µÚÒ»Õ һЩ»ù±¾¸ÅÄîºÍ¶¨ÂÉ
±¾ÕÂ×ÜÄ¿±ê£º
1£ºÑ§Ï°ÎïÖʵľۼ¯×´Ì¬·ÖÆøÌ¬¡¢¹Ì̬¡¢ÒºÌ¬ÈýÖÖ£¬ÒÔ¼°ÓÃÀ´±íʾÕâÈýÖÖ¾Û¼¯Ì¬µÄÏà¹Ø¸ÅÄî¡£
2;ÖØµãÕÆÎÕÀíÏëÆøÌå״̬·½³Ì¡¢µÀ¶û¶Ù·Öѹ¶¨ÂÉÒÔ¼°ÀÎÚ¶û¶¨ÂÉ¡£ ¸÷С½ÚÄ¿±ê µÚÒ»½Ú£ºÆøÌå
1£ºÁ˽âÀíÏëÆøÌåµÄ¸ÅÄѧϰÀíÏëÆøÌåµÄ״̬·½³ÌÍÆµ¼Êµ¼ÊÆøÌå״̬·½³ÌµÄ·½·¨¡£
2£ºÕÆÎÕÀíÏëÆøÌå״̬·½³ÌµÄ¸÷¸öÎïÀíÁ¿µÄµ¥Î»¼°Ïà¹ØµÄ¼ÆËã¡£
ÀíÏëÆøÌ壺ºöÂÔÆøÌå·Ö×ÓµÄ×ÔÉíÌå»ý£¬½«·Ö×Ó¿´³ÉÊÇÓÐÖÊÁ¿µÄ¼¸ºÎµã£»¼ÙÉè·Ö×Ó¼äûÓÐÏ໥ÎüÒý£¬·Ö×ÓÖ®¼ä¼°·Ö×ÓÓëÆ÷èµÖ®¼ä·¢ÉúµÄÅöײʱÍêÈ«µ¯ÐԵ쬲»Ôì³É¶¯ÄÜËðʧ¡£
3£ºÕÆÎÕDalton·Öѹ¶¨ÂɵÄÄÚÈݼ°¼ÆËã¡£ µÚ¶þ½Ú£ºÒºÌåºÍÈÜÒº
1£ºÕÆÎÕÈÜҺŨ¶ÈµÄËÄÖÖ±íʾ·½·¨¼°¼ÆËã 1ÎïÖʵÄÁ¿Å¨¶È£¨·ûºÅ£ºc¡ðÒÔÈÜÒºµÄÌå»ý¡£ 2ÖÊÁ¿Ä¦¶ûŨ¶È£¨bB?¡ðÒÔÈܼÁµÄÖÊÁ¿¡£
mB£©£ºBµÄÖÊÁ¿Óë»ìºÏÎïµÄÖÊÁ¿Ö®±È¡£ mn4Ħ¶û·ÖÊý£¨?B?B£©£ºÈÜÒºÖÐÈÜÖʵÄÎïÖʵÄÁ¿ÓëÈÜÒºµÄ×ÜÎïÖʵÄÁ¿Ö®±È¡£ ¡ðn?1mol?Lµ¥Î»£©£ºÈÜÒºÖÐËùº¬ÈÜÖÊBµÄÎïÖʵÄÁ¿³ýBnB£¬µ¥Î»£ºmol?kg?1£©£ºÈÜÒºÖÐÈÜÖÊBµÄÎïÖʵÄÁ¿³ýmA3ÖÊÁ¿·ÖÊý£¨?B?¡ð
2£ºÁ˽â·Çµç½âÖÊÏ¡ÈÜÒºµÄÒÀÊýÐÔ¼°ÆäÓ¦ÓᣠµÚÈý½Ú£º¹ÌÌå
1£ºÁ˽ⳣ¼ûµÄËÄÖÖ¾§ÌåÀàÐÍ
2£ºÕÆÎÕËÄÀྦྷÌåµÄ½á¹¹ÌØÕ÷¼°¶ÔÎïÖÊÐÔÖʵÄÓ°Ï죬±È½ÏÆäÈ۷еã²îÒì¡£ ¢ò ϰÌâ Ò» Ñ¡ÔñÌ⣺
1
1.Èç¹ûijˮºÏÑεÄÕôÆûѹµÍÓÚÏàͬζÈϵÄÕôÆûѹ£¬ÔòÕâÖÖÑοÉÄÜ·¢ÉúµÄÏÖÏóÊÇ£¨ £© (¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
A.ÆøÅÝ B.·Ö»¯ C.³±½â D.²»ÊÜ´óÆø×é³ÉÓ°Ïì
2.ÑϸñµÄ½²£¬Ö»ÓÐÔÚÒ»¶¨µÄÌõ¼þÏ£¬ÆøÌå״̬·½³Ìʽ²ÅÊÇÕýÈ·µÄ£¬ÕâʱµÄÆøÌå³ÆÎªÀíÏëÆøÌå¡£ÕâÌõ¼þÊÇ£¨ £©
A.ÆøÌåΪ·Ö×Ó¼ûµÄ»¯Ñ§·´Ó¦ºöÂÔ²»¼Æ
B.¸÷ÆøÌåµÄ·ÖѹºÍÆøÌå·Ö×Ó±¾ÉíµÄÌå»ýºöÂÔ²»¼Æ
C.¸÷ÆøÌå·Ö×ӵġ°ÎïÖʵÄÁ¿¡±ºÍÆøÌå·Ö×Ó¼äµÄÒýÁ¦ºöÂÔ²»¼Æ D.¸÷ÆøÌå·Ö×Ó¼äµÄÒýÁ¦£¬ÆøÌå·Ö×ÓµÄÌå»ýºöÂÔ²»¼Æ
3.ÔÚ300K£¬°Ñµç½âË®µÃµ½µÄ²¢¾¸ÉÔïµÄH2ºÍO2µÄ»ìºÏÆøÌå40.0¿Ë£¬Í¨Èë60.0LµÄÕæ¿ÕÈÝÆ÷ÖУ¬H2ºÍO2µÄ·Öѹ±ÈΪ£¨ £©
A.3:1 B.2:1 C.1:1 D.4:1
4.ÔÚÏÂÊöÌõ¼þÖУ¬ÄÜʹʵ¼ÊÆøÌå½Ó½üÀíÏëµÄÊÇ£¨ £©
A.µÍΡ¢¸ßѹ B.¸ßΡ¢µÍѹ C.µÍΡ¢µÍѹ D.¸ßΡ¢¸ßѹ
5.Ä³Î´ÖªÆøÌåÑùƷΪ5.0¿Ë£¬ÔÚζÈΪ1000Cʱ£¬Ñ¹Á¦Îª291KPaʱÌå»ýÊÇ0.86L£¬¸ÃÆøÌåµÄĦ¶ûÖÊÁ¿ÊÇ£¨ £©
A.42g/mol B.52g/mol C.62g/mol D.72g/mol
6.´¦ÓÚÊÒÎÂÒ»ÃܱÕÈÝÆ÷ÄÚÓÐË®¼°ÓëË®ÏàÆ½ºâµÄË®ÕôÆø¡£ÏÖ³äÈë²»ÈÜÓÚˮҲ²»ÓëË®·´Ó¦µÄÆøÌ壬ÔòË®ÕôÆøµÄѹÁ¦£¨ £©(¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
A.Ôö¼Ó B.¼õÉÙ C.²»±ä D.²»ÄÜÈ·µÄ
7.½«300K¡¢500KPaµÄÑõÆø5L¡£400K¡¢200KPaµÄÇâÆø10LºÍ200K¡¢200KPaµÄµªÆø3L£¬ÈýÖÖÆøÌåѹÈë10LÈÝÆ÷ÖÐά³Ö300K£¬ÕâÊ±ÆøÌåµÄ״̬ÊÇ£¨ £©
A.ÑõÆøµÄѹÁ¦½µµÍ£¬µªÆø¡¢ÇâÆøÑ¹Á¦Ôö¼Ó B.ÇâÆøµÄѹÁ¦½µµÍ£¬µªÆø¡¢ÑõÆøµÄѹÁ¦Ôö¼Ó C.µªÆøµÄѹÁ¦²»±ä£¬×ÜѹÁ¦±È»ìºÏǰµÍ
D.ÑõÆø¡¢µªÆø¡¢ÇâÆøµÄѹÁ¦½µµÍ£¬×ÜѹÁ¦±È»ìºÏǰµÍ
8.ÍÁÈÀÖÐNACLº¬Á¿¸ßʱֲÎïÄÑÒÔÉú´æ£¬ÕâÓëÏÂÁÐÏ¡ÈÜÒºµÄÐÔÖÊÓйصÄÊÇ£¨ £© (¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
A. ÕôÆûѹϽµ B.·ÐµãÉý¸ß C. ±ùµãϽµ D. ÉøÍ¸Ñ¹
9.Ò»ÖÖÔªËØµÄÏà¶ÔÔ×ÓÖÊÁ¿£¬ÊǸÃÔªËØµÄÒ»¶¨ÖÊÁ¿ÓëºËËØ126CµÄĦ¶ûÖÊÁ¿µÄ1/12µÄ±ÈÖµ£¬ÕâÒ»ÖÊÁ¿ÊÇ£¨ £©
A.Ô×ÓÖÊÁ¿ B.¸÷ºËËØÔ×ÓÖÊÁ¿µÄƽ¾ùÖÊÁ¿ C.ƽ¾ùÖÊÁ¿ D.1molÔ×ÓÆ½¾ùÖÊÁ¿
10.ÔÚÒ»´ÎÉøÁ÷ÊÔÑéÖУ¬Ò»¶¨ÎïÖʵÄÁ¿µÄÎ´ÖªÆøÌåͨ¹ýС¿×ÉøÏàÕæ¿Õ£¬ÐèÒªµÄʱ¼äΪ5S£¬ÔÚÏàͬÌõ¼þÏÂÏàͬÎïÖʵÄÁ¿µÄÑõÆøÉøÁ÷ÐèÒª20S¡£ÔòÎ´ÖªÆøÌåµÄÏà¶Ô·Ö
2
×ÓÖÊÁ¿Îª£¨ £© (¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
A.2 B.4 C.8 D.16
11.ÏÂÊöÀíÏëÆøÌå³£ÊýRËùÓõ¥Î»´íÎóµÄÊÇ£¨ £©
A.8.314Pa?m3? mol-1?K-1 B. 8.314KJ?mol-1?K-1 C. 8.314KPa?L? mol-1?K-1 D.8.314J?mol-1?K-1
12.ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨ £©
A.44gCO2ºÍ32gO2 Ëùº¬µÄ·Ö×ÓÊýÏàͬ£¬Òò¶øÌå»ý²»Í¬ B.12gCO2ºÍ12gO2µÄÖÊÁ¿ÏàµÈ£¬Òò¶ø¡°ÎïÖʵÄÁ¿¡±Ïàͬ
C.1molCO2ºÍ1molO2µÄ¡°ÎïÖʵÄÁ¿¡±Ïàͬ£¬Òò¶øËüÃǵķÖ×ÓÊýÏàͬ D. 22.4LCO2ºÍ22.4LO2µÄÌå»ýÏàͬ£¬¡°ÎïÖʵÄÁ¿¡±Ò»¶¨ÏàµÈ
13.½«Ñ¹Á¦Îª200KPaµÄÑõÆø5.0LºÍ100KPaµÄÇâÆø15.0Lͬʱ»ìºÏÔÚ20LµÄÃܱÕÈÝÆ÷ÖУ¬ÔÚζȲ»±äµÄÌõ¼þÏ£¬»ìºÏÆøÌåµÄ×ÜѹÁ¦Îª£¨ £©
A.120KPa B.125KPa C.180 KPa D.300KPa
14.ÔÚ±ê׼״̬Ï£¬ÆøÌåAµÄÃܶÈΪ2g?dm-3£¬ÆøÌåBµÄÃܶÈΪ0.08g?dm-3¡£ÔòÆøÌåA¶ÔBµÄÏà¶ÔÀ©É¢ËÙ¶ÈΪ£¨ £© (¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
A. 25:1 B. 5:1 C. 1:2 D. 1:5
15.ʵÑé²âµÃH2µÄÀ©É¢ËÙ¶ÈÊÇÒ»Î´ÖªÆøÌåÀ©É¢ËٶȵÄ2.9±¶¡£Ôò¸ÃÎ´ÖªÆøÌåµÄÏà¶Ô·Ö×ÓÖÊÁ¿Ô¼Îª£¨ £© (¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
A.51 B.34 C.17 D.28
16.¹ØÓÚÆøÌå³£ÊýR£¬ÏÂÁУ¨ £©ÖÖ˵·¨ÊÇ´íÎóµÄ¡£
A.ÊýÖµÓëʹÓõ¥Î»ÓÐ¹Ø B.ÊÇÀíÏëÆøÌå״̬·½³ÌʽµÄ³£Êý C.ÓëʵÑé²â¶¨µÄÌõ¼þÎÞ¹Ø D.Ö»ÔÚÆøÌåÖÐʹÓÃ
17.³£Ñ¹Ï½«1dm3 ÆøÌåµÄζȴÓ0¡æÉýµ½273¡æ£¬ÆäÌå»ý½«±äΪ£¨ £© (¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
A.0.5dm3 B.1dm3 C.1.5dm3 D.2dm3
18.ÔÚ25¡æ£¬101.3 KPaʱ£¬ÏÂÃæ¼¸ÖÖÆøÌåµÄ»ìºÏÆøÌåÖзÖѹ×î´óµÄÊÇ£¨ £© (¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
A.0.1gH2 B. 1.0gHe C.5.0gN2 D.10gCO2
19.ºÏ³É°±µÄÔÁÏÖÐÇâÆøºÍµªÆøµÄÌå»ý±ÈΪ3£º1£¬ÈôÔÁÏÆøÖк¬ÓÐÆäËüÔÓÖÊÆøÌåµÄÌå»ý·ÖÊýΪ4%£¬ÔÁÏÆø×ÜѹΪ15198.75KPa£¬ÔòµªÆøµÄ·ÖѹΪ£¨ £©(¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
A.3799.688 KPa B.10943.1 KPa C.3647.7 KPa D.11399.06 KPa
20.ÓÉNH4NO2µÃµªÆøºÍË®¡£ÔÚ23¡æ¡¢95549.5PaÌõ¼þÏ£¬ÓÃÅÅË®¼¯Æø·¨ÊÕ¼¯µ½57.5 cm3µªÆø¡£ÒÑ֪ˮµÄ±¥ºÍÕôÆûѹΪ2813.1Pa£¬Ôò¸ÉÔïºóµªÆøµÄÌå»ýΪ£¨ £© (¡¶ÎÞ
3
»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
A.55.8cm3 B.27.9cm3 C.46.5cm3 D.18.6cm3
¶þ Ìî¿ÕÌâ
1.ʵ¼ÊÆøÌåÓëÀíÏëÆøÌå·¢ÉúÆ«²îµÄÖ÷ÒªÔÒòÊÇ ¡£(¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
2.µ±ÆøÌåΪ1molʱ£¬Êµ¼ÊÆøÌåµÄ״̬·½³ÌʽΪ ¡£(¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
3.Ò»¶¨Ìå»ýµÄ¸ÉÔï¿ÕÆø´ÓÒ×»Ó·¢µÄÈýÂȼ×ÍéÒºÌåÖÐͨ¹ýºó£¬¿ÕÆøÌå»ý±ä £¬¿ÕÆø·Öѹ±ä ¡£(¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
4.ÔÚ±ê׼״̬Ï£¬¿ÕÆøÖÐÑõµÄ·ÖѹÊÇ Pa¡£ (¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
5.ijÀíÏëÆøÌåÔÚ273KºÍ101.3KPaʱµÄÌå»ýΪ0.312m3 £¬ÔòÔÚ298KºÍ98.66KPaʱÆäÌå»ýΪ m3¡£ (¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
6.½«32.0gO2ºÍ56.0gN2Ê¢ÓÚ10.0 dm3µÄÈÝÆ÷ÖУ¬ÈôζÈΪ27¡æ£¬ÔòÆøÌåµÄ·ÖѹP£¨O2£©= KPa£¬P£¨N2£©= KPa¡£
7.ÔÚÏàͬµÄζȺÍѹÁ¦Ï£¬Á½¸öÈÝ»ýÏàͬµÄÉÕÆ¿Öзֱð³äÂúO3ÆøÌåºÍH2SÆøÌå¡£ÒÑÖªH2SµÄÖÊÁ¿Îª0.34g£¬ÔòO3µÄÖÊÁ¿Îª g¡£(¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
8.ÔÚ57¡æÊ±£¬ÓÃÅÅË®¼¯Æø·¨ÔÚ1.0¡Á105PaÏÂ°Ñ¿ÕÆøÊÕ¼¯ÔÚÒ»¸ö´ø»îÈûµÄÆ¿ÖУ¬´Ëʱʪ¿ÕÆøÌå»ýΪ1.0 dm3¡£ÒÑÖª57¡æÊ±Ë®µÄ±¥ºÍÕôÆøÑ¹Îª1.7¡Á104Pa£¬10¡æÊ±Ë®µÄ±¥ºÍÕôÆøÑ¹Îª1.2¡Á103Pa¡£(¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
£¨1£©Î¶Ȳ»±ä£¬Èôѹǿ½µÎª5.0¡Á104Paʱ£¬¸ÃÆøÌåÌå»ý±äΪ dm3£» £¨2£©Î¶Ȳ»±ä£¬ÈôѹǿÔöΪ2.0¡Á105Paʱ£¬¸ÃÆøÌåÌå»ý±äΪ dm3£»
£¨3£©Ñ¹Ç¿²»±ä£¬ÈôζÈΪ100¡æ£¬¸ÃÆøÌåÌå»ýÓ¦ÊÇ dm3£»ÈôζÈΪ10¡æ£¬¸ÃÆøÌåÌå»ýΪ dm3¡£
9.º£Ë®½á±ùµÄζȱȴ¿Ë®½á±ùµÄÎÂ¶È £¬ÆäζȸıäÖµ¿ÉÒÔÓà ¹ØÏµÊ½±íʾ¡£(¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
10.ÔÚ26.6gÂȷ£¨CHCL3£©ÖÐÈܽâ0.402gÝÁ£¨£¨C10H8£©£¬Æä·Ðµã±ÈÂȷµķеã¸ß0.455K£¬ÔòÂÈÆøµÄ·ÐµãÉý¸ß³£ÊìΪ ¡£(¡¶ÎÞ»ú»¯Ñ§ÀýÌâÓëϰÌâ¡·¼ª´ó°æ)
Èý ¼ÆËãÌâ
1.½«µªÆøºÍÇâÆø°´ 1£º3µÄÌå»ý±È×°ÈëÒ»ÃܱÕÈÝÆ÷ÖУ¬ÔÚ4000CºÍ10MPaÏ´ﵽ
4