¾«Æ·Îĵµ
2016Äê±±¾©Êи÷Çø¸ßÈýÄ£Ä⿼ÊÔÊýѧÎÄ¿ÆÊÔÌâ·ÖÀà»ã±à------º¯ÊýÓëµ¼Êý
Ñ¡ÔñÌⲿ·Ö£º
£¨2016Î÷³ÇÆÚÄ©£©2. ÏÂÁк¯ÊýÖУ¬ÖµÓòΪ[0,??)µÄżº¯ÊýÊÇ£¨ £©
£¨A£©y?x2?1 £¨B£©y?lgx £¨C£©y?|x| £¨D£©y?xcosx
?x, x?1,? ÔòÏÂÁнáÂÛÕýÈ·µÄÊÇ£¨ £© £¨2016º£µíÆÚÄ©£©7. ÒÑÖªº¯Êýf(x)??¦Ðsinx, x?1,??2A£®?x0?R,f(?x0)??f(x0) B£®?x?R,f(?x)?f(x) C£®º¯Êýf(x)ÔÚ[?¦Ð¦Ð,]Éϵ¥µ÷µÝÔö D£®º¯Êýf(x)µÄÖµÓòÊÇ[?1,1] 221x C£®f(x)?e D£®f(x)?sinx x£¨2016³¯ÑôÆÚÄ©£©2. ÏÂÁк¯ÊýÖУ¬¼ÈÊÇÆæº¯ÊýÓÖ´æÔÚÁãµãµÄÊÇ£¨ £©
A£®f(x)?x B£®f(x)?£¨2016³¯ÑôÆÚÄ©£©8.É躯Êýf(x)µÄ¶¨ÒåÓòΪD£¬Èç¹û´æÔÚÕýʵÊým£¬Ê¹µÃ¶ÔÈÎÒâx?D£¬µ±x?m?Dʱ£¬¶¼.ÒÑÖªº¯Êýf(x)ÊǶ¨ÒåÔÚRÉÏµÄÆæº¯Êý£¬ÓÐf(x?m)?f(x)£¬Ôò³Æf(x)ΪDÉϵġ°mÐÍÔöº¯Êý¡±ÇÒµ±x?0ʱ£¬
f(x)?x?a?a£¨a?R£©£¬Èôf(x)ΪRÉϵġ°20ÐÍÔöº¯Êý¡±£¬ÔòʵÊýaµÄȡֵ·¶Î§ÊÇ£¨ £©
A. a?0 B. a?20 C.a?10D.a?5
£¨2016·ą́ÆÚÄ©£©1.º¯Êýf(x)?log0.5(x?1)µÄ¶¨ÒåÓòΪ£¨ £©
£¨A£©(?1,??) £¨B£©(1,??) £¨C£©(0,??) £¨D£©(??,0)
£¨2016·ą́ÆÚÄ©£©8. ijµØÊµÐн×Ìݵç¼Û£¬ÒÔÈÕÀúÄê(ÿÄê1ÔÂ1ÈÕÖÁ12ÔÂ31ÈÕ)ΪÖÜÆÚÖ´ÐоÓÃñ½×Ìݵç¼Û£¬¼´£ºÒ»»§¾ÓÃñÓû§È«Äê²»³¬¹ý2880¶È£¨1¶È=ǧÍßʱ£©µÄµçÁ¿£¬Ö´ÐеÚÒ»µµµç¼Û±ê×¼£¬Ã¿¶Èµç0.4883Ôª£»È«Ä곬¹ý2880¶ÈÖÁ4800¶ÈÖ®¼äµÄµçÁ¿£¬Ö´Ðеڶþµµµç¼Û±ê×¼£¬Ã¿¶Èµç0.5383Ôª£»È«Ä곬¹ý4800¶ÈÒÔÉϵĵçÁ¿£¬Ö´ÐеÚÈýµµµç¼Û±ê×¼£¬Ã¿¶Èµç0.7883Ôª.ÏÂÃæÊǹØÓÚ½×Ìݵç¼ÛµÄͼÐαíʾ£¬ÆäÖÐÕýÈ·µÄÓУ¨ £© µ¥¼Û£¨Ôª/¶È£©µç·Ñ£¨Ôª/Ä꣩0.78830.53830.48832439.841406.30BA28804800ÄêÓõçÁ¿£¨¶È£©o¾«Æ·Îĵµ
28804800ÄêÓõçÁ¿£¨¶È£©O ¾«Æ·Îĵµ
¢Ù ¢Ú
o28800.7883Ôª/¶È0.5383Ôª/¶È0.4883Ôª/¶ÈPÏß¶ÎPQ×ó²àÒõÓ°²¿·ÖµÄÃæ»ý±íʾÄêÓõçÁ¿Îªx¶ÈʱµÄµç·ÑQx4800ÄêÓõçÁ¿£¨¶È£© ¢Û ²Î¿¼Êý¾Ý£º0.4883Ôª/¶È?2880¶È=1406.30Ôª£¬
0.5383Ôª/¶È?(4800-2880)¶È+1406.30Ôª=2439.84Ôª.
(A) ¢Ù¢Ú (B) ¢Ú¢Û (C) ¢Ù¢Û (D)¢Ù¢Ú¢Û
£¨2016ʯ¾°É½ÆÚÄ©£©3£®Èôº¯Êýy?f(x)µÄ¶¨ÒåÓòΪM??x|?2?x?2?,ÖµÓòΪN??y|0?y?2?, Ôòº¯Êýy?f(x)µÄͼÏó¿ÉÄÜÊÇ( )
y y y y 2 222 x -2 o 2 x 2 x -2 o-2 o x -2 o 2 A BCD£¨2016ʯ¾°É½ÆÚÄ©£©7£®ÒÑÖªf(x)?x?1£¬Èôf(x)?ax?1ÔÚx?RÉϺã³ÉÁ¢,ÔòʵÊýaµÄȡֵ·¶Î§ÊÇ( )
A.
?0,1? B.???,?1???1,??? C.??1,1? D.???,0???1,???
x B. y?2x C.y?sinx D. y?cosx
£¨2016²ýƽÆÚÄ©£©£¨2£©ÏÂÁк¯ÊýÖУ¬ÎªÅ¼º¯ÊýµÄÊÇ£¨ £© A. y?0.52£¨2016²ýƽÆÚÄ©£©£¨5£©Éèa?2,b?0.5,c?log20.5£¬Ôòa,b,cµÄ´óС¹ØÏµÎª£¨ £©
A£®c?a?b B£®c?b?a C£®a?b?c D£®b?a?c
£¨2016¶«³ÇÆÚÄ©£©£¨8£©ÒÑÖªº¯Êýf(x)?a?x(1?x?2)Óëg(x)?x?1µÄͼÏóÉÏ´æÔÚ¹ØÓÚxÖá¶Ô³ÆµÄµã£¬Ôò
ʵÊýaµÄȡֵ·¶Î§ÊÇ£¨ £©
25,??) £¨B£©[1,2] 45£¨C£©[?,1] £¨D£©[?1,1]
4£¨A£©[?£¨2016¶«³Çһ죩£¨3£©ÒÑÖªa?log46£¬b?log40.2£¬c?log23£¬ÔòÈý¸öÊýµÄ´óС¹ØÏµÊÇ£¨ £©
£¨A£©c?a?b £¨B£©a?c?b £¨C£©a?b?c £¨D£©b?c?a ¾«Æ·Îĵµ
¾«Æ·Îĵµ
£¨2016¶«³Çһ죩£¨8£©º¯Êýf(x)µÄ¶¨ÒåÓòΪ??1,1?£¬Í¼ÏóÈçͼ1Ëùʾ£»º¯Êýg(x)µÄ¶¨ÒåÓòΪ??1,2?£¬Í¼ÏóÈç
ͼ2Ëùʾ£®Èô¼¯ºÏA?xf(g(x))?0,B?xg(f(x))?0£¬Ôò AIBÖÐÔªËØµÄ¸öÊýΪ £¨ £©
y 1 y 1 1 -1 ͼ1
ͼ2
????-1 O x -1 O 1 2 x £¨A£©1 £¨B£©2 £¨C£©3 £¨D£©4
£¨2016·ą́һ죩2. ÏÂÁк¯ÊýÔÚÆä¶¨ÒåÓòÉϼÈÊÇÆæº¯ÊýÓÖÊÇÔöº¯ÊýµÄÊÇ( )
£¨A£©y?x £¨B£©y??31x
£¨C£©y?tanx £¨D£©y???x(x?0),
??x(x?0).£¨2016·ą́һ죩8. ¾¼Ãѧ¼ÒÔÚÑо¿¹©Çó¹ØÏµÊ±£¬Ò»°ãÓÃ×ÝÖá±íʾ²úÆ·¼Û¸ñ(×Ô±äÁ¿)£¬ÓúáÖá±íʾ²úÆ·ÊýÁ¿£¨Òò±äÁ¿£©£®Ä³Àà²úÆ·µÄÊг¡¹©Çó¹ØÏµÔÚ²»ÊÜÍâ½çÒòËØ£¨ÈçÕþ¸®ÏÞÖÆ×î¸ß¼Û¸ñµÈ£©µÄÓ°ÏìÏ£¬Êг¡»á×Ô·¢µ÷½â¹©Çó¹ØÏµ£ºµ±²úÆ·¼Û¸ñP1µÍÓÚ¾ùºâ¼Û¸ñP0ʱ£¬ÔòÐèÇóÁ¿´óÓÚ¹©Ó¦Á¿£¬¼Û¸ñ»áÉÏÉýΪP2£»µ±²úÆ·¼Û¸ñP2¸ßÓÚ¾ùºâ¼Û¸ñP0ʱ£¬Ôò¹©Ó¦Á¿´óÓÚÐèÇóÁ¿£¬¼Û¸ñÓÖ»áϽµ£¬¼Û¸ñÈç´Ë¼ÌÐø²¨¶¯ÏÂÈ¥£¬²úÆ·¼Û¸ñ½«»áÖ𽥿¿½ü¾ùºâ¼Û¸ñP0£®ÄÜÕýÈ·±íʾÉÏÊö¹©Çó¹ØÏµµÄͼÐÎÊÇ( )
£¨A£© £¨B£©
¾«Æ·Îĵµ
¾«Æ·Îĵµ
µ¥¼Û¹©Ó¦ÇúÏßÐèÇóÇúÏß
µ¥¼ÛÐèÇóÇúÏß
P2¹©Ó¦ÇúÏßP2P0P1P0
OÊýÁ¿P1
OÊýÁ¿£¨2016ʯ¾°É½Ò»Ä££©2£®ÏÂÁк¯ÊýÖУ¬¼ÈÊÇÆæº¯ÊýÓÖÊÇÔöº¯ÊýµÄΪ( )
A£®y?x?1 B£®y??x C£®y?D£®y?xx
x
£¨2016˳Òåһ죩3.ÏÂÁк¯ÊýÔÚÆä¶¨ÒåÓòÄÚ¼ÈÊÇÆæº¯ÊýÓÖÊÇÔöº¯ÊýµÄÊÇ £¨ £© £¨A£©y?2?x £¨B£©y?x3?x £¨C£©y??311 £¨D£©y?lnx xx£¨2016·¿É½Ò»Ä££©£¨7£©ÒÑÖª¶¨ÒåÔÚRÉϵĺ¯Êýf(x)µÄ¶Ô³ÆÖáΪx=-5£¬ÇÒµ±x?5ʱ£¬f(x)?2?3.
Èôº¯Êýf(x)ÔÚÇø¼ä(k,k+1)£¨k?Z£©ÉÏÓÐÁãµã£¬ÔòkµÄֵΪ( )
£¨A£©2»ò-11
£¨B£©2»ò-12
£¨C£©1»ò-12
£¨D£©1»ò-11
£¨2016Î÷³Ç¶þÄ££©2. ÏÂÁк¯ÊýÖУ¬¼ÈÊÇÆæº¯ÊýÓÖÔÚRÉϵ¥µ÷µÝ¼õµÄÊÇ£¨ £© £¨A£©y?1 x?x£¨B£©y?e
£¨C£©y??x3 £¨D£©y?lnx
£¨2016Î÷³Ç¶þÄ££©7.ijÊмÒÍ¥ÃºÆøµÄʹÓÃÁ¿£¨xm3£©ºÍÃºÆø·Ñf(x)(Ôª) Âú×ã¹ØÏµf(x)??ÒÑ֪ij¼ÒÍ¥½ñÄêǰÈý¸öÔµÄÃºÆø·ÑÈçÏÂ±í£º
ÔÂ·Ý Ò»ÔÂ·Ý ¶þÔÂ·Ý ÈýÔÂ·Ý ¾«Æ·Îĵµ
ÓÃÆøÁ¿ 4 m3 25 m3 35 m3 ÃºÆø·Ñ 4 Ôª 14 Ôª 19 Ôª ?C, 0 ?C?B(x?A), x?A.