£¨4£©·½°¸¼×ÖвÉÓÃÕôÁ󲻺ÏÀí£¬ÀíÓÉÊÇ µâµ¥ÖÊÒ×Éý»ª£¬»áµ¼ÖµâËðʧ £®
9£®[2015¡¤¸ß¿¼¸£½¨¾í25Ìâ]ij»¯Ñ§ÐËȤС×éÖÆÈ¡ÂÈËá¼ØºÍÂÈË®²¢½øÐÐÓйØÌ½¾¿ÊµÑé¡£ ʵÑéÒ» ÖÆÈ¡ÂÈËá¼ØºÍÂÈË®
ÀûÓÃÏÂͼËùʾµÄʵÑé×°ÖýøÐÐʵÑé¡£
(1)ÖÆÈ¡ÊµÑé½áÊøºó£¬È¡³öBÖÐÊÔ¹ÜÀäÈ´½á¾§£¬¹ýÂË£¬Ï´µÓ¡£¸ÃʵÑé²Ù×÷¹ý³ÌÐèÒªµÄ²£Á§ÒÇÆ÷ÓÐ________¡£
(2)Èô¶Ôµ÷BºÍC×°ÖõÄλÖã¬________(Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±)Ìá¸ßBÖÐÂÈËá¼ØµÄ²úÂÊ¡£ ʵÑé¶þ ÂÈËá¼ØÓëµâ»¯¼Ø·´Ó¦µÄÑо¿
(3)ÔÚ²»Í¬Ìõ¼þÏÂKClO3¿É½«KIÑõ»¯ÎªI2»òKIO3¡£¸ÃС×éÉè¼ÆÁËϵÁÐʵÑéÑо¿·´Ó¦Ìõ¼þ¶Ô·´Ó¦²úÎïµÄÓ°Ï죬ÆäÖÐϵÁÐaʵÑéµÄ¼Ç¼±íÈçÏÂ(ʵÑéÔÚÊÒÎÂϽøÐÐ)£º ÊԹܱàºÅ 0.20 mol¡¤L KI/mL KClO3(s)/g 6.0 mol¡¤L H2SO4/mL ÕôÁóË®/mL ʵÑéÏÖÏó £1£11 1.0 0.10 0 9.0 2 1.0 0.10 3.0 6.0 3 1.0 0.10 6.0 3.0 4 1.0 0.10 9.0 0 ¢ÙϵÁÐaʵÑéµÄʵÑéÄ¿µÄÊÇ______________________¡£ ¢ÚÉè¼Æ1ºÅÊÔ¹ÜʵÑéµÄ×÷ÓÃÊÇ__________________¡£ ¢ÛÈô2ºÅÊÔ¹ÜʵÑéÏÖÏóΪ¡°»ÆÉ«ÈÜÒº¡±£¬È¡ÉÙÁ¿¸ÃÈÜÒº¼ÓÈëµí·ÛÈÜÒºÏÔÀ¶É«£»¼ÙÉèÑõ»¯²úÎïΨһ£¬»¹Ô²úÎïΪKCl£¬Ôò´Ë·´Ó¦µÄÀë×Ó·½³ÌʽΪ__________________¡£
ʵÑéÈý ²â¶¨±¥ºÍÂÈË®ÖÐÂÈÔªËØµÄ×ÜÁ¿
(4)¸ÃС×éÉè¼ÆµÄʵÑé·½°¸Îª£ºÊ¹ÓÃÏÂͼװÖ㬼ÓÈÈ15.0 mL±¥ºÍÂÈË®ÊÔÑù£¬²â¶¨²úÉúÆøÌåµÄÌå»ý¡£´Ë·½°¸²»¿ÉÐеÄÖ÷ÒªÔÒòÊÇ________¡£(²»¿¼ÂÇʵÑé×°Öü°²Ù×÷ʧÎóµ¼Ö²»¿ÉÐеÄÔÒò)
(5)¸ù¾ÝÏÂÁÐ×ÊÁÏ£¬Îª¸ÃС×éÉè¼ÆÒ»¸ö¿ÉÐеÄʵÑé·½°¸(²»±ØÃèÊö²Ù×÷¹ý³ÌµÄϸ½Ú)£º____________________¡£
×ÊÁÏ£º¢¡.´ÎÂÈËá»áÆÆ»µËá¼îָʾ¼Á£»
£
¢¢.´ÎÂÈËá»òÂÈÆø¿É±»SO2¡¢H2O2ºÍFeCl2µÈÎïÖÊ»¹Ô³ÉCl¡£
10.[±±¾©¾íµÚ27Ìâ] Ñо¿CO2ÔÚº£ÑóÖеÄ×ªÒÆºÍ¹éËÞ£¬Êǵ±½ñº£Ñó¿ÆÑ§Ñо¿µÄÇ°ÑØÁìÓò¡£
£¨1£©ÈÜÓÚº£Ë®µÄCO2Ö÷ÒªÒÔ4ÖÖÎÞ»ú̼ÐÎʽ´æÔÚ£¬ÆäÖÐHCO3
-Õ¼95%£¬Ð´³öCO2ÈÜÓÚË®²úÉúHCO3µÄ·½³Ìʽ£º ¡£ £¨2£©ÔÚº£ÑóÑ»·ÖУ¬Í¨¹ýÓÒͼËùʾµÄ;¾¶¹Ì̼¡£
¢Ùд³ö¸Æ»¯×÷ÓõÄÀë×Ó·½³Ìʽ£º ¡£ ¢ÚÍ¬Î»ËØÊ¾×Ù·¨Ö¤Êµ¹âºÏ×÷ÓÃÊͷųöµÄO2Ö»À´×ÔÓÚH2O£¬18
ÓÃO±ê¼ÇÎïÖʵĹâºÏ×÷ÓõĻ¯Ñ§·½³ÌʽÈçÏ£¬½«Æä²¹
18
³äÍêÕû£º + ===(CH2O)x+xO2+xH2O £¨3£©º£Ë®ÖÐÈܽâÎÞ»ú̼ռº£Ë®×Ü̼µÄ95%ÒÔÉÏ£¬Æä׼ȷ²âÁ¿ÊÇÑо¿º£Ñó̼ѻ·µÄ»ù´¡£¬²âÁ¿ÈܽâÎÞ»ú ̼£¬¿É²ÉÓÃÈçÏ·½·¨£º
¢ÙÆøÌá¡¢ÎüÊÕCO2£¬ÓÃN2´ÓËữºóµÄ»¹ËµÖдµ³öCO2²¢ÓüîÒºÎüÊÕ£¨×°ÖÃʾÒâͼÈçÏ£©£¬½«ÐéÏß¿òÖеÄ×°Öò¹³äÍêÕû²¢±ê³öËùÓÃÊÔ¼Á¡£[À´Ô´:Z&xx&k.Com]
-
¢ÚµÎ¶¨¡£½«ÎüÊÕҺϴºóµÄÎÞ»ú̼ת»¯ÎªNaHCO3£¬ÔÙÓÃxmol/LHClÈÜÒºµÎ¶¨£¬ÏûºÄymlHClÈÜÒº£¬º£Ë®ÖÐÈܽâÎÞ»ú̼µÄŨ¶È= mol/L¡£ £¨4£©ÀûÓÃÓÒͼËùʾװÖôӺ£Ë®ÖÐÌáÈ¡CO2£¬ÓÐÀûÓÚ¼õÉÙ»·¾³ÎÂÊÒÆøÌ庬Á¿¡£
¢Ù½áºÏ·½³Ìʽ¼òÊöÌáÈ¡CO2µÄÔÀí£º ¡£
¢ÚÓøÃ×°ÖòúÉúµÄÎïÖÊ´¦ÀíbÊÒÅųöµÄº£Ë®£¬ºÏ¸ñºóÅŻش󺣡£´¦ÀíÖÁºÏ¸ñµÄ·½·¨ÊÇ ¡£
11.[È«¹ú2¾í] ±½·ÓºÍ±ûͪ¶¼ÊÇÖØÒªµÄ»¯¹¤ÔÁÏ£¬¹¤ÒµÉÏ¿ÎÓÃÒì±û±½Ñõ»¯·¨Éú²ú±½·ÓºÍ±ûͪ£¬Æä·´Ó¦ºÍ¹¤ÒÕÁ÷³ÌʾÒâͼÈçÏ£º ¢Ù¢Ú
+ O2´ß»¯¼ÁOOH ¡÷H=£116 kJ?mol
£1
+HOOH£1
OH+ CH3COCH3 ¡÷H=£253 kJ?mol
ZÒì±û±½YH2OTP
XA.·´Ó¦¸ªB.Õô·¢Æ÷·ÏË®²ÐÒºC.·Ö½â¸ªD.Öк͸ªE.ˮϴËþF.ÕôÁóËþÏà¹Ø»¯ºÏÎïµÄÎïÀí³£Êý£º
ÎïÖÊ Òì±û´¼ ±ûͪ Ïà¶Ô·Ö×ÓÖÊÁ¿ 120 58 ÃܶÈ(g/cm3) 0.8640 0.7898 ·Ðµã(¡æ) 153 56.5 ±½·Ó 94 1.0722 182 »Ø´ðÏÂÁÐÎÊÌ⣺ (1)ÔÚ·´Ó¦Æ÷AÖÐͨÈëµÄXÊÇ ¡£
(2)·´Ó¦¢ÙºÍ¢Ú·Ö±ðÔÚ×°Öà ºÍ ÖнøÐУ¨Ìî×°Ö÷ûºÅ£©¡£ (3)·Ö½âÔÚCÖмÓÈëµÄYΪÉÙÁ¿Å¨ÁòËᣬÆä×÷ÓÃ
ÊÇ £¬ÓŵãÊÇÓÃÁ¿ÉÙ£¬È±µãÊÇ ¡£
(4)·´Ó¦2Ϊ (Ìî¡°·ÅÈÈ¡±»ò¡°ÎüÈÈ¡±)·´Ó¦¡£·´Ó¦Î¶ÈÓ¦¿ØÖÆÔÚ50~60¡æ£¬Î¶ȹý¸ßµÄ°²È«Òþ»¼ÊÇ ¡£
(5)Öк͸ªDÖмÓÈëµÄZ×îÊÊÒ˵ÄÊÇ £¨ÌîÐòºÅ£¬ÒÑÖª±½·ÓÊÇÒ»ÖÖÈõËᣩ a.NaOH b.CaCO3 c.NaHCO3 d.CaO
(6)ÕôÁóËþFÖеÄÁó³öÎïTºÍP·Ö±ðÊÇ ºÍ £¬ÅжϵÄÒÀ¾ÝÊÇ ¡£
(7)Óø÷½·¨ºÏ³É±½·ÓºÍ±ûͪµÄÓŵãÊÇ ¡£ 12.[ 2015¡¤¸ß¿¼É½¶«¾í33Ìâ]¡¾»¯Ñ§¡ª¡ªÎïÖʽṹÓëÐÔÖÊ¡¿
·úÔÚ×ÔÈ»½çÖг£ÒÔCaF2µÄÐÎʽ´æÔÚ¡£
(1)ÏÂÁÐÓйØCaF2µÄ±íÊöÕýÈ·µÄÊÇ________¡£
2£«£
a£®CaÓëF¼ä½ö´æÔÚ¾²µçÎüÒý×÷ÓÃ
££
b£®FµÄÀë×Ӱ뾶СÓÚCl£¬ÔòCaF2µÄÈÛµã¸ßÓÚCaCl2 c£®ÒõÑôÀë×Ó±ÈΪ2¡Ã1µÄÎïÖÊ£¬¾ùÓëCaF2¾§Ìå¹¹ÐÍÏàͬ
d£®CaF2ÖеĻ¯Ñ§¼üΪÀë×Ó¼ü£¬Òò´ËCaF2ÔÚÈÛÈÚ״̬ÏÂÄܵ¼µç
3£«
(2)CaF2ÄÑÈÜÓÚË®£¬µ«¿ÉÈÜÓÚº¬AlµÄÈÜÒºÖУ¬ÔÒòÊÇ______________________(ÓÃÀë×Ó·½³Ìʽ±íʾ)¡£
ÒÑÖªAlF3£6ÔÚÈÜÒºÖпÉÎȶ¨´æÔÚ¡£
(3)F2ͨÈëÏ¡NaOHÈÜÒºÖпÉÉú³ÉOF2£¬OF2·Ö×Ó¹¹ÐÍΪ________£¬ÆäÖÐÑõÔ×ÓµÄÔÓ»¯·½Ê½Îª________¡£
(4)F2ÓëÆäËûÂ±ËØµ¥ÖÊ·´Ó¦¿ÉÒÔÐγÉÂ±ËØ»¥»¯ÎÀýÈçClF3¡¢BrF3µÈ¡£ÒÑÖª·´Ó¦Cl2(g)£«3F2(g)===2ClF3(g)
£1£1
¦¤H£½£313 kJ¡¤mol£¬F¡ªF¼üµÄ¼üÄÜΪ159 kJ¡¤mol£¬Cl¡ªCl¼üµÄ¼üÄÜΪ242 kJ¡¤mol£1£1
£¬ÔòClF3ÖÐCl¡ªF¼üµÄƽ¾ù¼üÄÜΪ________kJ¡¤mol¡£ClF3µÄÈÛ¡¢·Ðµã±ÈBrF3µÄ________(Ìî¡°¸ß¡±»ò¡°µÍ¡±)¡£
13.[º£ÄϾíµÚ19Ìâ]·°£¨23V£©ÊÇÎÒ¹úµÄ·á²úÔªËØ£¬¹ã·ºÓÃÓÚ´ß»¯¼°¸ÖÌú¹¤Òµ¡£»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©·°ÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪ £¬Æä¼Û²ãµç×ÓÅŲ¼Í¼Îª ¡£ £¨2£©·°µÄijÖÖÑõ»¯ÎïµÄ¾§°û½á¹¹Èçͼ1Ëùʾ¡£¾§°ûÖÐʵ¼ÊÓµÓеÄÒõ¡¢ÑôÀë×Ó¸öÊý·Ö±ðΪ ¡¢ ¡£
£¨3£©V2O5³£ÓÃ×÷SO2 ת»¯ÎªSO3µÄ´ß»¯¼Á¡£SO2 ·Ö×ÓÖÐSÔ×Ó¼Û²ãµç×Ó¶ÔÊýÊÇ ¶Ô£¬·Ö×ÓµÄÁ¢Ìå¹¹ÐÍΪ £»SO3ÆøÌ¬Îªµ¥·Ö×Ó£¬¸Ã·Ö×ÓÖÐSÔ×ÓµÄÔÓ»¯¹ìµÀÀàÐÍΪ £»SO3µÄÈý¾ÛÌå»·×´½á¹¹Èçͼ2Ëùʾ£¬¸Ã½á¹¹ÖÐSÔ×ÓµÄÔÓ»¯¹ìµÀÀàÐÍΪ £»¸Ã½á¹¹ÖÐS¡ªO¼ü³¤ÓÉÁ½À࣬һÀà¼ü³¤Ô¼140pm£¬ÁíÒ»Àà¼ü³¤Ô¼Îª160pm£¬½Ï¶ÌµÄ¼üΪ (Ìîͼ2ÖÐ×Öĸ)£¬¸Ã·Ö×ÓÖк¬ÓÐ ¸ö¦Ä¼ü¡£
(4)V2O5 ÈܽâÔÚNaOHÈÜÒºÖУ¬¿ÉµÃµ½·°ËáÄÆ£¨Na3VO4£©£¬¸ÃÑÎÒõÀë×ÓµÄÁ¢Ìå¹¹ÐÍΪ £»Ò²¿ÉÒԵõ½Æ«·°ËáÄÆ£¬ÆäÒõÀë×Ó³ÊÈçͼ3ËùʾµÄÎÞÏÞÁ´×´½á¹¹£¬ÔòÆ«·°ËáÄÆµÄ»¯Ñ§Ê½Îª ¡£ 14.[2015?½ËÕ17Ìâ]»¯ºÏÎïFÊÇÒ»ÖÖ¿¹Ðļ¡È±ÑªÒ©ÎïµÄÖмäÌ壬¿ÉÒÔͨ¹ýÒÔÏ·½·¨ºÏ³É£º
£¨1£©»¯ºÏÎïAÖеĺ¬Ñõ¹ÙÄÜÍÅΪ ºÍ £¨Ìî¹ÙÄÜÍŵÄÃû³Æ£©£® £¨2£©»¯ºÏÎïBµÄ½á¹¹¼òʽΪ £»ÓÉC¡úDµÄ·´Ó¦ÀàÐÍÊÇ£º £® £¨3£©Ð´³öͬʱÂú×ãÏÂÁÐÌõ¼þµÄEµÄÒ»ÖÖͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ £® ¢ñ£®·Ö×Óº¬ÓÐ2¸ö±½»·¢ò£®·Ö×ÓÖк¬ÓÐ3ÖÖ²»Í¬»¯Ñ§»·¾³µÄÇâ ÒÑÖª£ºRCH2CN
RCH2CH2NH2£¬Çëд³öÒÔ
ΪÔÁÏÖÆ±¸»¯ºÏÎï
X£¨½á¹¹¼òʽ¼ûͼ£©µÄºÏ³É·ÏßÁ÷³Ìͼ£¨ÎÞ»úÊÔ¼Á¿ÉÈÎÑ¡£©£®ºÏ³É·ÏßÁ÷³ÌͼʾÀýÈçͼ£ºCH3CHO
CH3COOH
CH3COOCH2CH3£®
15. [2015¡¤¸ß¿¼Ð¿αêÈ«¹ú¾í¢ñ38Ìâ]A(C2H2)ÊÇ»ù±¾Óлú»¯¹¤ÔÁÏ¡£ÓÉAÖÆ±¸¾ÛÒÒÏ©´¼Ëõ¶¡È©ºÍ˳ʽ¾ÛÒìÎì¶þÏ©µÄºÏ³É·Ïß(²¿·Ö·´Ó¦Ìõ¼þÂÔÈ¥)ÈçÏÂËùʾ£º
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)AµÄÃû³ÆÊÇ________£¬Bº¬ÓеĹÙÄÜÍÅÊÇ________¡£
(2)¢ÙµÄ·´Ó¦ÀàÐÍÊÇ____________________________£¬¢ßµÄ·´Ó¦ÀàÐÍÊÇ____________________________¡£
(3)CºÍDµÄ½á¹¹¼òʽ·Ö±ðΪ________¡¢________¡£ (4)ÒìÎì¶þÏ©·Ö×ÓÖÐ×î¶àÓÐ________¸öÔ×Ó¹²Æ½Ã棬˳ʽ¾ÛÒìÎì¶þÏ©µÄ½á¹¹¼òʽΪ________¡£ (5)д³öÓëA¾ßÓÐÏàͬ¹ÙÄÜÍŵÄÒìÎì¶þÏ©µÄËùÓÐͬ·ÖÒì¹¹Ìå________(Ìî½á¹¹¼òʽ)¡£ (6)²ÎÕÕÒìÎì¶þÏ©µÄÉÏÊöºÏ³É·Ïߣ¬Éè¼ÆÒ»ÌõÓÉAºÍÒÒȩΪÆðʼÔÁÏÖÆ±¸1,3-¶¡¶þÏ©µÄºÏ³É·Ïß________¡£