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C. Ôö¼ÓѹÁ¦,ʹc(A)¼°c£¨B£©¾ùÔö¼Ó£¬Æ½ºâ²»Òƶ¯¡£ D. ¼ÓÈë´ß»¯¼ÁÖ»ÄÜËõ¶Ì´ïµ½Æ½ºâµÄʱ¼ä£¬²»¸Ä±äƽºâ³£Êý¡£

20¡¢250Cʱ·´Ó¦ N2(g) + 3 H2(g) = 2NH3(g) µÄ ¦¤rH?m = £­92 £¬ÔÚ

ÃܱÕÈÝÆ÷Öи÷´Ó¦´ïµ½Æ½ºâʱ£¬Èô¼ÓÈëÒ»¶¨Á¿µÄÄÊÆø»á³öÏÖ£¨ £©

A. ƽºâÓÒÒÆ,°±²úÁ¿Ôö¼Ó. B. ƽºâ×óÒÆ,°±²úÁ¿¼õÉÙ. C. ƽºâ״̬²»±ä. D. Õý·´Ó¦ËÙÂʼӿì.

21¡¢ºÏ³ÉÏõËáʱ,ÎüÊÕËþÄڵķ´Ó¦Îª:

3NO2(g) + H2O(l) = 2HNO3(aq) + NO(g) ¦¤rH?m = £­2001 £¬ÎªÁËÔö¼ÓHNO3µÄƽºâ²úÂÊ£¬±ØÐë( )

A. ¼Óѹ²¢½µÎ B. ¼Óѹ²¢ÉýΠC. ¼õѹ²¢ÉýΠD. ¼õѹ²¢½µÎÂ

?rH?m1122¡¢¸ù¾Ý ln(K2 /K1) =(?),ÔÚʲôÌõ¼þÏ£¬½µµÍÎÂ¶ÈÆ½

RT1T2?

?

ºâÏòÕý·´Ó¦·½ÏòÒÆ¶¯£¨ £©

A. ¦¤rHm?>0 B. ¦¤rHm?<0

C. ¦¤rSm?<0 D. µÍÎÂÇø

23¡¢Ð¡ËÕ´ò£¨NaHCO3£©°´ÏÂʽ·Ö½âÉú³É´¿¼î£¨Na2CO3£© 2NaHCO3(s) = Na2CO3(s) + CO2(g) + H2O(g)

ÒÑÖªÔÚ273K ʱ£¬K1?=£¬ÔÚ323Kʱ£¬K?=¡Á10-4,ÄÇôÉÏÊö·´Ó¦£¨£© 2 A. ?rH?<0 B. ?rG?m£¨323K£©<0 m C. ?rH?>0 D. ?rS?Ϊ¸ºÖµ mm24. ÈéËáµÄ»¯Ñ§Ê½ÓÃHLac±íʾ¡£ÒÑÖª HLac + H2O = H3O+ + Lac- K?=¡Á10-4 aH2O + H2O = H3O+ + OH- K?=¡Á10-14 wÄÇô·´Ó¦ Lac-1 + H2O = HLac + OH-1µÄK0ֵΪ£¨ £©

A. K?+K? B. K?-K? aaw w C. K?/ K? D. K?¡¤K? aaww25¡¢ÒÑÖª: (1) CaC2O4= Ca2+ + C2O42- K0=¡Á10-9

(2) Hac = H+ + Ac- K0=¡Á10-5 (3) HC2O4-= H+ + C2O42- K0=¡Á10-5

Ôò¿É¼ÆËã·´Ó¦CaC2O4 + Hac = Ca2+ + HC2O4- + Ac-µÄK0,È»ºó¿ÉÅжϵ¨½áʯ³É·ÖÖ®Ò»µÄ²ÝËá¸ÆÔÚ´×ËáÖУ¨ £©

A.¿ÉÈÜ B.΢ÈÜ C.ÄÑÈÜ D.·¢ÉúÑõ»¯»¹Ô­·´Ó¦

Èý¡¢ Ìî¿ÕÌâ

1¡¢673Kʱ£¬ ·´Ó¦ N2(g) + 3 H2(g) = 2NH3(g) µÄK? = Ôò·´Ó¦NH3(g)

= 1/2 N2(g) + 3/2 H2(g) µÄK? =_________¡£

2¡¢·´Ó¦Fe(s) + 2H+(aq) = Fe2+(aq) + H2(g)µÄ±ê׼ƽºâ³£ÊýµÄ±í´ï

ʽΪK? = ____________________¡£ 3¡¢ÒÑÖªÏÂÁз´Ó¦ÔÚÖ¸¶¨Î¶ȵĦ¤rG?mºÍK?£¬

(1) N2(g) + 1/2O2(g) = N2O(g) ¦¤rG?m1, K?1

(2) N2O4(g) = 2NO2(g) ¦¤rG?m2, K?2 (3) 1/2N2(g) + O2(g) = NO2(g) ¦¤rG?m3, K?3

Ôò·´Ó¦ 2 N2O(g) + 3 O2(g) = 2N2O4(g)µÄ¦¤rG?m = ______£¬K? =____________

4¡¢ÒÑÖª¦¤fH?m(NO,g) = £¬ ÔÚ2273Kʱ, ·´Ó¦N2(g) + O2(g) = 2NO(g) µÄK? = ,ÔÚ2273Kʱ,ÈôP(N2) = P(O2) = 10Kpa£¬ P(NO)=20Kpa£¬ ·´Ó¦ÉÌQ = _______£¬ ·´Ó¦Ïò______·½Ïò½øÐÐ; ÔÚ2000Kʱ, ÈôP(NO) = P(N2) =10 Kpa , P(O2) = 100Kpa, ·´Ó¦ÉÌQ = ______, ·´Ó¦Ïò__________·½Ïò½øÐÐ.

5¡¢PCl5(g) = PCl3(g) + Cl2(g)£¬ÔÚÒ»¶¨TºÍPÏ£¬ÈôÒ»¶¨Á¿µÄPCl5

ÆøÌåµÄÌå»ýΪ1Éý£¬ ´ËʱPCl5ÆøÌåÒÑÓÐ50%·Ö½âΪPCl3ºÍ Cl2¡£ Èô¼õÉÙѹÁ¦Ê¹Ìå»ý±äΪ2Éý£¬ÔòPCl5µÄ·Ö½âÂʽ«_____,Èô±£³ÖѹÁ¦²»±ä£¬¼ÓÈëº¤Æø£¬Ê¹Ìå»ý±äΪ2£¬,ÔòPCl5µÄ·Ö½âÂʽ«__________.(Ìî``Ôö´ó¡¯¡¯¡¢``¼õÉÙ¡¯¡¯¡¢``²»±ä¡¯¡¯)

6¡¢¿ÉÄæ·´Ó¦. 2Cl2 (g) + 2H2O(g) = 4HCl(g) + O2(g) ¦¤rH?m > 0 ,

·´Ó¦´ïµ½Æ½ºâºó,½øÐÐÒÔϲÙ×÷,ÊÔÌÖÂÛÆäÓ°Ïì:

(1)¡¢ Ôö´óÈÝÆ÷Ìå»ý , n(H2O,g)________________________; (2)¡¢ ¼ÓÈëO2 , n(H2O,g)____________; n(HCl,g)______________- (3)¡¢¼õСÈÝÆ÷Ìå»ý , n(Cl2,g)____________; P(Cl2,g)_____________;

K?=_____________.

(4)¡¢ ¼ÓÈëÏ¡ÓÐÆøÌå , ±£³ÖÌå»ý²»±ä, n(HCl,g)________________; ±£³ÖѹÁ¦²»±ä,n(HCl,g)__________;

(5) ¡¢¼ÓÈë´ß»¯¼Á ,n(HCl,g)________________¡£

ËÄ. ¼ÆËãÌâ

1¡¢£¨1£© д³ö·´Ó¦ O2 (g) ==O2(aq) µÄ±ê׼ƽºâ³£Êý±í´ïʽ£¬ÒÑÖª200C , p(O2)=101Kpa£¬ÑõÆøÔÚË®ÖеÄÈܽâ¶ÈΪ ¡Á 10¡ª3 mol¡¤l-1 ¼ÆËãÒÔÉÏ·´Ó¦ÔÚ20oCʱK?£¬ ²¢¼ÆËã200CʱÓë101Kpa´óÆøÆ½ºâµÄË®ÖÐC£¨O2£© £¨´óÆøÖÐP£¨O2£©= Kpa£©

£¨2£©. ÒÑ֪Ѫºìµ°°×(Hb)Ñõ»¯·´Ó¦ Hb(aq) + O2(g)=HbO2(aq) ÔÚ200CʱK? = ,¼ÆËãÏÂÁз´Ó¦µÄK?(293K).Hb(aq) + O2(g) = HbO2(aq)

2¡¢383Kʱ,·´Ó¦Ag2CO3(s) = Ag2O(s) + CO2(g) µÄ¦¤rG?m = ,Çó´Ë·´Ó¦µÄK?(383K);ÔÚ383Kºæ¸ÉAg2CO3(s)ʱΪ·ÀÖ¹ÆäÊÜÈÈ·Ö½â,¿ÕÆøÖÐP(CO2)×îµÍӦΪ¶àÉÙKpa