ºÚÁú½­Ê¡¹þ¶û±õʦ·¶´óѧ¸½ÊôÖÐѧ2019½ì¸ßÈýÉÏѧÆÚÆÚÖп¼ÊÔÊýѧ(Àí)ÊÔÌâ¼°´ð°¸Ïê½â ÏÂÔØ±¾ÎÄ

ºÚÁú½­Ê¡¹þ¶û±õʦ·¶´óѧ¸½ÊôÖÐѧ2019½ì¸ßÈýÉÏѧÆÚÆÚÖп¼ÊÔÊýѧ£¨Àí£©ÊÔÌâ

Ò»¡¢Ñ¡ÔñÌ⣨±¾´óÌâ¹²12СÌ⣬¹²60.0·Ö£©

2

1. Èô¼¯ºÏA={x|x+x-2£¼0}£¬¼¯ºÏ £¾ £¬ÔòA¡ÉB=£¨ £©

A. C. A.

B. D.

B.

2

2. ÒÑÖª2sin¦È+cos¦È=0£¬Ôòsin¦Ècos¦È-cos¦ÈµÄÖµ£¨ £©

C.

D.

=£¨1£¬ £©£¬ÏòÁ¿ ? =2£¬Ôò| |µÈÓÚ£¨ £© 3. ÒÑÖªÏòÁ¿ £¬ µÄ¼Ð½ÇÊÇ £¬

A. B. 4 C. 2 D.

4. Èôm£¬nÊÇÁ½Ìõ²»Í¬µÄÖ±Ïߣ¬¦Á£¬¦Â£¬¦ÃÊÇÈý¸ö²»Í¬µÄÆ½Ãæ£¬ÔòÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ£¨ £©

A. £¬ £¬ B. £¬

C. £¬ £¬

D. £¬ £¬

5. ¡¶ÖÜ÷ÂËã¾­¡·ÖÐÓÐÕâÑùÒ»¸öÎÊÌ⣺´Ó¶¬ÖÁÈÕÆð£¬ÒÀ´ÎСº®¡¢´óº®¡¢Á¢´º¡¢ÓêË®¡¢¾ªÕÝ¡¢´º·Ö¡¢ÇåÃ÷¡¢

¹ÈÓê¡¢Á¢ÏÄ¡¢Ð¡Âú¡¢Ã¢ÖÖÕâÊ®¶þ¸ö½ÚÆøÆäÈÕÓ°³¤ÒÀ´Î³ÉµÈ²îÊýÁУ¬¶¬ÖÁ¡¢Á¢´º¡¢´º·ÖÈÕÓ°³¤Ö®ºÍΪ31.5³ß£¬Ç°¾Å¸ö½ÚÆøÈÕÓ°³¤Ö®ºÍΪ85.5³ß£¬ÔòâÖÖÈÕÓ°³¤Îª£¨ £©

A. ³ß B. ³ß C. ³ß

D. ³ß

6. º¯Êýf£¨x£©=Asin£¨¦Øx+¦Õ£©£¨ÆäÖÐA£¾0£¬¦Ø£¾0£¬|¦Õ|£¼ £©µÄͼÏóÈçͼËùʾ£¬ÎªÁ˵õ½y=cos2xµÄͼÏó£¬

ÔòÖ»Òª½«f£¨x£©µÄͼÏó£¨ £©

A. Ïò×óÆ½ÒÆ ¸öµ¥Î»³¤¶È C. Ïò×óÆ½ÒÆ ¸öµ¥Î»³¤¶È

B. ÏòÓÒÆ½ÒÆ ¸öµ¥Î»³¤¶È D. ÏòÓÒÆ½ÒÆ ¸öµ¥Î»³¤¶È

7. Ö±ÈýÀâÖùABC-A1B1C1ÖУ¬AB AC£¬AB=AC=AA1£¬ÔòÖ±ÏßA1BÓëAC1Ëù³É½ÇµÄ´óСΪ£¨ £©

A. B. C. D.

0.3

8. Èôº¯Êý ÔÚÇø¼ä£¨a-1£¬a+1£©Éϵ¥µ÷µÝ¼õ£¬ÇÒb=1g0.3£¬c=2£¬Ôò£¨ £©

A. B. C. D. 9. ÒÑÖªÊýÁÐ{an}µÄÊ×Ïîa1=2£¬ÊýÁÐ{bn}ΪµÈ±ÈÊýÁУ¬ÇÒbn=

£¬Èôb10b11=2£¬Ôòa21=£¨ £©

A. B. C. D.

10. ij¼¸ºÎÌåµÄÈýÊÓͼÈçͼËùʾ£¬Ôò¸Ã¼¸ºÎÌåµÄÌå»ýΪ£¨ £©

µÚ1Ò³£¬¹²17Ò³

A.

B. C.

D. 2

11. ÒÑÖª¶¨ÒåÓòΪRµÄÆæº¯Êýf£¨x£©£¬µ±x£¾0ʱ£¬f£¨x£©=2f£¨x+3£©£¬µ±-3£¼x¡Ü0ʱ£¬f£¨x£©=log3£¨1-x£©£¬

Ôòf£¨2018£©=£¨ £©

A.

B.

C.

D.

12. ÒÑÖªf£¨x£©ÊǶ¨ÒåÔÚRÉÏµÄÆæº¯Êý£¬Âú×ãf£¨2-x£©+f£¨x£©=0£¬ÇÒµ±x¡Ê[0£¬1£©Ê±£¬f£¨x£©= £¬Ôòº¯Êýg£¨x£©=f£¨x£©+2sin¦ÐxÔÚÇø¼ä£¨-3£¬5£©ÉϵÄËùÓÐÁãµãÖ®ºÍΪ£¨ £© A. 12 B. 13 C. 14 D. 15 ¶þ¡¢Ìî¿ÕÌ⣨±¾´óÌâ¹²4СÌ⣬¹²20.0·Ö£©

13. ¹ýµã£¨-1£¬2£©ÇÒÓëÖ±Ïß2x-3y+9=0´¹Ö±µÄÖ±Ïß·½³ÌΪ______£® 14. ÒÑÖªsin£¨ £©= £¬Ôòsin¦È=______£®

|=1£¬Ôò ? =______£® £¬| 15. Èçͼ£¬ÔÚ¡÷ABCÖУ¬AD AB£¬ =

16. ÒÑÖªÕý¡÷ABCÈý¸ö¶¥µã¶¼Ôڰ뾶Ϊ2µÄÇòÃæÉÏ£¬ÇòÐÄOµ½Æ½ÃæABCµÄ¾àÀëΪ1£¬

µãEÊÇÏß¶ÎABµÄÖе㣬¹ýµãE×÷ÇòOµÄ½ØÃ棬Ôò½ØÃæÃæ»ýµÄ×îСֵÊÇ______£® Èý¡¢½â´ðÌ⣨±¾´óÌâ¹²7СÌ⣬¹²82.0·Ö£©

17. ÔÚ¡÷ABCÖУ¬½ÇA£¬B£¬CËù¶ÔµÄ±ß·Ö±ðΪa£¬b£¬c£¬ÇÒ3cosAcosC£¨tanAtanC-1£©=1£®

£¨¢ñ£©ÇósinBµÄÖµ£»

£¨¢ò£©Èôa+c=3 £¬b= £¬Çó¡÷ABCµÄÃæ»ý£®

*

18. ÈôÊýÁÐ{an}µÄǰnÏîºÍSnÂú×ã2Sn=3an-1£¨n¡ÊN£©£¬µÈ²îÊýÁÐ{bn}Âú×ãb1=3a1£¬b3=S2+3£®

£¨1£©ÇóÊýÁÐ{an}¡¢{bn}µÄͨÏʽ£»

£¨2£©Éècn= £¬ÇóÊýÁÐ{cn}µÄǰnÏîºÍΪTn£®

µÚ2Ò³£¬¹²17Ò³

19. ÒÑÖªÍÖÔ²E£º

=1£¨a£¾b£¾0£©µÄ×ó£¬ÓÒ½¹µã·Ö±ðΪF1£¬F2£¬ÆäÀëÐÄÂÊe= £¬½¹¾àΪ4£®

£¨¢ñ£©ÇóÍÖÔ²EµÄ·½³Ì£»

¡Î £¬ |+| ¡Î £¬ =0£¬ |µÄB£¬C£¬DÊÇÍÖÔ²Éϲ»ÖغϵÄËĸöµã£¬£¨¢ò£©ÈôÖ±ÏßA£¬ÇÒÂú×ã Çó|

×îСֵ£®

AD¡ÎBC£¬20. Èçͼ£¬ÔÚËÄÀâ×¶S-ABCDÖУ¬²àÀâSA µ×ÃæABCD£¬µ×ÃæABCDÊÇÖ±½ÇÌÝÐΣ¬

AB AD£¬ÇÒSA=AB=BC=2£¬AD=1£¬MÊÇÀâSBµÄÖе㣮 £¨¢ñ£©ÇóÖ¤£ºAM¡ÎÆ½ÃæSCD£»

£¨¢ò£©ÇóÆ½ÃæSCDÓëÆ½ÃæSABËù³ÉÈñ¶þÃæ½ÇµÄÓàÏÒÖµ£»

£¨¢ó£©ÉèµãNÊÇÏß¶ÎCDÉϵ͝µã£¬MNÓëÆ½ÃæSABËù³ÉµÄ½ÇΪ¦È£¬Çósin¦ÈµÄ×î´óÖµ£®

2

21. º¯Êýf£¨x£©=x+mln£¨x+1£©£®

£¨1£©µ±m=-4ʱ£¬Çóº¯Êýf£¨x£©µÄµ¥µ÷¼õÇø¼ä£»

£¨2£©Èôº¯Êýf£¨x£©ÓÐÁ½¸ö¼«Öµµãx1¡¢x2£¬ÇÒx1£¼x2£¬Çó

¦ÕΪ²ÎÊý£¬¦Õ¡Ê[0£¬2¦Ð£© £©£®ÒÔ22. ÔÚÆ½ÃæÖ±½Ç×ø±êϵ xOy ÖУ¬ÒÑÖªÇúÏß C1£ºx+y=1ÓëÇúÏß C2£º £¨

×ø±êÔ­µãOΪ¼«µã£¬xÖáµÄ·Ç¸º°ëÖáΪ¼«ÖὨÁ¢¼«×ø±êϵ£®

£¨I£©Ð´³öÇúÏß C1£¬C2µÄ¼«×ø±ê·½³Ì£»

£¨II£©ÔÚ¼«×ø±êϵÖУ¬ÒÑÖªµãAÊÇÉäÏß l£º¦È=¦Á £¨ ¦Ñ¡Ý0£©Óë C1 µÄ¹«¹²µã£¬µã B ÊÇlÓëC2µÄ¹«¹²µã£¬µ±¦Á

µÄȡֵ·¶Î§£®

µÚ3Ò³£¬¹²17Ò³

ÔÚÇø¼ä[0£¬ ]Éϱ仯ʱ£¬Çó µÄ×î´óÖµ£®

23. ÒÑÖªº¯Êýf£¨x£©=|2x- |+|2x+ |£®

£¨¢ñ£©Çóº¯Êýf£¨x£©µÄ×îСֵa£»

+

£¨¢ò£©ÔÚ£¨¢ñ£©µÄÌõ¼þÏ£¬Éèm£¬n¡ÊR£¬ÇÒm+n=1£¬ÇóÖ¤£º £®

µÚ4Ò³£¬¹²17Ò³