NaAc [pKa(HAc) = 4.74] HCOOH [pKa(HCOOH) = 3.74]
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ÎïÖÊ CH3NH2(¼×°·) NaAc H3BO3(ÅðËá) Na2B4O7¡¤10H2O(Åðɰ) C6H5NH3+Cl(ÑÎËá±½°·) ÄÜ·ñÖ±½ÓµÎ¶¨ ָʾ¼Á [pKb(CH3NH2) = 3.38, pKb(C6H5NH2) = 9.38, pKa(HAc) = 4.74, pKa(H3BO3) = 9.24] 0623
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Ìîдϱí 0.1 mol/L C2H5NH2(pKb = 3.25) 0.1 mol/L HA(pKa = 2.86) + 0.1 mol/L H3BO3(pKa = 9.24) 0.1 mol/L NaAc[pKa(HAc) = 4.74] ÄÜ·ñÖ±½ÓµÎ¶¨ µÎ¶¨¼Á ָʾ¼Á 0625 NH4+µÄËáÐÔÌ«Èõ,ÓÃNaOHÖ±½ÓµÎ¶¨Ê±Í»Ô¾Ì«Ð¡¶ø²»ÄÜ׼ȷµÎ¶¨¡£²ÉÓ÷µµÎ¶¨·¨___________׼ȷ²â¶¨(ÌîÄÜ»ò²»ÄÜ),ÆäÔÒòÊÇ____________________________________ _____________¡£ 0626
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¿ËÊÏ·¨²â¶¨µªÊ±, ³ÆÈ¡0.2800 gÓлúÎï, ¾Ïû»¯´¦ÀíºóÕô³öµÄNH3ÕýºÃÖкÍ20.00 mL 0.2500 mol/L µÄH2SO4, Ôò¸ÃÓлúÎïÖеªµÄÖÊÁ¿·ÖÊýw(N)[Ar(N)=14.00]Ϊ ____________¡£ 0631
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1 V1> V2 2 V1< V2 3 V1 = V2 4 V1 = 0 5 V2 = 0 0635 ÒÆÈ¡25.00 mL¿ÉÄܺ¬HClºÍ¸÷ÖÖÁ×ËáÑεĻìºÏÈÜÒº,ÓÃ0.1000 mol/L NaOH ±ê×¼ÈÜÒºµÎ¶¨, ϱíÖÐV1(NaOH)ΪÓü׻ù³È×÷ָʾ¼ÁËùºÄÌå»ý, V2(NaOH)ΪѡÓ÷Ó̪×÷ָʾ¼ÁËùºÄÌå»ý¡£ÇëÌîдÒÔÏÂÈÜÒº×é³É¼°Å¨¶È¡£
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V1(NaOH)/mL 18.72 0.00 V2(NaOH)/mL 23.60 16.77 ×é³É Ũ¶ÈcB/(mol/L) ÒÆÈ¡25.00 mL¿ÉÄܺ¬HClºÍ¸÷ÖÖÁ×ËáÑεĻìºÏÈÜÒº, ÓÃ0.1000 mol/L NaOH±ê×¼ÈÜÒºµÎ¶¨, Óü׻ù³ÈΪָʾ¼ÁºÄÈ¥ V1(NaOH) (mL), Èô¸ÄÓ÷Ó̪Ϊָʾ¼ÁÔòºÄÈ¥V2(NaOH) (mL),ÇëÌîдÒÔÏÂÈÜÒºµÄ×é³É¼°Å¨¶È
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1 2 3 4 V1 = V2 V1
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1 2 3 4 5 V1(HCl)/mL 22.42 15.60 28.84 18.02 0.00 V2(HCl)/mL 22.44 41.33 35.16 36.03 24.87 ×é³É 0641
ÔÚ´¿CH3OHÈܼÁÖÐÓÃ0.1 mol/L Ç¿¼îµÎ¶¨0.1 mol/L Ç¿Ëá,»¯Ñ§¼ÆÁ¿µãµÄpHÊÇ______, »¯Ñ§¼ÆÁ¿µãǰ0.1£¥µÄpHÊÇ______, »¯Ñ§¼ÆÁ¿µãºó0.1£¥µÄpHÊÇ______¡£ [pKs(CH3OH) = 16.7] 0642
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[Mr(NaOH) = 40.00, Mr(Na2CO3) = 106.0] 0643
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{Mr(NH4NO3) = 80.04, pKb[(CH2)6N4] = 8.85} 0644
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(NH4)2HPO4¡¤12MoO3¡¤H2O+24OH- = 12MoO42-+HPO42-+2NH4++13H2O ¼ÆËãÁ×ôûÖÊÁ¿·ÖÊýw(P4O10)¡£ [Mr(P4O10) = 283.9] 0645
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[Mr(Na2B4O7¡¤10H2O) = 381.4, Mr(NaOH) = 40.00, Mr(Na2CO3) = 106.0] 0646
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