char *name; short int data; char ha;

short ba[5]; }*p;

p=0x1000000; p+0x200=____; (Ulong)p+0x200=____; (char*)p+0x200=____;

希望各位达人给出答案和原因，谢谢拉 解答：假设在32位CPU上， sizeof(long) = 4 bytes

sizeof(char *) = 4 bytes

sizeof(short int) = sizeof(short) = 2 bytes sizeof(char) = 1 bytes

由于是4字节对齐，

sizeof(struct BBB) = sizeof(*p)

= 4 + 4 + 2 + 1 + 1/*补齐*/ + 2*5 + 2/*补齐*/ = 24 bytes (经Dev-C++验证)

p=0x1000000;

p+0x200=____;

= 0x1000000 + 0x200*24

(Ulong)p+0x200=____; = 0x1000000 + 0x200

(char*)p+0x200=____; = 0x10000