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1.1 A pressure of 2?106N/m2 is applied to a mass of water that initially filled a 1,000cm3 volume. Estimate its volume after the pressure is applied.

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(999.1cm3)

1.2 As shown in Fig.1-9, in a heating system there is a dilatation water tank. The whole volume of the water in the system is 8m3. The largest temperature rise is 500C and the coefficient of volume expansion is ?v=0.0005 1/K, what is the smallest cubage of the water bank?

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(0.2m3) Fig. 1-9 Problem 1.2

1.3 When the increment of pressure is 50kPa, the density of a certain liquid is 0.02%. Find the bulk modulus of the liquid.

µ±Ñ¹Ç¿ÔöÁ¿Îª50kPaʱ£¬Ä³ÖÖÒºÌåµÄÃܶÈÔö¼Ó0.02%¡£Çó¸ÃÒºÌåµÄÌå»ýÄ£Á¿¡£( 2.5?108Pa)

1.4 Fig.1-10 shows the cross-section of an oil tank, its dimensions are length a=0.6m, width b=0.4m, height H=0.5m. The diameter of nozzle is d=0.05m, height h=0.08m. Oil fills to the upper edge of the tank, find:

(1) If only the thermal expansion coefficient ?v=6.5?10-41/K of the oil tank is

considered, what is the volume Fig.1-10 Problem 1.4

of oil spilled from the tank when the temperature of oil increases from t1=-200C to t2=200C?

(2) If the linear expansion coefficient ?l=1.2?10-51/K of the oil tank is considered, what is the result in this case?

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(1) Èç¹ûÖ»¿¼ÂÇÓÍÒºµÄÈÈÅòÕÍϵÊý?v=6.5?10-41/Kʱ£¬ÓÍÒº´Ót1=-200CÉÏÉýµ½ t2=200Cʱ£¬ÓÍÏäÖÐÓжàÉÙÌå»ýµÄÓÍÒç³ö£¿

(2) Èç¹û»¹¿¼ÂÇÓÍÏäµÄÏßÅòÕÍϵÊý?l=1.2?10-51/K£¬ÕâʱµÄÇé¿öÈçºÎ£¿

((1)2.492?10-3m3 (2)2.32?10-3m3)

1.5 A metallic sleeve glides down by self weight, as shown in Fig. 1-11. Oil of ?=3?10-5m2/s and ?=850kg/m3 fills between the sleeve and spindle. The inner diameter of the sleeve is D=102mm, the outer diameter of the spindle is d=100mm, sleeve length is L=250mm, its weight is 100N. Find the maximum velocity when the sleeve glides down freely (neglect air resistance).

Fig. 1-11 Problem 1.5

ÓÐÒ»½ðÊôÌ×ÓÉÓÚ×ÔÖØÑØ´¹Ö±ÖáÏ»¬£¬Èçͼ 1-11Ëùʾ¡£ÖáÓëÌ×¼ä³äÂúÁË?=3?10-5m2/s¡¢?=850kg/m3µÄÓÍÒº¡£Ì×µÄÄÚ¾¶D=102mm£¬ÖáµÄÍâ¾¶d=100mm£¬Ì׳¤L=250mm£¬Ì×ÖØ100N¡£ÊÔÇóÌ×Ͳ×ÔÓÉÏ»¬Ê±µÄ×î´óËÙ¶ÈΪ¶àÉÙ(²»¼Æ¿ÕÆø×èÁ¦)¡£ (50 m/s)

1.6 The velocity distribution for flow of kerosene at 200C (?=4?10-3N?s/m2) between two walls is given by u=1000y(0.01-y) m/s, where y is measured in meters and the spacing between the walls is 1 cm. Plot the velocity distribution and determine the shear stress at the walls.

ÔÚ200Cʱ£¬ÃºÓÍ(?=4?10-3N?s/m2)ÔÚÁ½±ÚÃæ¼äÁ÷¶¯µÄËÙ¶È·Ö²¼ÓÉu=1000y(0.01-y) m/sÈ·¶¨£¬Ê½ÖÐyµÄµ¥Î»Îªm£¬±ÚÃæ¼ä¾àΪ1cm¡£»­³öËÙ¶È·Ö²¼Í¼£¬²¢È·¶¨±ÚÃæÉϵļôÓ¦Á¦¡£ (4?10-2Pa)

1.7 As shown in Fig.1-12, the velocity distribution for viscous flow between stationary plates is given as follows:

Fig. 1-12 Problem 1.7

If glycerin is flowing (T=200C) and the pressure gradient dp/dx is 1.6kN/m3, what is the velocity and shear stress at a distance of 12 mm from the wall if the spacing By is 5.0 cm? What are the shear stress and velocity at the wall?

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¸ø³ö¡£Èç¹ûÁ÷ÌåΪ¸ÊÓÍ(T=200C) ÇÒѹǿÌݶÈdp/dxΪ1.6kN/m3£¬¼ä¾àByΪ5.0 cm£¬¾àƽ°å12mm´¦µÄËÙ¶ÈÓë¼ôÓ¦Á¦Îª¶àÉÙ£¿Æ½°å´¦µÄ¼ôÓ¦Á¦ÓëËÙ¶ÈΪ¶àÉÙ£¿

(u12=0.59m/s£»¦Ó12=20.8N/m2£»u0=0£»¦Ó0=40.4N/m2)

1.8 What is the ratio of the dynamic viscosity of air to that of water at standard pressure and T=200C? What is the ratio of the kinematic viscosity of air to water for the same conditions?

ÔÚ±ê×¼´óÆøÑ¹¡¢T=200Cʱ£¬¿ÕÆøÓëË®µÄ¶¯Á¦Õ³¶ÈÖ®±ÈΪ¶àÉÙ£¿Í¬ÑùÌõ¼þÏÂËüÃǵÄÔ˶¯Õ³¶ÈÖ®±ÈÓÖΪ¶àÉÙ£¿ (?A/?W=0.0018£»?A/?W=15.1)

1.9 The device shown in Fig. 1-13 consists of a disk that is rotated by a shaft. The disk is positioned very close to a solid boundary. Between the disk and boundary is viscous oil.

(1) If the disk is rotated at a rate of 1 rad/s, what will be the ratio of

the shear stress in the oil at r=2cm to Fig. 1-13 Problem 1.9 the shear stress at r=3cm?

(2) If the rate of rotation is 2 rad/s, what is the speed of oil in contact with the disk at r=3cm?

(3) If the oil viscosity is 0.01 N?s/m2 and the spacing y is 2mm, what is the shear stress for the condition noted in (b)?

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(1) Èç¹ûÔ²Å̵ÄÐýתËÙÂÊΪ1 rad/s£¬Îʰ뾶Ϊr=2cmÓër=3cm´¦µÄ¼ôÓ¦Á¦Ö®±ÈΪ¶àÉÙ£¿

(2) Èç¹ûÐýתËÙÂÊΪ2 rad/s£¬r=3cm´¦Óë

Ô²Å̽Ӵ¥µÄÓͲãµÄËÙ¶ÈΪ¶àÉÙ£¿ (3) Èç¹ûÓ͵ÄÕ³¶ÈΪ0.01 N?s/m2 ¡¢ÇÒ¼ä¾àyΪ2mm£¬(b)Çé¿öϵļôÓ¦Á¦Îª¶àÉÙ£¿ ((1) 2:3£»(2) 6cm/s£»(3) 0.3Pa)

1.10 As shown in Fig. 1-14, a cone rotates around its vertical center axis at uniform velocity. The gap between two cones is ?=1mm. It filled with lubricant which

?=0.1Pa?s. In the Figure, R=0.3m, H=0.5m, Fig. 1-14 Problem 1.10 ?=16 rad/s. What is the moment needed to rotate the cone?

Èçͼ1-14Ëùʾ£¬Ò»Ô²×¶ÌåÈÆÊúÖ±ÖÐÐÄÖáµÈËÙÐýת£¬×¶ÌåÓë¹Ì¶¨µÄÍâ×¶ÌåÖ®¼äµÄ϶·ì?=1mm£¬ÆäÖгäÂú?=0.1Pa?sµÄÈó»¬ÓÍ¡£ÒÑ֪׶Ìå¶¥Ãæ°ë¾¶R=0.3m£¬×¶Ìå¸ß¶ÈH=0.5m£¬µ±Ðýת½ÇËÙ¶È ?=16 rad/s ʱ£¬ÇóËùÐèÒªµÄÐýתÁ¦¾Ø¡£ (39.6N?m)

2.1 Two pressure gauges are located on the side of a tank that is filled with oil. One gauge at an elevation of 48m above ground level reads 347 kPa. Another at elevation 2.2m reads 57.5 kPa. Calculate the specific weight and density of the oil.

Á½¸ö²âѹ¼ÆÎ»ÓÚÒ»³äÂúÓ͵ÄÓÍÏäµÄÒ»²à¡£Ò»¸ö²âѹ¼Æ¸ßÓÚµØÃæµÄλÖø߶ÈΪ48m£¬¶ÁÊý57.5 kPa¡£ÁíÒ»¸öλÖø߶ÈΪ2.2m£¬¶ÁÊý347kPa¡£¼ÆËãÓ͵ÄÖØ¶ÈÓëÃܶȡ£(?=6.32kN/m3,?=644kg/m3)

2.2 Two hemispherical shells are perfectly sealed together, and the internal pressure is reduced to 20 kPa, the inner radius is 15 cm and the outer radius is 15.5 cm. If the atmospheric pressure is 100 kPa, what force is required to pull the shells apart?

Á½°ëÇò¿ÇÍêÃÀÃܱÕÔÚÒ»Æð£¬ÄÚѹ¼õÖÁ20 kPa£¬ÄÚ¾¶15 cm£¬Íâ¾¶15.5 cm¡£Èç¹û´óÆøÑ¹Ç¿Îª100 kPa£¬ÇóÒª½«°ëÇòÀ­¿ªËùÐèµÄÁ¦Îª¶àÉÙ¡£(24.5kN)

2.3 As shown in the figure, there is a quantity of oil with density of 800 kg/m3, and a quantity of water below it in a closed container. If h1=300mm, h2=500mm, and h=400mmHg, find the pressure at the free surface of the oil.

ÈçͼËùʾ£¬ÃܱÕÈÝÆ÷ÖÐÓ͵ÄÃܶÈΪ800 kg/m3£¬ÆäÏ·½ÎªË®¡£Èç¹ûh1=300mm, h2=500mm, ¼° h=400mmHg£¬ÇóÓ͵Ä×ÔÓÉ

±íÃæÉϵÄѹǿ¡£(46.1kPa) Problem 2.3 2.4 According to the diagram, one end of a tube connected to an evacuated container and the other end is put into a water pool whose surface is exposed to normal atmospheric pressure. If hv=2m, what is the pressure inside of container A?

Èçͼ£¬Ò»¸ù¹Ü×ÓÒ»¶ËÓëÒ»³é¿ÕµÄÈÝÆ÷ÏàÁ¬£¬ÁíÒ»¶Ë²åÈ뱩¶ÓÚ´óÆøµÄË®³ØÖС£Èçhv=2m£¬ÈÝÆ÷ÄÚµÄѹǿÊǶàÉÙ£¿(81.7kPa)

P

Problem 2.4

2.5 A pressure gauge is placed under sea level. If the gauge pressure at a point 300m below the free surface of the ocean, it registers 309 kPa, find the average specific weight of sea water.

Ò»²âѹ¼ÆÖÃÓÚº£Æ½ÃæÏ£¬Èç¹ûÔÚ×ÔÓɱíÃæÏÂ300mÉî´¦²âѹ¼ÆµÄ¶ÁÊýΪ309 kPa£¬Çóº£Ë®µÄƽ¾ùÖØ¶È¡£(1.03kN/m3)

2.6 If the local atmospheric pressure is given by 98.1 kPa absolute, find the relative

pressure at points a, b and c in water. (see attached figure)

Èç¹ûµ±µØ´óÆøÑ¹µÄ¾ø¶ÔѹǿΪ98.1 kPa£¬ÇóË®ÖÐa¡¢b ¼° c µãµÄÏà¶Ôѹǿ¡££¨¼û¸½Í¼£©(Pa=68.6kPa£¬Pb=31.3kPa£¬Pc=-29.4kPa)

Problem 2.6

2.7 There is an applied load of 5788N on the piston within a cylindrical container, in which is filled with oil and water. The oil column height is h1=30cm when the water column h2=50cm. The diameter of the container is giver as d=40cm. The density of oil is ?1=800kg/m3 and that of mercury as ?3=13 600kg/m3. Compute the height H(cm) of the mercury column in the U-tube.

Ô²ÖùÐÎÈÝÆ÷µÄ»îÈûÉÏ×÷ÓÃÒ»5788NµÄÁ¦£¬ÈÝÆ÷ÄÚ³äÓÐË®ºÍÓÍ¡£µ±Ë®Öù¸ßh2=50cmʱ£¬ÓÍÖù¸ßh1=30cm¡£ÈÝÆ÷Ö±¾¶d=40cm£¬Ó͵ÄÃܶÈ?1=800kg/m3£¬Ë®ÒøÃܶÈ?3=13 600kg/m3¡£ÇóUÐιÜÄڵĹ¯Öù¸ßH(cm) ¡£(14.07cm)

Problem 2.7

2.8 According to the diagram, a closed tank contains water that has a relative pressure on the water surface of po= - 44.5kN/m2.

(1) What is the distance h?

(2) What is the pressure at point M with 0.3m below water surface?

(3) What is the piezometric head of point M relative to datum plane1-1?

ÈçͼËùʾ£¬Ò»ÃܱÕÈÝÆ÷ÄÚÊ¢ÓÐ×ÔÓɱíÃæÏà¶Ô Problem 2.8 ѹǿΪpo=- 44.5kN/m2µÄË®¡£

(1) Çó¾àÀëh£»

(2) Ë®ÃæÏÂ0.3m´¦µÄMµã µÄѹǿΪ¶àÉÙ£¿

(3) MµãÏà¶ÔÓÚ»ù×¼Ãæ1-1µÄ²âѹ¹ÜˮͷÊǶàÉÙ£¿ (h=4.54m£¬Pm=-41.6kPa£¬hm=-4.24m)

2.9 An upright U-tube is fixed on the hood of a car which traveling in a straight-line, with a constant acceleration a=0.5m/s2. The length L=500mm. Find the height difference of the two free surfaces in the U-tube.

Ò»ÊúÖ±µÄUÐιܰ²×°ÔÚÒÔÔȼÓËÙ¶Èa=0.5m/s2×÷Ö±ÏßÔËÐеijµÕÖÉÏ£¬³¤¶ÈL=500mm¡£ÇóUÐιÜÄÚÁ½×ÔÓÉÒºÃæµÄ¸ß¶È²î¡£ (25.5mm)

Problem 2.9 2.10 According to the diagram, an open tank containing water moves with an acceleration a=3.6m/s2, along a slope of 30o. What is the inclined angle ? with the horizontal plane and the equation of water pressure p at the free surface?

ÈçͼËùʾ£¬Ò»Ê¢Ë®µÄ¿ª¿ÚÈÝÆ÷ÒÔ¼ÓËÙ¶Èa=3.6m/s2ÑØ30oµÄÐ±ÃæÔ˶¯¡£Çó×ÔÓÉÒºÃæÓëË®Æ½ÃæµÄ¼Ð½Ç?£¬²¢Ð´³öË®µÄѹǿpµÄ·Ö²¼·½³Ì¡£

(?=15o£¬p=pa+?gh)

Problem 2.10

2.11 As shown in the figure, a gate of 2m wide, extends out of the plane of the diagram toward the reader. The gate is pivoted at hinge H, and weighs 500kg. Its center of gravity is 1.2m to the right and 0.9m above H. For what values of water depth x above H will the gate remain closed? (Neglect friction at the pivot point and neglect the thickness of the gate) ÈçͼËùʾ£¬Õ¢ÃÅ¿í2m£¬ÖØ500kg£¬ÈƽÂÁ´Hת¶¯¡£Õ¢ÃÅÖØÐÄÔÚ¾àÓÒ¶Ë1.2m´¦ÇÒ¸ßÓÚH 0.9m¡£ÎʽÂÁ´HÉÏ·½Ë®ÉîxΪ¶àÉÙʱ£¬Õ¢ÃÅ

½«¹Ø±Õ£¿£¨ºöÂÔ½ÂÁ´Ä¦²Á¼°Õ¢Ãŵĺñ¶È£©(1.25m) Problem 2.11

2.12 A flat 1 m high gate is hinged at point O, and can rotate around the point (see attached diagram). The height of point O is a=0.4m. What is the water depth when the gate can automatically open around point O?

Ò»1Ã׏ߵį½°åÕ¢ÃÅÔÚOµã´¦ÓýÂÁ´Á¬½Ó£¬ÇÒ¿ÉÈÆ½ÂÁ´×ª¶¯£¨¼û¸½Í¼£©¡£OµãµÄ¸ß¶ÈΪa=0.4m¡£Ë®Éî¶àÉÙʱ£¬Õ¢ÃŽ«×Ô¶¯¿ªÆô£¿ (h=1.33m)

Problem 2.12

2.13 As shown in the diagram, a closed tank forming a cube is half full of water, find: (a) the absolute pressure on the bottom of the tank, (b) the force exerted by the fluids on a tank wall as a function of height, (c) the location of the center of pressure by water on the tank wall.

ÈçͼËùʾ£¬Ò»ÃܱÕÁ¢·½ÌåË®Ïä×°ÁËÒ»°ëµÄË®£¬Çó£º(a) Ïäµ×µÄ¾ø¶Ôѹǿ£»(b) ½«Á÷Ìå¶ÔÒ»²àÏä±ÚµÄ×÷ÓÃÁ¦±íʾΪ¸ß¶ÈµÄº¯Êý£»

(c) Ë®¶ÔÏä±ÚµÄѹÁ¦ÖÐÐÄλÖᣠProblem 2.13 (17.8kPa£¬F=2h(8000+0.5?gh)£¬2/3)

2.14 A circular sluice gate of diameter d=1m is submerged in water as shown in the figure. The slant angle ?=60o, the submerged depth hc=4.0m, and the weight of the gate FG=1kN. Determine the magnitude of the vertical force T so as to make the gate rotate upward about axis a (neglect friction at axis a).

ÈçͼËùʾµÄÒ»Ö±¾¶d=1mÔ²ÐÎÕ¢ÃÅÑÍûÓÚË®ÖС£Çã½Ç?=60o£¬ÑÍÉîhc=4.0m£¬Õ¢ÃÅÖØFG=1kN¡£ÇóʹբÃÅÈÆaÖáÏòÉÏת¶¯µÄǦֱÁ¦TµÄ´óС¡£(230kN)

Problem 2.14

2.15 The gate M shown in the figure rotates about an axis through N. If a=33m, b=13m, d=20m and the width perpendicular to the plane of the figure is 3m, what torque applied to the shaft through N is required to hold the gate closed?

ͼʾբÃÅMÈÆNÖáת¶¯¡£Èça=33m¡¢ b=13m¡¢d=20mÇÒÓëͼÐδ¹Ö±µÄ¿í¶ÈΪ3m£¬ÒªÊ¹Õ¢ÃŹرգ¬ÐèҪʩ¼Ó¶à´óµÄÁ¦¾ØÔÚתÖáÉÏ£¿(666?103kN?m)

Problem 2.15

2.16 Find the horizontal and vertical components of the force exerted by fluids on the fixed circular cylinder shown in the figure, if:(1) the fluid to the left of the cylinder is a gas confined in a closed tank at a pressure of 35kPa, and (2) the fluid to the left of the cylinder is water with a free surface at an elevation coincident with the uppermost part of the cylinder. Assuming in both cases that normal atmospheric pressure conditions exist to the right and top of the cylinder.

ÇóÏÂÊöÁ÷Ìå¶ÔͼʾԲÖùÌåËùÊ©¼ÓµÄˮƽÓëǦֱ·½ÏòµÄ·ÖÁ¦¡£(1)Ô²ÖùÌå×ó±ßÊÇѹǿΪ35kPaµÄÃܱկøÌ壻(2)Ô²ÖùÌå×ó±ßÊÇ×ÔÓÉÒºÃæ¸ÕºÃÓëÖù¶¥Æ½ÆëµÄË®¡£ÉèÁ½ÖÖÇé¿öÏÂÔ²Öù

ÌåµÄÓÒ±ßÓë¶¥²¿Îª±ê×¼´óÆøÑ¹¡£ Problem 2.16 ((1) Fx=130.5kN£¬Fz=35kN£»(2) Fx=68.1kN£¬Fz=100.5kN)

2.17 The cross section of a tank is as shown in the figure. BC is a cylindrical surface with r=6m, and h=10m. If the tank contains gas at a pressure of 8kPa, determine the magnitude and location of the horizontal and vertical force components acting on unit width of tank wall ABC. ͼʾΪһÈÝÆ÷µÄÆÊÃæ£¬BCÊǰ뾶r=6mµÄÔ²ÖùÃæ¡£ÈÝÆ÷¸ßh=10m¡£Èç¹ûÈÝÆ÷×°ÓÐѹǿΪ8kPaµÄÆøÌ壬Çó×÷ÓÃÔÚÈÝÆ÷±ÚABCÉϵ¥Î»¿í¶ÈµÄˮƽ·ÖÁ¦ÓëǦֱ·ÖÁ¦µÄ´óСÓë×÷ÓÃλÖá£

(Fx=80kN£¬Fz=48kN) Problem 2.17

2.18 Find the minimum value of z for which the gate in the figure will rotate counterclockwise if the gate is: (a) rectangular 5m high by 4m wide; (b) triangular, 4m base as axis, height 5m. neglect friction in bearings.

Problem 2.18

µ±ÏÂÊöÇé¿öʱ£¬ÇóʹͼʾբÃÅÑØÄæÊ±Õë·½Ïòת¶¯µÄzµÄ×îСֵ£º(a) Õ¢ÃÅΪ¸ß5m¡¢¿í4mµÄ¾ØÐΣ»(b) Õ¢ÃÅΪÉϵ×4m£¨×ªÖᣩ¡¢¸ß5mµÄÈý½ÇÐΡ£ ((a) z=307.5m£¬(b)305m)

2.19 A curved surface is formed as a quarter of a circular cylinder with R=0.75m, as shown in the figure. The cylinder surface is w=3.55m wide (out of the plane of the figure toward the reader). Water standstill to the right of the curved surface to a depth of H=0.65m. Determine

(1) The magnitude of the hydrostatic force on the surface.

(2) The direction of the hydrostatic force. Problem 2.19 Ò»ÇúÃæÓɰ뾶ΪR=0.75mµÄËÄ·ÖÖ®Ò»µÄÔ²ÖùÌå×é³É£¬ÈçͼËùʾ¡£Ô²ÖùÃæ¿íw=3.55m£¨´¹Ö±ÓÚͼÐÎÆ½Ã棩¡£ÇúÃæÓҲྲˮÉî¶ÈH=0.65m¡£ÊÔÇó£º

(1) ×÷ÓÃÓÚÇúÃæÉϾ²Ë®Ñ¹Á¦µÄ´óС£» (2) ¾²Ë®Ñ¹Á¦µÄ·½Ïò¡£ (Fx=7357N£¬Fz=6013N)

2.20 As shown in the diagram, there is a cylinder with diameter D=4m and length L=12m in water. The depth of water on the right and left side of the cylinder are 4m and 2m respectively. Find the magnitude and direction of the force on the cylinder exerted by water.

ÈçͼËùʾ£¬Ö±¾¶D=4m¡¢³¤L=12m Problem 2.20

µÄÔ²ÖùÌå·ÅÓÚË®ÖУ¬Ô²ÖùÌå×óÓÒÁ½±ßË®µÄÉî¶È·Ö±ðΪ4m ºÍ 2m¡£ÇóË®¶ÔÔ²ÖùÌåµÄ×÷ÓÃÁ¦µÄ´óСÓë·½Ïò¡£

(Fx=706kN£¬Fz=1579kN)

2.21 As shown in the figure, determine the pivot location y of the rectangular gate, so that the gate will just open.

ÈçͼËùʾ£¬ÇóբßպÿªÆôʱתÖáµÄλÖÃyΪ¶àÉÙ¡£(y=0.44m)

Problem 2.21

Problems

3.1 A two-dimensional, incompressible flow field is given by

Find the velocity and acceleration at point (1,2).

¶þά²»¿ÉѹËõÁ÷¶¯ÓÉ

È·¶¨¡£ÊÔÇóµã£¨1£¬2£©´¦µÄËÙ¶È

Óë¼ÓËÙ¶È¡£(vx=5£¬vy=?30£»ax=75£¬ay=150)

3.2 Suppose velocity distribution of a flow field is given by

Find:(1) the expression of local acceleration; (2) the acceleration of the fluid particle at point (1,1) when t=0.

ÉèÁ÷³¡µÄËÙ¶È·Ö²¼Îª

¡£Ç󣺣¨1£©µ±µØ¼ÓËٶȵÄ

±í´ïʽ£»£¨2£©t=0ʱÔڵ㣨1£¬1£©´¦Á÷ÌåÖʵãµÄ¼ÓËÙ¶È¡£

((1) ?vx/?t=4, ?vy/?t=0£»(2) ax=3, ay=?1)

3.3 The velocity components of a flow field is

Determine the streamline equation through point (x0,y0) at t=t0. Ò»Á÷³¡µÄËÙ¶È·ÖÁ¿Îª

È·¶¨ÔÚt=t0ʱ¿Ìͨ¹ýµã(x0,y0)µÄÁ÷Ïß·½³Ì¡£(x2?y?Aty+C=0)

3.4 A two-dimensional velocity field is given by

What is the streamline equation in this flow field? ÒÑÖª¶þάËٶȳ¡

3.5 It is known the velocity field is

Try to find the streamline equation passing through point£¨2£¬1£¬1£©.

ÒÑÖªËٶȳ¡

(x

=2£¬5-z=2z)

vx£¬ÇóÁ÷Ïß·½³Ì¡£(x1+t=cy)

£¬Çóͨ¹ýµã£¨2£¬1£¬1£©µÄÁ÷Ïß·½³Ì¡£

3.6 An oil transportation pipeline, the velocity at the section of diameter 20cm is 2m/s, what is the velocity and mass flow rate at the section of diameter 5cm? The density of the oil is 850kg/m3.

ÓÐÒ»ÊäÓ͹ܵÀ£¬ÔÚÄÚ¾¶Îª20cmµÄ½ØÃæÉÏÁ÷ËÙΪ2m/s£¬ÇóÔÚÁíÒ»ÄÚ¾¶Îª5cmµÄ½ØÃæÉϵÄÁ÷ËÙÒÔ¼°¹ÜÄÚµÄÖÊÁ¿Á÷Á¿¡£Ó͵ÄÃܶÈΪ850kg/m3¡£(32m/s£¬53.4kg/s)

3.7 In a pipeline of inner diameter 5cm, the mass flow rate of air is 0.5kg/s, pressure at a certain is 5?105Pa, the temperature is 1000C. Find the average air flow velocity on this section.

ÔÚÄÚ¾¶Îª5cmµÄ¹ÜµÀÖУ¬Á÷¶¯¿ÕÆøµÄÖÊÁ¿Á÷Á¿Îª0.5kg/s£¬ÔÚijһ½ØÃæÉÏ

ѹǿΪ5?105Pa£¬Î¶ÈΪ1000C¡£Çó¸Ã½ØÃæÉÏÆøÁ÷µÄƽ¾ùËÙ¶È¡£(54.5m/s)

3.8 The velocity distribution of an incompressible fluid is

£¬

Try to deduce the expression of vz by adopting continuity equation.

ÒÑÖªÒ»²»¿ÉѹËõÁ÷ÌåµÄËÙ¶È·Ö²¼Îª

ÓÃÁ¬Ðø·½³ÌÍÆµ¼³övzµÄ±í´ïʽ¡£(vz=-z(2x+2y+z+1)+c(x,y))

3.9 As shown in Fig. 3-25, water flows steadily into a two-dimensional tube at a uniform velocity v. Since the tube bends an angle of 900, velocity distribution at the outlet becomes

. Assuming the width h

of the tube is constant, find constant C.

Èçͼ3-25Ëùʾ£¬Ë®ÒÔ¾ùÔÈËÙ¶Èv¶¨³£Á÷ÈëÒ»¸ö¶þάͨµÀ£¬ÓÉÓÚͨµÀÍäÇúÁË900£¬ÔÚ³ö¿Ú¶ËËÙ¶È·Ö²¼±äΪ

£¬

¡£ÊÔ

¡£ÉèͨµÀ¿í¶ÈhΪ³£Êý£¬ Fig. 3-25 Problem 3.9

Çó³£ÊýC¡£( C=v/3)

3.10 Water is flowing in a river, as shown in Fig. 3-26. Two Pitot tubes are stacked and connected to a differential manometer containing a fluid of specific gravity 0.82. Find vA and vB.

Ë®ÔÚºÓµÀÖÐÁ÷¶¯£¬Èçͼ3-26Ëùʾ¡£Á½¸öÖØµþµÄƤÍйÜÓëÒ»×°ÓбÈÖØÎª0.82µÄÁ÷ÌåµÄѹ²î¼ÆÁ¬½Ó¡£ÊÔÇóvA ¼° vB¡£

(vA=1.212m/s£¬vB =1.137m/s) Fig. 3-26 Problem 3.10

vvv 3.11 As shown in Fig. 3-27, a pipe of diameter 1m is installed horizontally, of which a part bends an angle of 300. Oil of specific gravity 0.94 flows inside the pipe with a flow rate of 2m3/s. Assume pressure in the pipe is uniform, the gauge pressure is 75kPa, find the horizontal force exerting on the elbow pipe.

Ö±¾¶Îª1mµÄˮƽװÖÃµÄ¹Ü Fig. 3-27 Problem 3.11 µÀÓÐÒ»¶Î300µÄÍä¹Ü£¬Èçͼ3-27

Ëùʾ¡£¹ÜÄÚ±ÈÖØÎª0.94µÄÓÍÒÔ2m3/sµÄÁ÷Á¿Á÷¶¯¡£ÉèÍä¹ÜÄÚѹǿ¾ùÔÈ£¬±íѹΪ75kPa£¬ÇóÍä¹ÜÊܵ½µÄˮƽÁ¦¡£(Fx=8.64kN£¬Fy=31.9kN)

3.12 The height of the mercury column in U-tube is 60mm, as shown in Fig. 3-28. Assume the diameter of the conduit is 100mm, find the volume flow rate of water through the conduit at section A.

Èçͼ3-28Ëùʾ£¬UÐιÜÄÚ¹¯Öù¸ß¶ÈΪ60mm¡£ÉèÅÅË®¹ÜµÄÖ±¾¶Îª100mm£¬

ÇóÔÚ½ØÃæA´¦Í¨¹ýÅÅË®¹ÜµÄÌå»ýÁ÷Á¿¡£

(0.0314m3/s)

Fig. 3-28 Problem 3.12

3.13 A nozzle is connected at one end of a water pipe, as shown in Fig. 3-29. The outlet diameter of the water pipe is d1=50mm, and that of the nozzle is d2=25mm. The nozzle and the pipe are connected by four bolts. The gauge pressure at inlet of the nozzle is 1.96?105Pa, volume flow rate is 0.005m3/s, try to find the tension applied on each bolt.

ÔÚË®¹ÜµÄ¶Ë²¿½ÓÓÐÅç×죬Èçͼ3-29Ëùʾ¡£Ë®¹Ü³ö¿ÚÖ±¾¶d1=50mm£¬

Åç×ì³ö¿ÚÖ±¾¶d2=25mm¡£Åç×ìÓë Fig. 3-29 Problem 3.13 ¹ÜÖ®¼äÓÃËĸöÂÝ˨Á¬½Ó¡£Åç×ìÈë¿Ú

´¦µÄ±íѹΪ1.96?105Pa£¬Á÷Á¿Îª0.005m3/s£¬Çóÿ¸öÂÝ˨ËùÊܵ½µÄÀ­Á¦¡£(86.75N)

3.14 A centrifugal pump draws water from a well, as shown in Fig.3-30. Assume the inner diameter of the slouch is d=150mm, volume flow rate is qv=60 m3/h, and the vacuum value at point A where the slouch and the pump are connected is pv=4?104Pa. Neglect head loss, what is the suction height Hs of the pump?

ÀëÐÄʽˮ±Ã´Ó¾®Àï³éË®£¬Èçͼ3-30Ëùʾ¡£ÉèÎüË®¹ÜÄÚ¾¶d=150mm£¬Á÷Á¿Îªqv=60 m3/h£¬ÎüË®¹ÜÓëË®±Ã½ÓÍ·´¦AµãµÄÕæ¿ÕֵΪpv=4?104Pa¡£²»¼ÆË®Í·Ëðʧ£¬ÇóË®±ÃµÄÎüË®¸ß¶ÈHs¡£(4.03m)

Fig. 3-30 Problem 3.14 3.15 As shown in Fig.3-31, an oil of specific gravity 0.83 rushes towards a vertical plate at velocity v0=20m/s, find the force needed to support the plate.

Èçͼ3-31Ëùʾ£¬Ïà¶ÔÃܶÈΪ0.83

µÄÓÍˮƽÉäÏòÖ±Á¢µÄƽ°å£¬ÒÑÖªv0=20m/s£¬ÇóÖ§³Åƽ°åËùÐèµÄÁ¦F¡£(652N)

Fig.3-31 Problem 3.15 3.16 A horizontal jet flow with volume flow rate qv0 rushes towards an inclined plate at velocity v0, as shown in Fig. 3-32. Neglect the effects of gravity and impact loss of the fluid, the pressure and velocity of the jet flow remain the same after it splits into two distributaries. Find the formulas of the two distributaries¡¯ flow rate qv1and qv2, and the force acting on the plate.

Èçͼ3-32Ëùʾ£¬Ò»¹ÉËÙ¶ÈΪv0¡¢Ìå»ýÁ÷Á¿Îªqv0µÄˮƽÉäÁ÷£¬Éäµ½ÇãбµÄ¹â»¬Æ½°åÉÏ¡£ºöÂÔÁ÷Ìåײ»÷µÄËðʧºÍÖØÁ¦µÄÓ°Ï죬ÉäÁ÷µÄѹǿÓëËÙ¶ÈÔÚ·ÖÁ÷ºóҲûÓб仯£¬ÇóÑØ°åÃæÏòÁ½²àµÄ·ÖÁ÷Á÷Á¿qv1Óëqv2µÄ±í´ïʽ£¬ÒÔ¼°Á÷Ìå¶Ô°åÃæµÄ

×÷ÓÃÁ¦¡£ Fig. 3-32 Problem 3.16

(

)

3.17 As shown in Fig.3-33, a cart carrying an inclined smooth plate moves at velocity v against a jet flow, the velocity , flow rate and density of the jet flow are v0, qv£¬and ? respectively. Ignore the friction between the cart and ground, what is the power W needed for driving the cart?

Èçͼ3-33Ëùʾ£¬´øÓÐÇãб¹â»¬Æ½°åµÄС³µÄæ×ÅÉäÁ÷·½ÏòÒÔËÙ¶ÈvÔ˶¯£¬ÉäÁ÷µÄËٶȺÍÁ÷Á¿·Ö±ðΪv0ºÍqv£¬ÉäÁ÷µÄÃܶÈΪ?£¬²»¼ÆÐ¡³µÓëµØÃæµÄĦ²Á

Á¦£¬ÇóÍÆ¶¯Ð¡³µËùÐèµÄ¹¦ÂÊW¡£ Fig.3-33 Problem 3.17

(

)

3.18 A crooked pipe stretches out from a big container, as shown in Fig. 3-34, the diameter of the pipe is 150mm, and that of the nozzle is 50mm. If neglect the head loss, try to find the flow rate of the pipe, and pressures at point A, B, C, and D.

´ÓÒ»´óÈÝÆ÷Òý³öÒ»ÍäÇúµÄ¹ÜµÀÈçͼ3-34Ëùʾ£¬¹Ü¾¶Îª150mm£¬Åç×ìÖ±¾¶Îª50mm£¬²»¼ÆË®Í·Ëðʧ£¬Çó¹ÜµÄÊäË®Á÷Á¿£¬ÒÔ¼°A¡¢B¡¢C¡¢D¸÷µãµÄѹǿ¡£

(0.0174m3/s£¬68.2¡¢-0.47¡¢-20.1¡¢38.8kPa) Fig. 3-34 Problem 3.18

3.19 A Venturi flowmeter is installed bias as shown in Fig.3-35, diameter at the inlet is d1, and diameter at the throat is d2, try to deduce its flow rate expression.

ÎÄÇðÀï¹ÜÁ÷Á¿¼ÆÇãб°²×°Èçͼ3-35Ëùʾ£¬Èë¿ÚÖ±¾¶Îªd1£¬ºí²¿Ö±¾¶Îªd2¡£ÊÔÍÆµ¼³öÆäÁ÷Á¿µÄ¼ÆË㹫ʽ¡£

(

)

Fig.3-35 Problem 3.19

3.20 As shown in Fig.3-36, water flows out from a big container and into another small container. Suppose that the free surface elevations of the two containers keep unchanged, find the velocity ve at the outlet.

Èçͼ3-36Ëùʾ£¬´óÈÝÆ÷ÖеÄË®ÓÉС¿×Á÷³ö£¬Á÷ÈëÁíһʢˮСÈÝÆ÷¡£ÈôÁ½ÈÝÆ÷µÄË®Ãæ¸ß¶È±£³Ö²»±ä£¬ÇóС¿×Á÷³öµÄËÙ¶Ève¡£

(

) Fig.3-36 Problem 3.20

3.21 A Pitot tube is submerged in a prismatic pipeline, which is shown as in Fig.3-37. If the density of the fluid inside the pipeline is ?, and that in the U-tube is ?¡¯, the elevation difference in the U-tube is ?h, find the velocity in the pipeline.

һƤÍйÜÖÃÓڵȽØÃæµÄ¹Ü·ÖУ¬Èçͼ3-37Ëùʾ¡£UÐιÜÄÚÁ÷Èô¹ÜÄÚÁ÷ÌåµÄÃܶÈΪ?£¬

ÌåµÄÃܶÈΪ?¡¯£¬ÒºÃæ¸ß¶È²îΪ?h£¬Çó¹ÜÁ÷ËÙ¶È¡£(

)

Fig.3-37 Problem 3.21 3.22 As shown in Fig.3-38, transport water from container A to container B by means of a siphon. If the volume flow rate is 100m3/h, H1=3m, z=6m, and neglect the head loss, find the diameter of the siphon and the vacuum value in the upper part of the siphon.

Èçͼ3-35Ëùʾ£¬ÀûÓúçÎü¹Ü°ÑË®´ÓÈÝÆ÷AÒýµ½ÈÝÆ÷B¡£ÒÑÖªÌå»ýÁ÷Á¿Îª100m3/h£¬H1=3m£¬z=6m£¬²»¼ÆË®Í·Ëðʧ£¬ÇóºçÎü¹ÜµÄ

¹Ü¾¶£¬ÒÔ¼°É϶˹ÜÖеÄÕæ¿ÕÖµ¡£ Fig.3-38 Problem 3.22 (0.068m£¬5.89?104Pa)

3.23 A water sprinkler is shown as in Fig. 3-39, the lengths of its two arms are l1=1m and l2=1.5m respectively, if the diameter of the nozzle is d=25mm, do not take the frictional moment into account, find the rotating speed n.

È÷Ë®Æ÷Èçͼ3-39Ëùʾ£¬Á½±Û³¤·Ö±ðΪl1=1m¡¢l2=1.5m£¬ÈôÅç¿ÚÖ±¾¶d=25mm£¬Ã¿¸öÅç¿ÚµÄÁ÷Á¿qv=3L/s£¬²»¼ÆÄ¦²Á×èÁ¦¾Ø£¬ÇóתËÙn¡£(44.9 r/min)

Fig. 3-39 Problem 3.23

v3.24 A symmetrical sprinkler is shown as in Fig. 3-40. The rotating radius is R=200mm, ?=450, the nozzle diameter is d=8mm, the total flow rate is qv=0.563L/s, if the frictional moment is 0.2N?m, find the rotating speed n. And what is the magnitude of the moment needed to hold the sprinkler at rest while it is in operation?

¶Ô³ÆÈ÷Ë®Æ÷Èçͼ3-40Ëùʾ¡£Ðýת°ë¾¶ Fig. 3-40 Problem 3.24 R=200mm£¬?=450£¬Åç¿ÚÖ±¾¶d=8mm£¬×Ü

Á÷Á¿qv=0.563L/s£¬ÈôÒÑ֪Ħ²Á×èÁ¦¾ØÎª0.2N?m£¬ÇóתËÙn¡£ÈôÅçˮʱ²»ÈÃÆäÐýת£¬Ó¦Êܵ½¶à´óµÄÁ¦¾Ø£¿(103 r/min£¬0.441 N?m)

Problems

1.1 The velocity field of a rotational flow is given by

Find the average angular rotating velocity at point (2,2,2).

ÒÑÖªÓÐÐýÁ÷¶¯µÄËٶȳ¡Îª

ÇóÔڵ㣨2,2,2£©´¦Æ½¾ùÐýת½ÇËÙ¶È¡£(?x=0.5£¬?y=?2£¬?z=?0.5)

1.2 Determine whether the following flow field is rotational flow or irrotational flow.

È·¶¨ÏÂÁÐÁ÷³¡ÊÇÓÐÐýÔ˶¯»¹ÊÇÎÞÐýÔ˶¯£º

(1) (2)

( (1)ÓÐÐý£¬(2)ÎÞÐý)

4.3 The velocity distribution of a flow field is described by v=x2yi?xy2j Is the flow irrotational?

Á÷³¡µÄËÙ¶È·Ö²¼Îª

v=x2yi?xy2j

¸ÃÁ÷¶¯ÊÇ·ñÎÞÐý£¿(ÓÐÐý)

4.4 For a certain incompressible, two-dimensional flow field the velocity component in the y direction is given by vy=x2+2xy

Determine the velocity component in the x direction so that the continuity equation is satisfied.

ijһ²»¿ÉѹËõÆ½ÃæÁ÷³¡ÔÚy·½ÏòµÄËÙ¶È·ÖÁ¿Îª vy=x2+2xy

È·¶¨x·½ÏòµÄËÙ¶È·ÖÁ¿£¬ÒÔÂú×ãÁ¬ÐøÐÔ·½³Ì¡£(vx=?x2+C)

4.5 For a certain incompressible flow field it is suggested that the velocity components are given by the equations

vx=x2y vy=4y3z vz=2z Is this a physically possible flow field?

ijһ²»¿ÉѹËõÁ÷³¡Á÷³¡µÄËÙ¶È·ÖÁ¿ÓÉÏÂÁз½³Ì¸ø³ö vx=x2y vy=4y3z vz=2z ÊÔÎʸÃÁ÷³¡ÔÚÎïÀíÉÏÊÇ·ñ¿ÉÄÜ£¿(²»¿ÉÄÜ)

vvxxv

4.6 It is known that streamlines are concentric circles, and velocity distribution is ÒÑÖªÁ÷ÏßΪͬÐÄÔ²×壬ÆäËÙ¶È·Ö²¼Îª

Find the velocity circulation along circle x2+y2=R2, where the radiuses of the circle are

(1) R=3£»(2) R=5£»(3) R=10 respectively.

ÇóÑØÔ²ÖÜx2+y2=R2µÄËÙ¶È»·Á¿£¬ÆäÖÐÔ²µÄ°ë¾¶R·Ö±ðΪ (1) R=3£»(2) R=5£»(3) R=10¡£

((1) 18?/5£¬(2) 10?£¬(3) 10? )

4.7 Assume there is a vortex of ?=?0 locating at point (1£¬0), and another vortex of ?=-?0 at point (-1£¬0). Find the velocity circulation along the following routes: (1) x2+y2=4£» (2) (x-1)2+y2=1£»

(3) Square of x= ?2£¬y= ?2£» (4) Square of x= ?0.5£¬y= ?0.5.

ÉèÔÚµã(1£¬0)´¦ÖÃÓÐ?=?0µÄÐýÎУ¬ÔÚµã(-1£¬0)´¦ÖÃÓÐ?=-?0µÄÐýÎС£ÊÔÇóÏÂÁзÏßµÄËÙ¶È»·Á¿£º

(1) x2+y2=4£» (2) (x-1)2+y2=1£»

(3) x= ?2£¬y= ?2µÄ·½Ðοò£»

(4) x= ?0.5£¬y= ?0.5µÄ·½Ðοò¡£( (1) 0£¬(2) ?0£¬(3) 0£¬(4) 0 )

4.8 For incompressible fluid, determine if there exist stream functions in the following flow fields, where K is a constant.

¶ÔÓÚ²»¿ÉѹËõÁ÷Ì壬ÊÔÈ·¶¨ÏÂÁÐÁ÷³¡ÊÇ·ñ´æÔÚÁ÷º¯Êý£¿Ê½ÖÐKΪ³£Êý¡£ (1) vx=Ksin(xy)£¬vy=-K sin(xy)

(2) vx=Kln(xy)£¬vy=-Ky/x ( (1) ²»´æÔÚ£¬(2) ´æÔÚ)

4.9 Demonstrate the following planar flow of an incompressible fluid

?satisfies continuity equation, and is a potential flow, then find the potential function. ÊÔÖ¤Ã÷ÒÔϲ»¿ÉѹËõÁ÷ÌåÆ½ÃæÁ÷¶¯

v

Âú×ãÁ¬ÐøÐÔ·½³Ì£¬ÊÇÓÐÊÆÁ÷¶¯£¬²¢ÇóÊÆº¯Êý¡£( ?=x2/2+x2y?y2/2?y3/3)

4.10 A velocity field is given by vx=x2y+y2£¬vy=x2?xy2£¬vz=0£¬questions£º (1) If there exist stream function and potential function?

(2) Find the expressions of stream function and potential function if they exist. ¸ø¶¨Ëٶȳ¡vx=x2y+y2£¬vy=x2?xy2£¬vz=0£¬ÎÊ£º (1) ÊÇ·ñ´æÔÚÁ÷º¯ÊýºÍÊÆº¯Êý£¿ (2) Èç¹û´æÔÚ£¬ÇóÆä¾ßÌå±í´ïʽ¡£

((1)´æÔÚÁ÷º¯Êý£¬²»´æÔÚÊÆº¯Êý£»(2) ?=x2y2/2+y2/3?x2/3) 4.11 The velocity potential in a certain flow filed is ?=4xy

Determine the corresponding stream function. ijÁ÷³¡µÄËÙ¶ÈÊÆÎª

?=4xy ÇóÏàÓ¦µÄÁ÷º¯Êý¡£( ?=2x2?2y2)

4.12 The velocity potential for an incompressible, planar flow is ?=x2?y2+x Find its stream function.

²»¿ÉѹËõÁ÷ÌåÆ½ÃæÁ÷¶¯µÄÊÆº¯ÊýΪ ?=x2?y2+x ÊÔÇóÁ÷º¯Êý¡£( ?=2xy+y) 4.13 The stream function for an incompressible, planar flow is

?=xy+2x?3y

Find the potential function.

²»¿ÉѹËõÁ÷ÌåÆ½ÃæÁ÷¶¯µÄÁ÷º¯ÊýΪ ?=xy+2x?3y ÊÔÇóÊÆº¯Êý¡£( ?=(x2?y2)/2?3x?2y)

4.14 Demonstrate the following two flow fields are identical:

(1) the potential function is ?=x2+x ?y2 (2) the stream function is ?=2xy+y Ö¤Ã÷ÏÂÁÐÁ½¸öÁ÷³¡ÊÇÏàͬµÄ¡£ (1) ÊÆº¯Êý ?=x2+x ?y2 (2) Á÷º¯Êý ?=2xy+y

4.15

Given the velocity distribution of a flow field as

vx=Ax+By

vy=Cx+Dy

If the flow is incompressible and irrotational, find

vx(1) What relationship should coefficients A¡¢B¡¢C¡¢D satisfy? (2) The stream function of the flow field. ÒÑÖªÁ÷³¡µÄËÙ¶È·Ö²¼Îª

vx=Ax+By vy=Cx+Dy ÈôÁ÷Ìå²»¿ÉѹËõ£¬ÇÒÁ÷¶¯ÎÞÐý£¬ÊÔÎÊ

(1) ϵÊýA¡¢B¡¢C¡¢DÓ¦Âú×ãÔõÑùµÄ¹ØÏµ£¿ (2) ÇóÁ÷³¡µÄÁ÷º¯Êý¡£

( (1) A=?D£¬B=C£»(2) ?=B(y2?x2)/2+Axy )

4.16 There is a fixed point vortex of circulation ? and distance a to a stationary wall. Find the velocity potential function of the flow and pressure distribution on the wall.

ÓÐÒ»»·Á¿Îª?µÄ¹Ì¶¨µãÎУ¬ÀëÒ»¾²Ö¹±ÚÃæµÄ¾àÀëΪa¡£ÊÔÇóÁ÷¶¯µÄËÙ¶ÈÊÆºÍ ±ÚÃæÉϵÄѹǿ·Ö²¼¡£ (

£¬

)

4.17 Given the velocity of an incompressible planar potential flow as vx=3ax2?3ay2, vx=vy=0 at point (0£¬0), find the volume flowrate passing the connecting line of points (0£¬0) and (0£¬1).

ÒÑÖª²»¿ÉѹËõÆ½ÃæÊÆÁ÷µÄËÙ¶È·Ö²¼Îª vx=3ax2-3ay2£¬ÔÚ(0£¬0)µãÉÏvx=vy=0£¬ÊÔÇóͨ¹ý(0£¬0)¡¢ (0£¬1)Á½µãÁ¬ÏßµÄÌå»ýÁ÷Á¿¡£( qv=a )

4.18 A two-dimensional flow field is formed by adding a source at the origin of the coordinate system to the velocity potential ?=r2cos2?

Locate any stagnation points in the upper half of the coordinate plane. (0????) Ò»¶þάÁ÷³¡ÊÇÔÚËÙ¶ÈÊÆ?=r2cos2?ÉÏÓÚ×ø±êÔ­µã´¦µþ¼ÓÒ»µãÔ´¶øÐγɡ£ÊÔÔÚ×ø

0.5

±êÆ½ÃæÉϰ벿ȷ¶¨ÈÎһפµãµÄλÖá£( ?s=?/2£¬rs=(m/4?))

4.19 The stream function for a two-dimensional, incompressible flow field is given by the equation

?=2x-2y

where the stream function has the units of m2/s with x and y in meter.

(1) Sketch the stream function for this flow field, indicate the direction of flow along the streamlines;

(2) Is this an irrotational flow field?

(3) Determine the acceleration of a fluid particle at the point x=1m and y=2m. ¶þά²»¿ÉѹÁ÷³¡µÄÁ÷º¯ÊýΪ

?=2x-2y ʽÖÐx¡¢yµÄµ¥Î»Îªm£¬Á÷º¯Êýµ¥Î»Îªm2/s¡£

(1) ×ö³öÁ÷Ïß·Ö²¼Í¼£¬±êÃ÷Á÷Ïß·½Ïò£»

(2) Á÷¶¯ÊÇ·ñÎÞÐý£¿

(3) È·¶¨µã(1,2)´¦Á÷ÌåÖʵãµÄ¼ÓËÙ¶È¡£ ( (1) ?=2x?2y£¬(2) ÎÞÐý£¬(3) a=0)

4.20 The stream function for the flow of a nonviscous, incompressible fluid in the vicinity of a corner (see Fig. 4-27) is

?=2r4/3sin(4?/3). Determine an expression for the pressure gradient along the boundary ?=3?/4.

Ò»ÎÞÕ³²»¿ÉѹÁ÷ÌåÔÚÈçͼ4-27ËùʾµÄת½Ç¸½½üÁ÷¶¯µÄÁ÷º¯ÊýΪ?=2r4/3sin(4?/3)£¬

ÊÔÈ·¶¨Ñر߽ç?=3?/4µÄѹǿÌݶȱí´ïʽ¡£ Fig. 4-27 Problem 4.20

(

)

4.21 Two sources are located at points (1£¬0) and (-1£¬0)£¬their source strength are all 4?£¬find the velocity at points (0£¬0)¡¢ (0£¬1)¡¢ (0£¬-1)¡¢(1£¬1).

λÓÚ(1£¬0)ºÍ(-1£¬0)Ö®Á½¸öµãÔ´£¬ÆäÔ´Ç¿¶È¾ùΪ4?£¬ÊÔÇóÔÚ(0£¬0)¡¢ (0£¬1)¡¢

(0£¬-1)¡¢(1£¬1)´¦µÄËÙ¶È¡£

( vx=vy=0£»vx=0£¬vy=2£»vx=0£¬vy=?2£»vx=4/5£¬vy=12/5)

4.22 A source with strength 20m2/s is located at point (-1£¬0)£¬another source with strength 40m2/s is located at point (2£¬0). Given the pressure at the coordinate base point of the overlapped flow field is 100Pa£¬the fluid density is 1.8kg/m3£¬find the velocity and pressure at point (0£¬1) and (1£¬1).

Ç¿¶ÈΪ20m2/sµÄµãԴλÓÚ(-1£¬0)£¬Ç¿¶ÈΪ40m2/sµÄµãԴλÓÚ(2£¬0)£¬ÒÑÖªµþ¼ÓÁ÷³¡ÔÚ×ø±êÔ­µã´¦µÄѹǿΪ100Pa£¬Á÷ÌåµÄÃܶÈΪ1.8kg/m3£¬ÇóÔÚµã(0£¬1)ºÍµã(1£¬1)´¦µÄËÙ¶ÈÓëѹǿ¡£

(

?p)

Problems

5.1 A 1:25 scale model of an airship is tested in water at 200C. If the airship travels 5m/s in air at atmospheric pressure and 200C, find the velocity for the model to achieve dynamic similitude. Also, find the ratio of the drag force on the prototype to that on the model. The densities of water and air at these conditions are 1000kg/m3 and 1.2kg/m3 respectively. The corresponding dynamic viscosities of water and air are 10-3N?s/m2 and 1.81?10-5 N?s/m2¡£

Ò»±È³ßΪ1:25µÄ·ÉͧģÐÍÔÚ200CµÄË®ÖÐʵÑé¡£Èç¹û·ÉͧÊÇÔÚ200C¡¢´óÆøÑ¹Á¦ÏÂµÄ¿ÕÆøÖÐÒÔ5m/sµÄËÙ¶È·ÉÐУ¬ÎªÁË´ïµ½¶¯Á¦ÏàËÆ£¬ÇóÄ£Ð͵ÄËÙ¶È¡£²¢ÇóÔ­ÐÍÓëÄ£Ð͵Ä×èÁ¦Ö®±È¡£ÒÑÖªÔÚʵÑéÌõ¼þÏÂË®Óë¿ÕÆøµÄÃܶȷֱðΪ1000kg/m3 ¼° 1.2kg/m3£¬ÏàÓ¦µÄ¶¯Á¦Õ³¶ÈΪ10-3N?s/m2 Óë 1.81?10-5 N?s/m2¡£(8.29m/s£¬0.273)

5.2 A scale model of a pumping system is to be tested to determined the head losses in the actual system. Air with a specific weight of 0.085kg/m3 and a viscosity of 3.74?10-7 m2/s is used in the model. Another fluid with a specific weight of 62.4kg/m3 and a viscosity of 2.36?10-5m2/s is used in the prototype. The velocity in the prototype is 2m/s. A practical upper limit for the air velocity in the model to avoid compressibility effects is 100m/s. Find the scale ratio for the model and the ratio of the pressure losses in the prototype to those in the model.

¶ÔÒ»³éËÍϵͳµÄËõСģÐͽøÐÐʵÑéÒÔÈ·¶¨Ô­Ð͵ÄˮͷËðʧ¡£Ô­ÐÍËùʹÓÃµÄ¿ÕÆøÖضÈΪ0.085kg/m3 ¡¢Õ³¶ÈΪ3.74?10-7 m2/s¡£ÁíÒ»ÖÖÖØ¶ÈΪ62.4kg/m3¡¢Õ³¶ÈΪ2.36?10-5m2/sµÄÁ÷ÌåÓÃÓÚÔ­ÐÍʵÑé¡£Ô­ÐÍËÙ¶ÈΪ2m/s¡£ÎªÁ˱ÜÃâѹËõÐÔЧӦ£¬Ä£ÐÍÖÐ¿ÕÆøÁ÷ËÙµÄʵ¼ÊÉÏÏÞΪ100m/s¡£ÇóÄ£Ð͵ıȳßÓëÔ­Ðͼ°Ä£ÐÍÖÐѹǿËðʧ±È³ß¡£(0.294)

5.3 To study the flow of a spillway with a model of the length scale ratio kl=1:20. It is known that Fr of the prototype and model are equal, flowrate of the model is measured as 0.19m3/s. Find the flowrate of the prototype.

ÓÃÄ£ÐÍÑо¿ÒçÁ÷µÀµÄÁ÷¶¯£¬²ÉÓõij¤¶È±ÈÀýϵÊýkl=1:20£¬ÒÑÖªÔ­ÐÍÓëÄ£Ð͵Ä

3

FrÏàµÈ£¬²âµÃÄ£ÐÍÉϵÄÁ÷Á¿Îª0.19m/s¡£ÇóÔ­ÐÍÉϵÄÁ÷Á¿¡£(339m3/s)

5.4 The kinematic viscosity of a fluid in the prototype is ?=15?10-5m2/s, the length scale ratio of the model is 1:5, if let Fr and Eu be the decisive similitude numbers, what is the kinematic viscosity of the fluid in the model ?

Ô­ÐÍÖÐÁ÷ÌåµÄÔ˶¯Õ³¶È?=15?10-5m2/s£¬Ä£Ð͵ij¤¶È±ÈÀýϵÊýΪ1:5£¬ÈçÒÔFrºÍEu×÷Ϊ¾ö¶¨ÐÔµÄÏàËÆ×¼Êý£¬Ä£ÐÍÁ÷ÌåµÄÔ˶¯Õ³¶È?mӦΪ¶àÉÙ£¿(1.34?10-5m2/s)

5.5 The sloshing of oil in a tank is affected by both viscous and gravitational effects. A 1:4 scale model of oil with a kinematic viscosity of 1.1?10-4 m2/s is to be used to study the sloshing. Find the kinematic viscosity of the liquid to be used in the model.

ÓÍÔÚÈÝÆ÷ÖеĻε´Êܵ½Õ³ÐÔÓëÖØÁ¦µÄÓ°Ïì¡£ÓÃÒ»±È³ßΪ1:4µÄÄ£ÐÍÀ´Ñо¿Ô˶¯Õ³¶ÈΪ1.1?10-4 m2/sµÄÓ͵Ļε´¡£ÇóÄ£ÐÍÖÐÒºÌåµÄÔ˶¯Õ³¶È¡£(1.37?10-5m2/s)

5.6 A wind-tunnel test is performed on a 1: 20 scale model of a supersonic aircraft. The prototype aircraft flies at 480m/s in conditions where the speed of sound is 300m/s and the air density is 1.0kg/m3. The model aircraft is tested in a wind-tunnel in which the speed of sound is 279m/s and the air density is 0.43kg/m3. The drag force on the model is 100N. What speed must the flow in the wind-tunnel be for dynamic similitude, and what is the drag force on the prototype?

¶ÔÒ»±È³ßΪ1:20µÄ³¬ÒôËÙ·É»úÄ£ÐͽøÐз綴ʵÑé¡£Ô­ÐÍ·É»úÔÚÒôËÙΪ300m/s¡¢ÃܶÈΪ1.0kg/m3µÄ¿ÕÆøÖÐÒÔ480m/sµÄËÙ¶È·ÉÐС£Ä£ÐÍ·É»úÔÚÒôËÙΪ279m/s¡¢ÃܶÈΪ0.43kg/m3µÄ¿ÕÆøÖнøÐз綴ʵÑé¡£²âµÃÄ£Ð͵Ä×èÁ¦Î»100N¡£Îª´ïµ½¶¯Á¦ÏàËÆ£¬·ç¶´µÄÁ÷ËÙӦΪ¶àÉÙ£¿Ô­ÐÍÉϵÄ×èÁ¦ÊǶàÉÙ£¿(446m/s£¬108kN)

5.7 A ventilation pipe of diameter 1m and average flowing velocity 10m/s. Model test is performed on a water pipe of diameter 0.1m, what is the velocity in the water pipe to achieve dynamic similitude? Suppose the pressure and temperature of air and water are all 101kPa and 200C.

Ö±¾¶Îª1mµÄ¿ÕÆø¹ÜµÀ£¬Æ½¾ùÁ÷ËÙΪ10m/s£¬ÏÖÓÃÖ±¾¶Îª0.1mµÄË®¹Ü½øÐÐÄ£

200C¡£ ÐÍʵÑ飬ΪÁ˶¯Á¦ÏàËÆ£¬Ë®¹ÜÖеÄÁ÷ËÙӦΪ¶à´ó£¿Éè¿ÕÆøºÍË®¾ùΪ101kPa¡¢

(6.73 m/s)

5.8 In order to predict the drag on a smooth, streamlined object flying in air, a model is designed to test in water. It is known that the length of the prototype is 3m, flies in air at a speed of 10 m/s. The designing length of the model is 50cm, what is the velocity of water? If the drag on model is measured as 15N, what is the drag on the prototype? Suppose the pressure and temperature of the prototype and model are all 101kPa and 200C.

ΪÁËÔ¤²âÒ»¹â»¬Á÷ÏßÐÍÎïÌåÔÚ¿ÕÆøÖеķÉÐÐ×èÁ¦£¬Éè¼ÆÒ»Ä£ÐÍÔÚË®ÖÐʵÑé¡£ÒÑÖªÔ­Ð͵ij¤¶ÈΪ3m£¬ÒÔ10 m/sµÄËÙ¶ÈÔÚ¿ÕÆøÖзÉÐС£Ä£Ð͵ij¤¶ÈÉè¼ÆÎª50cm£¬Ë®Á÷µÄËÙ¶ÈӦΪ¶àÉÙ£¿Èô²âµÃÄ£ÐÍÊܵ½µÄ×èÁ¦Îª15N£¬Ô­ÐÍÊܵ½µÄ×èÁ¦½«ÊǶàÉÙ£¿ÉèÔ­ÐÍ¡¢Ä£Ð;ù´¦ÓÚ101kPa¡¢200C¡£(4 m/s£¬4.05N)

5.9 The height of an automobile is 1.5m, travels in air 200C at a speed of 108km/h. Air in model test is 00C and its flowing velocity is 60m/s. Find the height of the model. If the front resistance in model test is measured as 1300N, what is the front resistance on the prototype automobile when running ?

Æû³µ¸ß¶ÈΪ1.5m£¬ËÙ¶ÈΪ108km/h£¬ ÐÐÊ»ÔÚ200CµÄ¿ÕÆøÖУ¬Ä£ÐÍʵÑéµÄ¿ÕÆøÎª00C£¬ÆøÁ÷ËÙ¶ÈΪ60m/s¡£ÇóÄ£ÐÍÊÔÑéÆû³µµÄ¸ß¶È¡£Èç¹ûÔÚÄ£ÐÍʵÑéÖвâµÃÕýÃæ×èÁ¦Î»1300N£¬ÇóʵÎïÆû³µÐÐʻʱµÄÕýÃæ×èÁ¦ÊǶàÉÙ¡£(0.654m£¬1586N)

5.10 The surface tension of pure water is 0.073N/m, and the surface tension of soapy water is 0.025N/m. If a pure water droplet breaks up in an airstream that is moving at 10m/s, at what speed would the same size soapy water droplet break up? ´¿¾»Ë®µÄ±íÃæÕÅÁ¦Îª0.073N/m£¬·ÊÔíË®µÄ±íÃæÕÅÁ¦Îª0.025N/m¡£Èç¹û´¿¾»Ë®µÎÔÚ10m/sµÄÆøÁ÷ÖÐÆÆÁÑ£¬ÎʳߴçÏàͬµÄ·ÊÔíË®µÎµÄÆÆÁÑÆøÁ÷ËÙ¶ÈΪ¶àÉÙ£¿ (5.85 m/s)

5.11 A 1:49 scale model of a ship is tested in a water tank. The speed of the prototype is 10m/s. The purpose of the test is to measure the wave drag on the ship. Find the velocity of the model and the ratio of the wave drag on the prototype to that on the model.

Ò»±È³ßΪµÄ´¬Ä£ÔÚË®³ØÖÐʵÑé¡£Ô­ÐÍÖеÄËÙ¶ÈΪ10m/s¡£ÊµÑéµÄÄ¿µÄÊDzⶨ×÷ÓÃÔÚ´¬ÉϵIJ¨ÀË×èÁ¦¡£ÇóÄ£Ð͵ÄËÙ¶È£¬¼°Ô­ÐÍÓëÄ£Ð͵IJ¨ÀË×èÁ¦±ÈÖµ¡£ (1.43 m/s£¬1.18?105)

5.12 A Venturi tube with diameter D1=300mm and d1=150mm is used to measure the flowrate of oil of kinematic viscosity ?1=4.5?10-6m2/s and density ?1=820kg/m3. The flowrate Q1 is 100L/s. Use water of kinematic viscosity ?2=1?10-6m2/s and a 1:3 model to perform the test.

(1) What must the water flow rate Q2 be for dynamic similarity?

(2) If the head loss hf2 is measured at 0.2m and the pressure difference ?p2 at 1.0 bar in the model test, find the real head loss and pressure difference of the prototype. Ò»Ö±¾¶ÎªD1=300mm ¼° d1=150mmµÄÎÄÇðÀï¹ÜÓÃÓÚ²âÁ¿Ô˶¯Õ³¶ÈΪ?1=4.5?10-6m2/s¡¢ÃܶÈΪ?1=820kg/m3µÄÓ͵ÄÁ÷Á¿¡£Á÷Á¿Q1 Ϊ100L/s¡£ÓÃÔ˶¯Õ³¶ÈΪ?2=1?10-6m2/sµÄË®¡¢±È³ßΪ1:3µÄÄ£ÐͽøÐÐʵÑé¡£

(1) ΪÁË´ïµ½¶¯Á¦ÏàËÆ£¬Ë®µÄÁ÷Á¿Q2Ϊ¶àÉÙ£¿

(2) Èç¹ûÄ£ÐÍʵÑé²âµÃˮͷËðʧhf2Ϊ0.2m¡¢Ñ¹²î?p2Ϊ1.0 bar£¬ÇóÔ­Ð͵ÄË® Í·ËðʧÓëѹ²îΪ¶àÉÙ¡£?

5.13 The flowrate qv of a fluid passing through a horizontal capillary pipe has relationship with the diameter d, dynamic viscosity ? and pressure gradient ?p/l, derive the expression of the flowrate.

Á÷Ìåͨ¹ýˮƽëϸ¹ÜµÄÁ÷Á¿qvÓë¹Ü¾¶d¡¢¶¯Á¦Õ³¶È?¡¢Ñ¹Ç¿ÌݶÈ?p/lÓйأ¬ÊÔµ¼³öÁ÷Á¿µÄ±í´ïʽ¡£(

)

5.14 A small ball travels at a constant velocity in an incompressible viscous fluid, the drag is related with the diameter of the ball, velocity v, the density ? of the fluid, and the dynamic viscosity ?. Find the expression of the drag.

СÇòÔÚ²»¿ÉѹËõÕ³ÐÔÁ÷ÌåÖеÈËÙÔ˶¯Ê±£¬×èÁ¦FDÓëСÇòµÄÖ±¾¶d¡¢Ô˶¯ËÙ¶Èv¡¢( Á÷ÌåÃܶÈ?¡¢¶¯Á¦Õ³¶È?Óйأ¬ÊÔÍÆµ¼³ö×èÁ¦µÄ±í´ïʽ¡£

)

5.15 The outlet velocity v of an orifice is related with the orifice diameter d, fluid density ?, dynamic viscosity ? and hydrostatic head ?p, derive the expression of the outlet velocity.

Éè¿×¿Ú³öÁ÷µÄËÙ¶ÈvÓë¿×¿ÚÖ±¾¶d¡¢Á÷ÌåÃܶÈ?¡¢¶¯Á¦Õ³¶È?ÒÔ¼°¾²Ñ¹Í·?pÓйأ¬µ¼³öÁ÷Ëٵıí´ïʽ¡£(

)

5.16 The velocity of a sphere depends on the sphere diameter, sphere density, fluid density, fluid viscosity, and gravitational acceleration£º

Find a nondimensional form for the velocity.

Ò»ÇòÌåµÄËÙ¶ÈÓëÇòÌåµÄÖ±¾¶¡¢ÇòÌåµÄÃܶȡ¢Á÷ÌåµÄÃܶȡ¢Á÷ÌåµÄÕ³¶È¼°ÖØÁ¦¼ÓËÙ¶ÈÓйأº ÊÔµ¼³öËٶȵÄÎÞÁ¿¸Ù±í´ïʽ¡£(

5.17 The pressure drop in a smooth horizontal pipe in a turbulent, incompressible flow depends on the pipe diameter, pipe length, fluid velocity, fluid density, and dynamic viscosity:

Find a nondimensional relationship for the pressure drop.

һˮƽ·ÅÖù⻬¹ÜµÀÄÚ²»¿ÉѹËõÁ÷ÌåµÄÍÄÁ÷ѹ½µÓë¹ÜµÀÖ±¾¶¡¢¹Ü³¤¡¢Á÷ÌåËÙ¶È¡¢Á÷ÌåÃܶȼ°¶¯Á¦Õ³¶ÈÓйأº Çóѹ½µµÄÎÞÁ¿¸Ù¹ØÏµÊ½¡£(

5.18 A small ball is dropped into a large tube containing an incompressible, viscous liquid. Experimental results show that the resistance force FD acted on the ball is related to the diameter D, velocity of the ball v, the fluid density ?, and viscosity ? of the fluid. Derive an expression for the resistance force FD.

һСÇòµôÈëÊ¢Óв»¿ÉѹËõµÄÕ³ÐÔÒºÌåµÄ´ó¹ÜµÀÖС£ÊµÑé½á¹û±íÃ÷£¬×÷ÓÃÔÚСÇòÉϵÄ×èÁ¦FDÓëСÇòµÄÖ±¾¶D¡¢ËÙ¶Èv¡¢Á÷ÌåµÄÃܶÈ?¼°Õ³¶È?Óйء£µ¼³ö×èÁ¦FDµÄ±í´ïʽ¡£(FD=k?D2v2f(Re))

5.19 Experimental results show that the flowrate qv across an orifice meter is related to the pressure difference ?p between the upstream and downstream sides of the orifice, diameter D of the pipe, viscosity ? and density ? of the fluid. Using the Buckingham ? theorem to derive an expression for the flowrate q.

ʵÑé½á¹û±íÃ÷£¬¿×¿ÚÁ÷Á¿¼ÆµÄÁ÷Á¿qvÓë¿×¿ÚÉÏÏÂÓεÄѹ²î?p¡¢¹ÜµÀÖ±¾¶D¡¢Á÷ÌåµÄÕ³¶È?¼°ÃܶÈ?Óйء£ÊÔÓÃÅÁ½ðºº?¶¨Àíµ¼³öÁ÷Á¿qvµÄ±í´ïʽ¡£ (qv?kD?f(D2?p??2))

vt?tp)

)

Problems

6.1 A fluid flows in round pipe of diameter d=15mm at velocity v£½14m/s, determine the flow regime. In order to ensure that the flow is laminar flow, what is the maximum allowed velocity in the pipe for fluid of (1) lubricant ?£½l.0?10-4m2 /s; (2) water ?£½l.0?10-6m2 /s, and (3) air ?£½l.5?10-5m2 /s?

Á÷ÌåÒÔv£½14m/s µÄÁ÷ËÙÔÚÖ±¾¶ d£½15mmµÄÔ²¹ÜÖÐÁ÷¶¯£¬ÊÔÈ·¶¨Á÷¶¯×´Ì¬¡£

(1) Èó»¬ÓÍ?£½l.0?10-4m2 /s£¬(2) Ë®?£½l.0?10-6m2 ÈôÒª±£Ö¤Á÷̬Ϊ²ãÁ÷£¬¶ÔÓÚÁ÷Ì壺

/s£¬(3) ¿ÕÆø?£½l.5?10-5m2 /s£¬ËüÃÇÔڹܵÀÖеÄ×î´óÔÊÐíËٶȸ÷Ϊ¶àÉÙ£¿ ((1) ²ãÁ÷£¬15.47m/s (2) ÍÄÁ÷£¬0.155m/s (3) ÍÄÁ÷£¬2.32m/s)

6.2 Oil of density ?=740kg/m3 and dynamic viscosity ?£½4.03?10-3Pa?s flows in a horizontal round pipe of diameter d=2.54cm at an average velocity of v=0.3m/s. Calculate the pressure drop of oil along pipe of length l£½30m, and the oil velocity at place with distance of 0.6cm to pipe wall.

ÃܶÈ?=740kg/m3£¬¶¯Á¦Õ³¶È ?£½4.03?10-3Pa?sµÄÓÍÒºÒÔÆ½¾ùÁ÷ËÙv=0.3m/sÁ÷¹ýÖ±¾¶ d=2.54cmµÄˮƽ·ÅÖõÄÔ²¹Ü¡£ÊÔ¼ÆËãÓÍÒºÔÚl£½30m³¤µÄ¹ÜµÀÉϵÄѹǿ½µ£¬²¢¼ÆËã¾àÔ²¹ÜÄÚ±Ú0.6cm´¦ÓÍÒºµÄÁ÷ËÙ¡£(1799Pa 0.433m/s)

6.3 The diameter and length of oil transporting pipe are d£½15cm, l£½5000m respectively, its outlet is h£½10m higher that inlet, oil transporting flowrate is qm£½15489kg/h, oil density is ?=859.4kg/m3, oil pressure at the inlet is pi£½49?104Pa, friction loss factor is ?=0.03, find the pressure pe at the outlet.

ÊäÓ͹ܵÄÖ±¾¶d£½15cm£¬³¤l£½5000m£¬³ö¿Ú¶Ë±ÈÈë¿Ú¶Ë¸ßh£½10m£¬ÊäËÍÓ͵ÄÁ÷Á¿ qm£½15489kg/h£¬Ó͵ÄÃܶÈ?=859.4kg/m3£¬Èë¿Ú¶ËµÄÓÍѹpi£½49?104Pa£¬ÑسÌËðʧϵÊý?=0.03£¬Çó³ö¿Ú¶ËÓÍѹpe¡£(pe=3.712?105Pa)

6.4 A fluid flows through two horizontal pipes of equal length which are connected together to form a pipe of length 2l, as shown in Fig.6-30. The flow in pipes is laminar and fully developed. The pressure drop for the first pipe is 1.44 times greater than it is for the second. If the diameter of the first pipe is D, determine the diameter of the second pipe.

Á÷ÌåÁ÷¹ýÁ½¸ùÏ໥Á¬½Óˮƽ·ÅÖõij¤¶È½ÔΪlµÄ¹ÜµÀ£¬Èçͼ6-30Ëùʾ¡£¹ÜÄÚÁ÷¶¯Îª³ä·Ö·¢Õ¹

µÄ²ãÁ÷¡£µÚÒ»¸ù¹ÜÉϵÄѹ½µÊǵڶþ¸ùµÄ1.44±¶¡£ Fig.6-30 Problem 6.4 ÈçµÚÒ»¸ù¹ÜµÄÖ±¾¶ÎªD£¬È·¶¨µÚ¶þ¸ù¹ÜµÄÖ±¾¶¡£

6.5 As shown in Fig. 6-31, water flows from water tank A to storage tank B through a pipe of diameter d£½25mm and length l£½10m. If the gauge pressure of the water tank is p=1.96?105Pa, H1£½lm, H2£½5m, minor loss coefficients at inlet and outlet of the pipe are ?1=0.5 and ?4=1 respectively, for valve ?2£½4, for each elbow ?3£½0.2, friction loss factor is ?£½0.03, find the flowrate of water.

Èçͼ6£­31Ëùʾ£¬Ë®ÑØÖ±¾¶d£½25mm£¬³¤l£½10mµÄ¹ÜµÀ£¬´ÓË®ÏäAÁ÷µ½´¢

Ë®ÏäB¡£ÈôË®ÏäÖеıíѹǿp=1.96?105Pa£¬H1£½lm£¬H2£½5m£¬¹ÜµÀÈë¿ÚºÍ³ö¿ÚµÄ¾Ö²¿ËðʧϵÊý·Ö±ðΪ?1=0.5¡¢?4=1£¬·§Ãžֲ¿ËðʧϵÊý?2£½4£¬Ã¿¸öÍäÍ·µÄ¾Ö²¿ËðʧϵÊý?3£½0.2£¬ÑسÌËðʧϵÊý?£½0.03£¬ÊÔÇóË®µÄÁ÷Á¿¡£

(qv=2.04?10-3m3/s)

6.6 There are 250 identical brass pipes in a vapour condenser are in parallel connection, total flowrate of condensed water through the pipes is 80L/s, water kinetic viscosity of water is ?£½l.3?10-6m2/s, the Reynolds number should not be less than 15000 in order to guarantee flow regime in brass pipe

is turbulent, what is the magnitude that the inner diameter of brass pipe should not exceed? Fig.6-31 Problem 6.5

Ò»ÕôÆûÀäÄýÆ÷£¬ÄÚÓÐ250¸ùÍêÈ«Ïàͬ µÄ»ÆÍ­¹Ü²¢Áª£¬Í¨¹ý¹ÜÖеÄÀäÈ´Ë®µÄ×ÜÁ÷Á¿Îª80L/s£¬Ë®µÄÕ³¶ÈΪ?£½l.3?10-6m2/s£¬Îª±£Ö¤Ë®ÔÚ»ÆÍ­¹ÜÖеÄÁ÷̬ΪÍÄÁ÷£¬ÒªÇó¹ÜÖеÄÀ×ŵÊý²»µÃСÓÚ15000£¬ÎÊ»ÆÍ­¹ÜµÄÄÚ¾¶²»µÃ³¬¹ý¶àÉÙ£¿(d?0.021m)

6.7 Water flows in pipe of radius r0, the flow regime is laminar flow. Find the distance r to the pipe axis at where the velocity just equals the average velocity.

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2ro ) 2

6.8 A fluid flows through a pipe of radius R with Reynolds number of 100,000. At what location, r/R, does the fluid velocity equal the average velocity?

Á÷ÌåÒÔÀ×ŵÊýµÈÓÚ100,000Á÷¹ý°ë¾¶ÎªRµÄ¹ÜµÀ¡£ÎÊÔںδ¦r/RÁ÷ÌåµÄÁ÷ËٸպõÈÓÚÆ½¾ùÁ÷ËÙ£¿

6.9 A water pipe of diameter d£½25cm, length l£½300m, and absolute roughness ?£½0.25mm. If given the flowrate qv£½95l/s, kinetic viscosity ?£½l.0?10-6m2/s, what is the friction loss?

Ë®¹ÜÖ±¾¶d£½25cm£¬³¤l£½300m£¬¾ø¶Ô´Ö²Ú¶È?£½0.25mm£¬ÒÑÖªÁ÷Á¿qv£½95l/s£¬

-62

Ô˶¯Õ³¶È ?£½l.0?10m /s£¬ÇóÑØ³ÌËðʧΪ¶àÉÙ£¿(4.61mË®Öù)

6.10 Water at 800C flows through a 120mm diameter pipe with an average velocity of 2m/s. If the pipe wall roughness is small enough so that it does not protrude through the laminar sublayer, the pipe can be considered as smooth. Approximately what is the largest roughness allowed to classify this pipe as smooth?

800CµÄË®ÒÔ2m/sµÄƽ¾ùÁ÷ËÙÁ÷¹ýÖ±¾¶Îª120mmµÄ¹ÜµÀ¡£Èç¹û¹Ü±ÚµÄ´Ö²Ú¶È

ºÜС£¬Ã»ÓÐÑÓÉìµ½²ãÁ÷µ×²ã£¬¿ÉÈÏΪ¹ÜµÀÊǹ⻬¹Ü¡£ÎʹܵÀÊǹ⻬¹ÜµÄ¿ÉÈÝÐíµÄ×î´ó´Ö²Ú¶È´óԼΪ¶àÉÙ£¿

6.11 As shown in Fig.6-32, neglect minor loss, to ensure fluid flowrate in the siphon is qv£½10-3m3/s, determine: (1) when H=2m, l=44m, ?£½l.0?10-4m2 /s, ?=900kg/m3, what is d for ensuring laminar flow? (2) if the limitation vacuum on section A with a distance l/2 to the pipe inlet is pv=52 920Pa, what is the maximum allowed height Zmax of the siphon above the surface of upper oil storage pool?

Èçͼ6-32Ëùʾ£¬²»¼Æ¾Ö²¿Ëðʧ£¬Òª±£Ö¤ºçÎü¹ÜÖÐÒºÌåµÄÁ÷Á¿Îªqv£½10-3m3/s£¬ÊÔÈ·¶¨£º(1) µ±H=2m£¬l=44m£¬?£½l.0?10-4m2 /s£¬?=900kg/m3ʱ£¬Îª±£Ö¤²ãÁ÷£¬dӦΪ¶àÉÙ£¿(2)ÈôÔÚ¾à¹Ü½ø¿Úl/2´¦µÄA¶ÏÃæÉϵļ«ÏÞÕæ¿ÕΪpv=52 920Pa£¬ºçÎü¹ÜÔÚÉÏÃæÖüÓͳØÓÍÃæÒÔÉϵÄ×î´óÔÊÐí¸ß¶È

ZmaxΪ¶àÉÙ£¿ Fig. 6-32 Problem 6.11

((1) 0.055m (2) 4.97m)

6.12 Water flows in a smooth plastic pipe of 200mm diameter at a flow rate of 0.1m3/s. Determine the friction factor ? for this flow.

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6.13 Water flows from a tank along a vertical pipe of l£½2m and diameter d£½4m into atmosphere, as shown in Fig. 6-?. Neglect minor loss, friction loss factor is ?=0.04, find: (1) the relationship between the pressure at pipe¡¯s initial section area A and the water level h in the tank, and the magnitude of h when the absolute pressure at A equals atmospheric pressure; (2) the relationship of the flowrate qv and the pipe length l, and the relationship that water level h satisfies when it does not change with l.

Ë®´ÓË®ÏäÑØ×Ÿßl£½2m£¬Ö±¾¶d£½4mµÄÊúÖ±¹ÜµÀÁ÷Èë´óÆø£¬ÈçͼËùʾ¡£²»¼Æ¾Ö²¿Ëðʧ£¬²¢ÇÒÑØ³ÌËðʧϵÊý

?=0.04£¬ÊÔÇó£º(1)¹ÜµÀÆðʼ¶ÏÃæAµÄѹǿÓëÏäÄÚˮλhÖ®¼äµÄ¹ØÏµÊ½£¬²¢Çóµ±hΪ¶àÉÙʱ£¬A´¦µÄ¾ø¶ÔѹǿµÈ Fig.6-33 Problem 6.13 ÓÚ´óÆøÑ¹Ç¿£»(2)Á÷Á¿qvÓë¹Ü³¤lµÄ¹ØÏµ£¬²¢Çó³öÔÚˮλ hÂú×ãʲô¹ØÏµÊ±£¬½«²»Ëæl¶ø±ä»¯£¿

((1) pA?pa??g(?h?d)/(??d/l) h=1m (2) qv?h?d?4d22gd(h?l)

d??l? )

6.14 Air flows through the fine mesh gauze shown in Fig. 6-34 with an average velocity of 1.5m/s in the pipe. Determine the loss coefficient for the gauze.

¿ÕÆøÔڹܵÀÖÐÒÔ1.5m/sµÄƽ¾ùÁ÷ËÙͨ¹ýÈçͼ6-34ËùʾµÄϸɴ²¼¡£ÊÔÈ·¶¨É´²¼µÄËðʧϵÊý¡£(56.7)

Fig.6-34 Problem 6.14

6.15 As shown in Fig.6-35, the heating furnace consumes heavy oil at a rate of qm=300kg/h, density and kinetic viscosity of oil are ?=880kg/m3 and ?£½25?10-6m2/s respectively, the pressurized oil tank is h£½8m above the sprayer¡¯s axis, oil transporting pipe¡¯s diameter is d£½25mm and length is l=30m. Find the gauge

pressure of heavy oil in front of the oil sprayer.

Èçͼ6-35Ëùʾ£¬¼ÓÈȯÏûºÄqm=300kg/hµÄÖØÓÍ£¬ÖØÓ͵ÄÃܶÈ?=880kg/m3£¬Ô˶¯Õ³¶È?£½25?10-6m2/s£¬Ñ¹Á¦ÓÍÏäλÓÚÅçÓÍÆ÷ÖáÏßÒÔÉÏh£½8m´¦£¬¶øÊäÓ͹ܵÄÖ±¾¶d£½25mm£¬³¤l=30m¡£Çó

ÔÚÅçÓÍÆ÷Ç°ÖØÓ͵ıíѹǿ¡£( 62504Pa) Fig.6-35 Problem 6.15

6.16 Determine the pressure drop per 300m length of new 0.2m diameter horizontal cast iron water pipe when the average velocity is 1.7m/s.

È·¶¨Ö±¾¶Îª0.2m¡¢³¤300m¡¢Æ½¾ùÁ÷ËÙΪ1.7m/sµÄˮƽ·ÅÖÃÖýÌúË®¹ÜÉϵÄѹ½µ¡£

6.17 As shown in Fig. 6-36, the lubricant consumption of the engine is qv£½0.4cm3/s, the lubricant is supplied to the lubricant housings via an oil pipe from the pressurized tank, the pipe¡¯s diameter is d£½6mm and length is l£½5m. The density of the lubricant is ?=820kg/m3£¬and kinetic viscosity is ?£½15?10-6m2 /s. If the terminal pressure of the lubricant pipe equals atmospheric pressure, find the elevation h needed by the pressurized lubricant tank.

Èçͼ6-36Ëùʾ£¬·¢¶¯»úÈó»¬Ó͵ÄÓÃÁ¿qv£½0.4cm3/s£¬

ÓÍ´ÓѹÁ¦Ïä¾­Ò»ÊäÓ͹ܹ©¸øµ½È󻬲¿Î»£¬ÊäÓ͹ܵÄÖ±¾¶d£½6mm£¬³¤¶Èl£½5m¡£Ó͵ÄÃܶȲú?=820kg/m3£¬Ô˶¯Õ³¶È?£½15?10-6m2 /s£¬Èç¹ûÊäÓ͹ܵÀÖն˵ÄѹǿµÈÓÚ´óÆø Fig.6-36 Problem 6.17

ѹǿ£¬ÇóѹÁ¦ÓÍÏäËùÐèÒªµÄλÖø߶Èh¡£(0.095m)

6.18 An above ground reservior of diameter 9 m and depth 1.5m is to be filled from a garden hose(smooth interior) of length 30m and diameter 0.2m. If the pressure at the faucet to which the hose is attached remains at 38kPa, how long will it take to fill the pool? Water exits the hose as a free jet 1.8m above the faucet.

Ò»Ö±¾¶Îª9m¡¢Ë®ÉîΪ1.5m¸ßÓÚµØÃæµÄË®³ØÓÉÒ»¸ù³¤30m¡¢Ö±¾¶0.2mµÄÏð½ºÈí¹Ü£¨ÄÚ²¿¹â»¬£©¹àË®¡£Èç¹ûÁ¬½ÓÈí¹ÜµÄÁúͷѹǿ±£³ÖΪ38kPa£¬Çó¹àÂúÓÎÓ¾³ØËùÐèµÄʱ¼äΪ¶àÉÙ£¿Ë®ÔÚ¸ßÓÚÁúÍ·1.8m´¦ÉäÁ÷Á÷³ö¡£(32Сʱ)

6.19 As shown in Fig. 6-37, oil pump transports oil from an open oil pool to the oil tank of gauge pressure p£½0.98 ?105Pa. it is known that oil pump¡¯s flowrate qv£½3.14L/s, and the overall efficiency of the oil pump ?=0.8, oil density ?=800kg/m3£¬kinetic viscosity ?£½1.25cm2/s, oil pipe¡¯s diameter d£½2cm, length l=2m, total minor loss coefficient ??=2, altitude difference of oil surface h£½3m. Find the power P of the oil pump.

Èçͼ6-37Ëùʾ£¬Óͱôӿª¿ÚÓͳØÖн«ÓÍË͵½±íѹǿp£½0.98 ?105PaµÄÓÍÏäÖС£ÒÑÖªÓͱÃÁ÷Á¿qv£½3.14L/s£¬ÓͱÃ×ÜЧÂÊ?=0.8£¬Ó͵ÄÃܶÈ?=800kg/m3£¬Ô˶¯Õ³¶È?£½

1.25cm2/s£¬Ó͹ÜÖ±¾¶d£½2cm£¬³¤¶Èl=2m£¬×ֲܾ¿ËðʧϵÊýΪ??=2£¬ÓÍÃæ¸ß¶È²îh£½3m¡£ÊÔÇóÓͱõŦÂÊP¡£ Fig.6-37 Problem 6.19

(418.9W)

6.20 Water is to flow at a rate of 1.0m3/s through a rough concrete pipe(?=3mm) that connects two ponds. Determine the pipe diameter if the elevation difference between the two ponds is 10m and the pipe length is 1000m. Neglect minor losses.

Èç¹ûÁ½Ë®Ë®ÒÔ1.0m3/sµÄÁ÷Á¿Á÷¹ýÒ»Á¬½ÓÁ½Ë®³ØµÄ´Ö²Ú»ìÄýÍÁ¹Ü(?=3mm)¡£

³ØË®Î»²îΪ10m¡¢¹Ü³¤Îª1000m£¬È·¶¨¹Ü¾¶¡£ºöÂÔ¾Ö²¿Ëðʧ¡£(0.748m)

6.21 Without the pump shown in Fig. 6- 38, it is determined that the flow rate is to small. Determine the power added to the fluid if the pump causes the flowrate to be doubled. Assume the friction factor remains at 0.02 in either case. Èçͼ6-38Ëùʾ£¬Èç¹û²»¼ÓË®±Ã£¬·¢ÏÖ

Á÷Á¿Ì«Ð¡¡£ÒªÊ¹Á÷Á¿·­±¶£¬ÊÔÈ·¶¨Ë®±ÃÊ©¼ÓÔÚÁ÷ÌåÉϵŦÂÊΪ¶àÉÙ¡£ÉèÔÚÁ½ÖÖÇé¿ö Fig.6-38 Problem 6.21 ÏÂÑØ³ÌËðʧϵÊý¾ùΪ0.02¡£(3.7kW)

6.22 Water drains from a pressurized tank through a pipe system as shown in Fig. 6-39. The head of the turbine is equal to 116m. If the entrance effects are negligible, determine the flowrate.

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Fig.6-39 Problem 6.22

6.23 As shown in Fig. 6-40, centrifugal pump transports condensed water with a flowrate of 20m3/h to a boiler, the diameter of pump¡¯s sucking pipe is d£½90cm, total length is l=8m, there is an eblow of bending diameter R£½45mm and an inflow sluice valve of minor loss coefficient ?£½5, friction loss factor is ?£½0.02, according to specification, the inlet pressure of the pump should be 0.4?105Pa, find the maximum installation height of the pump above water surface.

ÀëÐıðÑÄý½áË®ÒÔ20m3/hµÄÁ÷Á¿ÊäË͵½¹øÂ¯ÖУ¬Èçͼ6£­40Ëùʾ£¬Ë®±ÃÎüÈë¹ÜÖ±¾¶d£½90cm£¬×ܳ¤¶Èl=8m£¬¾ßÓÐÒ»¸öÍäÇú°ë¾¶R£½45mmµÄÍäÍ·ºÍÒ»½øË®Õ¤·§£¬½øË®Õ¤·§µÄ¾Ö²¿ËðʧϵÊý?£½5£¬ÑسÌËðʧϵÊý?£½0.02£¬°´¹æ¶¨£¬Ë®±ÃµÄ½ø¿ÚѹǿӦΪ0.4?105Pa£¬

ÊÔÇóË®±ÃÔÚË®ÃæÒÔÉϵÄ×î´ó°²×°¸ß¶Èh¡£(h=5.88m) Fig.6-40 Problem 6.23

6.24 The three tanks shown in Fig. 6-41 are connected by pipes with friction factors of 0.03 for each pipe. Determine the water velocity in each pipe. Neglect minor loss.

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(v1=1.03m/s v2=0.835m/s)

Fig.6-41

Problem 6.24

6.25 Water pump pumps water into two tanks, as shown in Fig.6-42, elevations of the water pool and water tank are H1=2m and H2£½4m respectively, inner diameter of the pipe is d1£½d2=20cm, pipe lengths are l1£½40m, l2=45m, friction factors are ?1=?2=0.02, pump¡¯s head of delivery is Hp=20m, and neglect minor loss. Find: (1) pump¡¯s discharge; (2) when the overall efficiency of the pump is ?=70%, how much is the power which is transmitted to the pump by the motor driving the pump?

Èçͼ6£­42Ëùʾ£¬±Ã½«Ë®³ØÖеÄË®´òÈëÁ½Ë®Ï䣬ˮ³ØÓëË®ÏäË®ÃæµÄ¸ß¶È¸÷ΪH1=2m£¬H2£½4m£¬Ô²¹ÜÄÚ¾¶d1£½d2=20cm£¬¹Ü³¤l1£½40m£¬l2=45m£¬ÑسÌ

ËðʧϵÊý?1=?2=0.02£¬±ÃµÄÑï³ÌHp=20m£¬²»¼Æ¾Ö²¿Ëðʧ¡£ÊÔÇó (1) ±ÃµÄÅÅË®Á¿£»

(2) µ±±ÃµÄ×ÜЧÂÊ?=70%ʱ£¬´ø¶¯±ÃµÄµç¶¯»úÊ䏸±ÃµÄ¹¦ÂÊӦΪ¶àÉÙ£¿ Fig.6-42 Problem 6.25

((1) 0.57m3/s (2) 159.6kW)