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¡à T2 = T1Q2 /Q1 = 320 K ¼´£ºµÍÎÂÈÈÔ´µÄζÈΪ 320 K£® (2) ÈÈ»úЧÂÊ£º ??1?Q2Q?20% 1153£®½â£º

(1) ??WQ1?QQ?2?T1?T2T 1Q11 QT11?WTT ÇÒ Q2?T2

1?2Q1T1¡à Q2 = T2 Q1 /T1

33

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¼´ Q2?T1T?T2W?T2£½24000 J

1?T2T1T1?T2ÓÉÓÚµÚ¶þÑ­»·ÎüÈÈ Q1??W??Q2??W??Q2 ( ¡ß Q2??Q2) ???W?/Q1??29.4£¥ (2) TT21??1????425 K 154£®½â£º

ÓÉͼµÃ pA£½400 Pa£¬ pB£½pC£½100 Pa£¬

VA£½VB£½2 m3£¬VC£½6 m3£® (1) C¡úAΪµÈÌå¹ý³Ì£¬¾Ý·½³ÌpA /TA = pC /TC

TC = TA pC / pA =75 K

B¡úCΪµÈѹ¹ý³Ì£¬¾Ý·½³Ì VB /TB =VC TC

TB = TC VB / VC =225 K

(2) ¸ù¾ÝÀíÏëÆøÌå״̬·½³ÌÇó³öÆøÌåµÄÎïÖʵÄÁ¿(¼´Ä¦¶ûÊý)??Ϊ

???? pA VA??RTA ???????mol ÓÉ?£½1.4Öª¸ÃÆøÌåΪ˫ԭ×Ó·Ö×ÓÆøÌ壬C5V?2R£¬C7P?2R B¡úCµÈѹ¹ý³ÌÎüÈÈ Q72?2?R(TC?TB)??1400 J£® C¡úAµÈÌå¹ý³ÌÎüÈÈ Q53?2?R(TA?TC)?1500 J£® ¦¤E =0£¬Õû¸öÑ­»·¹ý³Ì¾»ÎüÈÈ

Q?W?12(pA?pC)(VB?VC)?600 J£® ¡à A¡úB¹ý³Ì¾»ÎüÈÈ£º Q1=Q£­Q2£­Q3=500 J 155£®½â£º

(1) Ta = paV2/R£½400 K Tb = pbV1/R£½636 K Tc = pcV1/R£½800 K Td = pdV2/R£½504 K

(2) Ec =(i/2)RTc£½9.97¡Á103 J

(3) b£­cµÈÌåÎüÈÈ Q1=CV(Tc?Tb)£½2.044¡Á103 J

d£­aµÈÌå·ÅÈÈ Q2=CV(Td?Ta)£½1.296¡Á103 J

34

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W=Q1?Q2£½0.748¡Á103 J 156£®½â£º

(1) ¹ý³ÌabÓëbcΪÎüÈȹý³Ì£¬ ÎüÈÈ×ܺÍΪ

Q1=CV(Tb£­Ta)+Cp(Tc£­Tb)?35(pbVb?paVa)?(pcVc?pbVb)=800 J 22 (2) Ñ­»·¹ý³Ì¶ÔÍâËù×÷×ܹ¦ÎªÍ¼ÖоØÐÎÃæ»ý W = pb(Vc£­Vb)£­pd(Vd £­Va) =100 J

(3)

Ta=paVa/R£¬Tc = pcVc/R£¬ Tb = pbVb /R£¬Td = pdVd/R£¬

TaTc = (paVa pcVc)/R2=(12¡Á104)/R2 TbTd = (pbVb pdVd)/R2=(12¡Á104)/R2

¡à TaTc=TbTd 157£®½â£º

ÓÉͼ£¬pA=300 Pa£¬pB = pC =100 Pa£»VA=VC=1 m3£¬VB =3 m3£® (1) C¡úAΪµÈÌå¹ý³Ì£¬¾Ý·½³ÌpA/TA= pC /TC

TC = TA pC / pA =100 K£® B¡úCΪµÈѹ¹ý³Ì£¬¾Ý·½³ÌVB/TB=VC/TCµÃ TB=TCVB/VC=300 K£®

(2) ¸÷¹ý³ÌÖÐÆøÌåËù×÷µÄ¹¦·Ö±ðΪ A¡úB£º W1?12(pA?pB)(VB?VC)=400 J£® B¡úC£º W2 = pB (VC£­VB ) = ?200 J£® C¡úA£º W3 =0

(3) Õû¸öÑ­»·¹ý³ÌÖÐÆøÌåËù×÷×ܹ¦Îª

W= W1 +W2 +W3 =200 J£®

ÒòΪѭ»·¹ý³ÌÆøÌåÄÚÄÜÔöÁ¿Îª¦¤E=0£¬Òò´Ë¸ÃÑ­»·ÖÐÆøÌå×ÜÎüÈÈ

Q =W+¦¤E =200 J.

158£®½â£º

(1) Q31?RT1ln(V2/V1)?5.35?10 J (2) ??1?T2T?0.25. 1 W??Q31?1.34?10 J (3) Q2?Q1?W?4.01?103 J 159£®½â£º

35

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¸ù¾Ý¾øÈȹý³Ì·½³Ì£º p1£­

??T ??³£Á¿£¬

¿ÉµÃ T 2=T 1( p1 / p2 )(1

£­???????

?

¸ÕÐÔ˫ԭ×Ó·Ö×Ó ?????? £¬´úÈëÉÏʽ²¢´úÈëÌâ¸øÊý¾Ý£¬µÃ T2 =410 K 160£®½â£º

(1) ¸ù¾Ý¾øÈȹý³Ì·½³Ì p??1T???C

ÓÐ

T2?(p2)(??1)/?Tp 11¡à Tp2(?2?T1(p)?1)/? 1º¤Îªµ¥Ô­×Ó·Ö×Ó£¬??5/3 ¡à T2=1200 K (2) n?p2?1.96?1026 m?3kT 2

36