¶þ¡¢¸ÅÄîÓëÃû´Ê½âÊÍ(¹²10·Ö£¬Ã¿Ð¡Ìâ 2·Ö) 1£® ÐØ¸ßÐÎÊý£ºf1.3?Vg1.3H£¬Ê½ÖÐ V¡ª¡ªÊ÷¸É²Ä»ý£»g1.3¡ª¡ªÐظ߶ÏÃæ»ý£»H¡ª¡ªÈ«
Ê÷¸ß¡£
2£® ÒìÁäÁÖ£ºÁÖ·ÖÖÐÊ÷ľÄêÁä²îÒ쳬¹ýÒ»¸öÁä¼¶£¬ÕâÑùµÄÁÖ·Ö³Æ×÷ÒìÁäÁÖ¡£ 3£® ÁÖ·Öµ÷²éÒò×Ó£º¿Í¹Û·´Ó³ÁÖ·ÖÌØÕ÷µÄÊýÁ¿ºÍÖÊÁ¿Òò×Ó¡£
4£® µ¥Ä¾¾ºÕùÖ¸±ê:ÃèÊöijһÁÖľÊÜÖÜΧ¾ºÕùľµÄÓ°Ïì¶ø³ÐÊܾºÕùѹÁ¦µÄÊýÁ¿Ö¸±ê¡£ 5£® ÁÖ·ÖÉú³¤Ä£ÐÍ£ºÃèÊöÁÖľÉú³¤ÓëÁÖ·Ö״̬ºÍÁ¢µØÌõ¼þ¹ØÏµµÄÒ»¸ö»òÒ»×éÊýѧº¯
Êý¡£
Èý¡¢¼òÊöÌâ(¹²20·Ö£¬Ã¿Ð¡Ìâ 5·Ö)
1£®ËµÃ÷ÐÎÊý¡¢ÐÎÂÊÓëÊ÷¸ßµÄ¹ØÏµ¡£
2f1.3?a?bq2?c q2hÁù¡¢¼ÆËãÌâ(¹²20·Ö£¬Ã¿Ð¡Ìâ 4·Ö)
1. ÒÑ֪ijÔľ³¤4m£¬0m´¦Ö±¾¶Îª18.0cm£¬2m´¦Ö±¾¶Îª16.0cm£¬4m´¦Ö±¾¶Îª
13.2cm£»ÊÔÓÃÖÐÑë¶ÏÃæ»ý¼°Æ½¾ù¶ÏÃæ»ý½üËÆÇó»ýʽ¼ÆËãÆä²Ä»ý¡£ 2. ÂäÒ¶ËÉÌìÈ»ÁÖ×î´óÃܶÈÏßΪ£º N?4500Dg2
?1.550£¬ÏÖʵÁÖ·ÖÖÐÁÖ·Öÿ¹«Çê
ÖêÊýΪ£º2580Öê/hm,ƽ¾ùÐØ¾¶Îª£º14.5 cm£¬¼ÆËã¸ÃÁÖ·ÖµÄÁÖ·ÖÃܶÈÖ¸Êý£¨SDI£©£¨×¢£º±ê×¼Ö±¾¶Îª20cm£©¡£
3232
3. ij¹Ì¶¨±ê×¼µØ1995Äêʵ²âÐî»ýΪ150m/hm,2000Ä긴²âΪ155m/hm,ÆÚ¼ä
323
¼ä·¥Á¿Îª30 m/hm,¿ÝËðÁ¿Îª8 m,ÊÔ¼ÆËã¸ÃÁÖ·ÖµÄëÉú³¤Á¿,´¿Éú³¤Á¿ºÍ¾»ÔöÁ¿¡£
2
4. ÔÚÃæ»ýΪ10 hmµÄijÈ˹¤ÓÍËÉ¡¢²à°Ø»ì½»ÁÖÖУ¬ÉèÖÃÒ»¿é±ê×¼µØ£¬ÆäÃæ»ý
23
Ϊ0.2 hm£¬¾¹ý±ê×¼µØµ÷²éºóµÃÖª£ºÓÍËɵÄÐî»ýÁ¿Îª44.8 m£¬²à°ØµÄÐî
3
»ýÁ¿Îª11.2 m¡£Çë¸ù¾ÝÉÏÊöÊý¾Ýд³ö¸Ã»ì½»ÁÖ·ÖµÄÊ÷ÖÖ×é³Éʽ²¢²âËã³ö¸Ã»ì½»ÁÖ·Ö×ÜÐî»ýÁ¿¡£
5. Ò»ÖêÕÁ×ÓËɵÄÊ÷¸ß×ÜÉú³¤·½³ÌΪ£º
H?30.5(1?e?0.053t)
ÊÔ¼ÆËã¸ÃÊ÷30Ä꣨t=30£©Ê±µÄÊ÷¸ßÁ¬ÄêÉú³¤Á¿¡£
Áù¡¢¼ÆËãÌâ(20·Ö£¬Ã¿Ð¡Ìâ4·Ö)
1. ÖÐÑë¶ÏÃæ»ý½üËÆÇó»ýʽΪ V?g1L?2?400002d1L 2ËùÒÔ V??40000?162?4?0.0804m3
2d02?dn1?()L ƽ¾ù¶ÏÃæ»ý½üËÆÇó»ýʽΪ V?(g0?gn)L?2400002182?13.22()?4?0.0782 m3¡£ ËùÒÔ V?400002?2. SDI?N?(DI/Dg)??2580?(20/14.5)?1.55?1567.3¡£
3. ëÉú³¤Á¿:Zgr=Mb-Ma+C+M0=155-150+30+8=43Á¢·½Ã×
´¿Éú³¤Á¿:Zne=Mb-Ma+c=155-150+30=35Á¢·½Ã× ¾»ÔöÁ¿=Mb-Ma=155-150=5Á¢·½Ãס£
22
4. »ì½»ÁÖÃæ»ýΪ10 hm, ±ê×¼µØÃæ»ýΪ0.2 hm,±ê×¼µØµ÷²é½á¹û£ºÊ÷ÖÖÓÍËÉÐî
333
»ýÁ¿Îª44.8 m,Ê÷ÖÖ²à°ØÐî»ýÁ¿Îª11.2 m¡£±ê×¼µØÁÖ·ÖÐî»ýÁ¿Îª56 m¡£
?44.8=0.80 5611.2 ²à°ØµÄ±ÈÖØÎª£º=0.20
56 ÓÍËɵıÈÖØÎª£º
¸Ã»ì½»ÁÖµÄÊ÷ÖÖ×é³ÉʽΪ£º8ÓÍËÉ2²à°Ø ¸Ã»ì½»ÁÖ·Ö×ÜÐî»ýÁ¿Îª£º M=
5.
56?10=2800 m3 0.2dH?30.5?0.053e?0.053?t?0.33m¡£ dtÒ»¡¢Ìî¿ÕÌâ(¹²10·Ö£¬Ã¿Ð¡Ìâ1·Ö,¹²¼Æ10СÌâ)
1. ²â¶¨Ê÷¸É²Ä»ýµÄÈýÒªËØÎªÐØ¾¶¡¢£¨Ê÷¸ß £©ºÍÐÎÊý¡£
2. µØÎ»Ö¸ÊýÊǸù¾ÝÁÖ·ÖÄêÁäºÍ£¨ ÓÅÊÆÄ¾Æ½¾ù¸ß £©¶øÈ·¶¨µÄ¡£ 3. µäÐÍÒìÁäÁÖÖ±¾¶·Ö²¼Îª£¨ ·´¡°J¡±ÐÍ £©ÇúÏß¡£
4. Ò»¶¨ÆÚ¼äÄÚijµ÷²éÒò×ÓµÄÉú³¤Á¿¼´Îª£¨ ¶¨ÆÚ £©Éú³¤Á¿¡£ 5. ·¥µ¹Ä¾²Ä»ý²â¶¨Ê±£¬Çø·Ö¶Î¸öÊýÔ½¶à£¬£¨ Îó²î £©Ô½Ð¡¡£ 6. ½Ç¹æ²âÊ÷ʱ,FgԽС£¬²âÁ¿Îó²î£¨ Ô½´ó £©¡£
7. ²ÄÖֲĻý±ÈÊǸ÷²ÄÖֲĻýÓ루 Ê÷¸É´øÆ¤²Ä»ý £©±ÈÖµ¡£ 8. ij½âÎöľ7.9Ã×£¬ÓÃÒ»Ã×Çø·Ö¶ÎÇø·Ö£¬ÔòÉÒÍ·³¤¶ÈÊÇ(0.9£©Ãס£
9. ÊÕ»ñ±íµÄÖÖÀàÓÐÕý³£ÊÕ»ñ±í¡¢¾ÑéÊÕ»ñ±íºÍ£¨ ¿É±äÃܶÈÊÕ»ñ±í £©¡£
10. Ïà¶ÔÖ±¾¶ÊÇÁÖľֱ¾¶Ó루 ÁÖ·ÖÆ½¾ùÖ±¾¶ £©µÄ±ÈÖµ¡£ ¶þ¡¢¸ÅÄîÓëÃû´Ê½âÊÍ(¹²10·Ö£¬Ã¿Ð¡Ìâ 2·Ö) 6£® ʵÑéÐÎÊý£ºf1.3?V£¬Ê½ÖÐ V¡ª¡ªÊ÷¸É²Ä»ý£»g1.3¡ª¡ªÐظ߶ÏÃæ»ý£»
g1£¨H£«3£©.3H¡ª¡ªÈ«Ê÷¸ß¡£
7£® ²Ä»ý±í£ºÊ÷¸É²Ä»ýÓëÆäÈýÒªËØÖ®¼äº¯Êý¹ØÏµ±àÖÆµÄ£¬²¢¼ÇÔØÓи÷¾¶½×µ¥Öêľƽ¾ù
²Ä»ýµÄÊý±í¡£
8£® ½Ç¹æ¿ØÖƼñ³ß£ºÔڽǹæÈƲâʱ£¬¶Ô¼ÆÊýµÄÁÖľʵ²âÆäÐØ¾¶µÄ¹¤×÷¡£ 9£® Ê÷¸ßÇúÏߣºÁÖ·ÖÖÐÁÖÄ¾ÐØ¾¶ÓëÊ÷¸ßµÄÏà¹ØÇúÏß¡£
10Ï÷¶È·½³Ì£ºd(h)=f(D1.3,H,h),ʽÖУºD1.3¡ªÐؾ¶£»H¡ªÊ÷¸ß£»h¡ª¾àµØÃæµÄ¸ß¶È¡£
Èý¡¢¼òÊöÌâ(¹²20·Ö£¬Ã¿Ð¡Ìâ 5·Ö)
1£® ·Ö¼¶±ê׼ľ·¨Ñ¡È¡±ê׼ľµÄÔÔò¡£
1. ·Ö¼¶±ê׼ľ·¨Ñ¡È¡±ê׼ľµÄÔÔò£º
(1)µÈÖê¾¶¼¶±ê׼ľ·¨£ºÒÀ¾¶½×ÓÉСµ½´óµÄ˳Ðò£¬½«ÁÖ·Ö·ÖΪÖêÊý»ù±¾ÏàµÈµÄ3¡ª5¸ö¾¶¼¶£»
(2)µÈ¶ÏÃæ¾¶¼¶±ê׼ľ·¨£ºÒÀ¾¶½×˳Ðò£¬½«ÁÖ·Ö·ÖΪ¶ÏÃæ»ý»ù±¾ÏàµÈµÄ3¡ª5¸ö¾¶¼¶£»
¾¶½×µÈ±È±ê׼ľ·¨£º·Ö±ð¾¶½×°´µÈ±Èѡȡ±ê׼ľ£¬¼´Ã¿¸ö¾¶½×ËùѡȡµÄ±ê׼ľµÄÖêÊýºÍ¸Ã¾¶½×ÄÚÁÖľÖêÊýµÄ±ÈÖµÒ»¶¨µÄ·½·¨¡£
4. ÁÖ·ÖÉú³¤Á¿µÄÖÖÀ༰ÆäÏ໥¹ØÏµ¡£
ÁÖ·ÖÉú³¤Á¿·ÖΪ£º(1)ëÉú³¤Á¿(Zgr)£»(2)´¿Éú³¤Á¿(Zne)£»(3)¾»ÔöÁ¿(?)£»(4)¿ÝËðÁ¿(M0)£»(5)²É·¥Á¿(C)£»(6)½ø½çÉú³¤Á¿(I)¡£Ï໥¹ØÏµÎª£º
Zne???CZgr?Zne?M0???C?M0
Áù¡¢¼ÆËãÌâ(¹²20·Ö£¬Ã¿Ð¡Ìâ 4·Ö)
6. ÒÑ֪ijÔľ³¤4m£¬0m´¦¶ÏÃæ»ýΪ0.0390m£¬2m´¦¶ÏÃæ»ýΪ0.0272m£¬4´¦
2
¶ÏÃæ»ýΪ0.0214m£¬ÊÔÓÃÖÐÑë¶ÏÃæ»ý¼°Æ½¾ù¶ÏÃæ»ý½üËÆÇó»ýʽ¼ÆËãÆä²Ä»ý¡£
7. ijһÖêÊ÷ľ½øÐÐÊ÷¸É½âÎöʱ£¬3ÄêºÍ8ÄêʱµÄÊ÷¸ß×ÜÉú³¤Á¿·Ö±ðΪ0.6 mºÍ
2.5 m, ÊÔ¼ÆËã5ÄêʱµÄÊ÷¸ß¡£
8. Óýǹæ¹Û²âijÊ÷,Fg=4,D1.3=18.0cm,½Ç¹æµãÖÁ¸ÃÊ÷µÄˮƽ¾àΪ9m,ÎʸÃÊ÷µÄ
¼ÆÊýÖµ?
23
9. ²âµÃ±ê×¼µØÁ½ÖêÆ½¾ù±ê׼ľ£ºg1=0.05107 m , v1=0.52260 m£»
2322
g2=0.05027m, v2 =0.44013 m , ÁÖ·Ö×ܶÏÃæ»ý G/hm=10.84m, ÊÔÇó¸ÃÁÖ·ÖµÄÐî»ýÁ¿¡£
2
2
10. Ò»ÖêÂäÒ¶ËÉÈ˹¤ÁÖÊ÷¸ß×ÜÉú³¤·½³ÌΪ£º
H?32.5e?18.64/t
ÊÔ¼ÆËã¸ÃÊ÷30Ä꣨t=30£©Ê±µÄÊ÷¸ßÁ¬ÄêÉú³¤Á¿¡£
Áù¡¢¼ÆËãÌâ(20·Ö£¬Ã¿Ð¡Ìâ4·Ö)
3 1. ÖÐÑë¶ÏÃæ»ý½üËÆÇó»ýʽΪ: V?g1L?0.0272?4?0.1088m
2ƽ¾ù¶ÏÃæ»ý½üËÆÇó»ýʽΪ :
V?11(g0?gn)L?(0.0390?0.0214)*4?0.1208m3 22t2?t8?5(y2?y1)?2.5?(2.5?0.6)?1.36m¡£ t2?t18?32. h?h2? 3. Ri?50DiFg?50?184?4.5m, R
4. M?G?v?gii?10.840.96073?103m3
0.101345.
dH?32.5e?18.64/t?18.64/t2?0.3616m¡£ dt
1. ²â¶¨Ê÷¸É²Ä»ýµÄÈýÒªËØÎªÐØ¾¶¡¢£¨ Ê÷¸ß £©ºÍÐÎÊý¡£
2. µØÎ»Ö¸ÊýÊǸù¾ÝÁÖ·ÖÄêÁäºÍ£¨ ÓÅÊÆÄ¾Æ½¾ù¸ß £©¶øÈ·¶¨µÄ¡£ 3. µäÐÍÒìÁäÁÖÖ±¾¶·Ö²¼Îª£¨ ·´¡°J¡±ÐÍ £©ÇúÏß¡£
4. Ò»¶¨ÆÚ¼äÄÚijµ÷²éÒò×ÓµÄÉú³¤Á¿¼´Îª£¨ ¶¨ÆÚ £©Éú³¤Á¿¡£ 5. ·¥µ¹Ä¾²Ä»ý²â¶¨Ê±£¬Çø·Ö¶Î¸öÊýÔ½¶à£¬£¨ Îó²î £©Ô½Ð¡¡£ 6. ½Ç¹æ²âÊ÷ʱ,FgԽС£¬²âÁ¿Îó²î£¨ Ô½´ó £©¡£
7. ²ÄÖֲĻý±ÈÊǸ÷²ÄÖֲĻýÓ루 Ê÷¸É´øÆ¤²Ä»ý £©±ÈÖµ¡£
8. ij½âÎöľ7.9Ã×£¬ÓÃÒ»Ã×Çø·Ö¶ÎÇø·Ö£¬ÔòÉÒÍ·³¤¶ÈÊÇ( 0.9 £©Ãס£ 9. ÊÕ»ñ±íµÄÖÖÀàÓÐÕý³£ÊÕ»ñ±í¡¢¾ÑéÊÕ»ñ±íºÍ£¨ ¿É±äÃܶÈÊÕ»ñ±í £©¡£ 10. Ïà¶ÔÖ±¾¶ÊÇÁÖľֱ¾¶Ó루 ÁÖ·ÖÆ½¾ùÖ±¾¶ £©µÄ±ÈÖµ¡£
1. ʵÑéÐÎÊý
f1.3?V£¬Ê½ÖÐ V¡ª¡ªÊ÷¸É²Ä»ý£»g1.3¡ª¡ªÐظ߶ÏÃæ»ý£»H¡ª¡ªÈ«Ê÷¸ß¡£
g1£¨H£«3£©.32. ²Ä»ý±í