ó¦£¬ÔòÔÚ375.3 KʱµÄ·Öѹ·Ö±ðΪ47.836 kPaºÍ44.786 kPa¡£½«ÈÝÆ÷±£³ÖÔÚ375.3 K£¬¾­Ò»¶¨Ê±¼äºó£¬×ÜѹÁ¦¼õÉÙÖÁ86.096 kPa£¬ÇÒά³Ö²»±ä¡£ÇóÏÂÁз´Ó¦µÄ

¡£

9. ¼×Íéת»¯·´Ó¦CH4(g)+H2O(g) = CO(g)+3H2(g)ÔÚ900KʱµÄ±ê׼ƽºâ³£ÊýK¦¨ =1.280£¬ ÈôÈ¡µÈĦ¶ûµÄ¼×ÍéÓëË®ÕôÆø·´Ó¦£¬Çó900K£¬101.325kPaÏ´ﵽƽºâʱϵͳµÄ×é³É¡£

10£®ÒÑÖªÏÂÁÐµç³ØPt|H2(100kPa)|HBr£¨¦Á¡À£½1£©|AgBr£¨s£©| Ag£¨s£©ÔÚ25oCʱµÄµç¶¯ÊÆE£½

??E?-4-1

0.0713V£¬µç¶¯ÊƵÄζÈϵÊý??£½£­5.0¡Á10V¡¤K¡£

??T?pÇó£¨1£©Ð´³öµç¼«·´Ó¦ºÍµç³Ø·´Ó¦¡£

£¨2£©¼ÆËã¸Ãµç³Ø·´Ó¦ÔÚ25oC ʱµÄ?rHm¡¢?rSm¡¢?rGm

£¨3£©ÈôÉÏÊöµç³ØµÄHBrÈÜÒºµÄŨ¶ÈB£½2.0mol¡¤kg£­1£¬ÔÚ25oC²âµÃµç³ØµÄµç¶¯ÊÆE£½0.0815V£¬ÇóÈÜÒºÖÐHBrµÄ»î¶È?HBr¡£

11£® ÒÑÖª25 OCʱ

ʱ²âµÃÆäµç×èΪ

KClÈÜÒºµÄµçµ¼ÂÊΪ

¡£ÔÚͬһµçµ¼³ØÖÐ×°ÈëͬÑùÌå»ýµÄÖÊÁ¿Å¨¶ÈΪ

¡£Ò»µçµ¼³ØÖгäÒÔ´ËÈÜÒº£¬ÔÚ25 OC

µÄCaCl2ÈÜÒº£¬²âµÃµç

×èΪ1050Å·Ä·¡£¼ÆË㣨1£©µçµ¼³ØÏµÊý£»£¨2£©CaCl2ÈÜÒºµÄµçµ¼ÂÊ£»£¨3£©CaCl2ÈÜÒºµÄĦ¶ûµçµ¼ÂÊ¡£

12£®2 molµ¥Ô­×ÓÀíÏëÆøÌåÓÉ500 K£¬405.2 kPaµÄʼ̬£¬ÒÀ´Î¾­ÏÂÁйý³Ì£º (1)ÔÚºãÍâѹ202.6 kPaÏ£¬¾øÈÈÅòÕÍÖÁƽºâ̬£¬ (2)ÔÙ¿ÉÄæ¾øÈÈÅòÕÍÖÁ101.3 kPa£» (3)×îºóºãÈݼÓÈÈÖÁ500 KµÄÖÕ̬¡£ÊÔÇóÕû¸ö¹ý³ÌµÄQ£¬W£¬¦¤U£¬¦¤H¼°¦¤S¡£

13. ÒÑÖªÏÂÁÐµç³ØPt|H2(100kPa)|HBr£¨¦Á¡À£½1£©|AgBr£¨s£©| Ag£¨s£©ÔÚ25oCʱµÄµç¶¯ÊÆE£½0.0713V£¬

??E?-4-1µç¶¯ÊƵÄζÈϵÊý??£½£­5.0¡Á10V¡¤K¡£

??T?pÇó£¨1£©Ð´³öµç¼«·´Ó¦ºÍµç³Ø·´Ó¦¡£

£¨2£©¼ÆËã¸Ãµç³Ø·´Ó¦ÔÚ25oC ʱµÄ?rGm¡¢?rSm¡¢?rHm

£¨3£©ÈôÉÏÊöµç³ØµÄHBrÈÜÒºµÄŨ¶Èb£½2.0mol¡¤kg£­1£¬ÔÚ25oC²âµÃµç³ØµÄµç¶¯ÊÆE£½0.0815V£¬ÇóÈÜÒºÖÐHBrµÄ»î¶È?HBr¡£

14£®¼×±½ºÍ±½ÄÜÐγÉÀíÏëҺ̬»ìºÏÎï¡£ÒÑÖªÔÚ900CÁ½´¿ÒºÌåµÄ±¥ºÍÕôÆûѹ·Ö±ðΪ54.22kPaºÍ136.12kPa¡£Çó£º

£¨1£© ÔÚ900CºÍ101.325kPaϼױ½£­±½ÏµÍ³³ÉÆø£­ÒºÆ½ºâʱÁ½ÏàµÄ×é³É¡£

£¨2£© ÈôÓÉ100.0g¼×±½ºÍ200.0g±½¹¹³ÉµÄϵͳ£¬ÇóÔÚÉÏÊöζÈѹÁ¦Ï£¬ÆøÏàºÍÒºÏàµÄÖÊÁ¿¸÷

Ϊ¶àÉÙ£¿

15. ÒÑ֪ͬһζȣ¬Á½·´Ó¦·½³Ì¼°±ê׼ƽºâ³£ÊýÈçÏ£º

C£¨Ê¯Ä«£©+ H2O ( g ) = CO( g ) + H2 ( g ) (1) K1¦¨ C£¨Ê¯Ä«£©+ 2H2O ( g ) = CO2( g ) + 2H2( g ) (2) K2¦¨ ÇóÏÂÁз´Ó¦µÄK¦¨¡£

CO ( g ) + H2O ( g ) = CO2( g ) + H2 ( g )

16. ÒÑÖªÏÂÁÐµç³ØPt|H2(100kPa)|HBr£¨¦Á¡À£½1£©|AgBr£¨s£©| Ag£¨s£©ÔÚ25oCʱµÄµç¶¯ÊÆE£½0.0713V£¬µç¶¯ÊƵÄζÈϵÊý???E?-4-1

?£½£­5.0¡Á10V¡¤K¡£ ??T?pÇó£¨1£©Ð´³öµç¼«·´Ó¦ºÍµç³Ø·´Ó¦¡£

£¨2£©¼ÆËã¸Ãµç³Ø·´Ó¦ÔÚ25oC ʱµÄ?rHm¡¢?rSm¡¢?rGm

£¨3£©ÈôÉÏÊöµç³ØµÄHBrÈÜÒºµÄŨ¶Èb£½2.0mol¡¤kg1£¬ÔÚ25oC²âµÃµç³ØµÄµç¶¯ÊÆE£½0.0815V£¬ÇóÈÜÒº

£­

ÖÐHBrµÄ»î¶È?HBr¡£

17. ÒÑÖª¼×±½¡¢±½ÔÚ90¡ãCÏ´¿ÒºÌåµÄ±¥ºÍÕôÆøÑ¹·Ö±ðΪ54.22 kPaºÍ136.12 kPa£¬Ä¦¶ûÖÊÁ¿

·Ö±ðΪ92.14g/molºÍ78.11 g/mol¡£Á½Õß¿ÉÐγÉÀíÏëҺ̬»ìºÏÎȡ200.0 g¼×±½ºÍ200.0 g±½ÖÃÓÚ´ø»îÈûµÄµ¼ÈÈÈÝÆ÷ÖУ¬Ê¼Ì¬ÎªÒ»¶¨Ñ¹Á¦ÏÂ90¡ãCµÄҺ̬»ìºÏÎï¡£ÔÚºãÎÂ90¡ãCÏÂÖð½¥½µµÍѹÁ¦£¬ÎÊ

£¨1£©Ñ¹Á¦½µµ½¶àÉÙʱ£¬¿ªÊ¼²úÉúÆøÏ࣬´ËÆøÏàµÄ×é³ÉÈçºÎ£¿

£¨2£©Ñ¹Á¦Îª92.00 kPaʱ£¬ÏµÍ³ÄÚÆø-ÒºÁ½ÏàÆ½ºâ£¬Á½ÏàµÄ×é³ÉÈçºÎ£¿Á½ÏàµÄÎïÖʵÄÁ¿¸÷Ϊ¶àÉÙ£¿

18£®Ð´³öÏÂÁÐµç³ØµÄµç³Ø·´Ó¦¡£¼ÆËã25 ¡æÊ±µç³ØµÄµç¶¯ÊÆE¡¢µç³Ø·´Ó¦µÄ¦¤rGm£¬²¢Ö¸Ã÷µç³Ø·´Ó¦ÄÜ·ñ×Ô·¢½øÐС£ÒÑÖªE¦¨( Zn2+|Zn ) = - 0.762V, E¦¨( Cl- |AgCl(s) |Ag ) = 0.22216V¡£

Zn| Zn Cl2£¨a=0.6£©|AgCl£¨s£©|Ag

*19. ÒÑÖªÒºÌå¼×±½£¨A£©ºÍÒºÌå±½£¨B£©ÔÚ 900CʱµÄ±¥ºÍÕôÆûѹ·Ö±ðΪp*A£½54.22kPaºÍpB£½

136.12kPa¡£Á½Õß¿ÉÐγÉÀíÏëҺ̬»ìºÏÎï¡£½ñÓÐϵͳ×é³ÉΪxB,0£½0.3µÄ¼×±½£­±½»ìºÏÎï5mol£¬ÔÚ900CÏÂ³ÉÆø£­ÒºÁ½ÏàÆ½ºâ£¬ÈôÆøÏà×é³ÉΪyB=0.4556£¬Çó £¨1£©Æ½ºâʱҺÏà×é³ÉxB¼°ÏµÍ³µÄѹÁ¦p¡£ £¨2£©Æ½ºâÊ±Æø¡¢ÒºÁ½ÏàµÄÎïÖʵÄÁ¿n£¨g£©£¬n£¨l£©¡£