¸ß¶þÎÄ¿Æ1105°àµÚ¶þÕÂÔ²×¶ÇúÏßÓë·½³Ì²âÊÔÌâ
Ò»£®Ñ¡ÔñÌ⣺£¨50·Ö£©
1£®ÒÑÖª¶¯µãMµÄ×ø±êÂú×ã·½³Ì13x?yA. Å×ÎïÏß B.Ë«ÇúÏß
22?|12x?5y?12|£¬Ôò¶¯µãMµÄ¹ì¼£ÊÇ£¨ £©
C. ÍÖÔ² D.ÒÔÉ϶¼²»¶Ô
x2y22£®ÉèPÊÇË«ÇúÏß2??1ÉÏÒ»µã£¬Ë«ÇúÏßµÄÒ»Ìõ½¥½üÏß·½³ÌΪ3x?2y?0,F1¡¢F2·Ö±ðÊÇË«ÇúÏß
9aµÄ×ó¡¢ÓÒ½¹µã£¬Èô|PF1|?5£¬Ôò|PF2|? £¨ £©
A. 1»ò5
B. 1»ò9 C. 1 D. 9
3¡¢ÉèÍÖÔ²µÄÁ½¸ö½¹µã·Ö±ðΪF1¡¢¡¢F2£¬¹ýF2×÷ÍÖÔ²³¤ÖáµÄ´¹Ïß½»ÍÖÔ²ÓÚµãP£¬Èô¡÷F1PF2ΪµÈÑüÖ±½ÇÈý½ÇÐΣ¬ÔòÍÖÔ²µÄÀëÐÄÂÊÊÇ £¨ £©. A. 22?1 B. C. 2?2 D. 2?1 2224£®¹ýµã(2,-1)ÒýÖ±ÏßÓëÅ×ÎïÏßy?xÖ»ÓÐÒ»¸ö¹«¹²µã,ÕâÑùµÄÖ±Ïß¹²ÓÐ ( )Ìõ A. 1
B.2 C. 3 D.4
x2y2??1ÉϵÄÒ»µã£¬F1,F2ÊÇÍÖÔ²µÄ½¹µã£¬Ôò|MF1|?|MF2|µÄ×î´óÖµÊÇ£¨ £© 5£®ÒÑÖªMÊÇÍÖÔ²94A£®4 B£®6 C£®9 D£®12
x2y26 £®£¨2012Äê¸ß¿¼£¨ºþÄÏÎÄ£©£©ÒÑ֪˫ÇúÏßC :2-2=1µÄ½¹¾àΪ10 ,µãP (2,1)ÔÚC µÄ½¥½üÏßÉÏ,
abÔòCµÄ·½³ÌΪ
£¨ £©
x2y2A£®-=1
205x2y2B£®-=1
5202x2y2C£®-=1
8020x2y2D£®-=1
20807. ÈôÖ±Ïßy?x?bÓëÇúÏßy?3?4x?xÓй«¹²µã£¬ÔòbµÄȡֵ·¶Î§ÊÇ ( ) A.[1?22,1?22] B.[1?2,3] C.[-1,1?22]
D.[1?22,3] x2y28 £®£¨2012Äê¸ß¿¼£¨½Î÷ÎÄ£©£©ÍÖÔ²2?2?1(a?b?0)µÄ×ó¡¢ÓÒ¶¥µã·Ö±ðÊÇA,B,×ó¡¢ÓÒ½¹µã·Ö±ð
abÊÇF1,F2.Èô|AF1|,|F1F2|,|F1B|³ÉµÈ±ÈÊýÁÐ,Ôò´ËÍÖÔ²µÄÀëÐÄÂÊΪ A£®
£¨ £©
1 4B£®
25 52C£®
1 2D£®5-2
29£®·½³Ìmx?ny?0Óëmx?ny?1(m?n?0)µÄÇúÏßÔÚÍ¬Ò»×ø±êϵÖеÄʾÒâͼӦÊÇ£¨ £©
1
A B C D
10.ÒÑÖªÁ½µãM(1,),N(?4,?),¸ø³öÏÂÁÐÇúÏß·½³Ì£º¢Ù4x?2y?1?0;¢Úx?y?3;¢Û
545422x2x22?y?1;¢Ü?y2?1.ÔÚÇúÏßÉÏ´æÔÚµãPÂú×ã|MP|=|NP|µÄËùÓÐÇúÏß·½³ÌÊÇ £¨ £© 22 £¨A£©¢Ú¢Ü £¨B£©¢Ù¢Ú¢Û £¨C£©¢Ú¢Û¢Ü £¨D£©¢Ù¢Û
¶þ¡¢Ìî¿ÕÌ⣨30·Ö£©
11.½¹µãÔÚÖ±Ïß3x?4y?12?0ÉϵÄÅ×ÎïÏß±ê×¼·½³ÌΪ _____ ___¡£
12.¹ýÅ×ÎïÏßy?ax(a>0)µÄ½¹µãF×÷Ò»Ö±Ïß½»Å×ÎïÏßÓÚP¡¢QÁ½µã£¬ÈôÏß¶ÎPFÓëFQµÄ³¤·Ö±ðΪp¡¢q£¬Ôò
211?µÈÓÚ¶¨Öµ pq2213.P(4,?2)ÓëÔ²x?y?4ÉÏÈÎÒ»µãÁ¬ÏßµÄÖеã¹ì¼£·½³ÌΪ £»
14¡¢Èô?ABCµÄ¶¥µã×ø±êA(?4,0),B(4,0)£¬?ABCÖܳ¤Îª18£¬Ôò¶¥µã£ÃµÄ¹ì¼£·½³ÌΪ 15.¡¢Å×ÎïÏßy??xÉϵĵ㵽ֱÏß4x?3y?8?0µÄ¾àÀëµÄ×îСֵÊÇ 2x2y216..ÒÑÖªF1£¬F2Ϊ˫ÇúÏß2?2?1(a?0£¬b?0ÇÒa?b)µÄÁ½¸ö½¹µã£¬PΪ˫ÇúÏßÓÒÖ§ÉÏÒìÓÚ¶¥µãµÄ
abÈÎÒâÒ»µã£¬OÎª×ø±êԵ㣮ÏÂÃæËĸöÃüÌâ
£Á£®¡÷PF1F2µÄÄÚÇÐÔ²µÄÔ²ÐıØÔÚÖ±Ïßx?aÉÏ£»£Â£®¡÷PF1F2µÄÄÚÇÐÔ²µÄÔ²ÐıØÔÚÖ±Ïßx?bÉÏ£» £Ã£®¡÷PF1F2µÄÄÚÇÐÔ²µÄÔ²ÐıØÔÚÖ±ÏßOPÉÏ£» £Ä£®¡÷PF1F2µÄÄÚÇÐÔ²±ØÍ¨¹ýµã?a£¬0?£® ÆäÖÐÕæÃüÌâµÄ´úºÅÊÇ Èý¡¢½â´ðÌâ(70·Ö£©
17.ÇóÁ½Ìõ½¥½üÏßΪx?2y?0ÇÒ½ØÖ±Ïßx?y?3?0ËùµÃÏÒ³¤Îª
218.ÒÑÖªÅ×ÎïÏßy?4x½ØÖ±Ïßy?2x?bËùµÃµÄÏÒABµÄ³¤Îª35£¬PÊÇÆä¶Ô³ÆÖáÉÏÒ»µã£¬Èô
£¨Ð´³öËùÓÐÕæÃüÌâµÄ´úºÅ£©£®
83µÄË«ÇúÏß·½³Ì¡£(10·Ö) 3S¡÷PAB=39£¬ÇóPµãµÄ×ø±ê¡££¨12·Ö£©
2
19.£¨±¾Ð¡Ìâ12·Ö£©Èçͼ£¬Ö±ÏßlÓëÅ×ÎïÏßy2?4x½»ÓÚA(x1,y1),B(x2,y2)Á½µã£¬ÓëxÖáÏཻÓÚµã
M£¬ÇÒy1y2??4.£¨1£©ÇóÖ¤£ºMµãΪ¶¨µã
£¨2£©ÇóÖ¤£ºOAÓëOBËù¼Ð½ÇΪ¶Û½Ç£»£¨3£©Çó?AOBµÄÃæ»ýµÄ×îСֵ.
20.ÒÑÖªÖ±Ïßy=ax+1ÓëË«ÇúÏß3x-y=1½»ÓÚA¡¢BÁ½µã£¬£¨1£©ÈôÒÔABÏß¶ÎΪֱ¾¶µÄÔ²¹ý×ø±êԵ㣬ÇóʵÊýaµÄÖµ¡££¨2£©ÊÇ·ñ´æÔÚÕâÑùµÄʵÊýa£¬Ê¹A¡¢BÁ½µã¹ØÓÚÖ±Ïßy?
2
2
y x 1x¶Ô³Æ£¿ËµÃ÷ÀíÓÉ¡£(12·Ö) 2x2?y2?1,ÍÖÔ²C2ÒÔC1µÄ³¤ÖáΪ¶ÌÖá,ÇÒÓëC1ÓÐÏàͬµÄ21£®£¨2012Äê¸ß¿¼£¨ÉÂÎ÷ÎÄ£©£©ÒÑÖªÍÖÔ²C1:4????????ÀëÐÄÂÊ.(1)ÇóÍÖÔ²C2µÄ·½³Ì;(2)ÉèOÎª×ø±êÔµã,µãA,B·Ö±ðÔÚÍÖÔ²C1ºÍC2ÉÏ,OB?2OA,ÇóÖ±ÏßABµÄ·½³Ì.£¨12·Ö£©
3
x2y222£®£¨2012Äê¸ß¿¼£¨±±¾©ÎÄ£©£©ÒÑÖªÍÖÔ²C:2?2?1(a?b?0)µÄÒ»¸ö¶¥µãΪA(2,0),ÀëÐÄÂÊΪ
ab2.Ö±Ïßy?k(x?1ÓëÍÖÔ²C½»ÓÚ²»Í¬µÄÁ½µãM,N.(¢ñ)ÇóÍÖÔ²CµÄ·½³Ì;(¢ò)µ±¡÷AMNµÃÃæ»ýΪ£©210ʱ,ÇókµÄÖµ. 3
¸ß¶þÎĿƵڶþÕÂÔ²×¶ÇúÏßÓë·½³Ì²âÊÔÌâ
Ò»£®Ñ¡ÔñÌ⣺£¨50·Ö£©
4