(1) What relationship should coefficients A¡¢B¡¢C¡¢D satisfy? (2) The stream function of the flow field. ÒÑÖªÁ÷³¡µÄËÙ¶È·Ö²¼Îª
vx=Ax+By vy=Cx+Dy ÈôÁ÷Ìå²»¿ÉѹËõ£¬ÇÒÁ÷¶¯ÎÞÐý£¬ÊÔÎÊ
(1) ϵÊýA¡¢B¡¢C¡¢DÓ¦Âú×ãÔõÑùµÄ¹ØÏµ£¿ (2) ÇóÁ÷³¡µÄÁ÷º¯Êý¡£
( (1) A=?D£¬B=C£»(2) ?=B(y2?x2)/2+Axy )
4.16 There is a fixed point vortex of circulation ? and distance a to a stationary wall. Find the velocity potential function of the flow and pressure distribution on the wall.
ÓÐÒ»»·Á¿Îª?µÄ¹Ì¶¨µãÎУ¬ÀëÒ»¾²Ö¹±ÚÃæµÄ¾àÀëΪa¡£ÊÔÇóÁ÷¶¯µÄËÙ¶ÈÊÆºÍ ±ÚÃæÉϵÄѹǿ·Ö²¼¡£ (
£¬
)
4.17 Given the velocity of an incompressible planar potential flow as vx=3ax2?3ay2, vx=vy=0 at point (0£¬0), find the volume flowrate passing the connecting line of points (0£¬0) and (0£¬1).
ÒÑÖª²»¿ÉѹËõÆ½ÃæÊÆÁ÷µÄËÙ¶È·Ö²¼Îª vx=3ax2-3ay2£¬ÔÚ(0£¬0)µãÉÏvx=vy=0£¬ÊÔÇóͨ¹ý(0£¬0)¡¢ (0£¬1)Á½µãÁ¬ÏßµÄÌå»ýÁ÷Á¿¡£( qv=a )
4.18 A two-dimensional flow field is formed by adding a source at the origin of the coordinate system to the velocity potential ?=r2cos2?
Locate any stagnation points in the upper half of the coordinate plane. (0????) Ò»¶þάÁ÷³¡ÊÇÔÚËÙ¶ÈÊÆ?=r2cos2?ÉÏÓÚ×ø±êԵ㴦µþ¼ÓÒ»µãÔ´¶øÐγɡ£ÊÔÔÚ×ø
0.5
±êÆ½ÃæÉϰ벿ȷ¶¨ÈÎһפµãµÄλÖá£( ?s=?/2£¬rs=(m/4?))
4.19 The stream function for a two-dimensional, incompressible flow field is given by the equation
?=2x-2y
where the stream function has the units of m2/s with x and y in meter.
(1) Sketch the stream function for this flow field, indicate the direction of flow along the streamlines;
(2) Is this an irrotational flow field?
(3) Determine the acceleration of a fluid particle at the point x=1m and y=2m. ¶þά²»¿ÉѹÁ÷³¡µÄÁ÷º¯ÊýΪ
?=2x-2y ʽÖÐx¡¢yµÄµ¥Î»Îªm£¬Á÷º¯Êýµ¥Î»Îªm2/s¡£
(1) ×ö³öÁ÷Ïß·Ö²¼Í¼£¬±êÃ÷Á÷Ïß·½Ïò£»
(2) Á÷¶¯ÊÇ·ñÎÞÐý£¿
(3) È·¶¨µã(1,2)´¦Á÷ÌåÖʵãµÄ¼ÓËÙ¶È¡£ ( (1) ?=2x?2y£¬(2) ÎÞÐý£¬(3) a=0)
4.20 The stream function for the flow of a nonviscous, incompressible fluid in the vicinity of a corner (see Fig. 4-27) is
?=2r4/3sin(4?/3). Determine an expression for the pressure gradient along the boundary ?=3?/4.
Ò»ÎÞÕ³²»¿ÉѹÁ÷ÌåÔÚÈçͼ4-27ËùʾµÄת½Ç¸½½üÁ÷¶¯µÄÁ÷º¯ÊýΪ?=2r4/3sin(4?/3)£¬
ÊÔÈ·¶¨Ñر߽ç?=3?/4µÄѹǿÌݶȱí´ïʽ¡£ Fig. 4-27 Problem 4.20
(
)
4.21 Two sources are located at points (1£¬0) and (-1£¬0)£¬their source strength are all 4?£¬find the velocity at points (0£¬0)¡¢ (0£¬1)¡¢ (0£¬-1)¡¢(1£¬1).
λÓÚ(1£¬0)ºÍ(-1£¬0)Ö®Á½¸öµãÔ´£¬ÆäÔ´Ç¿¶È¾ùΪ4?£¬ÊÔÇóÔÚ(0£¬0)¡¢ (0£¬1)¡¢
(0£¬-1)¡¢(1£¬1)´¦µÄËÙ¶È¡£
( vx=vy=0£»vx=0£¬vy=2£»vx=0£¬vy=?2£»vx=4/5£¬vy=12/5)
4.22 A source with strength 20m2/s is located at point (-1£¬0)£¬another source with strength 40m2/s is located at point (2£¬0). Given the pressure at the coordinate base point of the overlapped flow field is 100Pa£¬the fluid density is 1.8kg/m3£¬find the velocity and pressure at point (0£¬1) and (1£¬1).
Ç¿¶ÈΪ20m2/sµÄµãԴλÓÚ(-1£¬0)£¬Ç¿¶ÈΪ40m2/sµÄµãԴλÓÚ(2£¬0)£¬ÒÑÖªµþ¼ÓÁ÷³¡ÔÚ×ø±êԵ㴦µÄѹǿΪ100Pa£¬Á÷ÌåµÄÃܶÈΪ1.8kg/m3£¬ÇóÔÚµã(0£¬1)ºÍµã(1£¬1)´¦µÄËÙ¶ÈÓëѹǿ¡£
(
?p)
Problems
5.1 A 1:25 scale model of an airship is tested in water at 200C. If the airship travels 5m/s in air at atmospheric pressure and 200C, find the velocity for the model to achieve dynamic similitude. Also, find the ratio of the drag force on the prototype to that on the model. The densities of water and air at these conditions are 1000kg/m3 and 1.2kg/m3 respectively. The corresponding dynamic viscosities of water and air are 10-3N?s/m2 and 1.81?10-5 N?s/m2¡£
Ò»±È³ßΪ1:25µÄ·ÉͧģÐÍÔÚ200CµÄË®ÖÐʵÑé¡£Èç¹û·ÉͧÊÇÔÚ200C¡¢´óÆøÑ¹Á¦ÏÂµÄ¿ÕÆøÖÐÒÔ5m/sµÄËÙ¶È·ÉÐУ¬ÎªÁË´ïµ½¶¯Á¦ÏàËÆ£¬ÇóÄ£Ð͵ÄËÙ¶È¡£²¢ÇóÔÐÍÓëÄ£Ð͵Ä×èÁ¦Ö®±È¡£ÒÑÖªÔÚʵÑéÌõ¼þÏÂË®Óë¿ÕÆøµÄÃܶȷֱðΪ1000kg/m3 ¼° 1.2kg/m3£¬ÏàÓ¦µÄ¶¯Á¦Õ³¶ÈΪ10-3N?s/m2 Óë 1.81?10-5 N?s/m2¡£(8.29m/s£¬0.273)
5.2 A scale model of a pumping system is to be tested to determined the head losses in the actual system. Air with a specific weight of 0.085kg/m3 and a viscosity of 3.74?10-7 m2/s is used in the model. Another fluid with a specific weight of 62.4kg/m3 and a viscosity of 2.36?10-5m2/s is used in the prototype. The velocity in the prototype is 2m/s. A practical upper limit for the air velocity in the model to avoid compressibility effects is 100m/s. Find the scale ratio for the model and the ratio of the pressure losses in the prototype to those in the model.
¶ÔÒ»³éËÍϵͳµÄËõСģÐͽøÐÐʵÑéÒÔÈ·¶¨ÔÐ͵ÄˮͷËðʧ¡£ÔÐÍËùʹÓÃµÄ¿ÕÆøÖضÈΪ0.085kg/m3 ¡¢Õ³¶ÈΪ3.74?10-7 m2/s¡£ÁíÒ»ÖÖÖØ¶ÈΪ62.4kg/m3¡¢Õ³¶ÈΪ2.36?10-5m2/sµÄÁ÷ÌåÓÃÓÚÔÐÍʵÑé¡£ÔÐÍËÙ¶ÈΪ2m/s¡£ÎªÁ˱ÜÃâѹËõÐÔЧӦ£¬Ä£ÐÍÖÐ¿ÕÆøÁ÷ËÙµÄʵ¼ÊÉÏÏÞΪ100m/s¡£ÇóÄ£Ð͵ıȳßÓëÔÐͼ°Ä£ÐÍÖÐѹǿËðʧ±È³ß¡£(0.294)
5.3 To study the flow of a spillway with a model of the length scale ratio kl=1:20. It is known that Fr of the prototype and model are equal, flowrate of the model is measured as 0.19m3/s. Find the flowrate of the prototype.
ÓÃÄ£ÐÍÑо¿ÒçÁ÷µÀµÄÁ÷¶¯£¬²ÉÓõij¤¶È±ÈÀýϵÊýkl=1:20£¬ÒÑÖªÔÐÍÓëÄ£Ð͵Ä
3
FrÏàµÈ£¬²âµÃÄ£ÐÍÉϵÄÁ÷Á¿Îª0.19m/s¡£ÇóÔÐÍÉϵÄÁ÷Á¿¡£(339m3/s)
5.4 The kinematic viscosity of a fluid in the prototype is ?=15?10-5m2/s, the length scale ratio of the model is 1:5, if let Fr and Eu be the decisive similitude numbers, what is the kinematic viscosity of the fluid in the model ?
ÔÐÍÖÐÁ÷ÌåµÄÔ˶¯Õ³¶È?=15?10-5m2/s£¬Ä£Ð͵ij¤¶È±ÈÀýϵÊýΪ1:5£¬ÈçÒÔFrºÍEu×÷Ϊ¾ö¶¨ÐÔµÄÏàËÆ×¼Êý£¬Ä£ÐÍÁ÷ÌåµÄÔ˶¯Õ³¶È?mӦΪ¶àÉÙ£¿(1.34?10-5m2/s)
5.5 The sloshing of oil in a tank is affected by both viscous and gravitational effects. A 1:4 scale model of oil with a kinematic viscosity of 1.1?10-4 m2/s is to be used to study the sloshing. Find the kinematic viscosity of the liquid to be used in the model.
ÓÍÔÚÈÝÆ÷ÖеĻε´Êܵ½Õ³ÐÔÓëÖØÁ¦µÄÓ°Ïì¡£ÓÃÒ»±È³ßΪ1:4µÄÄ£ÐÍÀ´Ñо¿Ô˶¯Õ³¶ÈΪ1.1?10-4 m2/sµÄÓ͵Ļε´¡£ÇóÄ£ÐÍÖÐÒºÌåµÄÔ˶¯Õ³¶È¡£(1.37?10-5m2/s)
5.6 A wind-tunnel test is performed on a 1: 20 scale model of a supersonic aircraft. The prototype aircraft flies at 480m/s in conditions where the speed of sound is 300m/s and the air density is 1.0kg/m3. The model aircraft is tested in a wind-tunnel in which the speed of sound is 279m/s and the air density is 0.43kg/m3. The drag force on the model is 100N. What speed must the flow in the wind-tunnel be for dynamic similitude, and what is the drag force on the prototype?
¶ÔÒ»±È³ßΪ1:20µÄ³¬ÒôËÙ·É»úÄ£ÐͽøÐз綴ʵÑé¡£ÔÐÍ·É»úÔÚÒôËÙΪ300m/s¡¢ÃܶÈΪ1.0kg/m3µÄ¿ÕÆøÖÐÒÔ480m/sµÄËÙ¶È·ÉÐС£Ä£ÐÍ·É»úÔÚÒôËÙΪ279m/s¡¢ÃܶÈΪ0.43kg/m3µÄ¿ÕÆøÖнøÐз綴ʵÑé¡£²âµÃÄ£Ð͵Ä×èÁ¦Î»100N¡£Îª´ïµ½¶¯Á¦ÏàËÆ£¬·ç¶´µÄÁ÷ËÙӦΪ¶àÉÙ£¿ÔÐÍÉϵÄ×èÁ¦ÊǶàÉÙ£¿(446m/s£¬108kN)
5.7 A ventilation pipe of diameter 1m and average flowing velocity 10m/s. Model test is performed on a water pipe of diameter 0.1m, what is the velocity in the water pipe to achieve dynamic similitude? Suppose the pressure and temperature of air and water are all 101kPa and 200C.
Ö±¾¶Îª1mµÄ¿ÕÆø¹ÜµÀ£¬Æ½¾ùÁ÷ËÙΪ10m/s£¬ÏÖÓÃÖ±¾¶Îª0.1mµÄË®¹Ü½øÐÐÄ£
200C¡£ ÐÍʵÑ飬ΪÁ˶¯Á¦ÏàËÆ£¬Ë®¹ÜÖеÄÁ÷ËÙӦΪ¶à´ó£¿Éè¿ÕÆøºÍË®¾ùΪ101kPa¡¢
(6.73 m/s)
5.8 In order to predict the drag on a smooth, streamlined object flying in air, a model is designed to test in water. It is known that the length of the prototype is 3m, flies in air at a speed of 10 m/s. The designing length of the model is 50cm, what is the velocity of water? If the drag on model is measured as 15N, what is the drag on the prototype? Suppose the pressure and temperature of the prototype and model are all 101kPa and 200C.
ΪÁËÔ¤²âÒ»¹â»¬Á÷ÏßÐÍÎïÌåÔÚ¿ÕÆøÖеķÉÐÐ×èÁ¦£¬Éè¼ÆÒ»Ä£ÐÍÔÚË®ÖÐʵÑé¡£ÒÑÖªÔÐ͵ij¤¶ÈΪ3m£¬ÒÔ10 m/sµÄËÙ¶ÈÔÚ¿ÕÆøÖзÉÐС£Ä£Ð͵ij¤¶ÈÉè¼ÆÎª50cm£¬Ë®Á÷µÄËÙ¶ÈӦΪ¶àÉÙ£¿Èô²âµÃÄ£ÐÍÊܵ½µÄ×èÁ¦Îª15N£¬ÔÐÍÊܵ½µÄ×èÁ¦½«ÊǶàÉÙ£¿ÉèÔÐÍ¡¢Ä£Ð;ù´¦ÓÚ101kPa¡¢200C¡£(4 m/s£¬4.05N)
5.9 The height of an automobile is 1.5m, travels in air 200C at a speed of 108km/h. Air in model test is 00C and its flowing velocity is 60m/s. Find the height of the model. If the front resistance in model test is measured as 1300N, what is the front resistance on the prototype automobile when running ?
Æû³µ¸ß¶ÈΪ1.5m£¬ËÙ¶ÈΪ108km/h£¬ ÐÐÊ»ÔÚ200CµÄ¿ÕÆøÖУ¬Ä£ÐÍʵÑéµÄ¿ÕÆøÎª00C£¬ÆøÁ÷ËÙ¶ÈΪ60m/s¡£ÇóÄ£ÐÍÊÔÑéÆû³µµÄ¸ß¶È¡£Èç¹ûÔÚÄ£ÐÍʵÑéÖвâµÃÕýÃæ×èÁ¦Î»1300N£¬ÇóʵÎïÆû³µÐÐʻʱµÄÕýÃæ×èÁ¦ÊǶàÉÙ¡£(0.654m£¬1586N)
5.10 The surface tension of pure water is 0.073N/m, and the surface tension of soapy water is 0.025N/m. If a pure water droplet breaks up in an airstream that is moving at 10m/s, at what speed would the same size soapy water droplet break up? ´¿¾»Ë®µÄ±íÃæÕÅÁ¦Îª0.073N/m£¬·ÊÔíË®µÄ±íÃæÕÅÁ¦Îª0.025N/m¡£Èç¹û´¿¾»Ë®µÎÔÚ10m/sµÄÆøÁ÷ÖÐÆÆÁÑ£¬ÎʳߴçÏàͬµÄ·ÊÔíË®µÎµÄÆÆÁÑÆøÁ÷ËÙ¶ÈΪ¶àÉÙ£¿ (5.85 m/s)