Óлú»¯Ñ§ µÚËÄ°æ ¿ÎºóÁ·Ï°´ð°¸ - ͼÎÄ ÏÂÔØ±¾ÎÄ

(4) ROH + NaOHÈõËáRONa + H2O

Ç¿Ëá (Ê®ËÄ) ¸ø³öÏÂÁз´Ó¦µÄÊÔ¼ÁºÍ·´Ó¦Ìõ¼þ£º

(1) 1-ÎìȲ ¡ú ÎìÍé

(2) 3-¼ºÈ² ¡ú ˳-3-¼ºÏ© (3) 2¨CÎìȲ ¡ú ·´-2-ÎìÏ© (4) (CH3)2CHCH2CH=CH2(CH3)2CHCH2CH2CH2OH

(Ê®Îå) Íê³ÉÏÂÁÐת±ä(²»ÏÞÒ»²½)£º

(1) CH3CH=CH2(2) CH3CH2CH2CH2OHCH3CH2CH2Br

CH3CH2CClCH3

(3)

(CH3)2CHCHBrCH3Br(CH3)2CCHBrCH3OHCH3CCl2CH3

(4) CH3CH2CHCl2(Ê®Áù) ÓÉÖ¸¶¨Ô­ÁϺϳÉÏÂÁи÷»¯ºÏÎï(³£ÓÃÊÔ¼ÁÈÎÑ¡)£º

(1) ÓÉ1-¶¡Ï©ºÏ³É2-¶¡´¼ (2) ÓÉ1-¼ºÏ©ºÏ³É1-¼º´¼

CH3(3) CH3C=CH2CH3ClCH2CCH2

O(4) ÓÉÒÒȲºÏ³É3-¼ºÈ² (5) ÓÉ1-¼ºÈ²ºÏ³ÉÕý¼ºÈ©

(6) ÓÉÒÒȲºÍ±ûȲºÏ³É±û»ùÒÒÏ©»ùÃÑ

(Ê®Æß) ½âÊÍÏÂÁÐÊÂʵ£º

(1) 1-¶¡È²¡¢1-¶¡Ï©¡¢¶¡ÍéµÄż¼«¾ØÒÀ´Î¼õС£¬ÎªÊ²Ã´£¿

(2) ÆÕͨϩÌþµÄ˳ʽºÍ·´Ê½Òì¹¹ÌåµÄÄÜÁ¿²îΪ4.18kJ?mol-1,µ«4,4-¶þ¼×»ù-2-Îìϩ˳ʽºÍ·´Ê½µÄÄÜÁ¿²îΪ15.9 kJ?mol-1£¬ÎªÊ²Ã´£¿

(3) ÒÒȲÖеÄCH¼ü±ÈÏàÓ¦ÒÒÏ©¡¢ÒÒÍéÖеÄCH¼ü¼üÄÜÔö´ó¡¢¼ü³¤Ëõ¶Ì£¬µ«ËáÐÔÈ´ÔöÇ¿ÁË£¬ÎªÊ²Ã´£¿

(4) ȲÌþ²»µ«¿ÉÒÔ¼ÓÒ»·Ö×ÓÂ±ËØ£¬¶øÇÒ¿ÉÒÔ¼ÓÁ½·Ö×ÓÂ±ËØ£¬µ«È´±ÈÏ©Ìþ¼ÓÂ±ËØÀ§ÄÑ£¬·´Ó¦ËÙÂÊҲС£¬ÎªÊ²Ã´£¿

(5) ÓëÇ×µçÊÔ¼ÁBr2¡¢Cl2¡¢HClµÄ¼Ó³É·´Ó¦£¬Ï©Ìþ±ÈȲÌþ»îÆÃ¡£È»¶øµ±È²ÌþÓÃÕâЩÊÔ¼Á´¦Àíʱ£¬·´Ó¦È´ºÜÈÝÒ×Í£Ö¹ÔÚÏ©Ìþ½×¶Î£¬Éú³É±´úÏ©Ìþ£¬ÐèÒª¸üÇ¿ÁÒµÄÌõ¼þ²ÅÄܽøÐеڶþ²½¼Ó³É¡£ÕâÊÇ·ñÏ໥ì¶Ü£¬ÎªÊ²Ã´£¿

(6) ÔÚÏõËáÄÆµÄË®ÈÜÒºÖУ¬äå¶ÔÒÒÏ©µÄ¼Ó³É£¬²»½öÉú³É1,2-¶þäåÒÒÍ飬¶øÇÒ»¹²úÉúÏõËá-¦Â-äå´úÒÒõ¥(BrCH2CH2ONO2)£¬ÔõÑù½âÊÍÕâÑùµÄ·´Ó¦½á¹û£¿ÊÔд³ö¸÷²½·´Ó¦Ê½¡£

(7) (CH3)3CCH=CH2ÔÚËá´ß»¯Ï¼ÓË®£¬²»½öÉú³É²úÎï(CH3)3CCHCH3(A)£¬¶øÇÒ

OHÉú³É(CH3)2CCH(CH3)2(B),µ«²»Éú³É(CH3)3CCH2CH2OH(C)¡£ ÊÔ½âÊÍΪʲô¡£

OH (8) ±ûÏ©¾ÛºÏ·´Ó¦£¬ÎÞÂÛÊÇËá´ß»¯»¹ÊÇ×ÔÓÉ»ùÒý·¢¾ÛºÏ£¬¶¼Êǰ´Í·Î²Ïà½ÓµÄ·½Ê½£¬Éú³É¼×»ù½»ÌæÅÅÁеÄÕûÆë¾ÛºÏÎΪʲô£¿

(Ê®°Ë) »¯ºÏÎï(A)µÄ·Ö×ÓʽΪC4H8£¬ËüÄÜʹäåÈÜÒºÍÊÉ«£¬µ«²»ÄÜʹϡµÄ¸ßÃÌËá¼ØÈÜÒºÍÊÉ«¡£1 mol (A)Óë1mol HBr×÷ÓÃÉú³É(B)£¬(B)Ò²¿ÉÒÔ´Ó(A)µÄͬ·ÖÒì¹¹Ìå(C)ÓëHBr×÷Óõõ½¡£(C)ÄÜʹäåÈÜÒºÍÊÉ«£¬Ò²ÄÜʹϡºÍËáÐÔ¸ßÃÌËá¼ØÈÜÒºÍÊÉ«¡£ÊÔÍÆ²â(A)¡¢(B)ºÍ(C)µÄ¹¹Ôìʽ¡£²¢Ð´³ö¸÷²½·´Ó¦Ê½¡£

(Ê®¾Å) ·Ö×ÓʽΪC4H6µÄÈý¸öÒì¹¹Ìå(A)¡¢(B)¡¢(C)£¬¿ÉÒÔ·¢ÉúÈçÏµĻ¯Ñ§·´Ó¦£º (1) Èý¸öÒì¹¹Ìå¶¼ÄÜÓëäå·´Ó¦£¬µ«ÔÚ³£ÎÂ϶ԵÈÎïÖʵÄÁ¿µÄÊÔÑù£¬Óë(B)ºÍ(C)·´Ó¦µÄäåÁ¿ÊÇ(A)µÄ2 ±¶£»

(2) ÈýÕß¶¼ÄÜHCl·¢Éú·´Ó¦£¬¶ø(B)ºÍ(C)ÔÚHg2+´ß»¯ÏÂÓëHCl×÷Óõõ½µÄÊÇͬһ²úÎ

(3) (B) ºÍ(C)ÄÜѸËÙµØÓ뺬HgSO4µÄÁòËáÈÜÒº×÷Ó㬵õ½·Ö×ÓʽΪC4H8OµÄ»¯ºÏÎ

(4) (B)ÄÜÓëÏõËáÒøµÄÈÜÒº·´Ó¦Éú³É°×É«³Áµí¡£

ÊÔд³ö»¯ºÏÎï(A)¡¢(B)ºÍ(C)µÄ¹¹Ôìʽ£¬²¢Ð´³öÓйصķ´Ó¦Ê½¡£

(¶þÊ®) ij»¯ºÏÎï(A)µÄ·Ö×ÓʽΪC7H14£¬¾­ËáÐÔ¸ßÃÌËá¼ØÈÜÒºÑõ»¯ºóÉú³ÉÁ½¸ö»¯ºÏÎï(B)ºÍ(C)¡£(A)¾­³ôÑõ»¯¶øºó»¹Ô­Ë®½âÒ²µÃÏàͬ²úÎï(B)ºÍ(C)¡£ÊÔд³ö(A)µÄ¹¹Ôìʽ¡£

(¶þʮһ) ±´úÌþC5H11Br(A)ÓëÇâÑõ»¯ÄƵÄÒÒ´¼ÈÜÒº×÷Óã¬Éú³É·Ö×ÓʽΪC5H10µÄ»¯ºÏÎï(B)¡£(B)ÓøßÃÌËá¼ØµÄËáÐÔË®ÈÜÒºÑõ»¯¿ÉµÃµ½Ò»¸öͪ(C)ºÍÒ»¸öôÈËá(D)¡£¶ø(B)Óëä廯Çâ×÷Óõõ½µÄ²úÎïÊÇ(A)µÄÒì¹¹Ìå(E)¡£ÊÔд³ö(A)¡¢(B)¡¢(C)¡¢(D)ºÍ(E)µÄ¹¹Ôìʽ¼°¸÷²½·´Ó¦Ê½¡£

(¶þÊ®¶þ) »¯ºÏÎïC7H15Br¾­Ç¿¼î´¦Àíºó£¬µÃµ½ÈýÖÖÏ©Ìþ(C7H14)µÄ»ìºÏÎï(A)¡¢(B)ºÍ(C)¡£ÕâÈýÖÖÏ©Ìþ¾­´ß»¯¼ÓÇâºó¾ùÉú³É2-¼×»ù¼ºÍé¡£(A)ÓëB2H6×÷Óò¢¾­¼îÐÔ¹ýÑõ»¯Çâ´¦ÀíºóÉú³É´¼(D)¡£(B)ºÍ(C)¾­Í¬Ñù·´Ó¦£¬µÃµ½(D)ºÍÁíÒ»Òì¹¹´¼(E)¡£Ð´³ö(A)~(E)µÄ½á¹¹Ê½¡£ÔÙÓÃʲô·½·¨¿ÉÒÔÈ·Ö¤ÄãµÄÍÆ¶Ï£¿

(¶þÊ®Èý) ÓÐ(A)ºÍ(B)Á½¸ö»¯ºÏÎËüÃÇ»¥Îª¹¹ÔìÒì¹¹Ì壬¶¼ÄÜʹäåµÄËÄÂÈ»¯Ì¼ÈÜÒºÍÊÉ«¡£(A)ÓëAg(NH3)2NO3·´Ó¦Éú³É°×É«³Áµí£¬ÓÃKMnO4ÈÜÒºÑõ»¯Éú³É±ûËá(CH3CH2COOH)ºÍ¶þÑõ»¯Ì¼£»(B)²»ÓëAg(NH3)2NO3·´Ó¦£¬¶øÓÃKMnO4ÈÜÒºÑõ»¯Ö»Éú³ÉÒ»ÖÖôÈËá¡£ÊÔд³ö(A)ºÍ(B)µÄ¹¹Ôìʽ¼°¸÷²½·´Ó¦Ê½¡£

(¶þÊ®ËÄ) ij»¯ºÏÎïµÄ·Ö×ÓʽΪC6H10¡£ÄÜÓëÁ½·Ö×Óäå¼Ó³É¶ø²»ÄÜÓëÑõ»¯ÑÇÍ­µÄ°±ÈÜÒºÆð·´Ó¦¡£ÔÚ¹¯ÑεÄÁòËáÈÜÒº´æÔÚÏ£¬ÄÜÓëË®·´Ó¦µÃµ½4-¼×»ù-2-ÎìͪºÍ2-¼×»ù-3-ÎìͪµÄ»ìºÏÎï¡£ÊÔд³öC6H10µÄ¹¹Ôìʽ¡£

(¶þÊ®Îå) ij»¯ºÏÎï(A)£¬·Ö×ÓʽΪC5H8£¬ÔÚÒº°±ÖÐÓë½ðÊôÄÆ×÷Óúó£¬ÔÙÓë1-äå±ûÍé×÷Óã¬Éú³É·Ö×ÓʽΪC8H14µÄ»¯ºÏÎï(B)¡£ÓøßÃÌËá¼ØÑõ»¯(B)µÃµ½·Ö×ÓʽC4H8O2ΪµÄÁ½ÖÖ²»Í¬µÄôÈËá(C)ºÍ(D)¡£(A)ÔÚÁòËṯ´æÔÚÏÂÓëÏ¡ÁòËá×÷Ó㬿ɵõ½·Ö×ÓʽΪC5H10OµÄͪ(E)¡£ÊÔд³ö(A)~(E)µÄ¹¹Ôìʽ¼°¸÷²½·´Ó¦Ê½¡£

µÚËÄÕ ¶þÏ©ÌþºÍ¹²éîÌåϵϰÌâ(P147)

(Ò») ÓÃϵͳÃüÃû·¨ÃüÃûÏÂÁл¯ºÏÎ

(1) CH2=CHCH=C(CH3)2

(2) CH3CH=C=C(CH3)2

CH3

(4)

(3)

CH3CH2=CHCH=CHC=CH3C=CCH=CH2

HH(¶þ) ÏÂÁл¯ºÏÎïÓÐÎÞ˳·´Òì¹¹ÏÖÏó£ºÈôÓУ¬Ð´³öÆä˳·´Òì¹¹Ìå²¢ÓÃZ,E-ÃüÃû·¨ÃüÃû¡£

(1)2-¼×»ù-1£¬3-¶¡¶þÏ© (2)1,3-Îì¶þÏ© (3)3,5-ÐÁ¶þÏ© (4)1,3,5-¼ºÈýÏ© (5)2,3-Îì¶þÏ© (Èý) Íê³ÉÏÂÁз´Ó¦Ê½£º

½â£ººìÉ«À¨ºÅÖÐΪ¸÷СÌâËùÒªÇóÌî³äµÄÄÚÈÝ¡£

COOH(1)

+ HOOCCH=CHCOOHCOOH

(2)

+CHCHHCOOCH3COOCH3HCOOCH3H

COOCH3HHCOOCH3(3)

+H

(4) +CH3OOCCOOCH3HHCOOCH3MgX+ RH

(5)

+ RMgX(6)

+OCOCH3

(7) (8)

CHO+CHO