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2£® ·´Ó¦µÄ¦¤rHm¾ÍÊÇ·´Ó¦µÄÈÈЧӦ¡££¨ £©

3£® ÔÚ¸ø¶¨Ìõ¼þÏ£¬ÏÂÁз´Ó¦·½³ÌʽËù±í´ïµÄ·´Ó¦²úÉúµÄÈÈÁ¿ÊÇÒ»ÏàͬµÄÖµ¡££¨ £©

2H2(g) + O2(g) = 2H2O(l) ÓëH2(g) +

1 O2(g) = H2O(l) 24£® ·´Ó¦µÄ¦¤rSmΪÕýÖµ£¬¸Ã·´Ó¦ÊÇ×Ô·¢µÄ¡££¨ £©

5£® Èç¹û·´Ó¦µÄ¦¤rHmºÍ¦¤rSm½ÔΪÕýÖµ£¬ÉýÎÂʱ¦¤rGm¼õÉÙ¡££¨ £© 6£® ·²ÊǼª²¼Ë¹×ÔÓÉÄܽµµÍµÄ¹ý³ÌÒ»¶¨ÊÇ×Ô·¢¹ý³Ì¡££¨ £© 7£® ·Ö×ÓÊýÔö¼ÓµÄ·´Ó¦¦¤rSmÒ»¶¨ÎªÕýÖµ¡££¨ £©

8£® »¯Ñ§·´Ó¦µÄ¶¨Ñ¹ÈÈÓë;¾¶Î޹أ¬¹ÊÆäΪ״̬º¯Êý¡££¨ £© 9£® »¯Ñ§·´Ó¦µÄ¶¨Ñ¹ÈȲ»ÊÇ״̬º¯Êý£¬µ«Óë;¾¶Î޹ء££¨ £©

10£®Ö¸¶¨Î¶ÈÏ£¬ÔªËØÎȶ¨µ¥ÖʵĦ¤fH?m =0 ¡¢¦¤fG?m=0¡¢ S?m=0 ¡££¨ £©

11£®Ó¦ÓøÇ˹¶¨ÂÉ£¬²»½ö¿ÉÒÔ¼ÆË㻯ѧ·´Ó¦µÄ¦¤rHm, »¹¿É¼ÆË㦤rUm¡¢ ¦¤rGm ¡¢¦¤rSmµÈ¡££¨ £© 12£®¶ÔÓÚ¦¤rS?m>0µÄ·´Ó¦£¬±ê׼״̬Ï£¬¸ßÎÂʱ¾ù¿ÉÄÜÕýÏò·´Ó¦¡££¨ £© 13£®¦¤rG?m<0µÄ·´Ó¦Ò»¶¨ÄÜ×Ô·¢½øÐС££¨ £©

14£®ÄÜȼÉÕµÄÎïÖʺ¬ÓÐÈÈÁ¿£¬·´Ö®Ôò²»º¬ÓÐÈÈÁ¿¡££¨ £©

1

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1¡¢ÏÂÁи÷×é¾ùΪ״̬º¯ÊýµÄÊÇ£¨ £©

A£®U¡¢H¡¢S¡¢P¡¢V¡¢T B£® U¡¢H¡¢S¡¢W¡¢Q¡¢G C£®¦¤U¡¢¦¤H¡¢¦¤S¡¢W¡¢Q¡¢¦¤G D£®QP¡¢QV¡¢W¡¢P¡¢V¡¢T

2. ÏÂÁÐÎïÖÊÖУ¬¦¤fG?m = 0 µÄÊÇ£¨ £©

A. Br2( g) B. Br2(l) C. Br2(aq) D. Br ¨C(aq)

3¡¢ÏÂÁÐÐðÊöÖÐÕýÈ·µÄÊÇ£º£¨ £©

A. ʯīµÄìʲ»ÎªÁã B. µÈÎÂÌõ¼þÏÂ, ¦¤rGm? = ¦¤rH?m ¨C T¦¤rSm? C. ·´Ó¦µÄìʱäÔ½´ó,·´Ó¦ËÙÂÊÔ½´ó.

D. ÎÞÂÛÈκÎÇé¿öÏÂ,Ö»Òª¦¤S>0,¸Ã·´Ó¦Ò»¶¨ÊÇ×Ô·¢·´Ó¦. 4¡¢¾ßÓÐ×îСĦ¶ûìØµÄÎïÖÊÊÇ£¨ £©

A. Br2(l) B. NaCl(s) C. Na(s) D. Cl2(g)

5£® Èôij·´Ó¦µÄ¦¤rGm? = 10KJ.mol-1£¬ÓÉ´Ë¿ÉÍÆ¶Ï¸Ã·´Ó¦£¨ £©

A¡¢¦¤rHm?>0 ¦¤rSm?<0 B. Ò»¶¨²»ÄÜ×Ô·¢½øÐÐ C. ÔÚ±ê׼״̬ÏÂÒ»¶¨²»ÄÜ×Ô·¢½øÐÐ D. ÔڷDZê׼״̬ÏÂÒ»¶¨²»ÄÜ×Ô·¢½øÐÐ

6£® ÔÚ373K£¬101325Paʱ£¬Ë®Õô·¢ÎªË®ÕôÆûµÄ¹ý³ÌÖУ¬ÌåϵµÄÈÈÁ¦Ñ§º¬ÊýµÄ±äÁ¿ÎªÁãµÄ£¨ £©

A£®¦¤rH?m B. ¦¤rG?m C. ¦¤rSm? D. ¦¤rUm

7£® ÒÑÖªHClµÄ¦¤fH?m = 431KJ.mol-1£¬Ôò¿ÉÅжÏÏÂÁз´Ó¦£º

H2(g) + Cl2(g) = 2HCl(g) µÄ¦¤rH?mΪ£º£¨ £©

A. ¨C431KJ.mol-1 B. 862KJ.mol-1 C. ¨C862KJ.mol-1 D. ÎÞ·¨ÅжÏ

3

8£® ±íʾ CO2µÄ±ê׼Ħ¶ûÉú³Éìʵķ´Ó¦ÊÇ£¨ £©

A. CO(g) + 1/2O2(g) = CO2(g) ¦¤rH?m = £­283.0KJ.mol-1 B. C(½ð¸Õʯ ) + O2(g) = CO2(g) ¦¤rH?m = £­395.38KJ.mol-1 C. 2C(ʯī) + 2O2(g) = 2CO2(g) ¦¤rH?m = £­787.0KJ.mol-1 D. C(ʯī) + O2(g) = CO2(g) ¦¤rH?m = £­393.5KJ.mol-1 9£® °´¹æ¶¨£¬ÏÂÁÐÎïÖʵıê׼Ħ¶ûÉú³ÉìÊΪÁãµÄÊÇ£¨ £©

A. C(½ð¸Õʯ) B. O3(g) C. Br2(l) D. I2(g) 10£®ÏÂÁз´Ó¦ÖÐÄĸöÊDZíʾ¦¤fH?m (AgI,s)µÄ·´Ó¦Ê½£¨ £©

A. Ag+(aq) + I-(aq) = AgI(s) B. 2 Ag(s) + I2(s) = 2AgI(s) C. 2 Ag(s) + I2(g) = 2AgI(s) D. Ag(s) + 1/2I2(s) = AgI(s)

11£® ÒÑÖª C£¨Ê¯Ä«£©+ O2(g) = CO2(g) ¦¤fH?m = £­393.5KJ.mol-1 fH?

m =

£­395.8KJ.mol-1

Ôò£º C£¨Ê¯Ä«£©?C(½ð¸Õʯ)µÄ¦¤rH?mµÈÓÚ£¨ £©

A. ¨C789.3KJ.mol-1 B. 2.3KJ.mol-1 C. ¨C2.3KJ.mol-1 D. 789.3KJ.mol-1

12£® Ò»¶¨Î¶ÈÏ£¬ÏÂÁз´Ó¦ÖÐÄÇÒ»¸ö·´Ó¦µÄ¦¤rS?mÖµ×î´ó£¨ £©

A. CaSO4(s) + 2H2O(l) = CaSO4.2H2O(s) B.

MgCO3(s) = MgO(s) + CO2(g)

C. 2SO2(g) + O2(g) = 2SO3(g) D. H2(g) + Cl2(g) = 2HCl(g)

13£®·´Ó¦MgCl2(s) = Mg(s) + Cl2(g), ¦¤rHm¦¨

>0,±ê׼״̬Ï£¬´Ë·´Ó¦£º£¨ £© A. µÍÎÂ×Ô·¢ B. ¸ßÎÂ×Ô·¢

C. ÈκÎζȾù×Ô·¢ D. ÈκÎζȾù²»¿ÉÄÜ×Ô·¢

4

C£¨½ð¸Õʯ£©+ O2(g) = CO2(g) ¦¤

14£® °±µÄ·Ö½â·´Ó¦£º2NH3(g) = N2(g) + 3H2(g)£¬ ¸ßÎÂÏÂΪ×Ô·¢·´Ó¦£¬ ÔڽϵÍζÈÏÂÆäÄæ·´Ó¦Îª×Ô·¢£¬ÕâÒâ

ζןÃÕý·´Ó¦µÄ¦¤rH?mºÍ¦¤rS?m Ϊ£¨ £©

A. B. C. D.

¦¤rH?m > 0 ¦¤rS?m > 0 ¦¤rH?m > 0 ¦¤rS?m < 0 ¦¤rH?m < 0 ¦¤rS?m < 0 ¦¤rH?m < 0 ¦¤rS?m > 0

15£® ÔÚ298.15KºÍ±ê׼̬ʱ£¬ÏÂÁз´Ó¦¾ùΪ·Ç×Ô·¢·´Ó¦£¬ÆäÖÐÔÚ¸ßÎÂÏÂÈÔΪ·Ç×Ô·¢·´Ó¦µÄÊÇ£¨ £© £¨²»±Ø¼ÆË㣩

A. B.

Ag2O(s) = 2Ag(s) + N2O4(g) = 2NO2(g)

1O2(g) 2C. D.

Fe2O3(s) +

31C(s) = 2Fe(s) + CO2(g) 22 6C(s) + 6H2O(g) = C6H12O6(s)

16£® Èç¹ûÔÚÈÈÁ¦Ñ§Î¶ÈÏ£¬Ä³Ò»·´Ó¦µÄ¼ª²¼Ë¹×ÔÓÉÄܱ仯Ϊ¦¤G£¬ìʱäΪ¦¤H£¬Ôò¸Ã·´Ó¦µÄìØ±äΪ£¨ £©

A¡¢

?G??HT B¡¢

?H??G

TC¡¢ T(¦¤G-¦¤H) D¡¢T(¦¤H-¦¤G)

17£® Èç¹ûÒ»¸ø¶¨·´Ó¦µÄ¦¤rG?mÒÑÖª£¬³ýÁËÏÂÁÐÄÄÒ»ÏîÍ⣬ÆäÓà¸÷Ïî¾ù¿ÉÈ·¶¨£¨ £©

A¡¢ÔÚ±ê׼״̬Ï£¬×Ô·¢·´Ó¦µÄ·½Ïò¡£ B¡¢Í¬Ò»Î¶ÈÏÂµÄÆ½ºâ״̬¡£ C¡¢ÔÚ±ê׼״̬Ï¿ÉÄܲúÉúµÄ×î´óÓÐÓù¦¡£ D¡¢Óû¿ØÖÆ´Ë·´Ó¦£¬Ê¹Óô߻¯¼ÁÎÞЧ¡£

18£® CaO(s) + H2O(l) = Ca(OH)2(s)ÔÚ250C¼°101KPaʱÊÇ×Ô·¢·´Ó¦£¬¸ßÎÂÊ±Äæ·´Ó¦Îª×Ô·¢£¬Õâ±íÃ÷·´Ó¦£º£¨ £©

A. ¦¤rHm<0 ¦¤rSm<0 B. ¦¤rHm>0 ¦¤rSm >0 C. ¦¤rHm<0 ¦¤rSm>0 D. ¦¤rHm>0 ¦¤rSm<0

19£® ±ê׼״̬Ï£¬ H2(g)ÓëO2(g)·´Ó¦Éú³É2.0mol H2O(l)ʱ·ÅÈÈQ KJ£¬ ÔòH2O(l)µÄ¦¤fH?mֵΪ£¨ £© A. Q B. Q/2 C. Q/18 D. Q/36

¦¨

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5

20£® ÒÑÖª·´Ó¦ (1) MnO(s) + 1/2O2(g) = MnO2(s) µÄ¦¤rH1m? (2) MnO2(s) + Mn(s) = 2 MnO(s) µÄ¦¤rH2m? Ôò ¦¤fH?m£¨ MnO2¡¢S£© = £¨ £©

A£®¦¤rH1m?£­¦¤rH2m? B. 2¦¤rH1m?+¦¤rH2m? C. 2¦¤rH1m?£­¦¤rH2m? D. ¦¤rH1m?+2¦¤rH2m?

21¡¢¸ù¾ÝÊý¾Ý¦¤fG?m(NO,g) = 86.5KJ.mol-1 , ¦¤fG?m(NO2,g) = 51.3KJ.mol-1£¬ ·´Ó¦ (1) N2(g) + O2(g) = 2NO(g) ; (2)

2NO(g) + O2(g) = 2NO2(g) £¬ ÔÚ±ê׼״̬ϽøÐеÄÇé¿ö˵Ã÷ÕýÈ·µÄÊÇ£¨ £© A.£¨1£©ÄÜ×Ô·¢£¨2£©²»ÄÜ B. (1)ºÍ(2)¶¼ÄÜ×Ô·¢ C. (2)ÄÜ×Ô·¢ (1)²»ÄÜ D. (1)ºÍ(2)¶¼²»ÄÜ×Ô·¢ 22¡¢Ö¸³ö?fHmµÈÓÚÁãµÄµ¥ÖÊ£¨ £© A¡¢C(½ð¸Õʯ) B¡¢Fe(s) C¡¢O3(g) D¡¢Br2(l) 23¡¢¸ù¾Ý¸Ç˹¶¨ÂÉÅжÏÏÂÁеÈʽÄÄÒ»ÏîÊÇÕýÈ·µÄ£¿

?A ¡÷H3 C

¡÷H1 ¡÷H5 ¡÷H4

B ¡÷H2 D A¡¢¡÷H1+ ¡÷H2+¡÷H3 =¡÷H4 B¡¢¡÷H1+ ¡÷H2 = ¡÷H3 +¡÷H4

C¡¢£¨¡÷H1+ ¡÷H2 £©£­£¨¡÷H3 +¡÷H4£©= ¡÷H5 D¡¢¡÷H1£«¡÷H2£«¡÷H3£«¡÷H4 =¡÷H5

24¡¢ÔÚ298K£¬101Kpaʱ£¬·´Ó¦

C(s) +

1?

O2(g) = CO(g) ¡÷H1

2O2(g) =2 CO(g) ¡÷H?2

6

2C(s) +

ÏÂÁÐÄÄÒ»¸öµÈʽÊÇÕýÈ·µÄ£¿

A¡¢¡÷H1= ¡÷H2 B¡¢¡÷H1= 2¡÷H2 C¡¢2¡÷H1= ¡÷H2 D¡¢¡÷H1Óë¡÷H2ÎÞ¹Ø

25¡¢ÒÑÖª·´Ó¦N2(g) + 3 H2(g) = 2NH3(g) µÄ±ê׼Ħ¶ûìʱäΪ£­92.22KJ¡¤mol1£¬ÏÂÁÐÄÄÒ»Êý¾ÝΪNH3(g)µÄ±ê׼Ħ¶û

£­

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A¡¢£­46.11 KJ¡¤mol

£­1

B¡¢£­92.22KJ¡¤mol£­1

C¡¢46.11 KJ¡¤mol£­

1 D¡¢92.22KJ¡¤mol£­

1 26¡¢ÏÂÁзûºÅÖÐÄÄЩ²»ÊôÓÚ״̬º¯Êý£¨ £©

(1) T (2) P (3) U (4)

?H (5) Q

A¡¢(1) (4) (5) B¡¢(1)(2) (4)(5) C¡¢(4)(5) D¡¢¶¼²»ÊôÓÚ

27¡¢²»¾­¹ý¼ÆËãÍÆÂÛÔÚÏàͬζÈÏ£¬ÏÂÁÐÄÄÒ»¸ö·´Ó¦µÄºãѹ·´Ó¦ÈÈÓëºãÈÝ·´Ó¦ÈȲîÖµ×î´ó£¿£¨ A¡¢C(s) + 1/2 O2(g) = CO(g) B¡¢C(s) + O2(g) = CO2(g) C¡¢2C(s) +3H2(g) =C2H6(g) D¡¢C(ʯī)=C(½ð¸Õʯ)

28¡¢ÏÂÁÐÄÄÒ»·´Ó¦£¨»ò¹ý³Ì£©µÄìØÖµÊǼõСµÄ£¨ £© A¡¢NaCl¾§Ìå´ÓÈÜÒºÖÐÎö³ö B¡¢·´Ó¦C(s) + 1/2 O2(g) = CO(g) C¡¢CuSO4¡¤5H2O¾§ÌåÈÜÓÚË® D¡¢¹Ì̬I2µÄÉý»ª 29¡¢ÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ£¨ £©

A. Òò¦¤H=QP£¬¹ÊQÊÇ״̬º¯Êý B. ÔÚµÈѹÌõ¼þÏ£¬¦¤H=QP

7

£© C. µÈѹ²¢ÇÒÖ»×öÌå»ýÅòÕ͹¦µÄ¹ý³Ì¦¤H=QP

D.

QP×ÜÊÇ´óÓÚQV

30¡¢ÔÚ298KºÍ100KpaÌõ¼þÏ£¬N2ºÍH2»¯ºÏÉú³É1g NH3ʱ·ÅÈÈ27KJ£¬ÄÇôNH3µÄ?fH?ÊÇ ( ) m(298.15K)A. ¨C 46KJ?mol-1 B. ¨C 46KJ C. + 46KJ?mol-1 D. ¨C 2.7KJ?g-1

31¡¢ÌìÈ»ÆøµÄÖ÷Òª³É·ÖÊÇCH4, ÒÑÖªCH4£¨g£©,CO2(g)¼°H2O(l)µÄ?fHm(kJÒÔ¼°¨C286£¬ÄÇô1m3(273K,101Kpa) CH4ÍêȫȼÉÕʱ£¬Ó¦·ÅÈÈ£º( ) A. 2.7¡Á104KJ B. 891KJ¡¤mol-1 C. 3.98¡Á104KJ D. ÎÞ·¨¼ÆËã 32¡¢ÒÑÖªN2(g)+3H2(g)=2NH3(g),

= ¨C92.2KJ¡¤mol-1£¬ÆäÖÐmol-1ÊÇÖ¸£¨ £© ?rH?m??mol?1)·Ö±ðΪ ¨C75£¬¨C394

A. ÿmol NH3 B. ÿmol H2 C. ÿmol H2 D. ÿmol ÉÏÊö·´Ó¦

33¡¢Ê¯Ä«ºÍ½ð¸ÕʯµÄȼÉÕÈÈ·Ö±ðÊÇ394ºÍ396KJ¡¤mol-1, ÄÇô½ð¸ÕʯµÄ±ê×¼Éú³ÉìÊΪ£¨ £© A. ¨C790 KJ¡¤mol-1 B. 2KJ¡¤mol-1 C. +790 KJ¡¤mol-1 D. ¨C2 KJ¡¤mol-1 34¡¢ÒÑÖªÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ

£¨1£©C(g) + O2(g) = CO2(g) £¨2£©H2 (g) + 1/2O2(g) = H2O(l)

= ¨C394KJ¡¤mol-1 ?rH?m= ¨C286KJ¡¤mol-1 ?rH?m= ¨C286KJ¡¤mol-1 ?rH?m£¨3£©C2H6(g) + 7/2O2(g) = 2CO2(g) +3H2O(l)

Óɴ˿ɵÃC2H6 (g)µÄ?fH?µÈÓÚ ( ) m(298.15K)A. ¨C1560KJ¡¤mol-1 B. ¨C86KJ¡¤mol-1 C. +86 KJ¡¤mol-1 D. ÎÞ·¨¼ÆËã 35¡¢Í¬ÎÂͬѹÌõ¼þÏ£¬°´ìØÖµµÝÔö´ÎÐòÅÅÁÐÕýÈ·µÄ£¨ £©

A. B.

H2O(l) H2O(g) H2O(s) Cl2(l) Br2 (l) I2(s)

8

C. D.

Na(s) NaCl(s) CaCl2(s) O3(g) O2(g) O(g)

36¡¢±½µÄÈÛµãΪ5.0oC, ÈÛ»¯ÈÈΪ10.7 KJ¡¤mol-1£¬ÄÇô±½µÄÈÛ»¯¹ý³Ì¦¤SµÈÓÚ£¨ £© A. 2.1 KJ¡¤mol-1¡¤K B. 10.7KJ¡¤mol-1

-1

C. 38.5 KJ¡¤mol-1¡¤K D. 38.5 J¡¤mol-1¡¤K

-1

-1

37¡¢ÒÑÖªB2H6(g)ºÍH2O(l)µÄ?fH?·Ö±ðΪ+31.4 KJ¡¤mol-1ºÍ¨C286 KJ¡¤mol-1,ÓÖÒÑÖªB2H6(g)µÄȼÉÕm(298.15K)ֵΪ¨C2153 KJ¡¤mol-1£¬Ôò¿ÉÇóµÃB2O3(g)µÄ?fH?Ϊ£¨ £© m(298.15K)A. -1836 KJ¡¤mol-1 B.-1264 KJ¡¤mol-1 C . +2153 KJ¡¤mol-1 D.+1264 KJ¡¤mol-1

Èý¡¢ Ìî¿ÕÌâ

1£® Ìåϵ¶Ô»·¾³×öÁË200JµÄ¹¦£¬ÌåϵÐë´Ó»·¾³____ ÈÈ______ J£¬²ÅÄÜʹÌåϵÈÈÁ¦Ñ§ÄÜÔö¼Ó50J¡£ 2£®ÒÑÖª·´Ó¦ 4NH3(g) + 5O2(g) = 4NO(g) + 6H2O(l)

¦¤rH?m = £­1170KJ.mol-1

4NH3(g) + 3O2(g) = 2N2(g) + 6H2O(l)

¦¤rH?m = £­1530KJ.mol-1

ÔòNO(g) µÄ±ê׼Ħ¶ûÉú³Éìʦ¤fH?mΪ_______

3£® ÔÚ373KºÍ101.325Kpaʱ£¬ÒºÌ¬H2O±ä³ÉË®ÕôÆûµÄ¹ý³ÌÖÐ

¦¤rG?m___________£»¦¤rH?m_________£»¦¤rS?m______(Ìî>0 =0 <0)

4£® ·´Ó¦2N2(g) + O2(g) = 2N2O(g)ÔÚ298KʱµÄ¦¤rH?m = 164.0KJ.mol-1,Ôò´Ë·´Ó¦µÄ¦¤rU?mΪ_________KJ.mol-1 5£®ÔÚ298KºÍ101.325Kpaʱ£¬ÒÑÖªÏÂÁз´Ó¦

C(s) + H2O(g) = CO(g) + H2(g)

¦¤fH?m/KJ.mol-1 £­241.8 £­110.5

?.-1 ¦¤fGm /KJmol

£­228.6 £­137.2

Ôò¦¤rS?mΪ__________J.mol-1.K-1

6. Èç¹ûÒ»¸ö·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬¶ø·´Ó¦µÄìØ±äСÓÚÁ㣬Ôò¸Ã·´Ó¦ÔÚ__________ÊÇ¿ÉÒÔ×Ô·¢µÄ£¬__________ϾͲ»

9

ÊÇ×Ô·¢µÄ¡£

7. ·´Ó¦N2(g) + 3H2(g) = 2NH3(g) µÄ¦¤rH?m,298 = £­92.2KJ.mol-1£¬ ÈôÉý¸ßζȣ¬Ôò¦¤rH?m,T_______________£»¦¤rS?m,T______________£»¦¤rG?m,T_________£¨ÒªÇó¶¨ÐԻشð£©

8. »¯Ñ§·´Ó¦A(g) + B(g) = 2C(g)£¬ A¡¢B¡¢C¾ùΪÀíÏëÆøÌ壬ÔÚ250C±ê׼״̬Ï£¬¸Ã¹ý³Ì·Ö±ðÒÀÁ½¸ö²»Í¬Í¾¾¶Íê³É£º£¨1£©²»×ö¹¦£¬·ÅÈÈ40KJ£»£¨2£©×ö×î´ó¹¦£¬·ÅÈÈ2KJ¡£ÔòÔÚ£¨1£©¡¢£¨2£©Á½Çé¿öÏ£¬¦¤H?·Ö±ðΪ__________£¬__________£»¦¤G?·Ö±ðΪ__________£¬__________£» ¦¤S?·Ö±ðΪ__________£¬__________¡£ ËÄ¡¢ ¼ÆËãÌâ

1¡¢ÀûÓÃÏÂÁз´Ó¦µÄ¦¤rG?m£¬¼ÆËãFe3O4(s)ÔÚ298KʱµÄ±ê׼Ħ¶ûÉú³É¼ª²¼Ë¹×ÔÓÉÄܦ¤fG?m.

(1) 2Fe(s) + 3/2O2(g) = Fe2O3(s) ¦¤rG?m = £­742KJ.mol-1 (2) 4 Fe2O3(s) + Fe(s) = 3 Fe3O4(s) ¦¤rG?m = £­78 KJ.mol-1

2¡¢ÉèÏÂÁз´Ó¦

(1) A + B = C + D ¦¤rH?m = £­40 KJ.mol-1 (2) C +D = E ¦¤rH?m = 60 KJ.mol-1

ÊÔÎÊÏÂÁз´Ó¦µÄ¦¤rH?m¸÷Ϊ¶àÉÙ£¿

A. B. C.

C + D = A + B 2C +2D = 2A + 2B A + B = E

10

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S(s) + O2(g) = SO2(g) K2?

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A. K1?/ K2? B. K2?/ K1? C. K1?¡¤ K2? D. K1?£­ K2?

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17¡¢ÆøÌå·´Ó¦ A(g) + B(g) = C(g)£¬ ÔÚ·â±ÕÈÝÆ÷Öн¨Á¢ÁË»¯Ñ§Æ½ºâ£¬Èç¹ûζȲ»±ä£¬µ«Ìå»ýËõСÁË2/3£¬Ôòƽºâ

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A. K?+? B. K?-? aKw wKa C. K?/ K? D. K?¡¤K? aaww25¡¢ÒÑÖª: (1) CaC2O4= Ca2+ + C2O42- K0=2.3¡Á10-9

(2) Hac = H+ + Ac- K0=1.8¡Á10-5 (3) HC2O4-= H+ + C2O42- K0=6.4¡Á10-5

Ôò¿É¼ÆËã·´Ó¦CaC2O4 + Hac = Ca2+ + HC2O4- + Ac-µÄK0,È»ºó¿ÉÅжϵ¨½áʯ³É·ÖÖ®Ò»µÄ²ÝËá¸ÆÔÚ´×ËáÖУ¨ £©

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2¡¢·´Ó¦Fe(s) + 2H+(aq) = Fe2+(aq) + H2(g)µÄ±ê׼ƽºâ³£ÊýµÄ±í´ïʽΪK? = ____________________¡£ 3¡¢ÒÑÖªÏÂÁз´Ó¦ÔÚÖ¸¶¨Î¶ȵĦ¤rG?mºÍK?£¬

(1) N2(g) + 1/2O2(g) = N2O(g) ¦¤rG?m1, K?1 (2) N2O4(g) = 2NO2(g) ¦¤rG?m2, K?2

(3) 1/2N2(g) + O2(g) = NO2(g) ¦¤rG?m3, K?3

Ôò·´Ó¦ 2 N2O(g) + 3 O2(g) = 2N2O4(g)µÄ¦¤rG?m = ______£¬K? =____________

4¡¢ÒÑÖª¦¤fH?m(NO,g) = 90.25 KJ.mol-1£¬ ÔÚ2273Kʱ, ·´Ó¦N2(g) + O2(g) = 2NO(g) µÄK? = 0.100,ÔÚ2273Kʱ,ÈôP(N2) = P(O2) = 10Kpa£¬ P(NO)=20Kpa£¬ ·´Ó¦ÉÌQ = _______£¬ ·´Ó¦Ïò______·½Ïò½øÐÐ; ÔÚ2000Kʱ, ÈôP(NO) = P(N2) =10 Kpa , P(O2) = 100Kpa, ·´Ó¦ÉÌQ = ______, ·´Ó¦Ïò__________·½Ïò½øÐÐ.

5¡¢PCl5(g) = PCl3(g) + Cl2(g)£¬ÔÚÒ»¶¨TºÍPÏ£¬ÈôÒ»¶¨Á¿µÄPCl5ÆøÌåµÄÌå»ýΪ1Éý£¬ ´ËʱPCl5ÆøÌåÒÑÓÐ50%

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6¡¢¿ÉÄæ·´Ó¦. 2Cl2 (g) + 2H2O(g) = 4HCl(g) + O2(g) ¦¤rH?m > 0 ,·´Ó¦´ïµ½Æ½ºâºó,½øÐÐÒÔϲÙ×÷,ÊÔÌÖÂÛÆäÓ°Ïì:

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9¡¢Ìá¸ßζȣ¬¶Ô»î»¯ÄܽϴóµÄ·´Ó¦£¬·´Ó¦ËÙÂʵÄÔö¼Ó±È»î»¯ÄÜСµÄÒª´ó¡££¨ £©

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10¡¢Óз´Ó¦¢ñ¡¢¢ò,298Kʱ·´Ó¦ËÙÂʦÍI > ¦ÍII£¬ ¶ø318Kʱ

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1¡¢Ä³·Ö½â·´Ó¦£¬µ±·´Ó¦ÎïŨ¶ÈΪ0.2mol.l-1ʱ£¬·´Ó¦ËÙ¶ÈΪ0.3 mol.l-1.S-1,Èç¹ûÕâ¸ö·´Ó¦Îª¶þ¼¶·´Ó¦£¬µ±·´Ó¦ÎïŨ¶ÈΪ0.6 mol.l-1ʱ£¬Õâ¸ö·´Ó¦µÄ·´Ó¦ËÙ¶È£¨mol.l-1.S-1£©½«ÊÇ£¨ £©

A£®0.30 B. 0.60 C. 0.90 D. 2.70

2¡¢·´Ó¦ËÙ¶ÈËæ×ÅζÈÉý¸ß¶ø¼Ó¿ìµÄÖ÷ÒªÀíÓÉÊÇ£º£¨ £©

A¡¢¸ßÎÂÏ·Ö×ÓÅöײ´ÎÊýÔö¶à.

B¡¢¸ßÎÂÏ·Ö×ÓµÄÄÜÁ¿Ôö¼Ó,ʹÿ´ÎÅöײÄÜÁ¿Ôö´ó. C¡¢»î»¯·Ö×ÓËæÎ¶ÈÉý¸ß¶ø¼õÉÙ. D¡¢»î»¯·Ö×Ó°Ù·ÖÊýËæÎ¶ÈÉý¸ß¶øÔö¼Ó.

3¡¢·´Ó¦A + B ¡ú C Ϊһ»ùÔª·´Ó¦£¬¸Ã·´Ó¦µÄËٶȳ£ÊýµÄµ¥Î»Ó¦µ±ÊÇ£¨ £©

A. mol.l-1.S-1 B. S-1 C. L.S-1 D. mol-1.L.S-1

4¡¢ÒÑÖªÏÂÁз´Ó¦ 2A + B ¡ú C ÊÇ»ùÔª·´Ó¦£¬Ôò¦ÍA ºÍ¦ÍBµÄ¹ØÏµÊÇ£¨ £©

A. ¦ÍA =¦ÍB B. 1/2¦ÍA=¦ÍB C. 2¦ÍA=¦ÍB D. ¦ÍA =¦ÍB

5¡¢¸ø¶¨Ìõ¼þÏÂ,·´Ó¦2NO + 2H2 = N2 + 2H2O ·ÖÁ½²½½øÐÐ,

I. 2NO + H2 = N2 + H2O2 (Âý) II. H2O2 + H2 = 2H2O (¿ì)

ÈôÈÝÆ÷Ìå»ý¼õÖÁÔ­À´µÄÒ»°ë,Ôò·´Ó¦ËÙÂʱäΪԭÀ´µÄ( )±¶? A. 2 B. 4 C. 8 D. 16 6¡¢¶ÔÓÚ·´Ó¦ aA + Bb = ²úÎÈô±£³ÖC£¨A£©²»±ä£¬Ê¹C£¨B£©Ôö´ó1±¶£¬·´Ó¦ËÙÂÊÔöÖÁÔ­À´µÄ4±¶¡£Èô±£³ÖC

£¨B£©Ò»¶¨£¬Ê¹C£¨A£©Ôö´ó1±¶£¬·´Ó¦ËÙÂÊÔö¼Ó1±¶£¬Ôò¸Ã·´Ó¦¼¶Êý£¨ £© A£®3 B. 2 C. 4 D. 1 7¡¢¶ÔÓÚÁã¼¶·´Ó¦£¬ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ£¨ £©

2

20

A£®»î»¯ÄÜºÜµÍ B. ·´Ó¦ËÙÂÊÓë·´Ó¦ÎïŨ¶ÈÎÞ¹Ø

C£®·´Ó¦ÎïµÄŨ¶ÈÓëʱ¼äÎÞ¹Ø D£® ·´Ó¦ËÙÂʳ£ÊýΪ0

8¡¢ÏÂÁйØÓÚ´ß»¯¼ÁÐðÊö´íÎóµÄÊÇ£¨ £©

A¡¢ÔÚ¼¸¸ö·´Ó¦ÖÐ,¿ÉÑ¡ÔñµØ¼Ó¿ìÆäÖÐÒ»¸ö·´Ó¦µÄ·´Ó¦ËÙÂÊ. B¡¢¿ÉÒÖÖÆÄ³Ð©·´Ó¦µÄ½øÐÐ.

C¡¢¿ÉÒԸı仯ѧ·´Ó¦µÄƽºâ³£Êý,µ«²»Ó°ÏìÈÈЧӦ. D¡¢¿ÉÒԸıäijһ·´Ó¦µÄÕý¡¢Äæ·´Ó¦ËÙÂÊÖ®±È.

9¡¢·´Ó¦2SO2(g) + O2(g) ¡ú 2SO3(g)µÄ·´Ó¦ËÙÂÊ¿ÉÒÔ±íʾΪ¦Í= £­

dc(O2)£¬Ò²¿ÉÒÔ±íʾΪ£¨ £©

dt2dc(SO3)1dc(SO2)A. B. £­

dt2dtdc(SO2)dc(SO2)C. £­2 D. £­

dtdt10¡¢ÏÂÁÐÐðÊöÖÐÕýÈ·µÄÊÇ£¨ £©

A¡¢·Ç»ùÔª·´Ó¦ÊÇÓÉÈô¸É¸ö»ùÔª·´Ó¦×é³ÉµÄ.

B¡¢·²ËÙÂÊ·½³ÌʽÖи÷ÎïÖÊŨ¶ÈµÄÖ¸ÊýµÈÓÚ·´Ó¦·½³ÌʽÖи÷·´Ó¦ÎïµÄ¼ÆÁ¿ÏµÊý,´Ë·´Ó¦Îª»ùÔª·´Ó¦.

C¡¢ ·´Ó¦¼¶ÊýµÈÓÚ»¯Ñ§·´Ó¦Ê½Öи÷·´Ó¦Îï¼ÆÁ¿ÏµÊýºÍ. D¡¢ ·´Ó¦ËÙÂÊÓë·´Ó¦ÎïŨ¶ÈµÄ³Ë»ý³ÉÕý±È

11¡¢ÓÐÒ»»¯Ñ§·´Ó¦ A + B ¡ú D , Èý´ÎʵÑéÊý¾ÝÈçÏÂ:

³õʼ(A)¨Mmol.l ³õʼ(B)¨Mmol.l

-1

-1

Éú³ÉDµÄ³õʼËÙÂÊ(mol.l.S)

-4

-1_1

0.03 0.03 0.3 ¡Á 10

0.06 0.06 1.2 ¡Á 10-4 0.06 0.09 2.7 ¡Á 10-4

¸Ã·´Ó¦µÄËÙÂÊ·½³ÌʽΪ( )

A. ¦Í = kc(A)c(B) B. ¦Í= kc2(B)

21

C. ¦Í = kc(A)c(B) D. ¦Í = kc(A)

12¡¢Ä³»¯Ñ§·´Ó¦ËÙÂʳ£ÊýµÄµ¥Î»ÊÇmol.l.S,¸Ã»¯Ñ§·´Ó¦µÄ¼¶ÊýÊÇ( )

A. 2 B. 1 C. 0 D. 3

13¡¢·´Ó¦ A(g) + B(g) ¡ú C(g) µÄËÙÂÊ·½³ÌʽΪ¦Í = kc(A) c(B),ÈôʹÃܱյķ´Ó¦ÈÝ»ýÔö´ó1±¶,ÔòÆä·´Ó¦

ËÙÂÊΪԭÀ´µÄ( )±¶

A. 1/6±¶ B. 1/8±¶ C. 8±¶ D. 1/4±¶ 14¡¢ÒÑÖª·´Ó¦2NO(g) + 2H2(g) = N2(g) + 2H2O(g)µÄ·´Ó¦»úÀíΪ:

£¨1£© NO + NO == N2O2 (¿ì)

£¨2£©N2O2 + H2 == N2O + H2O (Âý) £¨3£©N2O + H2 == N2 + H2O (¿ì)

Ôò×Ü·´Ó¦ËÙÂÊ·½³ÌʽΪ:

A. ¦Í = kc(NO)c(H2) B. ¦Í = kc(NO)c(H2) C. ¦Í = kc(NO)c(H2) D. ¦Í = kc(NO) 15¡¢Ä³Ò»·´Ó¦µÄ»î»¯ÄÜÊÇ26KJ mol-1 ,ÆäÄæ·´Ó¦µÄ»î»¯ÄÜÊÇ( )

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2

2

2

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22

A. £­26KJ mol-1 B. >26KJ mol-1

.

.

C. <26KJ mol-1 D. ÎÞ·¨È·¶¨

.

16¡¢250Cʱ,·´Ó¦ N2(g) + 3 H2(g) = 2NH3(g) ¦¤rH?m = -922 KJ mol-1£¬ÈôÉý¸ßζÈ,Ôò( )

.

A¡¢ ·´Ó¦ËÙÂʼõÉÙ£¬Äæ·´Ó¦ËÙÂÊÔö´ó. B¡¢ ·´Ó¦ËÙÂʼõÉÙ, Äæ·´Ó¦ËÙÂÊÒ²¼õÉÙ. C¡¢Õý·´Ó¦ËÙÂÊÔö´ó, Äæ·´Ó¦ËÙÂʼõÉÙ. D¡¢Õý·´Ó¦ËÙÂÊÔö´ó, Äæ·´Ó¦ËÙÂÊÒ²Ôö´ó.

17¡¢¶ÔÓÚÒ»¸ö»¯Ñ§·´Ó¦,ÏÂÁÐÄÄÖÖÇé¿öÏÂËÙÂÊÔ½´ó?( )

A. »î»¯ÄÜÔ½´ó. B. ¦¤rH?m Ô½¸º C. »î»¯ÄÜԽС. D. ¦¤rG?m Ô½¸º

18¡¢Õý·´Ó¦µÄ»î»¯ÄÜ(EaÕý)´óÓÚÄæ·´Ó¦µÄ»î»¯ÄÜ(EaÄæ),ÔòÕý·´Ó¦µÄ±ê×¼ Ħ¶ûìʱä( )

22

A. ¦¤rH?m > 0 B. ¦¤rH?m = (EaÕý- EaÄæ)/2 C. ¦¤rH?m < 0 D. ÎÞ·¨È·¶¨

19¡¢²»»áÓ°Ïì·´Ó¦ËÙÂʳ£ÊýkµÄÒòËØ( )

A. ·´Ó¦ÎÂ¶È B. ¸Ä±ä·´Ó¦ÎïŨ¶È C. ·´Ó¦»î»¯ÄÜ D. ´ß»¯¼Á

20¡¢ÈçͼËùʾ,·´Ó¦A + B ¡ú C + D ËùÉæ¼°µÄìÊÏà¶Ô´óСΪ: »î»¯ÅäºÏÎï > A + B > C + D ,Òò´Ë:( )

A. ¸Ã·´Ó¦ÊDz»¿ÉÄæµÄ. B. ¸Ã·´Ó¦²»¿ÉÄÜÓд߻¯¼Á. C. ¸Ã·´Ó¦ÊÇ·ÅÈȵÄ.

D. Äæ·´Ó¦µÄ»î»¯ÄܵÍÓÚÕý·´Ó¦»î»¯ÄÜ.

21¡¢ÒÑ֪ij·´Ó¦A + B

?C + DµÄ?ÕýΪ+5.0L¡¤mol

£­

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22¡¢ÒÑÖª·´Ó¦2 A(g) + B(g)? 2 C(g) µÄ¦¤rH?m£¼0¡£ÏÂÁÐÄÄÒ»ÏîÐðÊöÊÇÕýÈ·µÄ( )

A¡¢ÓÉÓÚK

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B¡¢Éý¸ßζȣ¬?ÄæÔö´ó£¬?Õý¼õС£¬½«µ¼ÖÂÆ½ºâÏò×óÒÆ¶¯¡£ C¡¢¼ÓÈë´ß»¯¼Á£¬Í¬µÈ³Ì¶ÈµÄ¼Ó¿ìÕý¡¢Äæ·´Ó¦µÄËÙÂÊ£¬¼ÓËٴﵽƽºâ¡£ D¡¢Ôö¼ÓѹÁ¦£¬Ê¹p(A)¡¢p(B)Ôö´ó£¬?ÕýÔö´ó£¬Æ½ºâÏò×óÒÆ¶¯¡£ 23¡¢¶Ôijһ»¯Ñ§·´Ó¦£¬Ëæ×Å·´Ó¦µÄ½øÐн«·¢ÉúÏÂÁÐÄÄÏî±ä»¯£¨ £© A¡¢·´Ó¦ËÙÂʽµµÍ B¡¢ËÙÂʳ£Êý±äС C¡¢Æ½ºâ³£Êý±äС D¡¢»î»¯ÄܼõС

24¡¢ÊµÑé·¢ÏÖ·´Ó¦£º 2NO(g) + Cl2= 2NOCl ÊÇNOµÄ¶þ¼¶·´Ó¦ºÍCl2µÄÒ»¼¶·´Ó¦£¬ÏÂÁÐÄÄÖÖ·´Ó¦»úÀíÓпÉÄÜ£¨ £©

23

A¡¢ NO + NO + Cl2 =2 NOCl B¡¢ Cl2 = 2 Cl (Âý)

NO + Cl = NOCl (¿ì)

C¡¢ Cl2 = 2 Cl (¿ì)

NO + Cl = NOCl (Âý)

D¡¢2 NO= N2O2 (¿ì)

Cl2 + N2O2 = 2NOCl (Âý)

25¡¢Ã¸´ß»¯·´Ó¦£¬´ó¶¼ÊÇ0¼¶·´Ó¦£¬¹ØÓÚ0¼¶·´Ó¦£¬ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ£¨ £©

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B¡¢ ·´Ó¦ÎïŨ¶ÈÓ뷴Ӧʱ¼ä³ÉÏßÐÔ¹ØÏµ C¡¢ ·´Ó¦ÎïŨ¶ÈÓ뷴Ӧʱ¼ä³É·´±È D¡¢ ·´Ó¦ËÙÂÊÓ뷴Ӧʱ¼ä³É·´±È

26¡¢·´Ó¦A + B 3D£¬ÕýÄæ·´Ó¦»î»¯ÄÜ·Ö±ðΪm KJ¡¤mol-1ºÍn KJ¡¤mol-1 £¬Ôò·´Ó¦µÄ?rH?Ϊm(298.15K)( )

A. m-n B. n-m C.m-3n D. 3n-m

27¡¢300KʱÏÊÅ£ÄÌ4Сʱ±äÖÊ£¬µ«ÔÚ277K ʱ±£´æ48Сʱ£¬ÔòÅ£Ä̵ĻÄÜΪ£¨ £©

A.ÎÞ·¨¼ÆËã B. +5.75 KJ¡¤mol-1

C.-74.5 KJ¡¤mol-1 D. +74.5 KJ¡¤mol-1

28¡¢503KʱµÄ·´Ó¦µÄ»î»¯ÄÜΪ184.1 KJ¡¤mol-1£¬Èô¼ÓÈë´ß»¯¼Áºó±äΪ10416 KJ¡¤mol-1£¬´ËʱÕý·´Ó¦ËÙÂÊÔö¼ÓµÄ

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A. 1¡Á104 B.1¡Á106

C.1¡Á108 D. 1¡Á102

29 ÒÑÖªÒ»¼¶·´Ó¦2N2O5 4NO2(g) + O2(g) µÄk=0.35 min-1(304K)£¬ÔÚ¸ÃζÈÏÂN2O5µÄÆðʼŨ¶È´Ó0.16

mol¡¤L-1±äΪ0.02 mol¡¤L-1ʱÐ裨 £©

A.150s B. 356s

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C.594s D. 2.5s

30 »¯Ñ§·´Ó¦ËÙÂÊÓ¦±íÊöΪ£¨ £© A. µ¥Î»Ê±¼äÄÚ·´Ó¦ÎïŨ¶ÈµÄ¸Ä±äÁ¿

B. µ¥Î»Ê±¼äÄÚÉú³ÉÎïŨ¶ÈµÄ¸Ä±äÁ¿ C. ·´Ó¦ÎïŨ¶È¸Ä±äÁ¿µÄÕýÖµ D.ÎïŨ¶È¸Ä±äÁ¿µÄÕýÖµ

31. ·´Ó¦2NO + O2 = 2NO2µÄËÙÂʱíʾ£¨ £©

A. +dC(NO2) /dt B. -dC(NO2) /dt C. -2dC(NO2) /dt D. ¶¼²»¶Ô 32 ÏÂÁбíÊöÖÐÕýÈ·µÄÊÇ£¨ £©

A. Ea½Ï´óµÄ·´Ó¦£¬k±Ø¶¨´ó B. Ò»¶¨Î¶ÈÏ£¬k²»ËæÎ¶ȱ仯 C. k²»ËæÎ¶ȱ仯 D.

kÖµÓë´ß»¯¼ÁµÄ¼ÓÈëÎÞ¹Ø

33¡¢ÏÂÁбí´ï²»ÕýÈ·µÄÊÇ£¨ £©

A. VÕýͨ³£ËæÊ±¼ä¶ø¼õС

B. KÊÇij¸ö»¯Ñ§·´Ó¦ÔÚÒ»¶¨Î¶ÈϵÄÌØÕ÷³£Êý C. ζȲ»±ä£¬Å¨¶ÈÔ½´ó£¬vÔ½´ó

D¡¢ÆðʼŨ¶È²»Í¬£¬v²»Í¬£¬Æ½ºâŨ¶ÈÈ´Ïàͬ

34¡¢ CO + NO CO2 + 1/2 N2·ÅÈÈ·´Ó¦£¬ÈôζÈÉý¸ß10oC, Ôò»á£¨A. ʹËÙÂʳ£ÊýÔö¼Ó10±¶ B. ʹƽºâ³£ÊýÔö¼Ó1±¶ C. ʹƽºâ³£Êý¼õÉÙ D. ʹ·´Ó¦ËÙÂʼõÉÙ

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25

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A. ¸ù¾Ý»¯Ñ§·´Ó¦·½³Ìʽȷ¶¨ B. ͨ¹ýʵÑé²â¶¨ C. Óë·´Ó¦·Ö×ÓÊýÏàͬ D. ¸ù¾Ý·´Ó¦»úÀí²â¶¨µÄ

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A. B. C. D.

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A. Ôö´ó·´Ó¦ËÙÂÊ B. ¼õÉÙ·´Ó¦ËÙÂÊ C. Ôö´óת»¯ÂÊ D. ¶Ôת»¯ÂÊÎÞÓ°Ïì

38¡¢ÆøÌåÔÚ¹ÌÌå±íÃæ·¢ÉúµÄ·´Ó¦Ò»°ãÊÇ£¨ £©

A. Áã¼¶ B¡¢Ò»¼¶ C¡¢¶þ¼¶ D¡¢Èý¼¶

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3¡¢ ¸´ÔÓ·´Ó¦ 3ClO- == ClO3- + 2Cl- µÄ·Ö²½·´Ó¦ÈçÏÂ:

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26

4¡¢ ijһ·´Ó¦µÄËٶȾö¶¨²½Öè 2A(g) + B(g) == 3C(g), ½«1mol A(g)ºÍ2 mol B(g)»ìºÏ£¬ ·´Ó¦Á¢¼´·¢Éú£¬µ±A.B

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8¡¢·´Ó¦ 2AB(g) = A2(g) + B2(g), Õý·´Ó¦µÄ»î»¯ÄÜEa(+) = 44.3 KJ¡¤ mol-1, ABµÄ¦¤fH?m = 1.35 KJ¡¤ mol-1, Äæ·´Ó¦µÄ»î»¯ÄÜӦΪ£º_______________.

9¡¢·´Ó¦Aa + Bb ¡ú dD µÄ·´Ó¦ËÙÂÊ·½³Ìʽ¦Í = kcx(A)c(B)ÈôkµÄµ¥Î»ÎªL2. mol-2.S-1 £¬Ôòx+y=_________.

y

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A. C(H+)=C(AC-) B. C(H+)>C(AC-) D. ÒÔÉϴ𰸶¼²»ÕýÈ·

14. 0.10mol.l-1 ij¶þÔªÈõËáH2AµÄKa1Ϊ4.0 x 10-7 , Ka2 Ϊ8.0¡Á

10-10£¬Ôò¸ÃÈÜÒºµÄA-Àë×ÓŨ¶ÈԼΪ________ (mol.l-1) A. 1.0 x 10-4 B 2.0 x 10-4 C. 8.0 x 10-10 D. 4.0 x 10-10 15. ½«1Éý4 mol.l-1°±Ë®Óë1Éý2 mol.l-1ÑÎËáÈÜÒº»ìºÏ£¬»ìºÏºóOH-

Àë×ÓŨ¶ÈΪ¡ª¡ª¡ª¡ª¡ª¡ª£¨mol.l-1£©

A. 1 B. 2 C. 8.0 x 10-4 D. 1.79 x 10-5

16. ÈõËáµÄÇ¿¶ÈÖ÷ÒªÓëËüÔÚË®ÈÜÒºÖеÄÄÄÒ»ÖÖÊý¾ÝÓйØ________

A. Ũ¶È B. Àë½â¶È C. Àë½â³£Êý D. Èܽâ¶È

17. ¸ù¾ÝƽºâÒÆ¶¯Ô­Àí,ÔÚ0.10mol.l-1HACÈÜÒºÖÖ,ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ

A¡¢¼ÓÈëŨHAC,ÓÉÓÚÔö¼Ó·´Ó¦ÎïŨ¶È,ƽºâÏòÓÒÒÆ¶¯£¬

½á¹ûHACÀë½â¶ÈÔö´ó.

B¡¢¼ÓÈëÉÙNaOHÈÜÒº,ƽºâÏòÓÒÒÆ¶¯. C¡¢ÓÃˮϡÊÍ,Àë½â¶ÈÔö´ó.

36

D¡¢¼ÓÈëÉÙÁ¿HClÈÜÒº,HACµÄÀë½â¶È¼õÉÙ.

18. ÏÂÁÐÐðÊöÖÐÕýÈ·µÄÊÇ______

A¡¢Ç¿µç½âÖʵÄÀë½â¶È´óС±íʾÁ˸õç½âÖÊÔÚÈÜÒºÖÐÀë½â

¶È³Ì¶ÈµÄ´óС.

B¡¢µç½âÖÊÔÚÈÜÒºÖж¼ÊÇÈ«²¿Àë½âµÄ,¹ÊÀë½â¶ÈΪ100% C¡¢Å¨¶ÈΪ1 x 10-9 mol.l-1 µÄÑÎËáÈÜÒºÖÐ,PHΪ7 D¡¢Öк͵ÈÌå»ýPHÏàͬµÄHCl¼°HACÈÜÒº,ËùÐèµÄ

NaOHµÄÁ¿Ïàͬ.

19. Íù1Éý0.10mol.l-1µÄNH3Ë®ÈÜÒºÖмÓÈëһЩNH4Cl¾§Ì壬»áʹ___

A¡¢NH3Ë®µÄÀë½â³£ÊýKbÔö´ó. B¡¢NH3Ë®µÄÀë½â³£ÊýKb¼õС C¡¢ÈÜÒºµÄPHÔö´ó. D¡¢ÈÜÒºµÄPH ¼õС.

20. Íù1Éý0.10mol.l-1µÄHAcË®ÈÜÒºÖмÓÈëһЩˮ£¬´Ëʱ

A. HAcµÄÀë½â¶È¼õС B. HAcµÄÀë½â¶ÈÔö´ó. C. ÈÜÒºµÄPH¼õС D. ÈÜÒºµÄH+Àë×ÓŨ¶È²»±ä. 21. Ò»°ã×÷Ϊ»º³åÈÜÒºµÄÊÇ_________

A. ÈõËáÈõ¼îÑεÄÈÜÒº B. ÈõËá(»òÈõ¼î)¼°ÆäÑεĻìºÏÈÜÒº C. PH×ܲ»»á¸Ä±äµÄÈÜÒº D. Ç¿Ëá(»òÇ¿¼î)¼°ÆäÑÎ×é³ÉµÄÈÜÒº.

22. »º³åÈÜÒºµÄPHÖµ×îÖ÷ÒªÊÇÓÉÏÂÁÐÄÄÒ»¸öÒòËØ¾ö¶¨µÄ¡ª¡ª¡ª¡ª¡ª

A. ¹²éî¶ÔµÄƽºâ³£Êý B. ¹²éî¶ÔË«·½µÄŨ¶È±È C. ÈÜÒºµÄÎÂ¶È D. ¹²éî¶ÔË«·½µÄ×ÜŨ¶È

23. ÏÂÁÐÈÜÒºÖлº³åÄÜÁ¦×î´óµÄÊÇ_______

37

A¡¢0.10mol.l-1 NH3Ë®0.1Éý B¡¢0.10mol.l-1 NH4ClË®0.1Éý

C¡¢0.10mol.l-1 NH3Ë®0.5ÉýÓë0.10mol.l-1 NH4ClË®0.05Éý

µÄ»ìºÏÒº

D¡¢0.20mol.l-1 NH3Ë®0.5ÉýÓë0.20mol.l-1 NH4ClË®0.05Éý

µÄ»ìºÏÒº

24. 0.025mol.l-1 HACÈÜÒºÓëµÈÌå»ýNaACÈÜÒºÏà»ì£¬ÒªÊ¹PHά³Ö

4.05£¬»ìºÏºóËáºÍÑεÄŨ¶È±ÈӦΪ¡ª¡ª¡ª¡ª¡ª¡ª

A. 6 : 1 B. 50 : 1 C. 30 : 1 D. 5 : 1

25. ÓÃHSO3-[K(HSO3-) = 3 .0 x 10-8]ºÍSO32-ÅäÖÆµÄ»º³åÈÜÒºµÄPH·¶Î§__

A. 10~12 B. 6.5~8.5 C. 2.4~4.0 D. 2~4

26. ÏàͬŨ¶ÈµÄÏÂÁÐÑÎÈÜÒºµÄPHÖµ£¬ÓÉСµ½´óµÄ˳ÐòÊÇ£º:

NaA¡¢ NaB¡¢ NaC¡¢ NaD (A. B. C. D¶¼ÎªÈõËá¸ù),Ôò¸÷¶ÔÓ¦ËáÔÚͬŨ¶È, ͬζÈÏÂ, Àë½â¶È×î´óµÄËáÊÇ_______

A. HA B. HB C. HC D. HD

27. ÏòNa2CO3ÈÜÒºÖеÎÈëÁ½µÎ·Ó̪ÈÜÒº,ÈÜÒº³Ê·ÛºìÉ«,΢ÈȺó£¬ÈÜÒºµÄÑÕÉ«____

A. ¼ÓÉî B. ²»±ä C. ±ädz D. Ïûʧ

28. ʵÑéÊÒÅäÖÆSnCl2ÈÜҺʱ,±ØÐëÔÚÉÙÁ¿ÑÎËáÖÐÅäÖÆ,¶øºóÏ¡ÊÍÖÁËùÐè

Ũ¶È£¬²ÅÄܵõ½³ÎÇåÈÜÒº£¬ÕâÊÇÓÉÓÚ_______

A. Ðγɻº³åÈÜÒº B. ͬÀë×ÓЧӦ C. ÑÎЧӦ´ÙʹSnCl2Èܽâ D. ÒÖÖÆ SnCl2Ë®½â

29. ¸ù¾ÝËá¼îÖÊ×ÓÀíÂÛ,ÏÂÁÐÐðÊöÖв»ÕýÈ·µÄÊÇ________

A¡¢Ëá¼î·´Ó¦µÄ·½ÏòÊÇÇ¿ËáÓëÇ¿¼î·´Ó¦Éú³ÉÈõËáºÍÈõ¼î. B¡¢»¯ºÏÎïÖÐûÓÐÑεĸÅÄî. C¡¢ËáÓúÇ¿,Æä¹²éî¼îÒ²ÓúÇ¿.

38

D¡¢Ë®ÈÜÒºÖÐÀë½â·´Ó¦,Ë®½â·´Ó¦¼°Öкͷ´Ó¦ÈýÕß¶¼ÊÇÖÊ×Ó

×ªÒÆ·´Ó¦.

30. ÏÂÁÐÎïÖÊÖÐ,¼È¿ÉÒÔ×÷ΪËáÓÖ¿ÉÒÔ×÷Ϊ¼îµÄÊÇ________

A. PO43- B. NH4+ C. H3O+ D. HCO3-

31¡¢ÏÂÁÐÄÄÒ»Ïî²»Êǹ²éîËá¼î¶Ô£¨ £©

A¡¢NH4+, NH3 B¡¢HF, H2F+ C¡¢NH3£¬NH2 D¡¢H+3O,OH

£­

£­

32¡¢ ¶ÔÓÚÏÂÁз´Ó¦À´Ëµ,ÕýÈ·µÄÐðÊöÊÇ______

[Al(H2O)6]3+ + H2O ¡ú [Al(H2O)5(OH)]2+ + H3O+

A¡¢[Al(H2O)6]3+ ÊǼ¶øH2OÊÇËüµÄ¹²éîËá.

B¡¢[Al(H2O)6]3+ ÊǼ¶ø[Al(H2O)5(OH)]2+ÊÇËüµÄ¹²éîËá. C¡¢[Al(H2O)6]3+ ÊÇËᣬ¶øH2OÊÇËüµÄ¹²éî¼î

D¡¢ [Al(H2O)6]3+ ÊÇËᣬ¶ø[Al(H2O)5(OH)]2+ÊÇËüµÄ¹²éî¼î.

33¡¢H2O ¡¢H2AC+¡¢NH4+µÄ¹²éî¼îÐÔÇ¿Èõ˳ÐòÊÇ________

A. OH- > NH2- >AC- B. NH2- > OH- > AC- C. OH- > NH3 >HAC D. HAC>NH3 >OH-

34¡¢ ·´Ó¦Zn2+ + H2O = ZnOH+ + H+ µÄKֵΪ2.5 x 10-10,Ôò0.10mol.l-1

µÄ¸ÃÈÜÒºµÄPHÖµÊÇ______

A. 3.25 B. 5.30 C. 4.34 D. 6.78

35¡¢ÈôËá¼î·´Ó¦HA + B- = HB +A- µÄK =10-4,ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ_______

A. HBÊDZÈHAÇ¿µÄËá B. HAÊDZÈHBÇ¿µÄËá C. HAºÍHBËáÐÔÏàͬ D. ËáµÄÇ¿ÈõÎÞ·¨±È½Ï

36. ¾ùΪ0.10mol.l-1µÄÈýÖÖÑÎÈÜÒº:(1)NH4Cl. (2)NaCN (3)NH4CN ÕâÈý

ÖÖÑÎÈÜÒºPH´Ó´óµ½Ð¡µÄ˳ÐòÊÇ¡ª¡ª¡ª¡ª¡ª

A. (1) > (2) > (3) B. (2) > (1) > (3)

39

C. (2) > (3) > (1) D.(1) > (3) > (2)

37. Ïò0.10mol.l-1H3PO4ÈÜÒºÖеμÓNaOHÈÜÒºÖÁPH=8.0,ÈÜÒºÖÐŨ¶È×î´óµÄÁ×ËáÐÍÌåÊÇ_____________(H3PO4µÄPKa1=2.0,PKa2=7.2,PKa3=12.6)

A¡¢H3PO4 B¡¢H2PO4 C¡¢HPO42

£­

£­

D¡¢PO43

£­

38. ÔÚ110mlŨ¶ÈΪ0.10mol.l-1µÄHACÖÐ,¼ÓÈë10mlŨ¶ÈΪ0.10

mol.l-1µÄNaOHÈÜÒº,Ôò»ìºÏÈÜÒºµÄPHֵΪ_______

(ÒÑÖªHACµÄPKa=4.75)

A. 4.75 B. 3.75 C. 2.75 D.5.75

39¡¢ ÔÚ250Cʱ0.1 mol.l-1ijһԪÈõËáÈÜÒºµÄµçÀë¶ÈΪ0.2%£¬Ôò´ËÈÜÒºµÄOH-Ũ¶ÈΪ_______ mol.l-1

A. 2 ¡Á 10-4 B. 1 ¡Á 10-10 C. 5 ¡Á 10-5 D. 5 ¡Á10-11

.40¡¢ ¸ù¾ÝÏÂÁÐÖÊ×Ó´«µÝ·´Ó¦:

(1) HS- + H2O = S2- + H3O+ K1=1 x 10-12 (2) CN- + H3O+ = H2O + HCN K2=1 x 10-4 (3) HAC + H2O = H3O+ + AC- K3=1 x 10-5 (4) HNO2 + CN- = HCN +NO2- K4=1 x 10-6

×îÇ¿µÄÖÊ×Ó¼îÊÇ_________

A. NO2- B. AC- C. CN- D. S2-

41. Ëá¼îÖÊ×ÓÀíÂÛÈÏΪ,ÏÂÁÐÎïÖÊÖÐÈ«²¿ÊÇËáµÄÊÇ______

A¡¢H2S¡¢ C2O42- ¡¢ HCO3- B¡¢HPO42- ¡¢ NH4+¡¢ [Fe(H2O)6]3+ C¡¢Na(S)¡¢ BF3¡¢ H2O D¡¢NH4+¡¢CO32¡¢H2O

£­

42¡¢ ÒÑÖªÔÚ298015Kʱ,ÏÂÁз´Ó¦µÄƽºâ³£Êý:

HCN = H+ +CN- Ka=4.93 x 10-10 NH3 + H2O = NH4+ +OH- Kb=1.79 x 10-5

40

H2O = H+ + OH- Kw=1.00x 10-14 ÏÂÁз´Ó¦µÄƽºâ³£ÊýÊÇ________

NH3 + HCN = NH4+ + CN-

A. 8.82 x 10-29 B. 2.75 x 10-19 C. 8.82 x 10-1

43. ÏÂÁл¯ºÏÎïÖÐ,ÆäË®ÈÜÒºµÄPHÖµ×î¸ßµÄÊÇ________

A. NaCl B. Na2CO3 C. NH4Cl D. NaHCO3

44¡¢ ÔÚH2SµÄ±¥ºÍË®ÈÜÒºÖУ¬ÏÂÁÐŨ¶È¹ØÏµÕýÈ·µÄÊÇ¡ª¡ª¡ª¡ª¡ª

A. [S2-]¡Ö2[H+] B. [HS-]¡Ö[H+] C. [H2S]¡Ö[H+]+[HS-] D. [H2S]¡Ö[S2-]

45. ÏòHACÈÜÒºÖмÓһЩNaAC,»áʹ¡ª¡ª¡ª¡ª¡ª¡ª

A. HACµÄKa¼õÉÙ B. HAC µÄµçÀë¶È¼õÉÙ C. HACµÄH+Àë×ÓŨ¶ÈÔö¼Ó D. ÈÜÒºµÄPHÖµ¼õÉÙ

46. 0.10mol.l-1HACÈÜÒºÔÚ1Éý0.10mol.l-1NaACË®ÈÜÒºÖУ¬HACµÄµç

Àë¶ÈΪ¡ª¡ª¡ª¡ª¡ª¡ª¡ª

A. 10Ka% B. 1000Ka% C. 100Ka% D. 100¡ÌKa/0.1%

47. ÈõËáÐÔË®ÈÜÒºÖеÄÇâÀë×ÓŨ¶È¿É±íʾΪ_______

A. 14_POH B. KW/POH C. 10-POH D. 10-(14-POH)

48£® 0.20mol.l-1¼×ËáÈÜÒºÖÐ3.2%µÄ¼×ËáÒѵçÀ룬ËüµÄµçÀë³£ÊýÊÇ¡ª¡ª¡ª

A.2.1 x 10-4 B. 1.25 x 10-6 C. 4.8 x 10-5 D.2.1 x 10-8

49. Èç¹ûÒÒËáµÄÀë½â³£ÊýÊÇ1.75 x 10-5 mol.l-1,ÔòÒÔʲô±ÈÀý»ìºÏÒÒËáºÍÒÒËáÄÆµÃµ½PH=6.2µÄ»º³åÈÜÒº______

A. 6.3/17.5 B. 6.3/1.75 C. 6.3/35 D. 63/1.75

50¡¢ÔÚ0.30 mol.l-1µÄHClÈÜÒºÖÐͨH2SÖÁ±¥ºÍ£¬S2Ũ¶ÈΪÏÂÁÐÄÄÒ»Ï

£­

£¨±¥ºÍH2SÈÜÒºÖУ¬H2SµÄŨ¶ÈΪ0.10mol¡¤L1£©

£­

A¡¢0.10 mol.l-1 B¡¢0.30 mol.l-1 C¡¢Ka10¡¤Ka20 D¡¢1.1¡Á10

£­19

mol.l-1

41

¶þ¡¢ Ìî¿ÕÌâ

1¡¢NH4+¡¢Cl-¡¢AC-¡¢H2OµÈÎïÖÊÖУ¬¼ÈÊÇÖÊ×ÓËáµÄÓÖÊÇÖÊ×Ó¼îµÄÎïÖÊÊÇ________£¬Æä¹²éîËáÊÇ_____________________¡¢¹²éî¼îÊÇ________________¡£

2¡¢ÓÉNaH2PO4ºÍNa2HPO4×é³É»º³åÈÜÒºÖеĻº³å¶ÔÎïÖÊÊÇ_ ________________________________¡£¸Ã»º³åÈÜÒºµÄ

»º³å×÷ÓõÄÓÐЧ·¶Î§PHÖµÊÇ_________________________¡£

3¡¢°´Ëá¼îÖÊ×ÓÀíÂÛ£¬[Al(H2O)5(OH)]2+µÄ¹²éî¼îÊÇ_______________£¬Æä¹²éîËáÊÇ____________________¡£ 4¡¢0.10mol.l-1 NaHCO3ÈÜÒºµÄPH = ________________£¬

0.10mol.l-1 Na2CO3ÈÜÒºµÄPH = _____________________

£¨H2CO3µÄPKa1 = 6.4, PKa2 = 10.2£©.

5¡¢ÅäÖÆ»º³åÈÜҺʱ£¬Ñ¡Ôñ»º³å¶ÔµÄÔ­ÔòÊÇ__________________________¡£

6¡¢ÒÑÖª0.10mol.l-1 HACÆä[H+]=1.3 x 10-3 mol.l-1 ,ÔòHACµÄµçÀë¶ÈΪ_________£¬µçÀëÆ½ºâ³£ÊýΪ____________________¡£ 7¡¢ÔÚH2S±¥ºÍÈÜÒºÖÐ[S2-]½üËÆµÈÓÚ_________________¡£

8¡¢ÒÑÖªH3PO4µÄPKa1 =2.1, PKa2 = 7.2 £¬PKa3= 12.6£¬ÓÃÁ×ËáÑÎÅäÖÆ

»º³åÈÜҺʱ,ÈôÑ¡ÓÃNa2HPO4 ×÷ΪËᣬ¿ÉÅä³ÉPHÔÚ_______________·¶Î§µÄ»º³åÈÜÒº£»ÈôÑ¡ÓÃNa2HPO4 ×÷Ϊ¼î£¬¿ÉÅäÖÆ³ÉPHÔÚ____________________·¶Î§µÄ»º³åÈÜÒº¡£ 9¡¢ÔÚ50ml 0.12mol.l-1 µÄH3PO4ÈÜÒºÖмÓÈë60ml 0.20mol.l-1NaOH

ÈÜÒº£¬Ôò»ìºÏÈÜÒºµÄPH = ______________________¡£ÔÚ60ml 0.10mol.l-1µÄNa3PO4ÈÜÒºÖмÓÈë50ml0.20mol.l-1 HClÈÜÒº£¬Ôò»ìºÏÈÜÒºµÄPH = __________________¡£

10£®Àë½â¶È¦Á¡¢Àë½â³£ÊýKÓëŨ¶ÈCµÄ¹ØÏµÊÇ£º________________ËæÅ¨¶È

C¶ø±ä£¬¶ø________²»ËæÅ¨¶ÈC¶ø±ä¡£Ï¡ÊͶ¨ÂɵÄÊýѧ±íʾʽΪ__________¡£ 11£®ÒªÊ¹0.1Éý4.0 mol.l-1µÄNH3Ë®µÄÀë½â¶ÈÔö´ó1±¶£¬Ðè¼ÓÈëË®____

______Éý¡£

12£®0.10 mol.l-1 µÄH2SÈÜÒºÖУ¬H+Ũ¶ÈÊÇ9.5 x 10-5 mol.l-1 ,PH =_______£¬HS-Àë×ÓŨ¶È_____________mol.l-1£¬S2-Àë×ÓŨ¶ÈΪ________mol.l-1¡£

13£®·Ö±ðÖкÍͬÌå»ýµÄPHÏàͬµÄNaOHºÍNH3Ë®ÈÜÒº£¬ËùÐèHClÈÜÒºµÄÁ¿Îª_____________£»Öк͵ÈÌå»ýµÈŨ¶È

42

µÄHClºÍHACÈÜÒº£¬ËùÐèµÄNaOHµÄÁ¿Îª__________________¡££¨ÌîÏàµÈ»ò²»ÏàµÈ£©

14£®PHΪ3.0µÄÏÂÁÐÈÜÒº£¬ÓõÈÌå»ýµÄË®³åÊͺó£¬HACÈÜÒºPHΪ_________£»HClÈÜÒºPHΪ_____________£»HAC

¡ªNaACÈÜÒºPHΪ____________¡£

15£®ÓÚ0.1Éý0.10 mol.l-1 µÄHACÈÜÒºÖмÓÈë0.01mol¹ÌÌåNaAc£¨¼ÙÉèÌå»ý²»±ä£©ÔòÈÜÒºÖеÄH+Àë×ÓŨ¶È½«»á

__________£»PH

½«»á____________£¬AC-Àë×ÓŨ¶È½«»á_________£¨ÌîÔö´ó¡¢¼õС»ò²»±ä£©¡£¸Ã»ìºÏÈÜÒº³ÆÎª__________

ÈÜÒº£¬ÆäH+Àë×ÓŨ¶ÈΪ______ mol.l-1£¬Ïò¸ÃÈÜÒºÖмÓÈëÉÙÁ¿Ëá¡¢¼î»òË®ºó£¬ÈÜÒºPHΪ____¡£

16£®CO32-µÄ·Ö¼¶Ë®½â³£ÊýKn1ÓÚKn2ºÍH2CO3ÈÜÒºµÄ·Ö¼¶Àë½â³£ÊýKa1¡¢Ka2Ö®¼äµÄ¹ØÏµÊÇKn1 = ______________£¬

Kn2 =_____¡£

17£®¸ù¾ÝÖÊ×ÓÀíÂÛ£¬NH4+¡¢PO43+¡¢HCO3-¡¢S2-¡¢H3PO4ºÍAC-Àë×ÓÖÐÊÇÖÊ×ÓËá µÄÓÐ________£¬Æä¹²éî¼î·ÖÊÇ_______£»

ÊÇÖÊ×Ó¼îµÄÓÐ____________£¬Æä¹²éîËá·Ö±ðÊÇ______________________£»ÆäÖмÈÊÇËáÓÖÊǼîµÄÓÐ

__________________________¡£

Èý¡¢¼ÆËãÌâ

1¡¢¼ÆËã0.20 mol.l-1 Na2CO3Ë®ÈÜÒºµÄPHÖµ¡£ÈôÏò¸ÃÈÜÒºÖмÓÈëµÈÌå»ýµÄ0.20mol.l-1HCl£¬¼ÆËã»ìºÏÒºµÄPHÖµ

(H2CO3µÄKa1=4.3 x 10-7, Ka2=5.6x 10-11).

2¡¢ÅäÖÆPH = 8.25µÄ»º³åÈÜÒº£¬ÎÊÔÚ200ml 0.20 mol.l-1 NH3H2O ÖмÓÈë0.50 mol.l-1 HCl¶àÉÙºÁÉý?

(ÒÑÖªNH3.H2OµÄPKb = 4.75).

43

3¡¢½«10ml, 0.30 mol.l-1 µÄHCOONaÓë20ml, 0.15 mol.l-1µÄHF»ìºÏ.¼ÆËã·´Ó¦µÄƽºâ³£ÊýºÍÈÜÒºÖеÄ[HCOO-]¡¢

[F-]ºÍ[H+]¸÷Ϊ¶àÉÙ?

(KHCOOH = 1.7 x 10-4, KHF = 6.8 x 10-4).

4. ÒÑÖª298KʱijһԪÈõËáµÄ0.10 mol.l-1Ë®ÈÜÒºµÄPHֵΪ3.0, Çó: (1) Ka (2) ¦Á (3)Ï¡ÊÍÒ»±¶ºóµÄKa¡¢¦Á¡¢PHÖµ

£¨4£©Óë0.10 mol.l-1 NaOHÈÜÒºµÈÌå»ý»ìºÏºóËùµÃ»ìºÏÈÜÒºµÄPHÖµ Ìå»ý»ìºÏºóËùµÃ»ìºÏÈÜÒºµÄPHÖµ¡£

44

5£©Óë0.20 mol.l-1 NaOHÈÜÒºµÈ £¨µÚÁùÕ ³Áµí¡ªÈܽⷴӦ

Ò»¡¢

Ñ¡ÔñÌâ

1. ÏÂÁÐÐðÊöÖÐÕýÈ·µÄÊÇ¡ª¡ª¡ª¡ª¡ª

A. B. C.

ÄÑÈܵç½âÖÊÀë×ÓŨ¶ÈµÄ³Ë»ý¾ÍÊǸÃÎïÖʵÄÈܶȻý. ÈܶȻý´óÕß,ÆäÈܽâ¶È¾Í´ó.

ÈÜÒºÖÐ×é³ÉÄÑÈܵç½âÖʵÄÀë×Ó»ý´óÓÚËüµÄÈܶȻýʱ,¾Í»á ²úÉú³Áµí. D.

ÓÃˮϡÊͺ¬ÓÐAgCl ¹ÌÌåµÄÈÜҺʱ, AgClµÄÈܶȻý²»±ä,ÆäÈܽâ¶ÈÔö´ó.

2. Sr3(PO4)2µÄÈܶȻýK?SP±í´ïʽÊÇ________

A. K?SP = [Sr2+][PO43-] B. K?SP = [3Sr2+][2PO43-] C.K?SP = [Sr2+]3[PO43-]2 D. K?SP = [Sr32+][(PO4)23-]

3. ÔÚÏÂÁÐÄÑÈÜÒøÑεı¥ºÍÈÜÒºÖÐ, Ag+Àë×ÓŨ¶È×î´óµÄÊÇ(À¨ºÅÄÚΪÈܶȻý)________ A. AgCl (1.8 x 10-10) B. Ag2C2O4 (3.4 x 10-11) C. AgCrO4 (1.1 x 10-12) D. AgBr (5.2 x 10-13)

4. ÏÂÁб¥ºÍÈÜÒºÖÐ,SO42-Àë×ÓŨ¶È×îСµÄÊÇ(À¨ºÅÄÚΪÈܶȻý)________ A. BaSO4 (1.1 x 10-10) B. CaSO4(9.1 x 10-6) C. PbSO4 (1.6 x 10-8) D. Ag2SO4 (1.4 x 10-5)

5. Hg2Cl2 µÄ. K?SP Ϊ1.3 x 10-18 ,0.1Éý±¥ºÍÈÜÒºµÄŨ¶ÈÊÇ_____________mol.L-1 A. 6.88 x 10-7 B. 1.68 x 10-4 C. 6.88 x 10-8 D. 1.14 x 10-9

6. BaSO4µÄÈܶȻýΪ1.0 x 10-10 , ÆäÏà¶Ô·Ö×ÓÖÊÁ¿Îª233.3£¬Èô½«1.0 ¡Á 10-3 molµÄBaSO4·ÅÈë10ÉýË®ÖУ¬ÔòδÈܽâµÄÑùÆ·ÓÐ______

A. 0.21g B. 2.1g C. 2.1 x 10-2g D. 2.1 x 10-3g 7. CaF2µÄ±¥ºÍÈÜҺŨ¶ÈΪ2.0 x 10-4 mol.L-1,ËüµÄÈܶȻýΪ_______ A. 2.6 x 10-9 B. 3.2x 10-11 C. 4.0 x 10-8 D. 8.0 x 10-10

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8. 1ÉýAg2C2O4±¥ºÍÈÜÒºÖÐÈÜÖÊÖÊÁ¿Îª0.06257¿Ë£¬Èô²»¿¼ÂÇÈܽâºóÀë×ÓµÄË®½âµÈÒòËØ, Ag2C2O4µÄ. K?SP ÊÇ

__________

A¡¢4.24 x 10-8 B. 2.36 x 10-10 C. 3.50 x 10-11 D. 8.74 x 10-12

9. AgBrµÄÈܶȻýK?SP = 5.2 x 10-13, AgBrÔÚ0.1 mol.L-1 KBrÈÜÒºÖеÄÈܽâ¶ÈÊÇ_________ mol.L-1

A.2.6 x 10-6 B. 5.2 x 10-12 C. 4.0 x 10-13 D. 4.0 x 10-14

10. CaF2ÔÚ0.1 mol.L-1 KNO3ÈÜÒºÖеÄÈܽâ¶ÈÓëË®ÖеÄÈܽâ¶ÈÏà±È£¬ÊôÓÚÏÂÁÐÄÄÒ»ÖÖ________ A. Ôö´ó B. ¼õС C. Ïàͬ D. ÎÞ·¨ÅÐ¶Ï 11. ÏÂÁÐÐðÊöÖÐÕýÈ·µÄÊÇ__________

A. º¬ÓжàÖÖÀë×ÓµÄÈÜÒºÖÐ,ÄÜÐγÉÈܶȻýСµÄ³ÁµíÕßÒ»¶¨ÏȳÁµí. B. C. D.

·²ÈܶȻý´óµÄ³ÁµíÒ»¶¨»áת»¯³ÉÈܶȻýСµÄ³Áµí. ijÀë×Ó³ÁµíÍêÈ«ÊÇÖ¸ÍêÈ«±ä³ÉÁ˳Áµí.

µ±ÈÜÒºÖÐÄÑÈܵç½âÖʵÄÀë×Ó»ýСÓÚÆäÈܶȻýʱ,¸ÃÄÑÈܵç½âÖʾͻáÈܽâ.

12. ÒÑÖªPbCl2,¡¢PbI2 ºÍPbSµÄÈܶȻý¸÷Ϊ1.6 ¡Á10-5¡¢ 7.1 ¡Á 10-9 ºÍ8.0 ¡Á10-28¡£ÓûÒÀ´Î¿´µ½°×É«PbCl2,¡¢»ÆÉ«PbI2 ºÍºÚÉ«PbS³Áµí£¬ÍùPb2+ÈÜÒºÖеμÓÊÔ¼ÁµÄ´ÎÐòÊÇ_____________

A¡¢Cl¡¢I¡¢S2

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B¡¢S2¡¢Cl¡¢I

£­

£­

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C¡¢I¡¢Cl¡¢S2

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D¡¢S2¡¢I¡¢Cl

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13. µ±Mg(OH)2¹ÌÌåÔÚË®Öн¨Á¢Æ½ºâʱ Mg(OH)2 = Mg2+ + 2 OH-

ΪʹMg(OH)2¹ÌÌåÁ¿¼õÉÙ,ÐèÒª¼ÓÈëÉÙÁ¿µÄ________ A. Na2S B. MgSO4 C. NH4NO3 D. NaOH 14. ijÈÜÒºÖк¬ÓÐKCl¡¢KBrºÍK2CrO4£¬Å¨¶È¾ùΪ0.010 mol.L-1

ÏòÈÜÒºÖÐÖðµÎ¼ÓÈë0.1 mol.L-1AgNO3ÈÜҺʱ£¬×îÏȺÍ×îºó³ÁµíµÄÊÇ¡ª¡ª¡ª¡ª¡ª¡ª A. AgBr ºÍAg2Cr2O4 B. Ag2CrO4 ºÍAgCl C. AgCl ºÍAgBr D. AgCl ºÍAg2CrO4

15. ÔÚº¬ÓÐCl-¡¢Br-¡¢I-¡¢CrO42-Àë×ÓµÄŨ¶È¾ùΪ0.012 mol.L-1µÄ»ìºÏÈÜÒºÖУ¬Öð½¥¼ÓÈëAgNO3ÈÜҺʹÀë×Ó²úÉú

46

³Áµí£¬³ÁµíÎö³öµÄÏȺó´ÎÐòΪ_________(ÒÑÖªAgCl¡¢ AgBr¡¢AgI¡¢Ag2CrO4µÄÈܶȻý·Ö±ðΪ1.8 ¡Á 10-10¡¢5.0 ¡Á 10-13¡¢8.3 ¡Á10-17¡¢1.2 ¡Á 10-12)

A.

AgCl¡¢AgBr¡¢AgI¡¢Ag2CrO4

B. Ag2CrO4 ¡¢AgI¡¢ AgBr¡¢AgCl C. Ag2CrO4 ¡¢ AgBr¡¢AgI¡¢ AgCl D. AgI,¡¢AgBr¡¢AgCl,¡¢Ag2CrO4

16. ͬζÈϽ«ÏÂÁÐÎïÖÊÈÜÓÚË®³É±¥ºÍÈÜÒº,Èܽâ¶È×î´óµÄÊÇ____

A. AgCl (K?SP = 1.8 x 10-10) B. Ag2CrO4(K?SP = 1.1 x 10-12) C.Mg(OH)2(K?SP = 1.8 x 10-11) D.FePO4(K?SP = 1.3 x 10-22)

17. ÔÚ0.05 mol.L-1CuCl2ÈÜÒºÖеÎÈëH2SÖÁ±¥ºÍ [H2S] = 0.1 mol.L-1, ÈÜÒºÖвÐÁôµÄ[Cu2+]µÈÓÚ________ mol.L-1 A. 3.6 x 10-16 B. 6.3 x 10-18 C. 2.5 x 10-17 D. 6.3 x 10-19

(ÒÑÖª K?SP,CuS = 6.3 x 10-36 K×ÜH2S = 1.0 x 10-19 ) 18. ÓÐÒ»ÄÑÈܵç½âÖÊA2B,ÆäÈܽâ¶ÈΪS,ÔòK?SPÊÇ________ A. S3 B. 4S2 C. 2S3 D. 4S3

19.ÒÑÖªAgClºÍAg2CrO4µÄ. K?SP·Ö±ðΪ1.8 ¡Á10-10£¬1.1 ¡Á 10-12¡£Èôij»ìºÏÒºÖУ¬[Cl-] = [CrO42-] = 10-5 mol.L-1£¬

µ±¼ÓÈëAg+´ï104mol.L-1ʱ£¬Ôò»á·¢Éú_______

£­

A. AgC lÏȳÁµí B. Ö»ÓÐAgCl³Áµí C. Ö»ÓÐAg2CrO4³Áµí D. ¶þÕß¶¼³Áµí

20. CaF2µÄ±¥ºÍÈÜÒºÖÐ[CaF2] = 2.0 ¡Á 10-4 mol.L-1£¬ÆäÖÐK?SPÒ»¶¨ÊÇ

________

A.

¶þ¡¢Ìî¿ÕÌâ

6.0 ¡Á10-2 B. 4.0 ¡Á10-8 C. 3.2 ¡Á 10-11 D. 8.0 ¡Á 10-12

1. Èç¹ûCaC2O4µÄK?SPΪ2.6 ¡Á 10-9£¬ÒªÊ¹Ã¿Éýº¬ÓÐ0.02mol¸ÆÀë×ÓŨ¶ÈµÄÈÜÒºÉú³É³Áµí£¬ËùÐèµÄ²ÝËá¸ùÀë×ÓŨ

¶ÈÊÇ_______________mol.L-1

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2. PbI2ÔÚË®ÖеÄÈܽâ¶ÈΪ1.2 ¡Á 10-3 mol.L-1,ÆäK?SP = _____________, PbI2ÈÜÓÚ0.01 mol.L-1KIÈÜÒº,ÆäÈܽâ¶ÈΪ____________ mol.L-1.

3. ÔÚº¬ÓÐCl-¡¢Br-¡¢I-¡¢CrO42-Àë×ÓµÄŨ¶È¾ùΪ0.012 mol.L-1µÄ»ìºÏÈÜÒºÖУ¬Öð½¥¼ÓÈëAgNO3ÈÜҺʹÀë×Ó²úÉú³Áµí£¬³ÁµíÎö³öµÄÏȺó´ÎÐòÊÇ_____________________________________________

(ÒÑÖªAgCl¡¢AgBr¡¢AgI¡¢Ag2CrO4µÄÈܶȻý·Ö±ðΪ1.8 ¡Á 10-10¡¢ 5.0 ¡Á 10-13¡¢ 8.3 ¡Á 10-17¡¢1.2 ¡Á 10-12.) 4. ÏÂÁÐÄÑÈܵç½âÖʵÄÈܶȻý³£Êý±íʾʽ·Ö±ðΪ

K?SP (BaS) =_______________, . K?SP (PbCl2) =_________________ . K?SP (Ag2CrO4) =________________. 5. AgClµÄÈܶȻýµÈÓÚ1.2 ¡Á 10-10£¬´ÓCl-Àë×ÓŨ¶ÈΪ6.0 ¡Á 10-3mol.L-1µÄÈÜÒºÖпªÊ¼Éú³ÉAgCl³ÁµíµÄAg+Àë×ÓŨ¶È(mol.L-1)ÊÇ______________.

6. ÍùÒøÑÎÈÜÒºÖÐÌí¼ÓHClʹAgCl³Áµí£¬Ö±µ½ÈÜÒºÖÐÂÈÀë×ÓµÄŨ¶ÈΪ0.20 mol.L-1Ϊֹ£¬ ÀíÂÛÉÏ´ËÊ±ÒøÀë×ÓµÄŨ¶ÈΪ____________________________________________

(ÒÑÖª K?SP (AgCl) =1.56 ¡Á 10-10).

7. Ïò0.05 mol.L-1µÄCuCl2ÈÜÒºÖÐͨÈëH2SÆøÌåÖÁ±¥ºÍ,Ôò¸ÃÈÜÒºµÄPH = __________.(H2SµÄKa1 = 9.1 ¡Á 10-8, Ka2 = 1.1 ¡Á 10-12, . K?SP (CuS) = 6.3 ¡Á 10-36).

8. Ó°Ïì·Ö²½³Áµí˳ÐòµÄÈýÒòËØÊÇ___________¡¢______________¡¢__________________ . Èý¡¢¼ÆËãÌâ

1. ½ñÓÐMnS³Áµí0.1mol£¬ÎÊÒªÓÃ1Éý¶àÉÙŨ¶ÈµÄHAC²ÅÄÜʹËüÈܽ⣿ £¨ÒÑÖª: KSP(MnS) =2.5 ¡Á 10-10 KHAC = 1.8 ¡Á 10-5 Ka1(H2S) = 1.32 ¡Á 10-7, Ka2(H2S) = 7.10 ¡Á 10-15 £©

2. ½«0.02 mol.L-1Ba2+ÈÜÒºÓë0.2 mol.L-1 HFÈÜÒºµÈÌå»ý»ìºÏ£¬È»ºóµ÷½Ú»ìºÏÒºµÄPH = 1.0 £¨Éèµ÷PHֵʱÈÜÒºÌå»ý²»±ä£©

48

£¨1£©¡¢Í¨¹ý¼ÆËã˵Ã÷ÄÜ·ñÉú³ÉBaF2³Áµí¡£

£¨2£©¡¢Çó³öÄÜÉú³ÉBaF2³Áµí£¬¶øÓÖ²»ÖÁÉú³ÉBa(OH)2 µÄPH·¶Î§.

( KSP(BaF2) = 1.0 ¡Á 10-6, KSP(Ba(OH)2) = 5.0 ¡Á 10-3, Ka(HF) = 3.5 ¡Á 10-4).

3. ÔÚ0.50mol.L-1MgCl2ÈÜÒºÖмÓÈëµÈÌå»ýµÄ0.1mol.L-1°±Ë®£¬ÎÊÊÇ·ñÄÜÉú³ÉMg(OH)2³Áµí? ÈôÔÚ´Ë0.1mol.L-1°±Ë®ÈÜÒºÖÐÔÙ¼ÓÈëNH4Cl(s)£¬Ê¹NH4ClµÄÎïÖʵÄÁ¿Å¨¶ÈΪ0.020mol.L-1£¬ÎÊMg(OH)2ÄÜ·ñ³Áµí³öÀ´? ÈçÓУ¬ÐèÔÚÿÉý0.1mol.L-1°±Ë®ÖмÓÈë¶àÉÙ¹ÌÌåNH4Cl²ÅÄÜʹ Mg(OH)2²»³Áµí ?(¼ÓÈë¹ÌÌåºóÈÜÒºÌå»ý±ä»¯ºöÂÔ²»¼Æ)£¨ ÒÑÖª: KSP(Mg(OH)2 = 1.2 ¡Á 10-11, Kb(NH3.H2O)= 1.79 ¡Á 10-5, MNH4Cl = 53.5£©

4. µ±CaF2¹ÌÌåÈÜÓÚPH = 3.5µÄ»º³åÈÜÒº(²»º¬F-)´ïµ½Æ½ºâºó£¬²âµÃ[Ca2+] = 1.0 x 10-3 mol.L-1(¼ÙÉèÈÜÒºÖв»´æÔÚ

49

CaF+Àë×Ó)£¬ÇóCaF2µÄKSP¡£ (ÒÑÖª: Ka(HF) = 1.8 x 10-5)

5. ¼ÆËãÔÚ100ml 1.0 mol.L-1°±Ë®ÖÐÄÜÈܽâAgBrµÄ¿ËÊý¡£

µÚÆßÕ ԭ×ӽṹ

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9¡¢Í¬Ò»Ö÷×åÔªËØµÄµÚÒ»µçÀëÄÜI£¬ÓÉÉϵ½ÏÂÖð½¥¼õС¡££¨ £©

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