ÎïÀí»¯Ñ§ÉÏÊÔÌâ ÏÂÔØ±¾ÎÄ

ÎïÀí»¯Ñ§(ÉÏ)ÊÔÌâ

(Ó¦Óû¯Ñ§¡¢²ÄÁÏ»¯Ñ§×¨ÒµÓÃ)

Ò»¡¢µ¥ÏîÑ¡ÔñÌ⣨25·Ö£©

1. ÀíÏëÆøÌåµÄѹËõÒò×ÓZ ( )

a. Z?1b. Z?1c. Z?1d. ËæËù´¦×´Ì¬¶ø¶¨ 2. ʵ¼ÊÆøÌåµÄѹËõÒò×ÓZ ( )

a. Z?1b. Z?1c. Z?1d. ËæËù´¦×´Ì¬¶ø¶¨ 3. ·â±ÕÌåϵ¾­¹ýÒ»¸öÑ­»·¹ý³Ìºó£¬Ôò £¨ £©

a. ÌåϵµÄìØÔö¼Ó b. U = 0 c. Q = 0 d. ÌåϵµÄT¡¢p¶¼²»±ä 4. ÀíÏëÆøÌå¾­¹ý¾øÈÈ¿ÉÄæÅòÕ͹ý³Ì £¨ £© a. ?U?0b. ?H?0c. ?S?0d. ?G?0

5. H2O(l)ÓëH2O(g)³ÉƽºâµÄÌåϵ£¬Æä×ÔÓɶÈÊýf = 1, Òâζ×ÅÌåϵµÄ £¨ £© a. ζÈÒ»¶¨ b. ѹÁ¦Ò»¶¨ c. ×é³ÉÒ»¶¨ d. ζȡ¢Ñ¹Á¦Ö»ÓÐÒ»¸öÊǶÀÁ¢±äÁ¿ 6. ÈçÏÂͼËùʾ£¬Ìåϵ´Ó״̬A±ä»¯µ½×´Ì¬B£¬¾­ÀúÁ½Ìõ²»Í¬µÄ;¾¶£¬

(1)BA(2)

ÏÂʽÖÐÄǸö²»ÕýÈ·? £¨ £© a. Q1?Q2W1?W2b. Q1?W1?Q2?W2

?H1??H2d. ?U1??H2??U2??H1 c. ?U1??U27. AÓëBÐγÉÀíÏëÈÜÒº£¬Ôò £¨ £©

a. ÈܼÁ·Ö×ÓÓëÈÜÖÊ·Ö×Ó¼ä×÷ÓÃÁ¦ÎªÁã b. ¸ÃÈÜÒº·ÐµãÉý¸ß c. ÈÜÒºÖеÄÁ½×é·Ö¿Éͨ¹ý¾«Áó½øÐзÖÀë d. ?mixS?0

**p?pAB8. AÓëBÐγÉÀíÏëÈÜÒº£¬Ä³Î¶ÈTÏ£¬ÒÑÖªÏàͬÊýÁ¿µÄAÓëBÐγɵÄÌåϵÔÚ

¸ÃζÈT¼°Ñ¹Á¦pÏÂ´ïµ½ÆøÒºÆ½ºâ, ζȲ»±äÈô¶ÔÌåϵ¼Óѹʱ£¬Ôò ( ) a. yAÔö´ó£¬xAÔö´ó b. yBÔö´ó£¬xBÔö´ó c. yAÔö´ó£¬xA¼õС d. yBÔö´ó£¬xB¼õС

9. Èý×é·ÖÌåϵ×î¶àÓм¸ÏàÆ½ºâ¹²´æ? £¨ £©

a. 5Ïà b. 4Ïà c. 3Ïà d. 2Ïà

10. AºÍBÐγɵÄÈÜÒº²úÉúÒ»°ã¸ºÆ«²î, ÔòÒ»¶¨Ñ¹Á¦Ï£¬AºÍBÐγɵÄÈÜÒºµÄ·Ðµã £¨ £©

a. Ò»¶¨´óÓÚ´¿AµÄ·Ðµã b. Ò»¶¨´óÓÚ´¿BµÄ·Ðµã

c. Ò»¶¨ÔÚAºÍBµÄ·ÐµãÖ®¼ä d. Ò»¶¨Ð¡ÓÚ´¿AµÄ·ÐµãҲСÓÚ´¿BµÄ·Ðµã 11. 1Ħ¶ûÀíÏëÆøÌå¾­¹ý½ÚÁ÷ÅòÕ͹ý³Ìºó £¨ £©

a. ?S?0b. ?F?0c. ?G?0d. ??0

12. ÔÚºãκãѹ²»×öÆäËü¹¦Ìõ¼þÏ£¬Ò»·â±ÕÌåϵ¾­¹ý×Ô·¢¹ý³Ì²¢ÔÚ¸ÃÌõ¼þÏ´ﵽƽºâ£¬Ôò

ÌåϵµÄ¼ªÊÏ×ÔÓÉÄÜÖµ£¨GÖµ£© £¨ £© a. ´ï×î´ó b. ´ï×îС c. ²»ÄÜÈ·¶¨ d. ²»±ä

13. »¯Ñ§·´Ó¦µÄºãѹÈÈ £¨ £©

a. ´óÓÚºãÈÝÈÈ b. µÈÓÚºãÈÝÈÈ c. СÓÚºãÈÝÈÈ d. ǰÈýÕß½ÔÓпÉÄÜ

14. Ë®Óë±½°·²¿·Ö»¥ÈÜ£¬ÏàͬÖÊÁ¿µÄË®ºÍ±½°·Ò»¶¨Î¶ÈÏÂ·Ö³ÉÆ½ºâµÄÁ½¸öÒº²ã¡£½ñÏò¸ÃÌå ϵÖмÓÈëһЩˮºóÖØÐ·ֳÉÁ½¸öÒº²ã£¬Ôò £¨ £©

a. Á½Òº²ãÖÐË®µÄŨ¶È¶¼Ôö´ó b. Á½Òº²ãÖÐË®µÄŨ¶È¶¼¼õС c. Á½Òº²ãÖÐË®µÄŨ¶È¶¼²»±ä d. ÒÔÉÏÈýÕß½ÔÓпÉÄÜ

15. Ò»¶¨Î¶ÈѹÁ¦Ï£¬·´Ó¦aA?bB?lL?mM×Ô·¢ÏòÓÒ½øÐеÄÌõ¼þÊÇ £¨ £©

???Q?K?G?0?Gppa. rmb. c. rm?0d.

???vB?B?0B

p,m16. ÓûùŒª»ô·ò¹«Ê½

Çó £¨ £©

?rHm(T)??rHm(298K)??T298K?vC(B)dT¼ÆËã·´Ó¦ÈÈʱҪ

a. ·´Ó¦ºãÈÝ b. T>298K c.

?vCBp,m(B)?0d. 298K~TÎÞÏà±ä»¯

17. H2ºÍO2ÔÚ¾øÈȺãÈÝµÄ¸ÖÆ¿Öз¢Éú·´Ó¦ £¨ £©

a. ?U?0b. ?H?0c. ?S?0d. ?G?0 18. ¶ÔÓÚÒ»¶¨µÄÌåϵ£¬ÏÂÁкÎʽ²»ÕýÈ·? £¨ £©

a.

?B????n???B?T,p,n??G?C??V?VB,m????n??B?T,V,nC?b. ????S,V,nCd. V??nBVB,m

??G???n?Bc.

???U??????T,p,nC??nB19. ±ùµÄÈÛµãËæÑ¹Á¦µÄÔö¼Ó¶ø £¨ £©

a. Éý¸ß b. ½µµÍ c. ²»±ä d. ÎÞ·¨ÅÐ¶Ï 20. ÀíÏëÆøÌ廯ѧ·´Ó¦£¨

??B?0£©Æ½ºâµÄÌåϵÖУ¬ÏÂÁÐÄÄÒ»Ìõ¼þÏÂÌåϵÖмÓÈë¶èÐÔÆø

Ìåʱƽºâ²»»áÒÆ¶¯£¿ £¨ £©

a. ºãκãѹ b. ºãκãÈÝ c. ÈÎÒâ d. ¾øÈȺãѹ

21. 100?C¡¢1atmÏ£¬Ë®Æû»¯ÎªÏàͬζÈѹÁ¦ÏµÄË®ÕôÆû£¬Ôò £¨ £©

W??nRTlna.

V2V1b. W??p?Vc. W??Ud. W?0

22. ÆøÌåÈÈÁ¦Ñ§±ê׼̬Ϊ £¨ £©

a. 25¡æ¡¢100kPa״̬ b. 273.15K£¬101325Pa£¬ÀíÏëÆøÌå״̬ c. 100kPa£¬´¿ÀíÏëÆøÌå״̬ d. 25¡æ£¬100kPa´¿ÀíÏëÆøÌå״̬ 23. ¶Ô×é³É¸Ä±ä¡¢Wf = 0µÄ·â±ÕÌåϵ£¬ÏÂÃæÊ½×ÓÖÐÕýÈ·µÄÊÇ £¨ £©

dG??SdT?Vdp?a. dG??SdT?Vdpb.

dH?TdS?Vdp?c. dU?TdS?pdVd.

?vBB?B

??dnB

24. »¯Ñ§·´Ó¦µÄ?rGm £¨ £©

a. Ó뷴Ӧʽд·¨ÓÐ¹Ø b. Óë·´Ó¦ÌåϵËù´¦×´Ì¬ÓÐ¹Ø c. Ëæ·´Ó¦½ø¶È¶ø±ä»¯ d. ǰÈýÖÖ˵·¨¶¼¶Ô 25. ·´Ó¦

CaCO3(s)?CaO(s)?O2(g)µÄƽºâÌåϵ£¬Î¶ÈÒ»¶¨£¬Ôö¼ÓÌåϵµÄѹ

Á¦£¬Ôò £¨ £© a.

K?pÔö´ó b.

KpÔö´ó c.

KcÔö´ó d. Kx¼õС

¶þ¡¢Ìî¿ÕÌ⣨28·Ö£©

1. ÈÈÁ¦Ñ§µÚ¶þ¶¨Âɵľ­µä±íÊöÖ®Ò»¿ª¶ûÎÄ˵·¨ÊÇ £»

ìØÔö¼ÓÔ­Àí¿É±íÊöΪ £»Óù«Ê½±íʾΪ ¡£

**????RTlnx?BB£¬BÖ¸ 2. ÀíÏëÏ¡ÈÜÒºÖÐÈÜÖÊB»¯Ñ§ÊƵıí´ïʽΪ B״̬µÄ»¯Ñ§ÊÆ¡£

3. Ò»¶¨Î¶ÈѹÁ¦Ï£¬4mol±½ºÍ6mol¼×±½»ìºÏÐγÉÀíÏëҺ̬»ìºÏÎ´Ë»ìºÏ¹ý³ÌµÄ

¦¤mixH= £»¦¤mixV= £»¦¤mixS= ¡£

4. 15¡æÊ±£¬Ò»¶¨Á¿µÄ·Ç»Ó·¢ÐÔÈÜÖÊÈÜÓÚË®£¬²âµÃÈÜÒºµÄÕôÆøÑ¹Îª595.8Pa£¬15¡æÊ±´¿Ë®µÄ

*pH?1956Pa2O, ÔòÈÜÒºÖÐË®µÄ»î¶ÈΪ £¬ÔÚÈÜÒºÖкÍÔÚ´¿Ë®ÖÐË®µÄ»¯Ñ§ÊƵIJîÖµÊÇ ¡£

dlnp?vapH?dTRT2£¬´ËʽÊÊÓÃÓÚ Æ½ºâ ¼°ÆøÌå½üËÆÎª µÄÌõ¼þ¡£5. ¿ËÀÍÐÞ˹¡ª¿ËÀ­ÅåÁú·½³Ì

6. ·´Ó¦C(s)?H2O(g)?CO(g)?H2(g)£¬ÔÚ400¡æÊ±´ïµ½Æ½ºâ£¬ÒÑÖª

??rHm?133.5kJ?mol?1£¬ÎªÊ¹Æ½ºâÏòÓÒÒÆ¶¯£¬¿É²ÉÈ¡µÄ´ëÊ©Ö÷ÒªÓÐ £¬ £¬ £¬ µÈ¡£

7. ÒÑÖªAºÍBÐγɵÄÈÜÒº²úÉú×î´ó¸ºÆ«²î£¬Ò»¶¨Î¶ÈÏ£¬Æäp-x-yÏàͼÈçÏ£º

pT*pBTp*pAeAzBBA

£¨1£©Ö¸³ö¸Ãp-x-yÏàͼÖÐ×ÔÓɶÈÊýf=0 µÄµã£»

£¨2£©ÊÔÔÚÓÒͼÖл­³öÆäT-x-yʾÒâͼ£»

£¨3£©ÈôÏëͨ¹ý¾«Áó·ÖÀëµÃµ½´¿B×é·Ö£¬¶ÔÈÜÒº×é³ÉÓкÎÒªÇó£¿

B

Èý¡¢¼ÆËãÌ⣨47·Ö£©

1£®1molÒºÌåË®ÔÚ100 ?C¡¢101.325kPaÏ£¬ÏòÕæ¿ÕÅòÕͱäΪÏàͬζÈѹÁ¦ÏµÄË®ÕôÆû£¬Ë®Õô

Æû¿ÉÊÓΪÀíÏëÆøÌ壬ҺÌåË®µÄÌå»ý¿ÉºöÂÔ¡£Çó¸Ã¹ý³ÌµÄW¡¢Q¼°ÌåϵµÄ?U¡¢?H¡¢?S¡¢?F¼°?G£¬²¢ÅжϹý³ÌµÄ·½Ïò¡£ÒÑÖª100 ?C¡¢101.325kPaÏÂË®µÄÕô·¢ìÊ

??vapHm(H2O)?40.6kJ?mol?1 £¨15·Ö£©

**p?283.7kPap?50.66kPa¡£ÏÖÓÐ3mol AB2. AºÍBÁ½×é·Ö¿É¹¹³ÉÀíÏëÈÜÒº£¬100¡æÊ±,

AºÍ5 mol BÔÚ100¡æ¡¢101.325kPaÏÂ´ïµ½ÆøÒºÁ½ÏàÆ½ºâ£¬Çó£º¢Ù¸ÃÆ½ºâÌåϵµÄÒºÏà×é³ÉxAºÍÆøÏà×é³ÉyA£»¢Ú¸ÃƽºâÌåÏµÆø¡¢ÒºÁ½ÏàµÄÊýÁ¿·Ö±ðÊǶàÉÙĦ¶û£¿¢ÛÓûʹ´ËÌåϵ

È«²¿±ä³ÉÆøÏ࣬ӦÔõÑù¿ØÖÆÌåϵµÄѹÁ¦£¿ £¨15·Ö£©

3£®ÒÑÖªÀíÏëÆøÌå·´Ó¦

(CH3)2CHOH(g)?(CH3)2CO(g)?H2(g)ÔÚ457.4KʱµÄ

K?,p?0.36£¨1£©µ¼³ö

-1-1??1?C?4.0J?mol?K?H?61.5kJ?mol,ÔÚ298KʱµÄrm·´Ó¦µÄrp¡£

lnK?p?f(T)µÄ¹ØÏµÊ½£»£¨2£©¼ÆËã500Kʱ·´Ó¦µÄ

K?p¡£ £¨10·Ö£©

4£®ÔÚ300Kʱ£¬ÒºÌ¬AµÄÕôÆøÑ¹Îª37.33kPa£¬ÒºÌ¬BµÄÕôÆøÑ¹Îª22.66kPa£¬µ±2molAºÍ

2molB»ìºÏºó£¬ÒºÃæÉÏÕôÆøµÄѹÁ¦Îª50.66kPa£¬ÔÚÕôÆøÖÐAµÄĦ¶û·ÖÊýΪ0.60¡£ÉèÕôÆø