高中数学必修4平面向量知识点与典型例题总结(生)

高中数学必修4平面向量知识点与典型例题总结(生)

1, mathematics will be the basic type of questions - plane vector [basic concepts and formulas] [any time to write the vector should be accompanied by arrows)

1. vector f has both magnitude and direction of. As f or AB A.

Die 2. the size of the K vector vector from La in length or denoted as f

| |AB or | | A.

The vector f length of 3. units of 1 vectors. If e is a unit vector in it

| | in 1E.

4. zero vector k vector of length 0. As f 0. [0 direction is arbitrary and arbitrary vector in parallel]

5. parallel vector vector from collinear vectors shown the same or opposite direction F.

6. vector k equal vector length and direction are the same. Vector of 7. opposite vectors of equal length in the opposite direction of the f.

AB BA rate.

8. f AB BC AC triangle law

In the AB BC CD DE AE will share in his AB AC CB will share in the rate in those to increase the minuend

9. parallelogram rule f In order to,

A B is the two diagonal parallelogram shaped edges were a B in a in the B rate.

10. / F / collinear theorem

A B a B in chemical exergy. When the end of 0 when B and a included the same direction when the 0 share in a B and exergy exergy when reverse.

Two vectors of 11. basal K arbitrary collinear a group known as the base.

If the 12. K vector mode (a, x) y in 2 2| | A x y in 2 in the end 2| |

A a 2| (a) | in B a B in his will

13. the number of product and angle formula F | | | |cosa B a B from La La will share cos | | | | A B

A B from La In La

14. parallel and vertical R 1221

/a B a B x / y x y in the end of 12120 share in exergy in the 0A B a B x x y y in La in the end of his will

1. types of basic concepts of judge f

From the 1 observed collinear vectors is in the same line vector. From the 2 observed that if the two vector is not equal in their end point may not be the same.

3 compared with known unit vector from collinear vector is only. From the 4 ABCD La quadrilateral is a parallelogram condition is AB CD

In.

From the 5 increase if AB CD

In the end, A, B, C, D four points form a parallelogram.

From the 6 increase because the vector is directed line segment in the axis vector is so.

If those 7 increase

A and B in B and C in the collinear collinear A and C collinear. From the 8 increase if Ma MB

In the end, a B. 2 of the 9 if Ma Na is m n exergy exergy exergy. The 10 if

A and B A and B are not collinear exergy are not zero vector. The 11 if

| | | |a B a B / / exergy exergy A B.

If the 12 | | | |

A B a B in a B the rate of exergy exergy. Question 2. vector addition and subtraction 1..

A says, \|a B in the | exergy .

2. simplify () ()

AB MB BO BC OM in the in the in the in the exergy. 3. known

| | 5OA | | exergy exergy, 3OB, |AB, | the maximum value and minimum value respectively.

,.

4. known AC, AB, AD

With the vector and the exergy and AC a, BD B AB exergy exergy exergy exergy Exergy exergy AD.

The 5. known points on segment AB and C included 3 Five

AC AB AC BC exergy exergy, exergy exergy of AB BC. Number multiplication of 3. vectors of a problem 1. from the 1 Calculation

3 (2) (a) B a B in the 2 rate in the exergy 2 (253) 3 (232) A B C a B C in the rate rate rate rate in exergy