ÖйúµØÖÊ´óѧ£¨Î人£©´óѧÎïÀíϲáϰÌâ´ð°¸ ÏÂÔØ±¾ÎÄ

2-11 ijµ¯»É²»×ñÊØºú¿Ë¶¨ÂÉ£¬ÈôÊ©Á¦F£¬ÔòÏàÓ¦É쳤Ϊx£¬Á¦ÓëÉ쳤µÄ¹ØÏµÎª£º F = 52.8 x + 38.4 x2£¨SI£©£¬Çó£º

¢Å ½«µ¯»É´ÓÉ쳤x1 = 0.50 m À­Éìµ½É쳤 x2 = 1.00 mʱËùÐè×öµÄ¹¦£»

¢Æ ½«µ¯»Éºá·ÅÔÚˮƽ¹â»¬×ÀÃæÉÏ£¬Ò»¶Ë¹Ì¶¨£¬ÁíÒ»¶Ëϵһ¸öÖÊÁ¿Îª2.17 kgµÄÎïÌ壬Ȼºó½«µ¯»ÉÀ­Éìµ½É쳤 x = 1.00 m£¬ÔÙ½«ÎïÌåÓɾ²Ö¹ÊÍ·Å£®Çóµ±µ¯»É»Øµ½É쳤x1 = 0.50 mʱ£¬ÎïÌåµÄËÙÂÊ£® Ô­Ìâ 4-5

???qsin? t?j 2-12 Ò»ÖÊÁ¿Îªm µÄÖʵãÔÚxOyÆ½ÃæÉÏÔ˶¯£¬ÆäλÖÃʸÁ¿Îªr?pcos? t i(SI)£¬Ê½ÖÐp¡¢q¡¢?ÊÇÕýÖµ³£Êý£¬ÇÒp > q£®Ç󣺢ŠÇóÖʵãÔÚµã P ( p, 0 ) ºÍµãQ ( 0,

?q ) ´¦µÄ¶¯ÄÜ£» ¢Æ ÖʵãËùÊܵÄ×÷ÓÃÁ¦ F£¬ÒÔ¼°µ±Öʵã´Óµã PÔ˶¯µ½µãQµÄ¹ý³ÌÖеķÖÁ¦FxºÍFy·Ö±ð×÷µÄ¹¦£®

???qsin? t?j ¿ÉÖª£º x?pco?½â£º¢Å ÓÉλʸ r?pcos? t is t £¬y?qsin? t

?x?d xd t??p?sin? t£¬ ?y?d yd t?q?co?s t

22?1mvy?1mq2?2 µãP ( p, 0 ) ´¦ co?s t ?1£¬ sin? t ?0£¬ EkP?1mvx22222?1mvy?1mp2?2 µãQ ( 0, q ) ´¦ co?s t ?0£¬ sin? t ?1£¬ EkQ?1mvx2222 ? t ¢Æ ax?d?xd t??p?2cos? t £¬ ay?d?yd t??q?sin???qsin??Fy???ay?? t i? t ?j) F?Fxij?m(axij)??m?2(pcos0000ÓɵãP¡úQ Ax??pFxd x??pmaxd x???pmp?2cos? t?d x???pm?2x d x?1mp2?2

2Ay??0Fyd y??0mayd y???0mq?2sin? t?d y???0m?2y d y??1mq2?22qqqq 5

×÷Òµ4 ÆøÌ嶯ÀíÂÛ

4-1 ÑõÆø¸ÖÆ¿Ìå»ýΪ5Éý£¬³äÑõÆøºóÔÚ27¡æ ʱѹǿΪ20¸ö´óÆøÑ¹£¬ÊÔÇóÆ¿ÄÚÖü´æÓжàÉÙÑõÆø£¿Ïָ߿ÕÖÐʹÓÃÕâЩÑõÆø£¬ÔÚ¸ß¿Õ¿ÕÆøµÄѹǿΪ0.67¸ö´óÆøÑ¹£¬Î¶ÈΪ -27¡æ£¬ÊÔÎÊÕâʱ¸ÖÆ¿¿ÉÌṩÔڸ߿ÕʹÓõÄÑõÆøÊǶàÉÙÉý£¿

0.13 kg £¬117Éý£»

Ô­Ìâ 8¡ª1

4-2 ÔÚP-VͼÉϵÄÒ»µã´ú±íϵͳ ƽºâ״̬ £»Ò»Ìõ¹â»¬µÄÇúÏß´ú±í ÆøÌåµÄ×¼¾²Ì¬¹ý³Ì £®

4-3 ÉèÏëÿÃëÓÐ1023¸öÑõ·Ö×ÓÒÔ500 m/sµÄËÙ¶ÈÑØ×ÅÓëÆ÷±Ú·¨Ïß³É30¡ã½ÇµÄ·½ÏòײÔÚÃæ»ýΪ3?10?4m2µÄÆ÷±ÚÉÏ£¬ÇóÕâȺ·Ö×Ó×÷ÓÃÔÚÆ÷±ÚÉϵÄѹǿ£®

Ô­Ìâ 8¡ª3

6

4-4 Á½Æ¿²»Í¬ÀàÐ͵ÄÀíÏëÆøÌ壬ËüÃǵÄζȺÍѹǿÏàͬ£¬µ«Ìå»ý²»Í¬£¬ÔòËüÃǵķÖ×ÓÊýÃÜ¶È Ïàͬ £»ÆøÌåµÄÖÊÁ¿ÃÜ¶È ²»Í¬ £»µ¥Î»Ìå»ýÄÚÆøÌå·Ö×ӵį½¾ù¶¯ÄÜΪ ²»Í¬ £®

Ô­Ìâ 8¡ª4

4-5 ÈôÀíÏëÆøÌåµÄÌå»ýΪV£¬Ñ¹Ç¿ÎªP£¬Î¶ÈΪT£¬Ò»¸ö·Ö×ÓµÄÖÊÁ¿Îªm£¬kΪ²£¶úpV×ÈÂü³£Êý£¬Ôò¸ÃÀíÏëÆøÌåµÄ·Ö×ÓÊýΪ N?kT £®

½â£º p?nkT?NpV kT N?kTV4-6 ÖÊÁ¿ÏàͬµÄÇâÆøºÍº¤Æø£¬Î¶ÈÏàͬ£¬ÔòÇâÆøºÍº¤ÆøµÄÄÚÄÜÖ®±ÈΪ 10 : 3 £¬Çâ·Ö×ÓÓ뺤·Ö×ӵį½¾ù¶¯ÄÜÖ®±ÈΪ 5 : 3 £»Çâ·Ö×ÓÓ뺤·Ö×ӵį½¾ùƽ¶¯¶¯ÄÜÖ®±ÈΪ 1 : 1 £®

Ô­Ìâ 8¡ª6

4-7 ÊÔÖ¸³öÏÂÁи÷Á¿µÄÎïÀíÒâÒå

¢Å kT/2£» ¢Æ 3kT/2£» ¢Ç ikT/2.

´ð£º ¢Å kT/2 ¡ª¡ªÀíÏëÆøÌå·Ö×ÓÈÎÒ»×ÔÓÉ¶ÈµÄÆ½¾ù¶¯ÄÜ£» ¢Æ 3kT/2 ¡ª¡ªÀíÏëÆøÌåµÄ·Ö×ӵį½¾ùƽ¶¯¶¯ÄÜ£»

¢Ç ikT/2 ¡ª¡ªÀíÏëÆøÌåµÄ·Ö×ӵį½¾ù×ܶ¯ÄÜ

4-8 ½«0.2molÑõÆø´Ó27¡æ¼ÓÈȵ½37¡æ£¬ÆäÄÚÄÜÔö¼ÓÁ˶àÉÙ£¿·Ö×ӵį½¾ùƽ¶¯¶¯Äܱ仯Á˶àÉÙ£¿

½â£ºÑõÆøÎªË«Ô­×Ó·Ö×Ó£¬i?5£¬ÔòÄÚÄÜÔöÁ¿Îª

i5?E?? R(T2?T1)??0.2?8.31?10?41.55J

223·Ö×ӵį½¾ùƽ¶¯¶¯ÄÜΪEK?kT£¬ÆäÔöÁ¿Îª

2?EK?33k?T??1.38?10?23?10?2.07?10?22J 227

4-9 Ò»¾øÈÈÃÜ·âÈÝÆ÷µÄÌå»ýΪ10?2m3£¬ÒÔ100 m/sµÄËÙ¶ÈÔÈËÙÖ±ÏßÔ˶¯£¬ÈÝÆ÷ÖÐÓÐ100gµÄÇâÆø£¬µ±ÈÝÆ÷ͻȻֹͣʱ£¬ÇâÆøµÄζȡ¢Ñ¹Ç¿¸÷Ôö¼Ó¶àÉÙ£¿

Ô­Ìâ 8¡ª7

4-10 ÈÝÆ÷ÄÚÓÐһĦ¶ûµÄ˫ԭ×Ó·Ö×ÓÀíÏëÆøÌå£¬ÆøÌåµÄĦ¶ûÖÊÁ¿Îª?£¬ÄÚÄÜΪE£¬ÔòÆøÌåµÄζÈT = 2E5R £¬·Ö×ÓµÄ×î¿É¼¸ËÙÂÊ ?p= 2E(5?) £¬·Ö×ӵį½¾ùËÙÂÊ ?= 4E(5¦Ð?) £® Ô­Ìâ 8¡ª8

4-11 ÒÑÖªf(?)ΪÂó¿Ë˹ΤËÙÂÊ·Ö²¼º¯Êý£¬NΪ·Ö×Ó×ÜÊý£¬ ÔòËÙÂÊ´óÓÚ100 m/sµÄ·Ö×ÓÊýÄ¿µÄ±í´ïʽ N??dN??N???100f(?) d? £»

?ËÙÂÊ´óÓÚ100 m/sµÄ·Ö×ÓÊýĿռ·Ö×Ó×ÜÊýµÄ°Ù·Ö±ÈµÄ±í´ïʽ P?ËÙÂÊ´óÓÚ100 m/sµÄ·Ö×ӵį½¾ùËÙÂʵıí´ïʽ ??¡ß

?100?f(?) d? £» f(?)d? £®

??100?f(?) d? ?100dN??f(?) d? ¡ª¡ª ËÙÂÊÇø¼ä ?~??d?ÄڵķÖ×ÓÊýÕ¼×Ü·Ö×ÓÊýµÄ°Ù·Ö±È(¼¸ÂÊ)N8