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?? (Cd2+/Cd) = -0.403 V 77. 5 ·Ö (4414)

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µç³Ø£º Pt©¦H2(g,p?)©¦NaOH(0.5 mol¡¤kg-1)©¦HgO(s)©¦Hg(l)©¦Pt ÔÚ 298 K ʱµÄµç¶¯ÊÆE298 = 0.924 V£¬?? [HgO/Hg(l)] = 0.098 V .

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Éè»î¶ÈϵÊý¶¼µÈÓÚ 1¡£ 83. 10 ·Ö (4460)

25¡æÊ±£¬ÏÂÁÐµç³ØµÄµç¶¯ÊÆÎª 1.227 V Zn(s)©¦ZnCl2(0.005 mol¡¤kg-1)©¦Hg2Cl2(s)©¦Hg(l)

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Ag - Au ºÏ½ðÖУ¬Ag µÄĦ¶û·ÖÊý x(Ag) = 0.4000£¬½«´ËºÏ½ðÓÃÓÚ Ag©¦AgCl(s)©¦Ag - Au µç³ØÖУ¬ÔÚ 473 K ʱ£¬²âµÃµç³Øµç¶¯ÊÆ E = 0.0864 V£¬Çó¸ÃºÏ½ðÖÐ Ag µÄ»î¶ÈºÍ»î¶ÈϵÊý£¬²¢Ð´³öµç³Ø·´Ó¦¡£ 85. 10 ·Ö (4464)

25¡æ£¬·´Ó¦ H2(g) + AgO(s) = Ag(s) + H2O(l) µÄºãÈÝÈÈЧӦQv= -252.79 kJ¡¤mol-1£¬ÔÚ 101.325 kPa£¬298 KÏ£¬½«ÉÏÊö·´Ó¦Ìåϵ¹¹³ÉÒ»¿ÉÄæÔ­µç³Ø£¬ÔòÆäµç¶¯ÊƵÄζÈϵÊýΪ -5.044¡Á10-4 V¡¤K-1¡£Çó Ag©¦Ag2O©¦OH-µç¼«µÄ ??£¨ÒÑÖª 25¡æÊ±Ë®µÄÀë×Ó»ý Kw= 1¡Á10-14£©¡£ 86. 10 ·Ö (4465)

(a) 298 K ʱ£¬NaCl Ũ¶ÈΪ 0.100 mol¡¤dm-3µÄË®ÈÜÒºÖУ¬Na+Óë Cl- µÄµçÇ¨ÒÆÂÊΪ

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Pt©¦H2(p?)©¦HBr(0.100 mol¡¤kg-1)©¦AgBr(s)©¦Ag(s) AgBr µç¼«µÄ±ê×¼µç¼«µçÊÆ ?? ( Ag©¦AgBr©¦Br -) = 0.071 V Çëд³öµç¼«·´Ó¦Óëµç³Ø·´Ó¦£¬²¢ÇóËùָŨ¶ÈÏ£¬HBr µÄƽ¾ùÀë×Ó»î¶ÈϵÊý¡£ 87. 10 ·Ö (4466)

298 K ʱ£¬¶Ô·´Ó¦3Sn4+ + 2Al = 3Sn2+ + 2Al3+£¬ÒÑÖª±ê×¼µç¼«µçλ?? (Al3+/Al) = -1.66 V£¬ ? ? (Sn4+/Sn) = 0.007 V£¬ ?? (Sn2+/Sn) = -0.14 V

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ÒÑÖªµç³Ø·´Ó¦£º 2Fe3+ + Sn2+ £½ 2Fe2+ + Sn4+

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¼ÆËãÏÂÊöµç³ØÓÚ 298 K ʱµÄµç¶¯ÊƲ¢ÅÐ¶Ïµç³ØµÄ·´Ó¦·½Ïò£¬ Cu©¦Cu(OH)2(s)©¦OH-(0.1 mol¡¤kg-1)¡¬Cu2+(0.1 mol¡¤kg-1)©¦Cu

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ÒÑÖª ?? [Br-/AgBr(s)/Ag(s)] = 0.0711 V , ? ? (Ag+/Ag(s)) = 0.799 V£¬Çó 298 K ʱ AgBr µÄÈܶȻý¡£ 91. 10 ·Ö (4470)

µç³Ø Cd©¦Cd(OH)2©¦NaOH(0.01 mol¡¤kg-1)©¦H2(p?)©¦Pt 298 Kʱµç¶¯ÊÆÎª E = 0.000 V, (?E/?T)p= 0.002 V¡¤K-1£¬ ?? (Cd2+/Cd) = -0.403 V

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ÒÑÖªµç¼«·´Ó¦ CrSO4(s) + 2e- = Cr(s) + SO4 µÄ ?? (298 K) = -0.40 V £¬

2? (a) д³öµç³Ø Cr©¦CrSO4(s)©¦H2SO4(0.001 mol¡¤kg-1)©¦H2(p?)©¦Pt µÄµç³Ø·´Ó¦£» (b) ¼ÆËã 298 K ʱ£¬¸Ãµç³ØµÄµç¶¯ÊÆ£¨²»¿¼ÂÇ»î¶ÈϵÊýµÄУÕý£©£» (c) Ó¦Óõ°ݣ­Ðݿ˶û¼«ÏÞ¶¨ÂɼÆËã»î¶ÈϵÊý£¬Çó¸Ãµç³ØÔÚ 298 K ʱµÄµç¶¯ÊÆ¡£ ÒÑÖª A= 0.509 (mol¡¤kg)

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ÔÚ 298 K ʱÓÐÏÂÁÐÁ½¸öµç³Ø (1) Ag©¦AgCl(s)©¦HClÒÒ´¼ÈÜÒº(m1)©¦H2(p?)©¦Pt-Pt©¦H2(p?)©¦HClÒÒ´¼ÈÜÒº(m2)©¦AgCl©¦Ag(s)

(2) Ag©¦AgCl(s)©¦HClÒÒ´¼ÈÜÒº(m1)©¦HClÒÒ´¼Òº(m2)©¦AgCl(s)©¦Ag(s) ÒÑÖª HClÒÒ´¼ÈÜÒºµÄŨ¶È m1ºÍ m2·Ö±ðΪ 8.238¡Á10-2ºÍ 8.224¡Á10-3 mol¡¤kg-1£¬ Á½µç³Øµç¶¯ÊÆ·Ö±ðΪ E1= 8.22¡Á10-2 V ºÍ E2= 5.77¡Á10-2 V£¬ÊÔÇó£º (a) ÔÚÁ½ÖÖ HCl µÄÒÒ´¼ÈÜÒºÖУ¬Àë×ÓÆ½¾ù»î¶ÈϵÊýµÄ±ÈÖµ ??,1/??,2

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ÊÔΪÏÂÊö·´Ó¦Éè¼ÆÒ»µç³Ø Cd(s) + I2(s) ©¤¡úCd2+(a=1) + 2I-(a=1) Çóµç³ØÔÚ 298 K ʱµÄ E?£¬·´Ó¦µÄ ?rGm ºÍƽºâ³£Êý K?£¬È罫·´Ó¦Ð´³É£º

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ÁÐʽ±íʾÏÂÁÐÁ½×éµç¼«ÖÐÿ×é±ê×¼µç¼«µçÊÆ ?? Ö®¼äµÄ¹ØÏµ£º (1) Fe3++ 3e-©¤¡ú Fe(s), Fe2++ 2e-©¤¡ú Fe(s), Fe3++ e-©¤¡úFe2+ (2) Sn4++ 4e-©¤¡ú Sn(s), Sn2++ 2e-©¤¡ú Sn(s), Sn4++ 2e-©¤¡úSn2+ 98. 10 ·Ö (4482)

ÔÚ 298 K ʱ£¬·Ö±ðÓýðÊô Fe ºÍ Cd ²åÈëÏÂÊöÈÜÒºÖУ¬×é³Éµç³Ø£¬ÊÔÅжϺÎÖÖ½ð ÊôÊ×Ïȱ»Ñõ»¯£¿ (a) ÈÜÒºÖк¬Fe2+ ºÍCd2+ µÄŨ¶È¶¼ÊÇ 0.1 mol¡¤kg-1 (b) ÈÜÒºÖк¬Fe2+ Ϊ 0.1 mol¡¤kg-1£¬¶øCd2+ Ϊ 0.0036 mol¡¤kg-1

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ÔÚ 298 K ʱ£¬ÊÔ´Ó±ê×¼Éú³É×ÔÓÉÄܼÆËãÏÂÊöµç³ØµÄµç¶¯ÊÆ£º Ag(s)©¦AgCl(s)©¦NaCl(a=1)©¦Hg2Cl2(s)©¦Hg(l)

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ÒÑÖª 298 K ʱ 2H20(g) £½ 2H2(g) + O2(g) ·´Ó¦µÄƽºâ³£ÊýΪ 9.7¡Á10-81 £¬Õâʱ H2O µÄ±¥ºÍÕôÆøÑ¹Îª 3200 Pa£¬ÊÔÇó 298 K ʱÏÂÊöµç³ØµÄµç¶¯ÊÆ E¡£ Pt£¬H2(p?)©¦H2SO4(0.01 mol¡¤kg-1)©¦O2(p?)£¬Pt

£¨298 K ʱµÄƽºâ³£ÊýÊǸù¾Ý¸ßÎÂϵÄÊý¾Ý¼ä½ÓÇó³öµÄ¡£ÓÉÓÚÑõµç¼«ÉÏ·´Ó¦²»Ò״ﵽƽºâ£¬²»Äܲâ³ö E µÄ¾«È·Öµ£¬ËùÒÔ¿Éͨ¹ýÉÏ·¨À´¼ÆËã E Öµ£© 101. 10 ·Ö (4487)

¼ÆËãÏÂÁÐµç³ØÔÚ 298 K ʱµÄµç¶¯ÊÆ Pt£¬Cl2(g,p?)©¦HCl(10 mol¡¤kg-1©¦O2(g,p?)£¬Pt ÒÑÖª£ºÆøÏà·´Ó¦ 4HCl + O2= 2H2O + 2Cl2 µÄƽºâ³£Êý Kp= 1013£¬²¢ÒÑÖª¸Ãµç³ØµÄ HCl ÈÜ

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