º£ÄÏ´óѧ²ÄÁÏÓ뻯¹¤Ñ§Ôº
»¯¹¤¿Î³ÌÉè¼Æ
˵Ã÷Êé
Ìâ Ä¿£ºÄê²ú8Íò¶ÖÁÚ±½¶þ¼×Ëá¶þÐÁõ¥£¨DOP£©
Éú²ú³µ¼ä³õ²½¹¤ÒÕÉè¼Æ
ѧ ºÅ: 20070124071 ÐÕ Ãû£º ÕŲ¨ Äê ¼¶£º 2007¼¶ ѧ Ôº£º ²ÄÁÏÓ뻯¹¤Ñ§Ôº ר Òµ£º »¯Ñ§¹¤³ÌÓ빤ÒÕ Ö¸µ¼½Ìʦ£º XXXXX Íê³ÉÈÕÆÚ£º 2010 Äê 6 Ô 19 ÈÕ
ÕªÒª
ÁÚ±½¶þ¼×Ëá¶þÐÁõ¥,¼ò³ÆDOP¡£·Ö ×Ó Ê½£ºC24H38O4 ÊÇÖØÒªµÄͨÓÃÐÍÔöËܼÁ£¬ÊÇĿǰ¹úÄÚÍâÓÃÁ¿×î´óµÄÔöËܼÁÖ®Ò»£¬¹ã·ºÓÃÓÚÏ𽺡¢ËÜÁϺÍÒ½Ò©¹¤ÒµÓÃ;¹ã·º£¬ÔÚ¹úÃñ¾¼ÃÖÐÕ¼ÓÐÊ®·ÖÖØÒªµÄµØÎ»¡£¾¹ý·ÖÎö±È½Ï¸÷ÖÖÉú²úÔÁÏ¡¢ºÏ³É¹¤Òպ󣬱¾Éè¼Æ¹¤ÒÕÁ÷³ÌÊDzÉÓô®Áª¶à¸ª·´Ó¦Æ÷Á¬Ðøõ¥»¯¼¼Êõ£¬´ß»¯¼ÁÊDzÉÓÃÑõ»¯ÂÁÓëÐÁËáÑÇÎýÒÔ1£º1±ÈÀý¸´Åä´ß»¯¼ÁÄê²ú8Íò¶ÖÁÚ±½¶þ¼×Ëá¶þÐÁõ¥£¬ÒÔÂú×ã¹úÄÚÐèÇó¡£
±¾Éè¼Æ×ñÑ¡°¼¼Êõ³ÉÊ죬¹¤ÒÕÏȽø¡¢É豸ÅäÖÿÆÑ§¡¢»·±£°²È«¡¢¾¼ÃÐ§Òæ¡±µÈÔÔò£¬ÔڱȽϹúÄÚÍâ¸÷ÖÖÏȽøÉú²ú·½·¨¡¢¹¤ÒÕÁ÷³ÌºÍÉ豸ÅäÖûù´¡ÉÏ£¬Ñ¡ÓÃÊÇ´Ó±½ôûºÍÒìÐÁ´¼³ö·¢¾¹ýõ¥»¯·´Ó¦¡¢ÍÑ´¼¡¢¾«ÖƵõ½²úÆ·µÄ¹¤ÒÕ·ÏßÉú²úÁÚ±½¶þ¼×Ëá¶þÐÁõ¥¡£Éè¼ÆµÄÖØµãÊÇÉú²ú¹¤ÒÕÉè¼ÆÂÛÖ¤¡¢¹¤ÒÕ¼ÆËã¼°É豸Éè¼ÆÑ¡ÐÍ£¬¸½Óдø¿ØÖƵãµÄ¹¤ÒÕÁ÷³Ìͼ£¬Ö÷ÒªÉú²úÉ豸½á¹¹³ß´çͼ£¬Éú²ú³µ¼äµÄÉ豸ÅäÖÃͼ¡£×îºó²¿·Ö¿¼ÂÇ»·¾³±£»¤ºÍÀͶ¯°²È«£¬ÒÔ´ïµ½¼õÉÙ¡°Èý·Ï¡±ÅÅ·Å£¬¼ÓÇ¿¡°Èý·Ï¡±ÖÎÀí£¬È·±£°²È«Éú²ú£¬Ïû³ý²¢¾¡¿ÉÄܼõÉÙ¹¤³§Éú²ú¶ÔÖ°¹¤µÄÉ˺¦¡£
¹Ø¼ü´Ê£ºDOP ÒìÐÁ´¼ ±½ôû ¹¤ÒÕÉè¼Æ ¹¤ÒÕ¼ÆËã É豸ѡÐÍ
Abstract
Dioctyl phthalate ,referred to as DOP, Molecular Formula:
C24H38O4 .It is important to general-purpose plasticizer and has become the largest amount used of plasticizerthe at home and abroad, now it is widely used in rubber, plastics and pharmaceutical industry, plays an important role in the national economy. After
analysis and comparison of various raw materials, synthesis, the design process is the use of multi-tank reactors in series continuous esterification technology, the catalyst is alumina with a 1:1 ratio of Sn catalyst compound annual output of 100,000 tons Dioctyl phthalate, to meet domestic demand.
The design follows the \technology, advanced technology, equipment configuration scientific, environmental safety, economic efficiency,\the principle of reciprocity. After comparing domestic and foreign advanced production methods, process and equipment configuration , the choices are starting from phthalic anhydride and iso-octanol after esterification, de alcohol, refined by product line production process octyl phthalate. Design for production process design argument, the design of facilities and process selection, with a flow chart with control points, the main production equipment and size chart, workshop equipment configuration diagram. The last part is about environmental protection and labor safety, in order to achieve reduction of the \wastes\Key word: DOP Ethylhexanol Phthalic Process Design Process Calculation Equipment Selection
Ŀ¼
Ò»£®×ÜÂÛ ...................................................... 7
1£®¸ÅÊö .................................................... 7
1.1ÔöËܼÁDOPµÄÐÔÖÊ .................................... 7 1.2²úÆ·ÓÃ; ............................................ 7 1.3DOPÔÚ¹úÃñ¾¼ÃÖеÄÖØÒªÐÔ ............................ 7 1.4 DOPµÄÊг¡ÐèÇó ...................................... 8 2£®Éè¼ÆµÄÄ¿µÄºÍÒâÒå ........................................ 8 3£®Éè¼ÆÒÀ¾ÝºÍÔÔò .......................................... 8
3.1Éè¼ÆÒÀ¾Ý ............................................ 8 3.2Éè¼ÆÔÔò ............................................ 8 4£®Éè¼Æ·¶Î§ ................................................ 9 5£®DOPÉú²úÄÜÁ¦¼°²úÆ·ÖÊÁ¿±ê×¼ .............................. 9 5.1Éú²úÄÜÁ¦ ............................................ 9 5.2²úÆ·ÖÊÁ¿±ê×¼ ........................................ 9 ¶þ£®Éú²ú¹¤ÒÕÁ÷³ÌÉè¼ÆÓëÂÛÖ¤ ?????????????????10 1£®Éú²ú¹¤ÒÕÑ¡ÔñÓëÂÛÖ¤??????????????????10 2£®¹¤ÒÕ²ÎÊýµÄÈ·¶¨ ????????????????????11
2.1õ¥»¯¹¤Ðò ..........................................11 2.2Öк͡¢Ï´µÓ¹¤Ðò ....................................11 2.3ÍÑ´¼¹¤Ðò ..........................................12 2.4¸ÉÔï¡¢¹ýÂ˹¤Ðò ....................................12 3£®²ú¹¤ÒÕÁ÷³Ìͼ¼°Æä˵Ã÷ ?????????????????13 3.1 DOPÉú²ú¹¤ÒÕÁ÷³Ìͼ ????????????????13
3.2 Éú²ú¹¤ÒÕÁ÷³Ì˵Ã÷?????????????????13
Èý£®¹¤ÒÕ¼ÆËã???????????????????????????14
1.ÎïÁϺâËã??????????????????????????14 1.1Éè¼ÆÉú²úÄÜÁ¦ ??????????????????????14
1.2¶þ¼¶õ¥»¯¶Î¸ª1ÎïÁϼÆËã????????????????? 15 1.3õ¥»¯¹¤¶ÎÎïÁϺâ½á¹û ???????????????????16 2£®ÈÈÁ¿ºâËã ?????????????????????????17 ËÄ£®Ö÷ÒªÉ豸Éè¼ÆÓëÑ¡ÐÍ??????????????????????18 1£®·´Ó¦¸ªµÄÉè¼ÆÓëÑ¡ÐÍ?????????????????????19 1.1·´Ó¦¸ªÌå»ýÈ·¶¨ ?????????????????????19 1.2·´Ó¦¸ª¸ß¶ÈÓëµ×ÃæÖ±¾¶ ??????????????????20 1.3·´Ó¦¸ªÎ¶ÈÓëѹÁ¦ ????????????????????20 1.4·´Ó¦¸ª±Úºñ¶È¼ÆËã ????????????????????21 1.5½Á°èÆ÷µÄÉè¼Æ¼°Ñ¡ÐÍ ???????????????????22 1.5.1½Á°èÆ÷ÐÍʽÊÊÓÃÌõ¼þ±í ???????????????23 1.5.2 ½Á°èÆ÷µÄÑ¡Óü°³ß´ç ????????????????23 1.5.3½Á°è¹¦ÂʵļÆËã ??????????????????23 1.6¼ÐÌ×´«ÈÈÃæ»ýµÄ¼ÆËãÓëºËËã ????????????????23 1.6.1 ±»½Á°èÒºÌå²àµÄ¶ÔÁ÷´«ÈÈϵÊý ????????????23 1.6.2¼ÐÌ×ÀäÈ´Ë®¶ÔÁ÷´«ÈÈϵÊý ??????????????24 1.6.3¼ÐÌ×´«ÈÈÃæ»ý????????????????????25 1.7 ·´Ó¦¸ªµÄÖ÷Òª¼¼ÊõÌØÐÔ»ã×Ü ????????????????26 2£®ÀäÄýÆ÷µÄÉè¼ÆÓëÑ¡ÐÍ ?????????????????????27 2.1Ñ¡Ôñ»»ÈÈÆ÷µÄÀàÐÍ ????????????????????28 2.2Á÷¶¯¿Õ¼ä¼°Á÷ËÙµÄÈ·¶¨ ??????????????????28 2.3´«ÈÈÃæ»ýµÄÈ·¶¨ ?????????????????????28 2.4ÀäÄýÆ÷¹¤ÒճߴçµÄ¼ÆËã ??????????????????29 2.4.1¹Ü×ÓÊýnµÄÈ·¶¨ ???????????????????29 2.4.2¹Ü×ÓµÄÅÅÁз½Ê½£¬¹Ü¼ä¾àµÄÈ·¶¨ ???????????? 30 2.4.3 ¿ÇÌåÖ±¾¶µÄÈ·¶¨ ???????????????????30
2.4.4ÕÛÁ÷°å ?????????????????????? 30 2.4.5½Ó¹Ü ??????????????????????? 30 2.5.¿ÇÌåºñ¶È ????????????????????????31 2.6»»ÈÈÆ÷·âÍ·µÄÈ·¶¨ ????????????????????31 2.7ÈÝÆ÷·¨À¼µÄÑ¡Ôñ ?????????????????????31 2.8¿ª¿×²¹Ç¿ ????????????????????????31 2.9Ö§×ù ??????????????????????????31 2.10ÀäÄýÆ÷Éè¼Æ»ã×Ü ?????????????????????31 Î壮»·¾³±£»¤ÓëÀͶ¯°²È« .......................................... 32
1£®DOPÈý·Ï´¦Àí............................................... 32 2.DOP°²È«Éú²ú................................................ 33 Áù£®Éè¼Æ½á¹ûÆÀÎöÓë×ܽá........................................... 34 ÖÂл............................................................. 35 ²Î¿¼ÎÄÏ× ................................................................. ...........................................................35
¸½Í¼
1£®´ø¿ØÖƵãµÄ¹¤ÒÕÁ÷³Ìͼ
2£®Ö÷ÒªÉú²úÉ豸½á¹¹³ß´çͼ 3£®»»ÈÈÆ÷½á¹¹Ê¾Òâͼ 4£®Éú²ú³µ¼äµÄÉ豸ÅäÖò¼ÖÃͼ
5£®DOP³§·¿×ܲ¼ÖÃͼ
Ò»£®×ÜÂÛ
1£®¸ÅÊö
1.1ÔöËܼÁDOPµÄÐÔÖÊ
DOP»¯Ñ§ÃûΪÁÚ±½¶þ¼×Ëá¶þÐÁõ¥£¬ÊÇÒ»¸ö´øÓÐÖ§Á´µÄ²àÁ´´¼õ¥£¬ÎÞÉ«ÓÍ×´ÒºÌ壬ÓÐÌØÊâÆøÎ¶¡£±ÈÖØ0.9861(20/20 ),ÈÛµã-55 £¬·Ðµã370 £¨³£Ñ¹£©£¬²»ÈÜÓÚË®£¬ÈÜÓÚÒÒ´¼¡¢ÒÒÃÑ¡¢¿óÎïÓ͵ȴó¶àÊýÓлúÈܼÁ¡£Óë¶þ¶¡õ¥£¨DBP£©Ïà±È£¬DOPµÄ»Ó·¢¶ÈÖ»ÓÐDBPµÄ1/20£»ÓëË®µÄ»¥ÈÜÐԵͣ¬²¢ÓÐÁ¼ºÃµÄµçÐÔÄÜ£¬µ«Ò²ÓÐÆä²»×ãµã£¬ÆäÔÚÈÈÎȶ¨
ÐÔ¡¢ÄÍÇ¨ÒÆÐÔ¡¢Äͺ®ÐÔºÍÎÀÉúÐÔ·½ÃæÉԲ 1.2²úÆ·ÓÃ;
ÁÚ±½¶þ¼×Ëá¶þÐÁõ¥ÊÇÖØÒªµÄͨÓÃÐÍÔöËܼÁ£¬Ö÷ÒªÓÃÓÚ¾ÛÂÈÒÒÏ©Ê÷Ö¬µÄ¼Ó¹¤£¬»¹¿ÉÓÃÓÚ»¯ÏËÊ÷Ö¬¡¢´×ËáÊ÷Ö¬¡¢ABSÊ÷Ö¬¼°Ï𽺵ȸ߾ÛÎïµÄ¼Ó¹¤£¬Ò²¿ÉÓÃÓÚÔìÆá¡¢È¾ÁÏ¡¢·ÖÉ¢¼ÁµÈ¡£
ͨÓü¶DOP£¬¹ã·ºÓÃÓÚËÜÁÏ¡¢Ï𽺡¢ÓÍÆá¼°È黯¼ÁµÈ¹¤ÒµÖС£ÓÃÆäÔöËܵÄPVC ¿ÉÓÃÓÚÖÆÔìÈËÔì¸ï¡¢Å©Óñ¡Ä¤¡¢°ü×°²ÄÁÏ¡¢µçÀµȡ£
µçÆø¼¶DOP£¬¾ßÓÐͨÓü¶DOPµÄÈ«²¿ÐÔÄÜÍ⣬»¹¾ßÓÐºÜºÃµÄµç¾øÔµÐÔÄÜ£¬Ö÷ÒªÓÃÓÚÉú²úµçÏß¡£
Æ·¼¶DOP£¬Ö÷ÒªÓÃÓÚÉú²úʳƷ°ü×°²ÄÁÏ¡£
Ò½Óü¶DOP£¬Ö÷ÒªÓÃÓÚÉú²úÒ½ÁÆÎÀÉúÖÆÆ·£¬ÈçÒ»´ÎÐÔÒ½ÁÆÆ÷¾ß¼°Ò½Óðü×°²ÄÁϵȡ£ Ö÷ÒªÓÃ;£ºDOPÊÇͨÓÃÐÍÔöËܼÁ£¬Ö÷ÒªÓÃÓÚ¾ÛÂÈÒÒϩ֬µÄ¼Ó¹¤¡¢»¹¿ÉÓÃÓÚ»¯µØÊ÷Ö¬¡¢´×ËáÊ÷Ö¬¡¢ABSÊ÷Ö¬¼°Ï𽺵ȸ߾ÛÎïµÄ¼Ó¹¤£¬Ò²¿ÉÓÃÓÚÔìÆá¡¢È¾ÁÏ¡¢·ÖÉ¢¼ÁµÈ¡¢DOPÔöËܵÄPVC¿ÉÓÃÓÚÖÆÔìÈËÔì¸ï¡¢Å©Óñ¡Ä¤¡¢°ü×°²ÄÁÏ¡¢µçÀµȡ£±¾Æ·ÊÇÒ»ÖÖ¶àÖÖÊ÷Ö¬¶¼ÓкÜÇ¿ÈܽâÁ¦µÄÔöËܼÁ,ÄÜÓë¶àÖÖÏËÎ¬ËØÊ÷Ö¬¡¢Ï𽺡¢ÒÒÏ©»ùÊ÷Ö¬ÏàÈÜ£¬ÓÐÁ¼ºÃµÄ³ÉĤÐÔ¡¢Õ³×ÅÐԺͷÀË®ÐÔ¡£³£ÓëÁÚ±½¶þ¼×Ëá¶þÒÒõ¥ÅäºÏÓÃÓÚ´×ËáÏËÎ¬ËØµÄ±¡Ä¤¡¢ÇåÆá¡¢Í¸Ã÷Ö½ºÍÄ£ËÜ·ÛµÈÖÆ×÷ÖС£ÉÙÁ¿ÓÃÓÚÏõ»ùÏËÎ¬ËØµÄÖÆ×÷ÖС£Òà¿ÉÓÃ×÷¶¡ë潺µÄÔöËܼÁ¡£±¾Æ·»¹¿ÉÓÃ×÷ÇýÎÃÓÍ£¨ÔÓÍ£©¡¢¾Û·úÒÒϩͿÁÏ¡¢¹ýÑõ»¯¼×ÒÒͪÒÔ¼°ÏãÁÏ£¨ÈËÔì÷êÏ㣩µÄÈܼÁ¡£¿ÉÒÔ×÷Ϊõ¥½»»»·¨Éú²úÁÚ±½¶þ¼×Ëá¶þ»·¼ºõ¥ºÍÁÚ±½¶þ¼×Ëá¸ß̼´¼õ¥ÒÔ¼°ÆäËûÓлúºÏ³ÉµÄÔÁÏ¡£ 1.3 DOPÔÚ¹úÃñ¾¼ÃÖеÄÖØÒªÐÔ
ÁÚ±½¶þ¼×Ëá¶þÐÁõ¥(DOP)ÊÇĿǰʹÓÃ×î¹ã·ºµÄÔöËܼÁ£¬Ô¼Õ¼ÎÒ¹úÔöËܼÁ×ÜÁ¿45%£¬ÊÇÖØÒªµÄͨÓÃÐÍÔöËܼÁ£¬ÈκÎÔöËܼÁ¶¼ÊÇÒÔËüΪ»ù×¼À´¼ÓÒԱȽϵ쬼¼Êõ¾¼ÃÉÏÕ¼Óоø¶ÔÓÅÊÆ¡£¾ÝÓйØ×ÊÁϱ¨µÀ£¬½üÄêÀ´¹úÍâÔöËܼÁÉú²úÄÜÁ¦³¬¹ýÁË6400kt£¯a£¬¹úÄÚÔöËܼÁÐèÇóÔö³¤ÂÊΪ8£¥×óÓÒ£¬²úÆ·¾ßÓÐÖÊÁ¿¸ß¡¢Æ·ÖÖ¶à¡¢»·¾³ÎÛȾÉÙµÄÌØµã¡£ÔÚʯÓÍ»¯Ñ§¹¤Òµ¡¢Ò½Ò©¹¤Òµ¡¢Çá·Ä¹¤Òµ¡¢ÉúÎﻯ¹¤ÒÔ¼°ÄÜÔ´¡¢½»Í¨ÔËÊäÐÐÒµ¾ùÓй㷺ÓÃ;£¬ÔÚ¹úÃñ¾¼ÃÖÐÕ¼ÓÐÊ®·ÖÖØÒªµÄµØÎ»¡£ 1.4 DOPµÄÊг¡ÐèÇó
Ëæ×ÅÎÒ¹ú¹úÃñ¾¼Ã¿ìËÙÔö³¤£¬ÔöËܼÁ×÷Ϊ»ù´¡»¯¹¤ºÏ³É²ÄÁÏÖú¼ÁµÄÊг¡ÐèÇóÁ¿½«
´ó·ùÌá¸ß¡£ÔÚÓÃÁ¿´óµÄÐÂÁìÓò£¬¹úÄÚÊг¡ÐèÇó½«Ç¿¾¢Ôö³¤¡£µ«ÓÉÓÚÁÚ±½¶þ¼×Ëá¶þÒìÈÉõ¥(DINP)ÔÚijЩӦÓÃÁìÓòµÄÐÔÄܳ¬¹ýÁËDOP£¬Ô¤¼ÆÎ´À´¼¸ÄêÄÚ£¬È«ÇòDOPÊг¡½«ÃæÁÙDINPµÄÌôÕ½¡£ÔÚÊг¡ÉÏ£¬DOPÒ»Ö±Õ¼Óм۸ñÓÅÊÆ£¬¶øÎ´À´Ê±¼ä¹À¼ÆDOPµÄµÍ¼ÛÓÅÊÆ»áÓÐËùÏ÷Èõ¡£
2£®Éè¼ÆµÄÄ¿µÄºÍÒâÒå
ͨ¹ý±¾¿Î³ÌÉè¼ÆÁ¦Çó´ïµ½ÒÔÏÂÄ¿µÄºÍÒâÒ壺
£¨1£©ÔÚÑ§Ï°ÕÆÎÕËùѧµÄ»¯Ñ§¹¤ÒÕѧ¡¢»¯¹¤»úеÉ豸»ù´¡¡¢»¯¹¤ÔÀíµÈ¿Î³ÌµÄ»ù±¾ÀíÂۺͻù´¡ÖªÊ¶µÄ»ù´¡ÉÏ£¬Í¨¹ýÕâ´Î¿Î³ÌÉè¼Æ£¬ÅàÑøÎÒÃÇ×ÛºÏÔËÓÃÕâЩ֪ʶ·ÖÎöºÍ½â¾öʵ¼ÊÎÊÌâµÄÄÜÁ¦ÒÔ¼°Ð×÷¹¥¹ØµÄÄÜÁ¦£¬ÑµÁ·ÎÒÃÇʹÓÃÎÄÏ××ÊÁϺͽøÐм¼ÊõÉè¼Æ¡¢ÔËËãµÄÄÜÁ¦£¬Ìá¸ßÎÄ×ÖºÍÓïÑÔ±í´ïÄÜÁ¦£¬ÎªÒÔºóµÄѧϰºÍ±ÏÒµÂÛÎÄ£¨Éè¼Æ£©´òÏ»ù´¡¡£
£¨2£©Í¨¹ýÍê³ÉÉè¼Æ£¬¿ÉÒÔÖªµÀDOPµÄÓÃ;£»»ù±¾ÕÆÎÕ±½ôûºÍÒìÐÁ´¼ÖÆDOPµÄÉú²ú¹¤ÒÕ£»Á˽â¹úÄÚÍâDOP¹¤ÒµµÄ·¢Õ¹ÏÖ×´£»ÒÔ¼°DOP¹¤ÒµµÄ·¢Õ¹Ç÷ÊÆ¡£
3£®ÏîÄ¿Éè¼ÆÒÀ¾ÝºÍÔÔò
3.1Éè¼ÆÒÀ¾Ý
±¾»¯¹¤¿Î³ÌÉè¼Æ£¬ÒÔÉè¼ÆÈÎÎñÊéΪ»ù´¡£¬×ÛºÏÎÄÏ×¼ìË÷¡¢×ÊÁÏÊÕ¼¯£¬×ۺϷÖÎö£¬ÒÔ×îпÆÑгɹûºÍʵ¼Ê¾ÑéΪÒÀ¾Ý£¬²«ÖÚ¼ÒÖ®³¤£¬Ñ¡ÔñºÏÊÊÉè¼Æ·½°¸¡£ 3.2Éè¼ÆÔÔò
±¾¿ÎÌâ×ñѵÄÉè¼ÆÔÔòºÍÖ¸µ¼Ë¼ÏëÈçÏ£º
£¨1£©°´¼¼ÊõÏȽø¡¢³ÉÊì¿É¿¿¡¢¾¼ÃºÏÀíµÄÔÔò¶Ô¼¼Êõ·½°¸½øÐÐÂÛÖ¤£¬ÒÔÈ·¶¨×î¼Ñ·½°¸£»
£¨2£©¾¡¿ÉÄܲÉÓýÚÄܹ¤Òպ͸ßЧÉ豸£¬³ä·Ö·¢»Ó¹æÄ£Ð§Ó¦£¬½µµÍÄܺġ¢ÎïºÄºÍÉú²ú³É±¾£¬Ìá¸ßÏîÄ¿µÄ¾¼ÃÐ§ÒæºÍÉç»áÐ§Òæ£»
£¨3£©¿¼ÂÇ¡°Èý·Ï¡± ÖÎÀíºÍ×ÛºÏÀûÓø±²úÎ³ä·ÖÖØÊÓ»·±£·ÀÎÛ¡¢¿ÆÑ§Éú²ú¡¢Éú²ú°²È«ºÍÌá¸ßÉç»áÐ§ÒæÎªÔÔòÖ÷Ìå¡£
4£®Éè¼Æ·¶Î§
±¾Éè¼Æ·¶Î§°üÀ¨£º
£¨1£©¹¤ÒÕÉú²ú·½·¨È·¶¨¡¢Éú²úÁ÷³ÌÉè¼ÆÓëÂÛÖ¤ £¨2£©¹¤ÒÕ¼ÆË㣨°üÀ¨ÎïÁϺâË㣬ÈÈÁ¿ºâË㣩
£¨3£©õ¥»¯ºÏ³É¹¤ÒÕÖ÷ÒªÉú²úÉ豸Éè¼ÆÓëÑ¡ÐÍ £¨4£©°²È«Éú²úÓë»·±£ÖÎÀí´ëÊ© £¨5£©Éè¼Æ»æÍ¼
Éè¼ÆÖØµã£ºÉú²ú¹¤ÒÕÉè¼ÆÓëÂÛÖ¤£¬¹¤ÒÕ¼ÆË㣬É豸Éè¼ÆÓëÑ¡ÐÍ£¬Éè¼Æ»æÍ¼¡£
5£®DOPÉú²úÄÜÁ¦¼°ÖÊÁ¿±ê×¼
5.1Éú²úÄÜÁ¦
¸ÃÏîÄ¿Äê²ú8Íò¶ÖDOP£¬Ä꿪¹¤ÈÕΪ330Ì죨ȫÌìºò£©£¬ÈÕ²úDOP 242.42¶Ö¡£ 5.2²úÆ·ÖÊÁ¿±ê×¼
±¾²úÆ·ÖÊÁ¿¹æ¸ñΪһ¼¶Æ·£¬Ö´ÐвúÆ·ÖÊÁ¿¹ú±êGBl1406¡ª8±ê×¼£¬¼û±í1 Ëùʾ¡£
±í1 DOPÖÊÁ¿Ö¸±ê
ÏîÄ¿ Óż¶Æ· Íâ¹Û õ¥º¬Á¿£¬%¡Ý Ãܶȣ¨20¡æ£©£¬g/cm Ëá¶È£¨ÒÔ¶Ô±½¶þ¼×õ¥¼Æ£© % ¡Ü ÉÁµã£¬¡æ¡Ý É«¶È£¨²¬-îÜ£©ºÅ ¡Ü ¼ÓÈȼõÁ¿£¬% ¡Ü Ìå»ýµç×èÂÊ£¬¡Á10?.m¡Ý 113Ö¸±ê Ò»¼¶Æ· ºÏ¸ñÆ· ͸Ã÷ÒºÌ壬ÎÞÐü¸¡Îï 99.50 99.0 99.50 0.981£0.986 0.020 0.015 210 50 0.1 2 100 0.2 1 205 200 0.25 0.5 ¶þ¡¢Éú²ú¹¤ÒÕÁ÷³ÌÉè¼Æ
1£®Éú²ú¹¤ÒÕÑ¡ÔñÓëÂÛÖ¤
Éú²ú¹ý³Ì²Ù×÷·ÖΪ¼äЪʽºÍÁ¬Ðø²Ù×÷¡£¼äЪʽÉú²úµÄÓŵãÊÇÉ豸¼òµ¥¸Ä±äÉú²úÆ·ÖÖÈÝÁ¿£»È±µãÊÇÔÁÏÏûºÄ¶¨¶î¸ß£¬ÄÜÁ¿ÏûºÄ´ó£¬ÀͶ¯Éú²úЧÂʵͣ¬²úÆ·ÖÊÁ¿²»Îȶ¨¡£¼äЪʽÉú²ú·½Ê½ÊÊÓÃÓÚ¶àÆ·ÖÖ¡¢Ð¡ÅúÁ¿µÄÉú²ú¡£¶øÁ¬Ðø·¨Éú²úÄÜÁ¦´ó£¬ÊʺÏÓÚ´ó¶ÖλµÄDOPµÄÉú²ú¡£ÓÉÓÚ±¾Éè¼Æ²úÆ·Éú²úÁ¿½Ï´ó£¬¹Ê²ÉÓÃÁ¬Ðø·¨Éú²ú¡£
õ¥»¯·´Ó¦É豸·ÖËþʽ·´Ó¦Æ÷ºÍ´®Áª¶à¸ª·´Ó¦Æ÷Á½ÀࡣǰÕ߽ṹ¸´ÔÓ£¬µ«½ô´Õ£¬Í¶×ʽϵͣ¬²Ù×÷¿ØÖÆÒªÇó¸ß£¬¶¯Á¦ÏûºÄÉÙ¡£¶ø·´Ó¦¸ª£¬Á÷¶¯ÐÎʽ½Ó½ü·µ»ì£¬¸ªÄÚ¸÷²¿·Ö×é³ÉºÍζÈÍêȫһÖ£¬¶à¸ª´®Á¬ºó£¬¿ÉʹͣÁôʱ¼ä·Ö²¼ÌØÐÔÏòÆ½ÍÆÁ÷ת»¯¡£²¢ÇÒDOPµÈÖ÷ÔöËܼÁµÄÐèÒªÁ¿ºÜ´ó£¬ÇÒÈ«Á¬Ðø»¯Éú²úµÄ²úÆ·ÖÊÁ¿Îȶ¨£¬ÔÁϼ°ÄÜÁ¿ÏûºÄµÍ£¬ÀÍ
¶¯Éú²úÂʸߣ¬±È½Ï¾¼Ã¡£Òò´Ë±¾Éè¼Æ²ÉÓô®Áª¶à¸ª·´Ó¦Æ÷È«Á¬Ðø»¯Éú²ú¹¤ÒÕ¡£ ´ß»¯¼Á·ÖΪËáÐÔ´ß»¯¼ÁºÍ·ÇËáÐÔ´ß»¯¼Á£¬ÓÉÓÚ²ÉÓ÷ÇËáÐÔ´ß»¯¼Á¿ÉÒÔÃâÈ¥ÖкͺÍˮϴÁ½µÀ¹¤Ðò£¬ÇÒͨ¹ý¹ýÂ˼´¿É³ýÈ¥£¬¸úËáÐÔ´ß»¯¼ÁÏà±È£¬ÓÅÔ½ÐÔÔÚÓÚÄÜÉú²ú³ö¸ßÖÊÁ¿µÄÔöËܼÁ²úÆ·ºÍ¼õÉÙÎÛȾ¡£Òò´Ë±¾Éè¼Æ²ÉÓõÄÊÇ·ÇËáÐÔ´ß»¯¼Á¡£
·ÇËáÐÔ´ß»¯¼ÁÓÖ·ÖΪµ¥´ß»¯¼ÁºÍ¸´ÅäÐÍ´ß»¯¼Á£¬ÓÉÓÚµ¥´ß»¯¼Á´ß»¯·´Ó¦Ê±¼ä³¤£¬²»ÊʺÏ×öõ¥»¯·´Ó¦´ß»¯¼Á£¬Ïà·´£¬¸´ÅäÐÍ´ß»¯¼Á´ß»¯·´Ó¦Ê±¼ä¶Ì£¬×ª»¯Âʸߣ¬ËáÖµ½µµÍ·ù¶È´ó£¬±È½ÏÊʺÏ×öõ¥»¯·´Ó¦´ß»¯¼Á¡£Ñõ»¯ÂÁÓëÐÁËáÑÇÎýÒÔ1£º1±ÈÀý¸´Åä·ÇËáÐÔ´ß»¯¼ÁºÏ³ÉDOPЧ¹û×î¼Ñ£¬Á¦Çó´ïµ½Á÷³Ì¼òµ¥£¬É豸ÉÙ£¬ÈÈÄÜÀûÓúÏÀí£¬²úÆ·ÖÊÁ¿¸ß¡£ ¸ù¾Ý¹úÄÚÔÚÒý½ø×°ÖÃÉϳɹ¦Ê¹Óùú²ú´ß»¯¼ÁµÄ¾Ñ飬ѡÓùú²ú´ß»¯¼Á£¬¼ÈÂú×ãÁ˹¤ÒպͲúÆ·ÖÊÁ¿µÄÒªÇó£¬ÓÖ½ÚÔ¼ÁËÍâ»ã£¬¿ÉÒÔÊÕµ½Á¼ºÃµÄ¾¼ÃЧ¹û¡£Á¬Ðø·ÇËáÐÔ´ß»¯õ¥»¯¹¤ÒÕ£¬ÊÇÉÏÊÀ¼Í80Äê´ú³õ¿ªÊ¼³É¹¦Ó¦ÓÃÓÚ¹¤Òµ»¯Éú²úµÄÏȽø¼¼Êõ£¬ÆäµäÐ͵ŤÒÕÁ÷³ÌÓÐÁ½ÖÖ£º1¡¢õ¥»¯¡ªÍÑ´¼Ò»ÖкÍˮϴһÆûÌá¸ÉÔïÒ»¹ýÂË£»2¡¢õ¥»¯Ò»ÖкÍˮϴһÍÑ´¼--ÆûÌá--¸ÉÔïÒ»¹ýÂË¡£
¶þÕ߱Ƚϣ¬µÚ¢ÙÖÖ¼¼ÊõÓòÉÓÃÑõ»¯ÂÁÓëÐÁËáÑÇÎý1£º1±ÈÀý¸´Åä´ß»¯¼Áõ¥»¯·´Ó¦¾ßÓз´Ó¦Ê±¼ä¶Ì¡¢õ¥ÊÕÂʸߡ¢²úÆ·ÖÊÁ¿ºÃ(ËáÖµµÍ¡¢É«¶ÈµÍ¡¢ÈÈÎȶ¨ÐԺá¢Ìå»ýµç×èÂÊ´ó) ¡¢´¦ÀíÌõ¼þ¼òµ¥µÈÓŵ㡣²¢ÇÒ¹«Óù¤³ÌÏûºÄµÍ£¬ÈÈÄÜÀûÓúÏÀí£¬¿ÉÒÔÉú²ú¶àÅÆºÅµÄDOP²úÆ·£¬½áºÏ¹úÄÚÌõ¼þºÍÉú²ú²Ù×÷¾Ñ飬¹ÊÄâ²ÉÓâÙÀàµäÐ͹¤ÒÕÁ÷³Ì£¬Éè¼Æ¹ú²ú»¯ÐµĹ¤ÒÕÁ÷³Ì¡£
×ÛÉÏ·ÖÎö£¬±¾Éè¼ÆÑ¡ÓÃõ¥»¯¡ªÍÑ´¼Ò»ÖкÍˮϴһÆûÌá¸ÉÔïÒ»¹ýÂ˹¤ÒÕÁ÷³Ì£¬²ÉÓô®Áª¶à¸ª·´Ó¦Æ÷Á¬Ðøõ¥»¯¼¼Êõ£¬´ß»¯¼Á²ÉÓÃÑõ»¯ÂÁÓëÐÁËáÑÇÎýÒÔ1£º1±ÈÀý¸´ÅäÐÍ´ß»¯¼Á¡£
2£®¹¤ÒÕ²ÎÊýµÄÈ·¶¨
2.1 õ¥»¯¹¤Ðò
±½ôûºÍÐÁ´¼°´±ÈÀýÔÚ5¸ö´®Áª½×ÌÝÐεÄõ¥»¯¸ªÖУ¬ÔÚÑõ»¯ÂÁÓëÐÁËáÑÇÎýÒÔ1£º1±ÈÀý¸´Åä´ß»¯¼Á×÷ÓÃÏÂõ¥»¯·´Ó¦Éú³É´Öõ¥£¬Ö÷Òª¹¤ÒÕ²ÎÊýÈ·¶¨ÈçÏ£º (1)½øÁÏζȼ°5¸ªµÄ·´Ó¦Î¶ȼû±í2¡£ (2)ͶÁϱȣºPA£º2Ò»EH=1£º2£®30 (wt) (3)´ß»¯¼ÁÁ¿£º0£®03£¥ (wt) (4)õ¥»¯Ñ¹Á¦£º³£Ñ¹(´øµª·â)
±í2 ½øÁÏζȼ°Ó븪·´Ó¦Î¶È
PA 170 2Ò»EH 175 ´ß»¯¼Á 20 ¸ª1 190 ¸ª2 200 ¸ª3 210 ¸ª4 220 ¸ª5 230 (5)Í£Áôʱ¼ä£ºÔ¼7h£¬õ¥»¯¸ªÌå»ý27.4m3 (6)õ¥»¯¸ª½Á°èÆ÷תËÙ£º74r£¯min (7)×Üת»¯ÂÊ£ºÔ¼99£®5£¥ 2.2 ÍÑ´¼¹¤Ðò
ÓÉÓÚõ¥»¯·´Ó¦ÊÇÔÚ¹ýÁ¿´¼µÄÌõ¼þϽøÐе쬱ØÐ뽫´Öõ¥ÖеĴ¼Íѳý£¬»ØÊÕÖØ¸´ÀûÓᣱ¾Éè¼Æ²ÉÓÃÕæ¿Õ½µÄ¤ÍÑ´¼¹¤ÒÕ£¬ÈÈÄÜÀûÓúÏÀí£¬ÍÑ´¼Ð§Âʸߣ¬¿ÉÍÑ´¼ÖÁ1£¥×óÓÒ¡£ÍÑ´¼¹¤ÒÕ²ÎÊýÈ·¶¨ÈçÏ£º (1)½øÁÏ´Öõ¥Î¶ȣº230¡æ (2)½øÁÏ´Öõ¥º¬´¼Á¿£º16£¥¡«17£¥ (3)½µÄ¤ÍÑ´¼Õæ¿Õ¶È£º30mbar (4)¼ÓÈÈÕôÆûѹÁ¦£º20ba 2.3 Öк͡¢Ë®Ï´¹¤Ðò
ÓÉÓÚÔÚõ¥»¯¹ý³ÌÖлáÉú³ÉһЩËáÐÔÔÓÖÊ£¬Èçµ¥Ëáõ¥µÈ£¬±¾Éè¼Æ²ÉÓüÓÈëNa0HË®ÈÜÒº½øÐÐÖкͣ¬Éú³É¿ÉÈÜÓÚË®µÄÄÆÑÎÓëõ¥·ÖÀë¡£ÖкÍˮϴ¹¤ÒÕ²ÎÊýÈ·¶¨ÈçÏ£º (1)Na0HË®ÈÜҺŨ¶È£º0£®3(wt£¥) (2)ˮϴζȣº95¡æ (3)´Öõ¥£º¼î=6£º1(vo1) (4)ÖкͽÁ°èתËÙ£º180r£¯min (5)ˮϴ½Á°èתËÙ£º50r£¯min (6)NaOHµ¥ºÄ£º0£®4kg£¯tDOP
(7)ÖкÍˮϴºóËáÖµ£º0£®01¡«0£®02KOH mg£¯DOP 2.4 ÆûÌṤÐò
ÆûÌáÊÇͨ¹ýÖ±½ÓÕôÆû¼õѹÕôÁ󣬳ýÈ¥´Öõ¥ÖеĴ¼ºÍÓÐÆøÎ¶µÄµÍ·ÐÎ±¾Éè¼Æ²ÉÓùýÈÈÕôÆûÖ±½Ó¼õѹÆûÌṤÒÕ¡£ÆûÌá¸ÉÔ﹤ÒÕ²ÎÊýÈ·¶¨ÈçÏ£º (1)´Öõ¥ÈËËþζȣº140¡«1600C (2)ÆûÌáËþ¶¥²¿Õæ¿Õ¶È£º40mbar
(3)¸ÉÔïËþ¶¥²¿Õæ¿Õ¶È£º99mbar (4)´Öõ¥Á¿£ºÆûÌáÕôÆûÁ¿£º10£º1(wt)
(5)¸ÉÔïËþ³ö¿Úõ¥Öк¬Ë®Á¿£º0£®01£¥ ¡«0£®05£¥ (wt) 2.5 ¹ýÂ˹¤Ðò
ÔÚ´Öõ¥ÖмÓÈëÎü¸½¼ÁºÍÖúÂ˼Á£¬Íѳý´Öõ¥Öк¬É«ËصÄÓлúÎïºÍÎü¸½Íѳý²Ð´æµÄ´ß»¯¼ÁºÍÆäËü»úеÔÓÖÊ£¬ÒÔ±£Ö¤DOP²úÆ·Íâ¹ÛµÄ͸Ã÷¶ÈºÍ´¿¶È¡£±¾Éè¼Æ²ÉÓöþ¼¶¹ýÂ˹¤ÒÕ£¬´ÖÂ˲ÉÓÃʱ¼ä³Ì¿ØµÄ·Ò´ï¹ýÂËÆ÷£¬¾«Â˲ÉÓöà²ãÂËÖ½¡£¹ýÂ˹¤Ðò¹¤ÒÕ²ÎÊýÈ·¶¨ÈçÏ£º (1)´Öõ¥Î¶ȣº90¡æ
(2)·Ò´ï¹ýÂËÆ÷´ÖÂËÖÜÆÚ£º48h (3)¾«Â˺óDOPɫֵ£º10¡«15(HAzEN)
3. Éú²ú¹¤ÒÕÁ÷³Ìͼ¼°Æä˵Ã÷
3.1DOPÉú²ú¹¤ÒÕÁ÷³Ì¼òͼ£¨¼ûͼ1£© ±½ôû¡¢ÒìÐÁ´¼ ´ß»¯¼Á¡¢N2 NaOH ÎÞÀë×ÓË® ÖúÂ˼Á Ò»¼¶õ¥»¯ ¶þ¼¶õ¥»¯ ÖкÍˮϴ ÆûÌáÍÑ´¼ ¸ÉÔï ¹ýÂË ·ÏË® ͼ1 DOP¹¤ÒÕÁ÷³Ì·½¿éͼ
ÂËÒº ²úÆ· 3.2 Éú²ú¹¤ÒÕÁ÷³Ì˵Ã÷£¨²Î¿¼CADͼֽ¢ñ£º¹¤ÒÕÁ÷³Ìͼ£©
ÈÛÈÚ±½ôûºÍÐÁ´¼ÒÔÒ»¶¨µÄĦ¶û±È[(1:2.2¡«1:2.5)ÔÚ130-150ÏÈÖÆ³Éµ¥õ¥,ÔÙ¾Ô¤ÈȺó½øÈëËĸö´®ÁªµÄ½×ÌÝʽõ¥»¯¸ªµÄµÚÒ»¼¶.·ÇËữ´ß»¯¼ÁÒ²Ôڴ˼ÓÈë.µÚ¶þ¼¶õ¥»¯¸ªÎ¶ȿØÖƲ»µÍÓÚ180,×îºóÒ»¼¶õ¥»¯Î¶ÈΪ220¡«230,õ¥»¯²¿·ÖÓÃ3.9MPaµÄÕôÆû¼ÓÈÈ.ÁÚ±½¶þ¼×Ëáµ¥õ¥µÄת»¯ÂÊΪ99.5%¡«99.9%¡£ÎªÁË·ÀÖ¹·´Ó¦»ìºÏÎïÔÚ¸ßÎÂϳ¤ÆÚÍ£Áô¶ø×ÅÉ«£¬²¢Ç¿»¯õ¥»¯¹ý³Ì£¬ÔÚ¸÷¼¶õ¥»¯¸ªµÄµ×²¿¶¼Í¨Èë¸ß´¿¶ÈµÄµªÆø£¨Ñõº¬Á¿£¼10mg/kgÖкͣ¬Ë®Ï´ÊÇÔÚÒ»¸ö´ø½Á°èµÄÈÝÆ÷ÖÐͬʱ½øÐеġ£¼îµÄÓÃÁ¿Îª·´Ó¦»ìºÏÎïËá
ÖµµÄ3¡«5±¶¡£Ê¹ÓÃ20%µÄNaOHË®ÈÜÒº£¬µ±¼ÓÈëÎÞÀë×ÓË®ºó¼îҺŨ¶È½öΪ0.3%×óÓÒ¡£Òò´ËÎÞÐèÔÚ½øÐÐÒ»´Îµ¥¶ÀµÄˮϴ¡£·ÇËáÐÔ´ß»¯¼ÁÒ²ÔÚÖк͡¢Ë®Ï´¹¤Ðò±»Ï´È¥¡£ È»ºóÎïÁϾÍÑ´¼£¨1.32¡«2.67 kPa,50¡«80¡æ£©¡¢¸ÉÔ1.32 kPa,50¡«80¡æ£©ºóËÍÖÁ¹ýÂ˹¤Ðò¡£¹ýÂ˹¤Ðò²»ÓÃÒ»°ãµÄ»îÐÔÌ¿£¬¶øÓÃÌØÊâµÄÎü¸½¼ÁºÍÖúÂ˼Á¡£Îü¸½¼Á³É·ÖΪSiO2¡¢AL2O3¡¢Fe2O3 ¡¢MgOµÈ£¬ÖúÂ˼Á£¨¹èÔåÍÁ£©³É·ÖΪSiO2¡¢AL2O3¡¢Fe2O3 ¡¢CaO¡¢MgOµÈ¡£¸Ã¹¤ÐòµÄÖ÷ҪĿµÄÊÇͨ¹ýÎü¸½¼ÁºÍÖúÂ˼ÁµÄÎü¸½£¬ÍÑÉ«×÷Ó㬱£Ö¤²úÆ·DOPµÄÉ«ÔóºÍÌå»ýµç×èÂÊÁ½ÏîÖ¸±ê£¬Í¬Ê±³ýÈ¥DOPÖвдæµÄ΢Á¿´ß»¯¼ÁºÍÆäËû»úеÔÓÖÊ¡£×îºóµÃµ½¸ßÖÊÁ¿µÄDOP¡£DOPµÄÊÕÂÊÒÔ±½ôû»òÒÔÐÁ´¼Îª99.3%¡£
»ØÊÕµÄÐÁ´¼Ò»²¿·ÖÖ±½ÓÑ»·µ½õ¥»¯²¿·ÖʹÓã¬ÁíÒ»²¿·ÖÐè½øÐзÖÁóºÍ´ß»¯¼ÓÇâ´¦Àí¡£Éú²ú·ÏË®£¨CODÖµ700¡«1500mHg/L£©ÓûîÐÔÎÛÄà½øÐÐÉú»¯´¦ÀíºóÔÙÅÅ·Å¡£ ±¾¹¤ÒÕÁ÷³ÌÌØµã£ºÔÁϼòµ¥£¬¹¤ÒÕÁ÷³Ì¶Ì£¬ÎïÁÏÑ»·Ê¹Óã¬Éú²úЧÂʸߡ£
Èý¡¢¹¤ÒÕ¼ÆËã
1¡¢ÎïÁϺâËã
1.1 Éè¼ÆÉú²úÄÜÁ¦
DOPÄêÉú²úÄÜÁ¦ÎªÄêÉú²ú30000¶Ö/Ä꣬É蹤×÷ÈÕΪ330Ìì DOP 30000¶Ö ÄêÉú²úÈÕ 330Ìì ÈÕ²úDOP30000¡Â330=90.90¶Ö
ÿСʱDOPµÄ²úÁ¿Éú 90.90¡Â24=3.79¶Ö ÒªÇóDOPµÄÉú²ú¹æ¸ñ
²úÆ·¹æ¸ñ£ºÒ»µÈÆ· DOP º¬Á¿99.5% ÿСʱҪµÃ´¿DOPΪ£º3.79¡Á99.5%=3.77¶Ö ÉèÕû¸ö¹ý³ÌÖ®ÖÐDOPËðʧÁ¿Îª4%
Ôòʵ¼ÊÿСʱ²ú´¿DOPΪ3.77¡Â£¨1£4%£©=3.93¶Ö
·Ö×ÓÁ¿£º±½ôû 148.12 ÒìÐÁ´¼130.0 DOP 390.3 H2O 18 1.2Ò»¼¶õ¥»¯¶ÎÎïÁϼÆËã ¸ù¾ÝÒ»¼¶õ¥»¯·´Ó¦Ê½£º
¶þ¼¶õ¥»¯·´Ó¦Ê½£º
µÚÒ»²½õ¥»¯×ª»¯ÂÊΪ100%£¬µÚ¶þ²½õ¥»¯×ª»¯ÂÊΪ99.5%. һСʱһ¼¶õ¥»¯·´Ó¦¸ª
½ø¸ª ±½ôûµÄÁ¿Îª£º3.93¡Á1000¡Â390.3¡Â0.995= 10.12 kmol ¸ù¾ÝͶÁÏ±È ±½ôû£ºÒìÐÁ´¼=1 : 2.3 ÒìÐÁ´¼Í¶ÈëÁ¿Îª10.12¡Á2.2=23.28 kmol
ÒìÐÁ´¼Ò»²¿·Ö×÷Ϊ´øË®¼ÁÓëˮһÆð³ö¸ª£¬ÒìÐÁ´¼¾ÀäÄýÆ÷ÀäÈ´ÔÙ»ØÁ÷ÖÁ·´Ó¦¸ªÖУ¬¾²â¶¨ »ØÁ÷±ÈΪ2.5£¬Éè»ØÁ÷ÒìÐÁ´¼Á¿X kmol Ôò³ö¸ªÒìÐÁ´¼Îª 2.5X kmol ×ÜÒìÐÁ´¼Á¿(23.28 +X) kmol ³ö¸ª ÒìÐÁ´¼Á¿Îª2.5X=23.28¡ª10.12+X X=8.77kmol
×ÜÒìÐÁ´¼Îª 23.28+8.77=32.05 kmol ³ö¸ªÒìÐÁ´¼Îª 21.93 kmol µ¥Ëáõ¥µÄÁ¿ 10.12 kmol 1.2¶þ¼¶õ¥»¯¶Î¸ª1ÎïÁϼÆËã
+ H2O ½ø¸ª ÒìÐÁ´¼ 21.93 kmol µ¥Ëáõ¥µÄÁ¿ 10.12 kmol
Ñõ»¯ÂÁÓëÐÁËáÑÇÎý¸´Åä´ß»¯¼ÁÁ¿0.12 kmol N2 3 m3/h ³ö¸ª Éèת»¯ÂÊΪX
µÚÒ»¸ª DOP²úÁ¿Îª 10.12X kmol µÚ¶þ¸ª DOP²úÁ¿Îª 10.12X£¨1-X£©kmol µÚÈý¸ª DOP²úÁ¿Îª 10.12X£¨1-X£©kmol µÚËĸª DOP²úÁ¿Îª 10.12X(1-X)(1-X) kmol µÚÎ帪 DOP²úÁ¿Îª 10.12X£¨1-X£©(1-X)(1-X) kmol ËùÒÔ
10.12X+10.12X(1-X)+10.12X(1-X)+10.12X(1-X) 2 +10.12X(1-X) 3¡Ü10.12 X=0.523 ¼´·´Ó³µÄת»¯ÂÊΪX=0.523
DOPµÄÎïÖʵÄÁ¿nD?10.12?0.523?5.29kmol/h ÒìÐÁ´¼Á¿ÎªnB?21.93?5.29?16.64kmol/h µ¥Ëáõ¥µÄÁ¿ 10.12 £5.29=4.83kmol/h Ñõ»¯ÂÁÓëÐÁËáÑÇÎý¸´Åä´ß»¯¼ÁÁ¿0.12kmol
²úÉúµÄË®µÄÎïÖʵÄÁ¿nË®=10.12?0.523?5.29kmol/h
ÒìÐÁ´¼Ò»²¿·Ö×÷Ϊ´øË®¼ÁÓëˮһÆð³ö¸ª£¬ÒìÐÁ´¼¾ÀäÄýÆ÷ÀäÈ´ÔÙ»ØÁ÷ÖÁ·´Ó¦¸ªÖУ¬¾²â¶¨ nB:nË®=2.5:1¡£ËùÒÔnB=5.29?2.5=13.23 kmol/h N2 3m3/h,ת»¯ÎªÄ¦¶ûÁ÷Á¿£º
3?101500?0.121kmol
8.314?303.15 ¡àÿһСʱ½«ÓУº³ö·´Ó¦¸ª¡£
V?nRT(0.121?5.29?13.23)?8.314?473.15??722.46m3
ÅÅp101.5001.3õ¥»¯¹¤¶ÎÎïÁϺâ½á¹û
±í4£®Ò»¼¶õ¥»¯¶ÎÎïÁϺâËã±í
ÈëËþ ±½ôû ÒìÐÁ´¼ µ¥Ëáõ¥ ³öËþ ±½ôû ÒìÐÁ´¼ µ¥Ëáõ¥ Á¿£¨kmol/h£© 26.96 80.86 0 Á¿£¨kmol/h£© 0 53.90 26.96 Ħ¶ûº¬Á¿£¨%£© 25.0 75.0 0 Ħ¶ûº¬Á¿£¨%£© 0 66.67 33.33
±í5 ¶þ¼¶õ¥»¯¶Î¸ª1ÎïÁϺâËã±í
È븪 ÒìÐÁ´¼ µ¥Ëáõ¥ Ñõ»¯ÂÁÓëÐÁËáÑÇÎý N2 Ë® DOP Á¿£¨kmol/h£© 53.90 26.96 0.32 0.32216 0 0 ³ö¸ª ÒìÐÁ´¼ µ¥Ëáõ¥ Ñõ»¯ÂÁÓëÐÁËáÑÇÎý N2 Ë® DOP Á¿£¨kmol/h£© 39.80 12.86 0.32 0.32216 14.10 14.10 2.ÈÈÁ¿ºâËã
±í6 ¸÷ÎïÖʱÈÈÈÈÝ ÎïÖÊ Cp,m/kJ/(mol.k) (303K£© ÒìÐÁ´¼ ±½ôû ÁÚ±½¶þ¼×ËáÒ»ÐÁõ¥ ×¢£ºA------±½ôû£»B-----ÒìÐÁ´¼;C------ÁÚ±½¶þ¼×ËáÒ»ÐÁõ¥
0.2856 0.2559 0.4523 Cp,m/kJ/(mol.k) (423K£© 0..3454 0.2829 0.5347 Cp,m/kJ/?mol.K? 0.3155 0.2694 0.4935 ¦¤fHm?298K?/kJ/mol -373.2 -672.6 -1120.6 1.Ô¤ÈÈÆ÷ÏÔÈȼÆË㣺
Ô¤ÈÈÆ÷²ÉÓÃ3.9MPaÕôÆû½«ÔÁÏÏÈÔ¤Èȵ½1500C
QA =nACp,mA?T=10.12?269.4?[(150?30)?273.15]?1.072?106kJ QB=nBCp,mB?T?32.05?315.5?(120?273.15)?3.975?106kJ 2.·´Ó¦¸ªÈÈÁ¿µÄºâËã ÒÔÒ»¼¶õ¥»¯·´Ó¦¸ªÎªÀý£º
Á¬Ðø¸ªÊ½·´Ó¦Æ÷¿É¿´³ÉΪһ³¨¿ªÎïϵ£¬¸ù¾ÝÈÈÁ¦Ñ§µÚÒ»¶¨ÂÉ£¬ÆäÈÈÁ¦Ñ§ºâËãʽ¿É±í´ïΪ£º
?H?q
ʽÖУº?H¡ª¡ª¡ª¡ªÎïϵìʱ估·´Ó¦ìʱ䣬kJ; q¡ª¡ª¡ª¡ªÎïϵÓë»·¾³½»»»µÄÈÈ¡£ ÓÉÓÚ·´Ó¦ÊÇÔÚºãÎÂϽøÐУ¬ËùÒÔÎïϵìʱäΪÁã¡£
·´Ó¦ ìʱäµÄ¼ÆËãÈçÏ£º
A (l£¬423.15K)+ B(l,423.15K) ?H7 C(l,423.5K) ?H1
?H4
A(l£¬404.75K) ?H2 ?H6
A(s£¬404.75K)
?H3 ?H5
A (s£¬298.15K)+ B(l,298.15K) C(l,298.5K) ?H1?nACp,m?T??10.12?269.4?(423.15?404.75)??0.502?105kJ/h ÓÉÓÚÔÚºãκãѹϽøÐУ¬ËùÒÔ?H2=-32 kJ/h ?H3?nACp,m?T??10.12?269.4?(404.75?298.15)??0.291?106kJ/h ?H4?nBCp,m?T??32.05?311.5?(423.15?298.15)??1.248?106kJ/h
?H5?nC(?fHmC??fHmA??fHmB)?10.12(?1120.6?672.6?373.2)??0.757?106kJ/h ?H6?nC?Cp,mC?T?10.12?493.5?(423.15?298.15)?0.624?106kJ/h
ËùÒÔ£º?H7??H1??H2??H3??H4??H5??H6??1.73?106kJ/h
¹Ê·´Ó¦Îïϵ½«·Å³ö-1.73¡Á106kJ/h£¬Îª±£³Ö·´Ó¦ÔÚºãÎÂϽøÐУ¬ÐèÔÚ¼ÐÌ×ÖгåÒ»¶¨Á÷Á¿µÄÀäÈ´Ë®¡£ 3.»»ÈÈÆ÷µÄÈÈÁ¿ºâËã
·Ö×ÓÁ¿£º±½ôû 148.12 ÒìÐÁ´¼130.0 DOP 390.3 H2O 18
ÓÉÓÚ·´Ó¦Î¶ÈÔÚ2000CÒÔϽøÐУ¬Á½Á÷ÌåζȱäΪ£ºÈÈÁ÷Ìå½øÈë»»ÈÈÆ÷µÄζÈΪ1900C£¬³ö¿Úζȶ¨Îª700C£»ÀäÁ÷Ì壨ѻ·Ë®£©½ø¿ÚζÈΪ250C£¬³ö¿ÚζÈΪ600C¡£ Q1=mcp¡÷T, ¡÷T=1300C A-Òì±û´¼ B-Ë® C-N2 mA = nAMA =16.64¡Á130=2163.2 kg/h mB = nBMB =5.29¡Á18 =95.22 kg/h mc = ncMc = 0.121¡Á14 =1.694
Q1=mcp¡÷T=2163.2¡Á1.97¡Á130+95.22¡Á4.34¡Á130+1.694¡Á0.771¡Á130 =553995.52+53723.124+169.789 =607888.43 KJ/h
±í10ÈëÀäÄýÆ÷µÄÆøÌåµÄ±ÈÈÈÈÝ
×é·Ö ±ÈÈÈÈÝ ÒìÐÁ´¼ 200C 0Ë® 200C 4.505 5.29 53723.124 0N2 060C 060C 4.182 200C 0.796 0.121 169.789 060C 0.746 0KJ/(kg.¡æ) ×é³É kmol ²úÉúÈÈQ1 kJ/h 2.225 1.732 16.64 553995.25
±í11 ÀäÄýÒº×é·ÖÆø»¯ÈȺÍÒºÌåÈÈÈÝ
×é·Ö Æø»¯ÈÈwr KJ/mol ÒºÌå±ÈÈÈÈÝKJ/(kg.¡æ) ×é³É kmol/h ÀäÄý·ÅÈÈ kJ/h ÒìÐÁ´¼ 61.99 2.294 16.64 1031513.6 Ë® 40.69 4.178 5.29 215250.1 Q2 = 16.64¡Á61.99¡Á1000+5.29¡Á40.69¡Á1000 = 1031513.6+215250.1 = 1246763.7 kJ/h
ÀäÄý·Å³ö×ÜÈÈQ2=1031513.6+215250.1=1246763.7 kJ/h Q×Ü=Q1 + Q2 =607888.43+1246763.7=1854652.13kJ/h =515.18 kw ¹ÊÀäÈ´Ë®ÓÃÁ¿£ºwË®=
Q×Ü1854652.13??12683.12kg/h cË®?t4.178?35
ËÄ¡¢Ö÷ÒªÉ豸Éè¼ÆÓëÑ¡ÐÍ
1¡¢·´Ó¦¸ªµÄÉè¼ÆÓëÑ¡ÐÍ
1.1·´Ó¦¸ªÌå»ýÈ·¶¨
Ϊ·½±ãÆð¼û£¬ÒÔÏÂÓÃA±íʾ±½ôû£¬ÓÃB±íʾÒìÐÁ´¼¡£ÎïÁÏÔÚ·´Ó¦¹ý³ÌÖеÄÌå»ý
»ù±¾²»±ä¡£ÓÉÓÚ½Á°èËٶȽϴ󣬷´Ó¦ÎïÁÏÔÚ·´Ó¦Æ÷ÄÚµÄÁ÷¶¯×´¿ö¿ÉÊÓΪ³ÊÈ«»ìÁ÷£¬ÔÚ¶¨Ì¬Ê±£¬ÔÚµÈεÈÈÝÌõ¼þ϶ÔÕû¸ö·´Ó¦Æ÷×÷AµÄÎïÁϺâË㣺 ·´Ó¦¸ªÈÝ»ý°´ÏÂʽ¼ÆË㣺 VR=Q0¡Át¡Á(1+?)
(8)
(10)
Q0=QA+QB (9) QA=nAMA/¦ÑAt
ʽÖУºnAµ¥Î»Ê±¼äÄÚ£¨1Сʱ£©´¦ÀíµÄ±½ôûĦ¶ûÊý£»MA±½ôûµÄ·Ö×ÓÁ¿£»±½ôûÃÜ¶È ¦Ñ
A
=1.527g/cm3; tµ¥Î»Ê±¼ä£¨1 h£©QAºÍQB£¬·Ö±ðΪ±½ôûºÍÒìÐÁ´¼µÄÌå»ýÁ÷Á¿;?Ϊ½Á°èÈÝÆ÷µÄ±¸ÓÃϵÊý£¬Ò»°ãÈ¡0.1¡«0.15£¬È¡0.1¡£
QA=nAMA/¦Ñt=10.12¡Á1000¡Á148.12 ¡Â(1.527 ¡Á3600)=272.68cm3 / S ͬÀíÒìÐÁ´¼Ìå»ýÁ÷Á¿QB ÒìÐÁ´¼ÃܶȦÑB =0.8176g/cm3
QB=nBMB/¦ÑBt=32.05¡Á1000¡Á130.0 ¡Â(0.8176 ¡Á3600)=1415.56m3 / S Q0=QA+QB=272.68+1415.56=1688.24cm3 / S
µ¥¼¶õ¥»¯·´Ó¦¸ªÖУ¬ÎïÁÏµÄÆ½¾ùÍ£Áôʱ¼äΪ6.95¡Â5=1.37 h VR=Q0t£¨1+?£©
=1688.24¡Á1.37¡Á3600¡Á1.1 =9.25m3
×°ÁÏϵÊý?£¬¸ù¾Ýʵ¼ÊÉú²úÌõ¼þ»òʵÑé½á¹û¶ø¶¨£¬Èô½Á°è״̬ƽÎÈ»òÎïÁϵÄÕ³¶È½Ï¸ß?¿ÉÈ¡0.8¡«0.85¡£±¾Éè¼ÆÎïÁϽÁ°è״̬½ÏƽÎÈ£¬?È¡0.85¡£ ¹Ê½Á°è¸ªµÄÓÐЧÌå»ýΪ£º V=VR/0.85=9.25/0.85=10.88m3 1.2·´Ó¦¸ª¸ß¶ÈÓëµ×ÃæÖ±¾¶ ·´Ó¦¸ªµÄ¸ß¶ÈÓëµ×ÃæÖ±¾¶¹ØÏµ£º
H=1.3Di
µ×ÃæÖ±¾¶£º
Di?34V34?10.88.??2.20m 1.3?1.3?3.14H=1.3Di=1.3¡Á2.2=2.86m
¹ÊÒºÃæÉî¶Èh=4VR/?Di2=4¡Á9.25¡Â3.14¡Á2.2¡Á2.2=2.43m
µ±Di?2200mm£¬²é±í16-6µÃ¸÷²ÎÊýÈç±í6Ëùʾ
±í6 Ëù²éµÃµÄ¸÷²ÎÊý
ÇúÃæ¸ß¶Èh1 550mm
Ö±±ß¸ß¶Èh2
40mm
1.3·´Ó¦¸ªÎ¶ÈÓëѹÁ¦
²é±í4¡ª5 Éè¼ÆÎ¶ȣº150¡æ+20¡æ£½170¡æ
PT??gh?Pw
»ìºÏҺƽ¾ùÃܶÈ
¦Ñ=nAMA/(nAMA+nBMB)¡Á¦ÑA+ nBMB/(nAMA+nBMB)¡Á¦Ñ
B
=0.2646¡Á1.527 + 0.8176¡Á0.7354
=1.005g/m3 ÒÑÖª£ºPW =0.1015MPa Ôò¹¤×÷ѹÁ¦£º
PT??gh?Pw
?1.005?103?9.81?2.43?0.1015?1000000 ?0.125MPa
Éè¼ÆÑ¹Á¦Îª¹¤×÷ѹÁ¦µÄ110%£¬ÔòÉè¼ÆÑ¹Á¦Îª£º Pc=1.1PT=1.1¡Á0.125MPa=0.1375MPa
É豸ѡ²Ä£ºÓÉÓÚÔÁϺͲúÎï¶Ô¸Ö²ÄµÄ¸¯Ê´²»´ó£¬Î¶ÈΪ150¡æ£¬Ñ¹Á¦Îª³£Ñ¹£¬±¾Éè¼Æ´ÓÂú×ãÉú²ú¹¤ÒÕÐèÒª¼°±£Ö¤õ¥»¯¸ªÊ¹ÓÃÊÙÃüµÄ½Ç¶È³ö·¢£¬õ¥»¯¸ªµÄ²ÄÖÊÑ¡ÓøߺϽð¸Ö0Cr18Nil2M-o2Ti¡£ 1.4ºñ¶È¼ÆËã
Pc=0.1375MPa£¬T=170¡æ£¬Di=2200mm£¬[¦Ät]=104MPa£¬¦Õ=1.0(Ë«Ãæº¸¶Ô½Ó£¬100%̽ÉË)£¬¸¯Ê´Ô£Á¿C2=2mm
¼ÆËãºñ¶È¦ÄÈçÏ£º
¦Ä?PcDi2[?t]??Pc0.1375MPa?2200mm?2?104MPa?1.0?0.1375MPa ?1.46mmÉè¼Æºñ¶ÈSdÈçÏ£º
¦Äd?¦Ä?C2?1.46mm?2mm
?3.46mm¦Äd=4.3£¬²é±í4--9 ¸ºÆ«²îC1=0.25mm
¦Äd+C1=3.71mm Ô²ÕûºóΪ4mm£¬¼´ÃûÒåºñ¶È¦Än=4mm ¸´Ñé¦Än¡Á6%=0.24mm ËùÒԸ÷´Ó¦¸ª¿ÉÒÔÓÃ4mmµÄ 0Cr18Nil2M-o2Ti¸ßºÏ½ð¸Ö°åÖÆ×÷¡£ ˮѹУÑ飺 ¸ù¾Ý?T?1.25PC(Di?¦Äe)?0.9??s ÓУº 2¦Äe0.9??s?0.9?1.0?200MPa?180MPa 1.25PC(Di?¦Äe)?T?2¦Äe1.25?0.1375MPa?(2200mm?4mm?2mm)? 2?(4mm?2mm)?94.62MPaÓɴ˵ãº?T?0.9??S=180 ¹ÊÆäÇ¿¶ÈÂú×ãÒªÇó¡£ 1.5½Á°èÆ÷µÄÉè¼Æ¼°Ñ¡ÐÍ ±í8 ½Á°èÆ÷ÐÍʽÊÊÓÃÌõ¼þ±í ½Á°èÆ÷ÐͶÔʽ Á÷Ñ»· Á÷¶¯×´Ì¬ µÍÕ³¶È»ìºÏ ¡ð ¸ßÕ³¶ÈÒº·ÖÈÜ»ìºÏÉ¢ ½â ´«ÈÈ·´Ó¦ ¡ð ½Á°èÄ¿µÄ תËÙ·¶½Á°èÈÝΧÆ÷ÈÝ»ý (r/min3(m) ) ÍÄÁ÷À©É¢ ¼ôÇÐÁ÷ ¹ÌÌåÐü¸¡ ÆøÌåÎüÊÕ ½á¾§ ´«ÈÈ ÒºÏà·´Ó¦ ×î¸ßÕ³¶È(P) ÎÐÂÖ¡ð ¡ð ʽ ½°¡ð ¡ð ʽ ÍÆ½ø¡ð ¡ð ʽ ÕÛÒ¶¿ªÆô¡ð ¡ð ÎÐÂÖʽ ²¼¶ûÂí¡ð ¡ð ½ðʽ ê¡ð ʽ Âݸˡð ʽ ÂÝ´ø¡ð ʽ ¡ð ¡ð ¡ð ¡ð ¡ð ¡ð ¡ð ¡ð 1¡«100 10¡«300 10¡«300 10¡«500 500 ¡ð ¡ð ¡ð ¡ð ¡ð ¡ð ¡ð ¡ð 1¡«200 1¡«1000 20 ¡ð ¡ð ¡ð ¡ð ¡ð ¡ð ¡ð 500 ¡ð ¡ð ¡ð ¡ð ¡ð ¡ð 1¡«1000 10¡«300 500 ¡ð ¡ð ¡ð ¡ð ¡ð ¡ð 1¡«100 10¡«300 500 ¡ð ¡ð 1¡«100 1¡«100 0.5¡«50 0.5¡«50 1000 1000 1000 ¡ð ¡ð 1¡«50 ¡ð ¡ð 1¡«50 ×¢£ºÓСðÕßΪºÏÓ㬿հ×Õß²»Ïê»ò²»ºÏÓᣠ1.5.1 ½Á°èÆ÷µÄÑ¡Óü°³ß´ç ½Á°èÆ÷µÄÑ¡ÐÍÒª¸ù¾Ý½Á°èÄ¿µÄ£¬ÎïÁÏÕ³¶È£¬½Á°èÈÝÆ÷ÈÝ»ýµÄ´óСÀ´×ۺϿ¼ÂÇ¡£ ²ÎÕÕÉÏ±í£¬ÎªÁËʵÏÖÎïÁϵľùÏà»ìºÏ£¬´ïµ½·µ»ì£¬ËùÒÔ±¾Éè¼ÆÑ¡ÓÃÁùƬƽֱҶԲÅÌÎÐÂÖʽ½Á°èÆ÷¡£ÓÉ¡¶»¯¹¤ÔÀí¡·Éϲá½Ì²ÄÖбí4-1£¬Ñ¡È¡Ò¶ÂÖÖ±¾¶d/Di=0.33,¼´d=0.73m,Ò¶¿íb=0.2mתËÙÈ¡n=1.2r/s£¬Ò¶ÂÖ¾à²Ûµ×¸ß¶ÈCΪD/3=0.73m¡£ ΪÁËÏû³ý¿ÉÄܵĴòÐýÏÖÏó£¬Ç¿»¯´«ÈȺʹ«ÖÊ£¬°²×°nb=6¿é¿í¶ÈWΪ0.1Di¼´0.22mµÄµ²°å¡£È«µµ°åÅжÏÈçÏ£º (W1.2 ¡£0.221.2 )¡Á6=0.379£¬ÓÉÓÚ0.379>0.35,Òò´Ë£¬·ûºÏÈ«µµ°åÌõ¼þ¡£ N=()2.20D1.5.2½Á°è¹¦ÂʵļÆËã ²ÉÓÃÓÀÌï½øÖι«Ê½·¨¼ÆËã¡£ Re=(dn¦Ñ)/? 2 ʽÖУºd=0.22m,n=1.2r/s,»ìºÏҺƽ¾ùÃܶȦÑ=1.005g/cm3,?=3.5¡Á10-4Pa.s ¹ÊRe=1.83¡Á106>104ΪÍÄÁ÷£¬?=Np,?Ϊ¹¦ÂÊÒòÊý£¬NpΪ¹¦ÂÊÊý ²éͼRushtonËãͼ£¬µ±Re=4.7¡Á106ʱ?=Np=6.3 ¹Ê ½Á°è¹¦ÂÊN=Np¦Ñn3d5=6.3¡Á1.005¡Á1.23¡Á0.735¡Á1000=2268W 1.6¼ÐÌ×´«ÈÈÃæ»ýµÄ¼ÆËãÓëºËËã Ñ¡ÓÃÂÝÐý°å¼ÐÌ×£¬»·Ï¶E=100mm£¬ÂݾàP=50mm¡£ 1.6.1 ±»½Á°èÒºÌå²àµÄ¶ÔÁ÷´«ÈÈϵÊý?j ²ÉÓÃ×ôÒ°ÐÛ¶þÍÆ¼öµÄ¹ØÁªÊ½¼ÆËã: Nuj=0.512(?D4/?3)0.227Pr0.33(d/Di)0.52(b/Di)0.08 ?= 4N/(?Di2H¦Ñ),ʽÖÐN=2268W,Di=2.20m,¦Ñ=1005kg/m3,H=2.86m ¹Ê?=4¡Á2268/£¨3.14¡Á2.2¡Á2.2¡Á2.86¡Á1005£©=0.21w/kg ?=?/¦Ñ=3.5¡Á10-4/1005=3.48¡Á10-7m2/s (?Di4/?3)0.227=£¨0.21¡Á2.24/42.14¡Á10-21£©0.227=3.59¡Á104 223.9?0.00035Pr???0.71?0.110cp??jDi/?=0.512(?D4/?3)0.227Pr0.33(d/D)0.52(b/D)0.08 =0.512¡Á3.59¡Á104¡Á0.710.33¡Á0.330.52¡Á0.090.08 =0.76¡Á104 ¹Ê?j=0.11¡Á0.76¡Á104/2.2=380W/(m2.oC) 1.6.2¼ÐÌ×ÀäÈ´Ë®¶ÔÁ÷´«ÈÈϵÊý? ²ÉÓÃÏÂʽ¼ÆË㣺?De/?=0.027Re0.8Pr0.33V0.14(1+3.5(De/Dc)) ¼´?=0.027Re0.8Pr0.33V0.14(1+3.5(De/Dc))?/De ÀäÈ´Ë®½øÈë¼ÐÌ×ζÈ25oC,ÀäÈ´Ë®³ö¼ÐÌ×ζÈ55oC£¬ÔòÆä¶¨ÐÔÎÂ¶È t=40oC£¬ÔÚ´ËζÈÏ£¬Ë®µÄÏà¹ØÎïÐÔÈçÏ£º ±ÈÈÈÈÝcp=4.174kJ/(kg.oC) µ¼ÈÈϵÊý?=63.38 ÃܶȦÑ=992.2kg/m3 ð¤¶È?=0.000656Pa.s¡£ Pr?cp??=4.174¡Á0.000656/63.38=4.32¡Á10 -5 ÓÉÓÚ·´Ó¦Îïϵ·Å³öÈÈÁ¿Q1=1.73?106kJ/h=480.56kW£¬½Á°è¹¦ÂÊN=2268W ¹Ê½Á°è²ÛÐèÒÆ³öÈÈQ=Q1+N=482.72kW¡£ ËùÒÔÀäÈ´Ë®ÖÊÁ¿Á÷Á¿m=Q/cp(t2-t1)= 482.72/(4.174¡Á30)=3.85kg/s¡£ ¼ÐÌ×ÖÐË®Á÷ËÙu=m/(¦ÑPE)=3.85/(992.2¡Á0.05¡Á0.1)=0.78m/s£¬ De=4E=0.4m Dc=2.2m Re=Deu¦Ñ/?=0.4¡Á0.78¡Á992.2/0.000656=0.47¡Á106 ??De/?=0.027Re0.8Pr0.33V0.14(1+3.5(De/Dc)) µ±ÒºÌå±»¼ÓÈÈʱ ¦Õ=1.05 Pr?cp??4.174?0.000656?4.32¡Á10-5 63.38V?¦Ìb?1.05 ¦Ìw?De/?=0.027Re0.8 Pr0.33 (1+3.5(De/Dc))0 =0.027¡Á(0.47¡Á106)0.8¡Á(4.32¡Á10-5)0.33¡Á1.050.14 ¡Á(1+3.5¡Á0.4/2.2) =931.5¡Á0.036¡Á1.007¡Á1.64=55.38 ?=55.38¡Á63.38/0.4=8775.1W/(m2.oC) ËùÒÔ×Ü´«ÈÈϵÊý£º 1/K=1/?j+1/?=1/380+1/8775.1=0.0027 K=370.4W/(m2.oC) 1.6.3¼ÐÌ×´«ÈÈÃæ»ý ÓÉQ=KF?tm ?tm= ?t1??t2(150?25)?(150?55)??109.5oC ln(?t1/?t2)ln(125/95)µÃF=Q/K?tm=482.72¡Á103/(370.4¡Á109.5)=11.9m2 ÐèÒªºËËãһϼÐÌ׿ÉÄÜ´«ÈÈÃæ»ýÊÇ·ñÂú×ã´«ÈÈÒªÇó¡£ÓÉÓÚ½Á°è²ÛÄÜÌṩµÄ×îС´«ÈÈÃæ»ý£º?DiH=3.14¡Á2.2¡Á2.86=19.76m2¡£¸ÃÃæ»ý´óÓÚËùÐè´«ÈÈÃæ»ýF=11.9m2£¬Òò´Ë¼ÐÌ×Éè¼Æ·ûºÏÒªÇó¡£ Í¼2 ·´Ó¦¸ª»ù±¾¹¹Ôì 1.7·´Ó¦¸ªµÄÖ÷Òª¼¼ÊõÌØÐÔ»ã×Ü ±í9 ·´Ó¦¸ªµÄÖ÷Òª¼¼ÊõÌØÐÔ ÏîÄ¿ ·ûºÅ Éè¼Æ¼ÆËãÊý¾Ý¼°Ñ¡ÐÍ ½Á°èÐÎʽ ÁùƬƽֱҶԲÅÌÎÐÂÖʽ½Á°èÆ÷ Ò¶ÂÖÖ±¾¶ d 1.1m Ò¶ÂÖ¿í¶È ½Á °è Æ÷ Ò¶Â־สµ×¸ß¶È b 0.2m c 0.73m 1.2r/s ½Á°èתËÙ n ½°Ò¶Êý z 6 ½Á°è¹¦ÂÊ N 2268W 6 ½Á°è ¸½¼þ µ²°åÊý nb µ²°å¿í¶È w 0.2m ·´ ½Á°è¸ªÈ«ÈÝ»ý£¨²»°üÀ¨·âÍ·²¿·Ö£© V 29.1m 3ÒºÃæÉî¶È h 2.43m ½Á°è¸ªÊµ¼Ê¸ß¶È Ó¦ ¸ª ½Á°è¸ªÄÚ¾ H 2.86m Di 2.2m ¹¤×÷ѹÁ¦ PT 0.14MPa ½Á°è¸ªºñ¶È ¦Än 5mm ¼ÐÌ×ÐÎʽ ÂÝÐý°å¼ÐÌ× ÂÝÐý°åÂݾà P 0.05m ¼ÐÌ×»·Ï¶ ¼ÐÌ× ¼ÐÌ×ÄÚÀäÈ´Ë®Á÷ËÙ E 0.10m u 1.99m ÀäÈ´Ë®Ã¿Ð¡Ê±ÒÆ³öÈÈÁ¿ Q 482.72kW 380W/(m.C) 2o±»½Á°èÒºÌå²àµÄ¶ÔÁ÷´«ÈÈϵÊý ?j ¼ÐÌײàÀäÈ´Ë®¶ÔÁ÷´«ÈÈϵÊý ? K 8775.1W/(m.C) 2o½Á°è²Û×Ü´«ÈÈϵÊý 370.4W/(m.C) 2oËùÐè¼ÐÌ×Ãæ»ý F 11.9m 2ÓÉÓÚ¸ªÄÚ½éÖʾßÓÐÒ»¶¨µÄ¸¯Ê´ÐÔ, ÒªÇó¶Ô¸ªÌå¼°¸ª¸ÇÄÚ±íÃæ½øÐÐÌÂǦ´¦Àí(Ǧ²ãºñ6¡ª8 )²¢³ÄÄÍËá´É°å¶þ²ã¡£¿¼Âǵ½ÌÂǦ¹¤ÒÕµÄʵʩºÍÌÂǦʱµÄǦÖж¾£¬ ¸ªÌåºÍ¸ª¸ÇÐë²ÉÓ÷¨À¼Á¬½Ó¡£´ËÍâ £¬»¹¿¼Âǵ½¸ªÄÚ½éÖʵķ´Ó¦ËÙ¶ÈÄÑÒÔ¿ØÖÆÒÔ¼°½éÖʵĸ¯Ê´ÐÔ£¬ É豸²»Ò˲ÉÓð²È«·§×÷³¬Ñ¹Ð¹·Å×°Ö㬠¹ÊÉèÖÃÁËһй·Å¿Ú¾¶Îª200mmµÄ±¬ÆÆÆ¬ £¨ºñ 3mmµÄÇ¦ÖÆÆ½°åÐͱ¬ÆÆÆ¬Äڳĺñ 2mm µÄÄÍËáÏ𽺰壩×÷ΪÉ豸µÄ³¬Ñ¹Ð¹·Å×°Öᣠ2¡¢ÀäÄýÆ÷µÄÉè¼ÆÓëÑ¡ÐÍ ¶ÔÓÚ¶þ¼¶õ¥»¯·´Ó¦£¬ÓÉÓÚÊÇ¿ÉÄæ·´Ó¦£¬¹ý³ÌÖÐÓÐË®Éú³É£¬´Ó¶ø»áÓ°Ïì·´Ó¦µÄ½øÐг̶ȡ£ËùÒÔÐèÒª½«Ë®´ø³ö·´Ó¦¸ª£¬´Ù½ø·´Ó¦Ïò²úÎï·½Ïò½øÐС£·´Ó¦ÒºÖУ¬ÒìÐÁ´¼½«×÷Ϊ´øË®¼Á°ÑË®´Ó·´Ó¦¸ªÖдø³ö£¬¶øÕâÑù±Ø½«ÀË·ÑÔÁÏ£¬Òò´ËÔÚ·´Ó¦¸ªÉϰ²×°Ò»¸ö»»ÈÈÆ÷¼ÓÒ»¸ö·ÖÀëÆ÷£¬ÓÃÓÚÅÅË®ºÍ»ØÁ÷ÒìÐÁ´¼¡£ ÕâÀォÒÔ¶þ¼¶·´Ó¦µÚÒ»¸ö¸ªÎªÀý½øÐл»ÈÈÆ÷µÄ¼ÆËãÓëÑ¡ÐÍ¡£ 2.1Ñ¡Ôñ»»ÈÈÆ÷µÄÀàÐÍ ÓÉÓÚ·´Ó¦Î¶ÈÔÚ2000CÒÔϽøÐУ¬Á½Á÷ÌåζȱäΪ£ºÈÈÁ÷Ìå½øÈë»»ÈÈÆ÷µÄζÈΪ1900C£¬³ö¿Úζȶ¨Îª700C£»ÀäÁ÷Ì壨ѻ·Ë®£©½ø¿ÚζÈΪ250C£¬³ö¿ÚζÈΪ600C¡£¸Ã»»ÈÈÆ÷ÓÃÑ»·ÀäÈ´Ë®ÀäÈ´£¬¶¬¼¾²Ù×÷ʱ½ø¿ÚζȻήµÍ£¬¿¼Âǵ½ÕâÒ»ÒòËØ£¬¹À¼Æ¸Ã»»ÈÈÆ÷µÄ¹Ü±ÚκͿÇÌå±ÚÎÂÖ®²î½Ï´ó£¬Òò´Ë³õ²½È·¶¨Ñ¡ÓôøÅòÕͽڵĹ̶¨¹Ü°åʽʽ»»ÈÈÆ÷¡£ 2.2´«ÈÈÃæ»ýµÄÈ·¶¨ Ñ¡ÓÃ?25?2.5µÄ̼¸Ö¹Ü£¬ Á½¹ÉÁ÷ÌåµÄ½ø³ö¿ÚζÈΪ£ºÈÈÁ÷Ì壨³ö»»ÈÈÆ÷Æø£© 200¡ú70¡æ ÀäÁ÷Ìå £¨Ë®£© 65 ¡û 25 ¡æ ¹Ê´«ÈÈÍÆ¶¯Á¦£º ?tmÄæ = (200?65)?(70?25)=72.4¡æ (200?65)ln(70?25)ÈÈÁ÷ÌåµÄνµ130==3.7 ÀäÁ÷ÌåµÄνµ35ÀäÁ÷ÌåµÄζÈ35==0.2 Á½Á÷ÌåµÄ×î³õζÈ175ÐÞÕýϵÊý¦× R= P= ³õ²½¼ÙÉè²ÉÓõ¥¿Ç³Ì£¬Å¼Êý¹ÜµÄ¹Ì¶¨°å»»ÈÈÆ÷ ¾²é±í ¦×=0.88>0.8 ËùÒÔ¼ÙÉè¿ÉÐУ¬²ÉÓõ¥¿Ç³Ì£¬Å¼Êý¹ÜµÄ¹Ì¶¨°å»»ÈÈÆ÷ ?tm???tmÄæ?0.88?72.4?63.7¡æ ³õ²½¹À¼Æ´«ÈÈϵÊýK=370.4W/(©O¡¤¡æ)£¬ÔòÓɹ«Ê½Q=AK ¡÷Tm ¿ÉµÃ A¡¯=Q/£¨K¡÷Tm£©=515.18/£¨63.7¡Á370.4£©=21.83m2 ±í2 Áйܻ»ÈÈÆ÷²ÎÊý±í Íâ¿ÇÖ±¾¶D©v©L©w 450 ¹«³ÆÃæ»ý©v©O©w 0.0083 ¹«³ÆÑ¹Á¦©vMPa©w 1.0 ¹Ü×ӳߴç©vmm©w 25¡Á2.5 ¹Ü³¤©vm©w 3 ¹Ü³ÌÊýNp 4 ¹ÜÊýNT 106 ¹Ü×ÓÅÅÁз½Ê½ ÕýÈý½ÇÐÎ ¹ÜÖÐÐľà©vmm©w 32 ¼ÆËã»»ÈÈÃæ»ý©v©O©w 24.1 4¼ÆËã¹Ü³Ì¡¢¿Ç³ÌµÄ¶ÔÁ÷´«ÈÈϵÊýºÍѹ½µ 4.1¹Ü³ÌµÄ¶ÔÁ÷´«ÈÈϵÊýºÍѹ½µ ΪÁ˳ä·ÖÀûÓõÄÈÈÁ¿£¬²ÉÓÃÒºÌå×߹̡ܳ¢Ë®×߿dz̡£ £¨1£©¹Ü³ÌÁ÷Í¨Ãæ»ý Ai=¦Ð/4di2¡¤NT/Np =¦Ð/4¡Á0.022¡Á106/4 =0.0083©O ¼ÙÉèÎïÁÏÁ÷ËÙ 0.5m/s Rei?dui?i?i?0.02?0.5?10054?2.87?10 ?30.35?10 »ìºÏÎï±»ÀäÈ´£¬ËùÒÔ ?i?0.023ReiPridi?i0.30.11223.9?0.35?10?30.30.8?0.023??28700?()?421W/(m2??C)0.020.112ui?il ¹Ü³Ìѹ½µÎª ?Pi?(??3)fiNi d2 È¡¹Ü±Ú´Ö²Ú¶È??0.15mm£¬?/d?0.0075£¬¾²éͼ¿ÉµÃĦ²ÁϵÊý ??0.034 ¡à ui?i30.52?1005l?3)?1.4?4??5.7?103Pa =(0.034??Pi?(??3)fiNi0.022d22 b£®¿Ç³Ì Ñ¡ÓÃȱ¿Ú¸ß¶ÈΪ25£¥µÄ¹Ðε²°å£¬È¡ÕÛÁ÷°å¼ä¾àB=0.3Di,ÔòB=135mm¡£ £¬¹ÊÕÛÁ÷µ²°åÊýΪNB?l3?1??1?22 B0.1350.025)?0.0133m2 0.032 Á÷µÀÃæ»ý S0?hD(1?d0t)?0.135?0.45?(1? Ë®Á÷ËÙ u0?Wc12683.12??0.27m/s 3600?0S03600?992.2?0.0133 ÕýÈý½ÇÅÅÁеĵ±Á¿Ö±¾¶Îª 4(32?23?t?d0)4?(?0.0322??0.0252)2424??0.0202m ?d0??0.025?0.0202?0.27?992.2?8.25?103 0.000656 de? Re0? Pr0?deu0?0?0cp???4.174?0.000656?4.32?10?5 63.38 ¿ÇÖÐÔÓͱ»¼ÓÈÈ£¬È¡(?0?0.36?0de(Re0)0.55103?0.14)?1.05£¬ËùÒÔ ?W?0.14) ?WPr(163.380.553=0.36??8250?0.0000432?1.05?6135.53W/(m2??C) 0.0202 ¿Ç³Ìѹ½µ ?0.19??1.72Re0?1.72?8250?0.19?0.31 ?02??0D(NB?1)u00.45?(22?1)0.272?992.2? ?P0??0??0.41???7.6?103Pa de20.02022¢Û¼ÆËã´«ÈÈÃæ»ý ´«ÈÈϵÊý 111??? K¼Æ?0?i £¬ºöÂԹܱÚÈÈ×裬Ôò 111???0.00254 K¼Æ6135.53421K¼Æ?393.97W/(m2??C) A¼Æ?Q515180??20.53m2 K¼Æ?tm393.97?63.7 ÇÒ Aʵ24.1??1.174 A¼Æ20.53 ¼´´«ÈÈÃæ»ýÓÐ17.4£¥µÄÔ£¶È¡£ 2.5.¿ÇÌåºñ¶È ¿ÇÌå²ÄÁÏÑ¡ÓÃ20R¸Ö£¬¼ÆËã±ÚºñµÄ¹«Ê½Îª£º S=PcDi/£¨2¡¸¦Ò¡¹t§¶-Pc£© ʽÖУºPc¡ª¡ª¼ÆËãѹÁ¦£¬È¡PcΪ1¡Á1.1=1.1MPa £» Di=450mm£»§¶=0.85(¾Ö²¿ÎÞËð¼ì²â) ¡¸¦Ò¡¹80=130Mpa£¨È¡¿ÇÌåζÈΪ80¡æ£© ¦Ä=450¡Á1.1/£¨2¡Á130¡Á0.85-0.11£©=3.81mm È¡C2=2mm £»C1=0.25mm£¬Ô²ÕûºóÈ¡¦Ä=6mm£¬¸´Ñé6¡Á6%=0.36¡µ0.25 ¹Ê×îÖÕÈ¡C1=0.25mm ¹Ê¦Ä=6mm 2.6»»ÈÈÆ÷·âÍ·µÄÈ·¶¨ ÉÏÏ·âÍ·¾ù²ÉÓñê×¼ÍÖÇòÐηâÍ·£¬¸ù¾Ý·âͷΪDN1400¡Á5¡£ÇúÃæ¸ß¶Èh1=100mm£¬Ö±±ß¸ß¶Èh2=25mm£¬²ÄÁÏÑ¡ÓÃ20 R¸Ö¡£ 2.7ÈÝÆ÷·¨À¼µÄÑ¡Ôñ ²ÄÁÏÑ¡ÓÃ16MnR¸Ö£¬¸ù¾ÝJB/4703-2000±ê×¼£¬Ñ¡ÓÃPN1.6Mpa£¬DN400mmµÄé¾²ÛÃÜ·âÃæ³¤¾±¶Ôº¸·¨À¼¡£ 2.8¿ª¿×²¹Ç¿ »»ÈÈÆ÷·âÍ·ºÍ¿ÇÌåÉϵĽӹܶ¼ÐèÒª²¹Ç¿£¬ÔÚ¿ª¿×ÍâÃæº¸½ÓÉÏÒ»¿éÓëÈÝÆ÷±Ú²ÄÁϺͺñ¶È¶¼ÏàͬµÄ£¬¼´5mmºñµÄ20R¸Ö°å¡£ 2.9Ö§×ù Ñ¡ÓÃÐͺÅJB/4712-92 °°×ù BI 700 F ¡£ Èý¡¢»»ÈÈÆ÷µÄÖ÷Òª½á¹¹³ß´çºÍ¼ÆËã½á¹û É豸½á¹¹²ÎÊý ÐÎʽ ¿ÇÌåÄÚ¾¶/mm ¹Ü×ӳߴç/mm ¹Ü³¤/m ¹Ü×ÓÅÅÁз½Ê½ ¹Ì¶¨°å¹Üʽ 450 ?25?2.5 ¹«³ÆÃæ»ý ÕÛÁ÷µ²°åÊý ¹ÜÖÐÐľà/mm ²ÄÖÊ ¼ÆËã»»ÈÈÃæ»ý 0.0083©O 22 32 ̼¸Ö 24.1©O 3 ÕýÈý½ÇÐÎ ÎïÁϲÎÊý ²ÎÊý Á÷Á¿/£¨kg/h£© ½ø/³ö¿ÚζÈ/¡æ ÃܶÈ/£¨kg/m3£© ¹Ü³Ì 3?104 ¿Ç³Ì 4?104 200/70 1005 2.48 0.11 0.00035 25/6 992.2 4.178 63.38 0.000656 Îï ¶¨Ñ¹±ÈÈÈÈÝ/[kJ/£¨kg?¡æ£©] ÐÔ µ¼ÈÈϵÊý/[W/(m2?¡æ)] Õ³¶È/£¨Pa?s£© ¼ÆËã½á¹û ѹ½µ/Pa ´«ÈÈϵÊý/[W/£¨©O?K£©] ¼ÆËãÃæ»ýA¼Æ/©O Ô£¶È£¥ ¹Ü³Ì 5700 421 20.53 17.4 ¿Ç³Ì 7600 6135.53 Î壮»·¾³±£»¤ÓëÀͶ¯°²È« 1.DOPÉú²ú¹ý³Ì¡°Èý·Ï¡±´¦Àí Éú²ú¹ý³ÌÖй¤Òµ·ÏË®µÄÖ÷ÒªÀ´Ô´ÊÇõ¥»¯·´Ó¦ÖÐÉú³ÉµÄË®£»¾¶à´ÎÖкͺóº¬Óе¥õ¥ÄÆÑεÈÔÓÖʵķϼϴµÓ´Öõ¥ÓõÄË®£»ÍÑ´¼Ê±ÆûÌáÕôÆûµÄÀäÄýË®£¬ËüÃǵÄ×é³É´óÖÂÈçÏÂÃæËùʾ£º ±í12õ¥»¯ÒºÓëÖкͷÏË®µÄ×é³É õ¥»¯·´Ó¦Òº DOP ±½ôû ±½¶þ¼×Ëáµ¥ ÐÁõ¥ ÁòËáµ¥ÐÁõ¥ ÁòËáµ¥ÐÁõ¥ 1.16 0.19 % 90£®4 7£®83 0.065 ÖкͷϼîÒº DOP ±½ôû ±½¶þ¼×Ëáµ¥ ÐÁõ¥ÄÆ ÁòËáµ¥ÐÁõ¥ÄÆ ÁòËáµ¥ÐÁõ¥ÄÆ 23000 4000 Mg/L 2000 2000 1000 ÖÎÀíµÄ°ì·¨£¬Ê×ÏÈÓ¦´Ó¹¤ÒÕÉϼõÉÙ·ÏË®µÄÅÅ·ÅÁ¿£¬Ïó±¾Éè¼Æ²ÉÓõÄÊÇ·ÇËá´ß»¯¼Á£¬Ôò¿É¸ï³ýÖкÍˮϴÁ½¸ö¹¤Ðò£»Æä´Î£¬µ±È»Ò²²»¿É±ÜÃâµØÒª½øÐзÏË®´¦Àí¡£Ò»°ã˵ȫ²¿´¦Àí¹ý³Ì·ÖΪ»ØÊպ;»»¯Á½¼¶¡£»ØÊÕʱ±ØÐ뿼ÂǾ¼ÃÐ§Òæ£¬Èç¹û»ØÊÕÓÐЧ³É·ÖµÄ·ÑÓúܴ󣬾Ͳ»ÈçÓÃÉÙÁ¿¼î½«ÆäÆÆ»µ³ýÈ¥¡£ ¶ÔÓÚ±¾Éè¼Æ»ØÊÕµÄÐÁ´¼Ò»²¿·ÖÖ±½ÓÑ»·µ½õ¥»¯²¿·ÖʹÓã¬ÁíÒ»²¿·ÖÐè½øÐзÖÁóºÍ´ß»¯¼ÓÇâ´¦Àí¡£¶ø²úÉúµÄ·ÏË®£¨CODÖµ700¡«1500mHg/L£©¿ÉÒÔÓûîÐÔÎÛÄà½øÐÐÉú»¯´¦ÀíºóÔÙÅÅ·Å¡£ 2¡¢DOPÉú²ú¹ý³Ì°²È«ÊÂÏî »¯¹¤²úÆ·Éú²úÊÇÒ»Ïî¾ßÓи߷çÏÕÐÔµÄÐÐÒµ£¬Òò´ËÔÚÕû¸ö»¯¹¤Éú²úÖУ¬É豸°²×°¡¢Ê©¹¤¡¢²Ù×÷µÈµÈ¶¼±ØÒªÒª¿¼ÂǸ÷·½Ã氲ȫÒòËØ£¬Éè¼Æ¹ý³ÌÖÐÒªÖÜÃÜ¿¼ÂÇ£¬×î´ó³Ì¶ÈµÄÏû³ý°²È«Òþ»¼£¬Ê¹Ê¹ʸÅÂʽµµÍµ½×îС¡£ ÔÚÉè¼ÆÖУ¬Á÷³ÌÉÏÒª¿¼ÂǵݲȫÒòËØÖ÷ÒªÊDZÜÃâÉ豸ºÍ¹ÜµÀÄÚ½ØÖ¹µÄѹÁ¦³¬¹ýÔÊÐíµÄ³¬×öѹÁ¦¶øÔì³ÉÔÖÄÑÐÔʹʵķ¢Éú¡£Ò»°ãÀûÓð²È«Ð¹Ñ¹×°ÖÃÀ´¼°Ê±ÅŷŹܵÀÄÚµÄ ½éÖÊ£¬Ê¹¹ÜµÀÄÚ½ØÖ¹µÄѹÁ¦Ñ¸ËÙϽµ¡£É豸¼°¹ÜµÀÖпÉÒÔ²ÉÓõİ²È«Ð¹Ñ¹×°ÖÃÖ÷ÒªÓб¬ÆÆÆ¬ºÍ°²È«·§£¬»òÔڹܵÀÉϼӰ²È«Ë®·âºÍ°²È«·Å¿Õ¹Ü¡£ ½éÖʵÄÒ×ȼÓëÒ×±¬ÊÇÏ໥¹ØÁªµÄ£¬·À±¬µÄÊ×Òª´ëÊ©ÊÇ·À»ð£¬ËùÒÔDOPÉú²úµÄ°²È«£¬Ê×ÒªÏÈ´Ó·À»ð×öÆð¡£¸ù¾ÝDOPÉú²úµÄÌØµã£¬Ó¦²ÉÈ¡ÏÂÁзÀ»ð´ëÊ©£º £¨1£© Öü´æÊäËÍÔÁϼ°²úÆ·µÄÖü¹Þ¡¢¹ÜÏ߸½½üÑϽû»ðÔ´£¬²¢ÓÐÃ÷ÏÔµÄÖ¸Ê¾ÅÆºÍ±ê Ö¾¡£ £¨2£© ³§·¿ÄÚ²»´æ·ÅÒ×ȼÎïÖÊ£¬µØ¹µ±£³Öͨ³©£¬·ÀÖ¹¿ÉÈ¼ÆøÌå¡¢ÒºÌå»ý¾Û£¬¼ÓÇ¿ ³§·¿Àïͨ·ç¡£ £¨3£© µçÆøÉ豸ÐëÑ¡Ó÷À·À±¬ÐÍ£¬µçÀ¡¢µçÔ´¾øÔµÁ¼ºÃ£¬·ÀÖ¹²úÉúµç»ð»¨¡£½ÓµØ Àο¿£¬·ÀÖ¹²úÉú¾²µç¡£ £¨4£© ±¸ÓбØÐëµÄÏû·ÀÆ÷²Ä¡£ ¶ÔÓÚDOPÉú²ú·À±¬Ó¦¸Ã×¢ÒâÈçϼ¸µã£º £¨1£© ÑϸñÖ´ÐÐÊÜѹÈÝÆ÷¡¢ÊÜѹÉ豸ʹÓᢹÜÀíÓйع涨£¬²Ù×÷ÈËÔ±±ØÐë¾¹ýÑÏ ¸ñѵÁ·¡£ £¨2£© ²»×¼ÈÎÒâ¸Ä±äÔËÐÐÖеŤÒÕ²ÎÊý£¬²»µÃ³¬Î¡¢³¬Ñ¹¼°Ìá¸ßÉ豸µÄʹÓõȼ¶¡£ £¨3£© ÊÜѹÈÝÆ÷¡¢¹ÜÏߵݲȫÉèÊ©ÆëÈ«£¬ÇÒÖ¤Ã÷ȷʵÁéÃô¿É¿¿£¬È簲ȫ·§¡¢Ñ¹Á¦ ±í¡¢·À±¬°å¼°¸÷ÖÖÁ¬ËøÐźš¢×Ô¶¯µ÷½Ú×°Öõȡ£ ÑϸñÖ´ÐзÀ»ð¹æ¶¨¼°°²È«¼¼Êõ´ëÊ©£¬Ñϸñ¿ØÖƿɱ¬½éÖʲ»µÃÉÏÉýµ½±¬Õ¨·¶Î§¡£ Áù£®Éè¼Æ½á¹ûÆÀÎöÓë×Ü½á ¾¹ýÒ»¶Îʱ¼äµÄ×ÊÁϲéѯ¡¢ÎÄÏ×ËÑË÷¡¢Éè¼ÆÕûÀí£¬ÔÚÀÏʦµÄÖ¸µ¼ºÍͬѧµÄ°ïÖúÏ£¬ÎÒÃÇÕâ×é˳ÀûµØÍê³ÉÁ˱¾´Î¿Î³ÌÉè¼Æ¡£±¾´ÎÉè¼ÆÒÔ¡°¹¤ÒÕÏȽø¡¢¼¼Êõ¿É¿¿¡¢ÏµÍ³¿ÆÑ§¡¢¾¼ÃºÏÀí¡¢°²È«»·±£¡±ÎªÔÔò£¬ÒÀ¾Ý¿Î³ÌÉè¼ÆÈÎÎñÊ飬×ñѹ¤³ÌÉè¼ÆµÄ¹æÔòÓëÒªÇóÀ´Íê³É£¬Éè¼ÆË¼Â·ÇåÎú£¬ÄܽáºÏÉú²úʵ¼Ê¸¨ÖúÉè¼Æ£¬ÒýÓÃ×ÊÁϺÍÏà¹Ø¹«Ê½×¼È·£¬Éè¼ÆÊý¾ÝºÍÉè¼Æ½á¹û¿É¿¿£¬×ÔÎҸоõ±¾´Î¿Î³ÌÉè¼ÆÍê³É±È½ÏÀíÏë¡£ ±¾Éè¼ÆÔڱȽÏÁËÏÖÐйúÄÚ¹¤ÒµÉú²úÉÏDOP£¬ÆäµäÐ͵ŤÒÕÁ÷³ÌÓÐÁ½ÖÖ£º1¡¢õ¥»¯¡ªÍÑ´¼Ò»ÖкÍˮϴһÆûÌá¸ÉÔïÒ»¹ýÂË£»2¡¢õ¥»¯Ò»ÖкÍˮϴһÍÑ´¼--ÆûÌá--¸ÉÔïÒ»¹ýÂË¡£ÓÉÓÚµÚ¢ÙÓй«Óù¤³ÌÏûºÄµÍ£¬ÈÈÄÜÀûÓúÏÀí£¬¿ÉÒÔÉú²ú¶àÅÆºÅµÄDOP²úÆ·µÈÖÖÓŵ㣬²¢ÇÒ£¬½áºÏ¹úÄÚÌõ¼þºÍÉú²ú²Ù×÷¾Ñ飬ÔÚ½è¼øµÚ1ÀàµäÐ͹¤ÒÕÁ÷³Ì»ù´¡ÉÏ£¬²ÉÓõÄÊÇ ·ÇËá´ß»¯¼Á£¬¿É¸ï³ýÖкͲ»Ï´Á½¸ö¹¤Ðò£¬Éè¼Æ¹ú²ú»¯ÐµĹ¤ÒÕÁ÷³Ì¡£ÊÇÒ»ÖÖ½ÏÊʺÏÎÒ¹ú¹úÇéµÄÉú²ú·½·¨¡£ ±¾¹¤ÒÕÉè¼ÆÓëÒ»°ã¹¤ÒÕÏà±È£¬ÓÅÊÆÔÚÓÚ£º £¨1£©ÔÁÏÔ¤ÈÈ´¦Àí²½ÖèÌá¸ßÁËÔÁϵÄת»¯ÂÊ£¬Ê¹±½ôûÔÚÒ»¼¶õ¥»¯¸ª×ª»¯Âʽӽü100%¡£ £¨2£©²ÉÓõÄÊÇÑõ»¯ÂÁÓëÐÁËáÑÇÎý1£º1±ÈÀý¸´Åä·ÇËá´ß»¯¼Á£¬·´Ó¦Ê±¼ä¶Ì¡¢õ¥ÊÕÂʸߡ¢²úÆ·ÖÊÁ¿ºÃ(ËáÖµµÍ¡¢É«¶ÈµÍ¡¢ÈÈÎȶ¨ÐԺá¢Ìå»ýµç×èÂÊ´ó) ¡¢´¦ÀíÌõ¼þ¼òµ¥µÈÓŵ㣬ͬʱ¿É¸ï³ýÖкÍˮϴÁ½¸ö¹¤Ðò¡£ £¨3£©õ¥»¯·´Ó¦ÔÚ³£Ñ¹²Ù×÷½øÐУ¬¶Ô´«Í³¹¤ÒյĸĽøÊ¹µÃÆäÄÜÁ¿ÏûºÄ´óΪ¼õÉÙ£¬Éú²ú¹ý³ÌµÄÎȶ¨ÐÔºÍÁ¬ÐøÐÔ´óΪÌá¸ß£¬·ûºÏÏÖ´ú¹¤ÒÕÂÌÉ«¸ßЧÉú²úµÄÒªÇó¡£ £¨4£©½øÐзÏË®´¦Àí·ÖΪ»ØÊպ;»»¯Á½¼¶¡£¸ù¾Ýʵ¼ÊÇé¿ö£¬×î´óÏ޶ȵػØÊÕÀûÓ㬱ä·ÏΪ±¦¡£¶ÔÓÚ±¾Éè¼Æ»ØÊÕµÄÐÁ´¼Ò»²¿·ÖÖ±½ÓÑ»·µ½õ¥»¯²¿·ÖʹÓã¬ÁíÒ»²¿·ÖÐè½øÐзÖÁóºÍ´ß»¯¼ÓÇâ´¦Àí¡£¶ø²úÉúµÄ·ÏË®ÓûîÐÔÎÛÄà½øÐÐÉú»¯´¦ÀíºóÔÙÅÅ·Å£¬¶Ô»·¾³²»¾ßÓÐÎÛȾ¡£¼È·ûºÏ»·±£ÒªÇ󣬻¹½µµÍÁËÉú²ú×ۺϳɱ¾¡£ ÓÉÓÚ±¾Éè¼ÆÊôÓÚ³õ²½Éè¼Æ£¬ÐèÒª¸ü¶àµÄÌÖÂÛÓëÑо¿£¬²ÅÄÜͶÈëÉú²úʵ¼ù£¬Ê¹µÃ¼¼ÊõµÃµ½¸Ä½ø£¬Éú²úЧÂÊÌá¸ß¡£ÔÚ±àдÉè¼ÆµÄ¹ý³ÌÖÐÎÒÃǶԱ¾Éè¼ÆËµÃ÷Êé×÷Á˶à´ÎÐ޸쬵«ÏÞÓÚʱ¼äºÍˮƽ£¬ç¢Â©ÔÚËùÄÑÃ⣬¿ÒÇëÀÏʦÃÇÖ¸Õý¡£ Æß£®ÖÂл ±¾´ÎÉè¼ÆÔÚÉè¼ÆÐ´×÷ÆÚ¼ä£¬µÃµ½ÁËÕŵÂÀÀÏʦµÄ¾«ÐÄÖ¸µ¼£¬ÀÏʦÑϽ÷µÄÖÎѧ̬¶È£¬ ¾«ÒæÇ󾫵Ť×÷×÷·ç£¬ÆÓʵÎÞ»ª¡¢Æ½Ò×½üÈ˵ÄÈ˸ñ÷ÈÁ¦¶ÔÎÒÓ°ÏìÉîÔ¶¡£ ±¾Éè¼ÆÄܹ»Ë³ÀûµÄÍê³É£¬Àë²»¿ª¸÷λÀÏʦºÍͬѧ¸øÓèµÄÖ¸µ¼Óë¹ØÐÄ£¬ÌرðÊÇÎÒÃDZ¾Éè¼ÆÐ¡×é¸÷³ÉԱͨÁ¦ºÏ×÷£¬ÓÄѶøÉϾ«ÉñÖµµÃ¼ÌÐø·¢Ñï¡£ÔÚ´Ë£¬¶ÔËùÓйØÐĺͰïÖú¹ýÎÒµÄÀÏʦºÍͬѧ±íʾ³ç¸ßµÄ¾´ÒâºÍÖÔÐĵĸÐл¡£ °Ë£®²Î¿¼ÎÄÏ× [1] ÍõÑÓ¼ª.»¯¹¤²úÆ·ÊÖ²á.µÚËİæ.Óлú»¯¹¤ÔÁÏ.»¯Ñ§¹¤Òµ³ö°æÉç.54. [2] ÍôÊÙ½¨.ÌìÈ»ÆøµÄ×ÛºÏÀûÓü¼Êõ.µÚ1°æ.»¯Ñ§¹¤Òµ³ö°æÉç,2003. [3] ËÎά¶Ë£¬·¿¶¦Òµ.¼×´¼¹¤Ñ§.µÚ1°æ.»¯Ñ§¹¤Òµ³ö°æÉç,1991. [4] ÍõÑÓ¼ª.»¯¹¤²úÆ·ÊÖ²á.µÚËİæ.Óлú»¯¹¤ÔÁÏ.»¯Ñ§¹¤Òµ³ö°æÉç.55. [5] ѦÈÙÊé,Ì·ÊÀÓï.»¯¹¤¹¤ÒÕѧ.µÚ¶þ°æ.ÖØÇì´óѧ³ö°æÉç.238-239. [6] Îâ־Ȫ,Í¿½úÁÖ.¹¤Òµ»¯Ñ§.»ª¶«Àí¹¤´óѧ³ö°æÉç.35-36. [7] ÍõÓÀÈ«.¼×´¼¾«Áó¼¼Êõ¼òÊö¡¸J¡¹.»¯·ÊÉè¼Æ,2004,42(5):22¡«25. [8] ÁººìÌÎÖ÷±à.×îл¯¹¤Éú²ú¹¤ÒÕÉè¼ÆÓ뻯¹¤²úÆ·¼ì²â¼¼ÊõÊÖ²á.ÒøÉùÒôÏñ³ö°æ Éç,2004. [9] µóÓñçâ,ÍõÁ¢Òµ±àÖø.»¯¹¤É豸»úе»ù´¡.µÚ5°æ.´óÁ¬Àí¹¤´óѧ³ö°æÉç,2003. [10]ÁõµÀµÂµÈ±àÖø.»¯¹¤³§µÄÉè¼ÆºÍ¸ÄÔì.µÚ¶þ°æ.ÖÐÄÏ´óѧ³ö°æÉç,2005. [11]¦°®¾êµÈ±àÖø.»¯¹¤Éè¼Æ. µÚ1°æ.»ª¶«Àí¹¤´óѧ³ö°æÉç,2002. [12]²ñ³Ï¾´µÈ±àÖø.»¯¹¤ÔÀí. µÚ1°æ.Ìì½ò´óѧ³ö°æÉç,2003. £Û1£Ý·¿¶¦Òµ, Ò¦Åå·¼, Öì±þ³¿. ¼×´¼Éú²ú¼¼Êõ¼°½øÕ¹. µÚ1°æ. »ª¶«»¯¹¤Ñ§Ôº³ö°æÉç, 1990. £Û2£ÝÍõ¾²¿µÖ÷±à. »¯¹¤Éè¼Æ. µÚÒ»°æ. »¯Ñ§¹¤Òµ³ö°æÉ磬1995. £Û3£ÝÐìÕñ¸Õ, ¹¬Ô»ª£¬½¯ÏþÁÖ. CSP¼ÓÑ¹ÆøÁ÷´²Æø»¯¼¼Êõ¼°ÆäÔÚÖйúµÄÓ¦ÓÃǰ¾°[J].½à¾»Ãº¼¼Êõ£¬ 1998£¬£¨3£©:15¡«18. £Û4£ÝÀî´óÉÐ. GSP¼¼ÊõÊÇÃºÖÆºÏ³ÉÆø(»òH2)¹¤ÒÕµÄ×î¼ÑÑ¡Ôñ[J]. ú»¯¹¤, 2005£¬£¨3£©:1¡«6. £Û5£ÝÔø¼ÍÁú. ´óÐÍÃºÖÆ¼×´¼µÄÆø»¯ÓëºÏ³É¹¤ÒÕÑ¡Ôñ. ¡°2005ÄêÖйú̼һ»¯ÏÂÓë½à¾»Ãº¼¼ÊõÓ¦ÓÃ(ʯ ºÓ×Ó)¹ú¼ÊÑÐÌֻᡱժҪ£¬µÚ7ÆÚ. £Û6£ÝFritz Will. GSPÆø»¯¼¼Êõǰ¾°. ¡°2005ÄêÖйú̼һ»¯¹¤Óë½à¾»Ãº¼¼ÊõÓ¦ÓÃ(ʯºÓ×Ó)¹ú¼ÊÑÐÌֻᡱ ÕªÒª£¬µÚ7ÆÚ. £Û7£ÝÁÖÃñºè, ÕÅÈ«ÎÄ, ºúÐÂÌï. NHD·¨ÍÑÁòÍÑ̼¾»»¯¼¼Êõ. »¯Ñ§¹¤ÒµÓ빤³Ì¼¼Êõ£¬1995Ä꣬µÚ3 ÆÚ. £Û8£ÝÀîÇí¾Á, ÌÆËÃÈÙ, ¹Ë×ÓéÔ, ÖÜÊöÖ¾, ÕÔÅæ»ª. ½ü´ú¼×´¼ºÏ³É¹¤ÒÕÓëºÏ³ÉËþ¼¼Êõ(ÏÂ) [J]. »¯·ÊÉè ¼Æ, 2004, 42(1):3¡«8. £Û9£ÝÀîÇí¾Á, ÌÆËÃÈÙ, ¹Ë×ÓéÔ, ÖÜÊöÖ¾, ÕÔÅæ»ª. ½ü´ú¼×´¼ºÏ³É¹¤ÒÕÓëºÏ³ÉËþ¼¼Êõ(ÉÏ) [J].»¯·ÊÉè¼Æ, 2003, 41(6):5¡«10. £Û10£Ý³ÂÎÄ¿, ÎâÓñÌÁ, Áº¹ú»ª, ÓÚ×÷Áú. ºÏ³É¼×´¼´ß»¯¼ÁµÄÑо¿½øÕ¹.ʯÓÍ»¯¹¤, 1997Äê, µÚ26¾í. £Û11£ÝÌÆÖ¾±ó, ÍõС»¢, ¸¶³¬, ÓÚÐÂÁá. ÐÂÐ͵Íѹ¼×´¼ºÏ³É´ß»¯¼ÁXNC-98µÄ¹¤ÒµÓ¦ÓÃ.ʯ»¯¼¼ÊõÓë Ó¦ÓÃ, µÚ5ÆÚ, µÚ23¾í. £Û12£ÝÍôÊÙ½¨.ÌìÈ»ÆøµÄ×ÛºÏÀûÓü¼Êõ. µÚ1°æ.»¯Ñ§¹¤Òµ³ö°æÉç, 2003. £Û13£ÝËÎά¶Ë, ·¿¶¦Òµ. ¼×´¼¹¤Ñ§.µÚ1°æ.»¯Ñ§¹¤Òµ³ö°æÉç, 1991. £Û14£ÝÑî´ºÉú, º«¸£Ë³±à. ÖÐСÐͺϳɰ±³§Éú²ú²Ù×÷ÎÊ´ð£¬2001: 326¡«327. £Û15£ÝÍõÓÀÈ«. ¼×´¼¾«Áó¼¼Êõ¼òÊö[J]. »¯·ÊÉè¼Æ£¬2004£¬42(5): 22¡«25. £Û16£ÝÁõÖ¾³¼, ËïÕêÌÎ. ÈýËþ¼×´¼¾«Áó¼¼ÊõµÄÓ¦ÓÃ[J]. Сµª·Ê, 2004,£¨1£©: 11¡«12. £Û17£ÝÁõÖ¾³¼, ËïÕêÌÎ. ÈýËþ¼×´¼¾«Áó¼¼ÊõµÄÓ¦ÓÃ. Сµª·Ê, 2004Äê, £¨1£©: 6¡«7. £Û18£ÝÐí²¨. ´Ö¼×´¼µÄË«Ëþ¾«ÁóºÍÈýËþ¾«Áó[J]. Сµª·ÊÉè¼Æ¼¼Êõ, 1998, 19£¨3£©:15¡«17. £Û19£ÝÑî´ºÉú, º«¸£Ë³±à. ÖÐСÐͺϳɰ±³§Éú²ú²Ù×÷ÎÊ´ð. 2001: 328¡«329. £Û20£ÝËÎά¶Ë, ·¿¶¦Òµ.¼×´¼¹¤Ñ§. µÚ1°æ. »¯Ñ§¹¤Òµ³ö°æÉç, 1991. £Û21£ÝÁººìÌÎÖ÷±à. ×îл¯¹¤Éú²ú¹¤ÒÕÉè¼ÆÓ뻯¹¤²úÆ·¼ì²â¼¼ÊõÊÖ²á. ÒøÉùÒôÏñ³ö°æÉç, 2004. £Û22£ÝµóÓñçâ, ÍõÁ¢Òµ±àÖø. »¯¹¤É豸»úе»ù´¡. µÚ5°æ. ´óÁ¬Àí¹¤´óѧ³ö°æÉç, 2003. £Û23£ÝÌÆºêÇà. GSP¹¤ÒÕ¼¼Êõ[J]. Öеª·Ê, 2005, £¨2£©: 14¡«18. £Û24£ÝÁõµÀµÂµÈ±àÖø. »¯¹¤³§µÄÉè¼ÆºÍ¸ÄÔì. µÚ¶þ°æ. ÖÐÄÏ´óѧ³ö°æÉç, 2005. £Û25£Ý·ëÔªçùÖ÷±à. Áª´¼Éú²ú. µÚ2°æ. »¯Ñ§¹¤Òµ³ö°æÉç, 1994. £Û26£ÝÁõµÀµÂµÈ±àÖø. »¯¹¤³§µÄÉè¼ÆºÍ¸ÄÔì. µÚ¶þ°æ. ÖÐÄÏ´óѧ³ö°æÉç, 2005. £Û27£ÝºúËÉÌÎ. ¼×´¼¹¤ÒµÎÛË®Éî¶È´¦Àí¼°»ØÓõÄÑо¿. ºÚÁú½´óѧ˶ʿѧλÂÛÎÄ, 2006. 1. ½ÃÀ¾ê¡¢ÕźÆÇØÖ÷±à.»¯¹¤ÔÀí£¨Éϲᣩ£¬µÚ¶þ°æ.±±¾©£º»¯Ñ§¹¤Òµ³ö°æÉ磬2006 2. ÍõÖ¾¿ýÖ÷±à.»¯¹¤ÔÀí£¬µÚ3°æ.±±¾©£º»¯Ñ§¹¤Òµ³ö°æÉ磬2005 3. ²ñ³Ï¾´£¬ÕŹúÁÁÖ÷±à.»¯¹¤Á÷ÌåÁ÷¶¯Óë´«ÈÈ.±±¾©£º»¯Ñ§¹¤Òµ³ö°æÉ磬2000 4. ¼¾ÑôƼÖ÷±à.»¯¹¤ÖÆÍ¼.±±¾©£º»¯Ñ§¹¤Òµ³ö°æÉ磬2007