(3) ¶ÔÏõ»ùÂȱ½ (4) 4-Ïõ»ù-2,6¶þäå¼×±½ (5)
COOH (6)
CH=CHCH3
BrSO3H(7)
(8)
COOHNO2
NO2O(9)
(10)
H3CCO
O(Ê®¾Å) ÒÒõ£±½°·(C6H5NHCOCH3)ä廯ʱ£¬Ö÷ÒªµÃµ½2-ºÍ4-äåÒÒõ£±½°·£¬µ«2,6-¶þ¼×»ùÒÒõ£±½°·ä廯ʱ£¬ÔòÖ÷ÒªµÃµ½3äåÒÒõ£±½°·£¬ÎªÊ²Ã´?(P180)
(¶þÊ®) ËÄäåÁÚ±½¶þ¼×ËáôûÊÇÒ»ÖÖ×èȼ¼Á¡£Ëü×÷Ϊ·´Ó¦ÐÍ×èȼ¼Á£¬Ö÷ÒªÓÃÓÚ¾ÛÒÒÏ©¡¢¾Û±ûÏ©¡¢¾Û±½ÒÒÏ©ºÍABSÊ÷Ö¬µÈ¡£ÊÔ·Ö±ðÓÉÝÁ¡¢ÁÚ¶þ¼×±½¼°±ØÒªµÄÊÔ¼ÁºÏ³ÉÖ®¡£
(¶þʮһ) ijÌþµÄʵÑéʽΪCH£¬Ïà¶Ô·Ö×ÓÖÊÁ¿Îª208£¬Ç¿Ñõ»¯µÃ±½¼×Ëᣬ³ôÑõ»¯·Ö½â²úÎïµÃ±½ÒÒÈ©£¬ÊÔÍÆ²â¸ÃÌþµÄ½á¹¹¡£
(¶þÊ®¶þ) ij·¼ÏãÌþ·Ö×ÓʽΪC9H12£¬ÓÃÖØ¸õËá¼ØÑõ»¯ºó£¬¿ÉµÃÒ»ÖÖ¶þÔªËá¡£½«ÔÀ´µÄ·¼ÏãÌþ½øÐÐÏõ»¯£¬ËùµÃÒ»ÔªÏõ»ù»¯ºÏÎïÓÐÁ½ÖÖ¡£Ð´³ö¸Ã·¼ÏãÌþµÄ¹¹ÔìʽºÍ¸÷²½·´Ó¦Ê½¡£
(¶þÊ®Èý) ij²»±¥ºÍÌþ(A)µÄ·Ö×ÓʽΪC9H8£¬(A)ÄܺÍÂÈ»¯ÑÇͰ±ÈÜÒº·´Ó¦Éú³ÉºìÉ«³Áµí¡£(A)´ß»¯¼ÓÇâµÃµ½»¯ºÏÎïC9H12(B)£¬½«(B)ÓÃËáÐÔÖØ¸õËá¼ØÑõ»¯µÃµ½ËáÐÔ»¯ºÏÎïC8H6O4(C)£¬(C)¼ÓÈȵõ½»¯ºÏÎïC8H4O3(D)¡£.Èô½«(A)ºÍ¶¡¶þÏ©×÷Óã¬ÔòµÃµ½ÁíÒ»¸ö²»±¥ºÍ»¯ºÏÎï(E)£¬(E)´ß»¯ÍÑÇâµÃµ½2-¼×»ùÁª±½¡£ÊÔд³ö(A)~(E)µÄ¹¹Ôìʽ¼°¸÷²½·´Ó¦Ê½¡£
(¶þÊ®ËÄ) °´ÕÕHuckel¹æÔò£¬ÅжÏÏÂÁи÷»¯ºÏÎï»òÀë×ÓÊÇ·ñ¾ßÓз¼ÏãÐÔ¡£
(1)
Cl- (2)
(3) »·ÈÉËÄÏ©¸ºÀë×Ó
(4) (5) (6)
(7)
+ (8)
(¶þÊ®Îå)ÏÂÁи÷Ìþ¾²¬ÖØÕû»áÉú³ÉÄÇЩ·¼Ìþ£¿
(1) Õý¸ýÍé (2) 2,5-¶þ¼×»ùÒÒÍé
µÚÁùÕ Á¢Ì廯ѧ
(Ò») ÔÚÂȶ¡ÍéºÍÂÈÎìÍéµÄËùÓÐÒì¹¹ÌåÖУ¬ÄÄЩÓÐÊÖÐÔ̼Ô×Ó£¿ (¶þ) ¸÷д³öÒ»¸öÄÜÂú×ãÏÂÁÐÌõ¼þµÄ¿ªÁ´»¯ºÏÎ
(1) ¾ßÓÐÊÖÐÔ̼Ô×ÓµÄȲÌþC6H10£»
(2) ¾ßÓÐÊÖÐÔ̼Ô×ÓµÄôÈËáC5H10O2 (ôÈËáµÄͨʽÊÇCnH2n+1COOH)¡£ (Èý) Ïà¶Ô·Ö×ÓÖÊÁ¿×îµÍ¶øÓÐÐý¹âÐÔµÄÍéÌþÊÇÄÄЩ£¿ÓÃFischerͶӰʽ±íÃ÷ËüÃǵĹ¹ÐÍ¡£
(ËÄ) C6H12ÊÇÒ»¸ö¾ßÓÐÐý¹âÐԵIJ»±¥ºÍÌþ£¬¼ÓÇâºóÉú³ÉÏàÓ¦µÄ±¥ºÍÌþ¡£C6H12²»±¥ºÍÌþÊÇʲô£¿Éú³ÉµÄ±¥ºÍÌþÓÐÎÞÐý¹âÐÔ£¿ (Îå) ±È½Ï×óÐýÖÙ¶¡´¼ºÍÓÒÐýÖÙ¶¡´¼µÄÏÂÁи÷Ï
(1) ·Ðµã (2) ÈÛµã (3) Ïà¶ÔÃÜ¶È (4) ±ÈÐý¹â¶È
(5) ÕÛÉäÂÊ (6) Èܽâ¶È (7) ¹¹ÐÍ
COOHOHÒ»ÑùµÄ£¿ (Áù) ÏÂÁÐFischerͶӰʽÖУ¬ÄĸöÊÇͬÈéËáHCH3OHCH3COOHCH3COOH (3) COOHOH (4) HOCH3 (1) HOH (2) HCH3COOHHHCH3BrÊÇRÐÍ»¹ÊÇSÐÍ£¿ÏÂÁи÷½á¹¹Ê½£¬ÄÄЩͬÉÏÃæ(Æß) FischerͶӰʽHCH2CH3Õâ¸öͶӰʽÊÇͬһ»¯ºÏÎ
C2H5HHC2H5 (3) Br (2) CH3(1) HCH3CH3BrBrCH3HH (4)
CH3HCH3HHBr
(°Ë) °Ñ3-¼×»ùÎìÍé½øÐÐÂÈ»¯£¬Ð´³öËùÓпÉÄܵõ½µÄÒ»ÂÈ´úÎï¡£ÄÔÊǶÔÓ³Ì壿ÄÄЩÊǷǶÔÓ³Ì壿ÄÄЩÒì¹¹Ìå²»ÊÇÊÖÐÔ·Ö×Ó£¿
(¾Å) ½«10g»¯ºÏÎïÈÜÓÚ100ml¼×´¼ÖУ¬ÔÚ25¡æÊ±ÓÃ10cm³¤µÄÊ¢Òº¹ÜÔÚÐý¹âÒÇÖй۲쵽Ðý¹â¶ÈΪ+2.30¡ã¡£ÔÚͬÑùÇé¿öϸÄÓÃ5cm³¤µÄÊ¢Òº¹Üʱ£¬ÆäÐý¹â¶ÈΪ+1.15¡ã¡£¼ÆËã¸Ã»¯ºÏÎïµÄ±ÈÐý¹â¶È¡£µÚ¶þ´Î¹Û²ì˵Ã÷ʲôÎÊÌ⣿ (Ê®) (1) д³ö3-¼×»ù-1-ÎìȲ·Ö±ðÓëÏÂÁÐÊÔ¼Á·´Ó¦µÄ²úÎï¡£
(A) Br2£¬CCl4 (B) H2£¬Lindlar´ß»¯¼Á (C) H2O£¬H2SO4£¬HgSO4
(D) HCl(1mol) (E) NaNH2,CH3I
(2) Èç¹û·´Ó¦ÎïÊÇÓÐÐý¹âÐԵģ¬ÄÄЩ²úÎïÓÐÐý¹âÐÔ£¿ (3) ÄÄЩ²úÎïͬ·´Ó¦ÎïµÄÊÖÐÔÖÐÐÄÓÐͬÑùµÄ¹¹Ð͹ØÏµ£¿ (4) Èç¹û·´Ó¦ÎïÊÇ×óÐýµÄ£¬ÄÜ·ñÔ¤²âÄĸö²úÎïÒ²ÊÇ×óÐýµÄ£¿ (ʮһ) ÏÂÁл¯ºÏÎï¸÷ÓжàÉÙÁ¢ÌåÒì¹¹Ìå´æÔÚ£¿
OHOHCHCH3ClClCl (2)
OHClCl (1)
CH3CH2CHCH3CHCHCHC2H5 (3)
CH3CHCHCHCH3
(Ê®¶þ) ¸ù¾Ý¸ø³öµÄËĸöÁ¢ÌåÒì¹¹ÌåµÄFischerͶӰʽ£¬»Ø´ðÏÂÁÐÎÊÌ⣺
CHOHOHHOHCH2OHCHOHOHHOHCH2OHCHOCHOHOHHOHHOHHOHCH2OHCH2OH
(I) (II) (III) (IV) (1) (¢ò)ºÍ(¢ó)ÊÇ·ñÊǶÔÓ³Ì壿 (2) (¢ñ)ºÍ(¢ô) ÊÇ·ñÊǶÔÓ³Ì壿 (3) (¢ò)ºÍ(¢ô)ÊÇ·ñÊǶÔÓ³Ì壿 (4) (¢ñ)ºÍ(¢ò)µÄ·ÐµãÊÇ·ñÏàͬ£¿ (5) (¢ñ)ºÍ(¢ó)µÄ·ÐµãÊÇ·ñÏàͬ£¿
(6) °ÑÕâËÄÖÖÁ¢ÌåÒì¹¹ÌåµÈÁ¿»ìºÏ£¬»ìºÏÎïÓÐÎÞÐý¹âÐÔ£¿
(Ê®Èý) Ô¤²âCH3CH=C=CHCH=CHCH3ÓжàÉÙÁ¢ÌåÒì¹¹Ì壬ָ³öÄÄЩÊǶÔÓ³Ìå¡¢·Ç¶ÔÓ³ÌåºÍ˳·´Òì¹¹Ìå¡£
(Ê®ËÄ) д³öCH3CH=CHCH(OH)CH3µÄËĸöÁ¢ÌåÒì¹¹ÌåµÄ͸ÊÓʽ¡£Ö¸³öÔÚÕâЩÒì¹¹ÌåÖÐÄÄÁ½×éÊǶÔÓ³Ì壿Äļ¸×éÊǷǶÔÓ³Ì壿ÄÄÁ½×éÊÇ˳·´Òì¹¹Ì壿 (Ê®Îå) »·ÎìÏ©Óëäå½øÐмӳɷ´Ó¦£¬Ô¤ÆÚ½«µÃµ½Ê²Ã´²úÎ²úÆ·ÊÇ·ñÓÐÐý¹âÐÔ£¿ÊÇ×óÐýÌå¡¢ÓÒÐýÌå¡¢ÍâÏûÐýÌ壬»¹ÊÇÄÚÏûÐýÌ壿
(Ê®Áù) ijÌþ·Ö×ÓʽΪC10H14£¬ÓÐÒ»¸öÊÖÐÔ̼Ô×Ó£¬Ñõ»¯Éú³É±½¼×Ëá¡£ÊÔд³öÆä½á¹¹Ê½¡£
(Ê®Æß) ÓøßÃÌËá¼Ø´¦Àí˳-2-¶¡Ï©£¬Éú³ÉÒ»¸öÈÛµãΪ32¡æµÄÁÚ¶þ´¼£¬´¦Àí·´-2-¶¡Ï©£¬Éú³ÉÈÛµãΪ19¡æµÄÁÚ¶þ´¼¡£ËüÃǶ¼ÎÞÐý¹âÐÔ£¬µ«19¡æµÄÁÚ¶þ´¼¿É²ð·ÖΪÁ½¸öÐý¹â¶ÈÏàµÈ¡¢·½ÏòÏà·´µÄÁÚ¶þ´¼¡£ÊÔд³öËüÃǵĽṹʽ¡¢±ê³ö¹¹ÐÍÒÔ¼°ÏàÓ¦µÄ·´Ó¦Ê½¡£
(Ê®°Ë) ij»¯ºÏÎï(A)µÄ·Ö×ÓʽΪC6H10£¬¾ßÓйâѧ»îÐÔ¡£¿ÉÓë¼îÐÔÏõËáÒøµÄ°±ÈÜÒº·´Ó¦Éú³É°×É«³Áµí¡£ÈôÒÔPtΪ´ß»¯¼Á´ß»¯Ç⻯£¬Ôò(A)ת±äC6H14 (B)£¬(B)ÎÞ¹âѧ»îÐÔ¡£ÊÔÍÆ²â(A)ºÍ(B)µÄ½á¹¹Ê½¡£
(Ê®¾Å) »¯ºÏÎïC8H12(A)£¬¾ßÓйâѧ»îÐÔ¡£(A)ÔÚPt´ß»¯Ï¼ÓÇâÉú³ÉC8H18(B)£¬(B)ÎÞ¹âѧ»îÐÔ¡£(A)ÔÚ²¿·Ö¶¾»¯µÄîÙ´ß»¯¼Á´ß»¯Ï£¬Ð¡ÐļÓÇâµÃµ½²úÎïC8H14(C), (C)¾ßÓйâѧ»îÐÔ¡£ÊÔд³ö(A)¡¢(B)ºÍ(C)µÄ½á¹¹Ê½¡£
(Ìáʾ£ºÁ½¸ö»ùÍŹ¹ÔìÏàͬµ«¹¹ÐͲ»Í¬£¬ÊôÓÚ²»Í¬»ùÍÅ¡£)