(3) £¨Ã¿¿Õ1·Ö£©ÓÉ£¨a£©ÖÐͼÏñµÃ³ö½áÂÛ£ºvÓëW²»³ÉÕý±È ÓÉ£¨b£©ÖÐͼÏñµÃ³ö½áÂÛ£ºÔÚÎó²îÔÊÐí·¶Î§ÄÚ£¬v2¡ØW 23£®(9·Ö)£¨a£©R2£¨3·Ö£©£¨b£©Èçͼ£¨3·Ö£© (c)

24£®(13·Ö)

+ µçÔ´E

ͼÒÒ

R1 R2 R3 R¡ä 2 A1 + - 2 2 A R0 I2(R0?R2)I1+ - £¨3·Ö£© - S £¨1£©µ±Ð¡Îï¿éÔÚAB¶ÎÔ˶¯Ê±£¬Éè¼ÓËÙ¶ÈΪa1£¬Ôò a1?gsin? £¨2·Ö£© Óɱí¸ñ¿ÉÖª a1?12?02?0m/s2?6m/s £¨1·Ö£©

3520ËùÒÔ ??37»ò??arcsin £¨1·Ö£©

£¨2£©¹ýBµãºóÎï¿éµÄ¼ÓËÙ¶ÈÉèΪa2£¬Ôòa2?gsin???gcos? £¨2·Ö£© Óɱí¸ñ¿ÉÖª a2?29?216?4m/s?4m/s £¨1·Ö£©

22ËùÒÔ ??0.25 £¨1·Ö£© £¨3£©¿ÉÒÔÅжÏBµã¶ÔÓ¦ÓÚ2s~3sÖ®¼äµÄij¸öʱ¿Ì£¬Éèt1Ϊ´ÓµÚ2sʱ¿ÌÔ˶¯ÖÁBµãËùÓÃʱ¼ä£¬t2Ϊ´ÓBµãÔ˶¯ÖÁµÚ3sʱ¿ÌËùÓÃʱ¼ä¡£

Ôò t1?t2?1s £¨1·Ö£©

12m/s?a1t1?17m/s?a2t2 £¨1·Ö£©

½âÖ®µÃ t1?0.5s £¨1·Ö£©

ËùÒÔ xAB?25£®£¨19·Ö£©

12a1(2s?t1)2?18.75m £¨2·Ö£©

½â´ð£º£¨1£©ÒªÊ¹Ð¡ÇòÊͷźóÄÜÑØԭ··µ»Ø£¬ÔòСÇòÊͷźó×î¶àÖ»ÄÜ°ÚÖÁµÚ¶þÏóÏÞϸÏßÓëx£®£®£®£®ÖḺÏò³É45?½Ç´¦£¨ÓÉÖØÁ¦Óëµç³¡Á¦µÄºÏÁ¦·½Ïò¾ö¶¨£©¡£Ç¡°Úµ½ÓëxÖḺÏò³É45?½Ç¶ÔÓ¦µÄ¦È¼´Îª×îС¡£¶ÔÕâÒ»¹ý³ÌÓö¯Äܶ¨Àí£º

qELcos45?mg(Lsin??Lsin45)?0?0 £¨6·Ö£©

00½âÖ®µÃ ??0? £¨2·Ö£© £¨2£©ÒªÊ¹Ð¡ÇòÄÜÔÚÊúֱƽÃæÄÚ×öÍêÕûµÄÔ²ÖÜÔ˶¯£¬Ö»ÐèÒªÈÃСÇò´Ó??0?´¦³ö·¢ÄÜÑذ뾶ΪLµÄÔ²ÖÜͨ¹ýyÖá×î¸ßµã¼´¿É¡£Éèͨ¹ýyÖá×î¸ßµãʱСÇòËÙ¶ÈΪv ¶ÔÕâÒ»¹ý³ÌÓö¯Äܶ¨Àí£¨µç³¡Á¦×ö¹¦ÎªÁ㣩£º?mgL?mvL212mv2?12mv0 £¨6·Ö£©

2ÔÚ×î¸ßµãÓÉÅ£¶ÙµÚ¶þ¶¨Àí¿ÉµÃ£º mg? £¨3·Ö£©

ÁªÁ¢½âµÃ£º v0?26£®(15·Ö)

(1) (2·Ö)

3gL £¨2·Ö£©

(2)A(2·Ö) MnO2+4H++2Cl- ¡÷ Mn2++Cl2¡ü+2H2O£¨2·Ö£© (3) 2S2Cl2£«2H2O === 3S £« SO2 ¡ü £«4HCl ¡ü (2·Ö) (4)a¡úhi¡újk¡úbc¡úfg¡ú jk (3·Ö)

(5)Éè¼ÆÖÐȱÎüÊÕβÆøµÄ×°ÖÃÓëÒ©Æ·£¬ÔÚµ¼¹ÜbºóÌí¼ÓÒ»¸ö×°Óмîʯ»Ò¸ÉÔï¹Ü¡£ (»­Í¼2·Ö¡¢ÀíÓÉ2·Ö) 27£®£¨14·Ö£©(ÿ¿Õ2·Ö) £¨1£©CuSO4 ¡¢FeCl3 £¨2£©2NaCl£«2H2O £¨3£©¢Ú

£¨4£©ºìºÖÉ«ÒºÌåÖÐÏȳöÏÖºìºÖÉ«³Áµí£¬ºóÖð½¥Èܽâ±äΪ×Ø»ÆÉ«ÈÜÒº (5) 2OH£­£«Cl2 === ClO£­£«Cl£­£«H2O 28£®£¨14·Ö£©

µç½â 2NaOH£«Cl2¡ü£«H2¡ü 14

£¨1£©K=c(CO)/c(CO2)£¨1·Ö£© >£¨1·Ö£© 50%£¨2·Ö£© 0.1mol/(L¡¤min)£¨2·Ö£© £¨2£©BC£¨2·Ö£© £¨3£©A £¨2·Ö£©

£¨4£©2£¨a+b£©kJ/mol£¨2·Ö£© £¨5£©3.3ÖÁ9Ö®¼ä(2·Ö) 29£®£¨7·Ö£©

£¨1£©Í¨Í¸ÐÔ¹¦Äܸı䣬ʹÎïÖÊÔËÊ书ÄܽµµÍ£¨2·Ö£© £¨2£©ºËÌÇÌå ¡¢ÏßÁ£Ì壨2·Ö£©

£¨3£©ÒÖÖÆ£¨»òÆÆ»µ£©ÁËCa2+µÄÔØÌ壨1·Ö£© £¨4£©ÒȵºËØ£¨1·Ö£© £¨5£©ºËÌÇÌ壨1·Ö£© 30£®£¨13·Ö£©

(1)[¢Ú]µ°°×ÖÊ£¨1·Ö£© Ϊ°µ·´Ó¦(»òC3µÄ»¹Ô­)ÌṩÄÜÁ¿£¨1·Ö£© (2) 18(×óÓÒ²»³¬¹ý0.5)£¨2·Ö£©£©

CO2Ũ¶È£¨1·Ö£© Ê©¼ÓÓлú·Ê¡¢ºÏÀíÃÜÖ²ÀûÓÚͨ·ç(ÓÐÒ»Ïî¼´¿ÉµÃ·Ö) £¨1·Ö£©

¢Ú¼ûÓÒͼ(1·Ö) (3)ʵÑé²½Ö裺

µÚ¶þ²½£º¶ÔÕÕ×飺¸øÓèÊÊÒ˵Ŀɼû¹â¹âÕÕÒ»¶Îʱ¼ä(1·Ö) ʵÑé×飺¸øÓèͬµÈÇ¿¶ÈµÄ¿É¼û¹âºÍÒ»¶¨Ç¿¶È µÄ×ÏÍâ¹âÕÕÏàͬµÄʱ¼ä(2·Ö)

µÚÈý²½£º²âÁ¿Á½×éÖ²ÖêÖÐ3-ÑǼ׻ùÑõ´úßÅßáµÄº¬Á¿(1·Ö)

Ô¤²âʵÑé½á¹û£º¶ÔÕÕ×éÖ²Öê¸ßÓÚʵÑé×飬ÇÒʵÑé×éÖÐ3-ÑǼ׻ùÑõ´úßÅßẬÁ¿¸ßÓÚ¶ÔÕÕ×é(2·Ö) 31£®£¨10·Ö£©

(1)¸º£¨1·Ö£© (2)Í»´¥£¨2·Ö£© (3)b¡úa £¨1·Ö£© (4)¢ÙÖáÍ»(»ò´«³öÉñ¾­) £¨1·Ö£©¢Ú30 £¨2·Ö£© (5)¢ÙʵÑé½á¹ûÈçÓÒͼËùʾ¡££¨2·Ö£© ¢Ú¼ÙÉè2 £¨1·Ö£© 32£®£¨9·Ö£©

I£®£¨1£©X£¨2·Ö£© £¨2£© 10/11£¨2·Ö£©

II£®£¨3£©È¾É«Ìå(½á¹¹)±äÒ죨1·Ö£©

£¨4£©¢Ù°ôÑ۴ƹûÓ¬£¨1·Ö£© 2/3 £¨1·Ö£© ¢Ú 0£¨1·Ö£© 1/3£¨1·Ö£©

201510 5 B ¡¤ -5 A ¡¤ 0 ¹âÕÕÇ¿¶È CO2ÎüÊÕÁ¿ 2£¨mg£¯100cmÒ¶¡¤Ð¡Ê±£© C ¡¤ £¨¶þ£©Ñ¡¿¼Ì⣺

33£®[ÎïÀí¡ª¡ªÑ¡ÐÞ3-3]£¨15·Ö£© £¨1£©£¨6·Ö£©ABE £¨2£©£¨9·Ö£©

£¨a£©ÒÔÆø¸×Ϊ¶ÔÏ󣨲»°üÀ¨»îÈû£©ÁÐÆø¸×ÊÜÁ¦Æ½ºâ·½³Ì£º

p1S?Mg?p0S £¨3·Ö£©

½âÖ®µÃ£º p1?3?10Pa £¨1·Ö£©

5 £¨b£©µ±»îÈûÇ¡ºÃ¾²Ö¹ÔÚÆø¸×¸×¿ÚAB´¦Ê±£¬¸×ÄÚÆøÌåζÈΪT2£¬Ñ¹Ç¿Îªp2 ´ËʱÈÔÓÐp2S?Mg?p0S£¬¼´¸×ÄÚÆøÌåΪµÈѹ±ä»¯¡£ ¶ÔÕâÒ»¹ý³ÌÑо¿¸×ÄÚÆøÌ壬ÓÉ״̬·½³ÌµÃ£º S?0.5lT1?S?lT2 £¨3·Ö£© ËùÒÔ T2?2T1?600K £¨1·Ö£© ¹Ê t2?(600?273£½327¡æ £¨1·Ö£© )¡æ34£®[ÎïÀí¡ª¡ªÑ¡ÐÞ3-4]£¨15·Ö£©

£¨1£©£¨6·Ö£©BCD

(2)½âÎö£º(a)¹â·ͼÈçͼËùʾ¡££¨2·Ö£¬Èô°ÑÔÚÀâ¾µÄÚ²¿¶à´Î·´ÉäµÄ¹â·»­ÉÏ£¬Ö»ÒªÃ»»­´í£¬¸ø´Ë·Ö£© (b)¹âÏßÔÚBCÃæÉÏÇ¡ºÃ·¢ÉúÈ«·´É䣬ÈëÉä½ÇµÈÓÚÁÙ½ç½ÇC

B O C

A D 1

sinC£½ £¨2·Ö£©

n

ÔÚAB½çÃæÉÏ·¢ÉúÕÛÉ䣬ÕÛÉä½Ç¦È2£½90¡ã£­C £¨1·Ö£© ÓÉÕÛÉ䶨ÂÉ£º

sin¦È1

£½n £¨1·Ö£© sin¦È2

62ÓÉÒÔÉϼ¸Ê½½âµÃ n£½ £¨1·Ö£©

c

(c)¹âËÙ v£½£½6¡Á108m/s £¨2·Ö£©

n

35£®[ÎïÀí¡ª¡ªÑ¡ÐÞ3-5]£¨15·Ö£©

£¨1£©£¨6·Ö£©BCE (2)£¨9·Ö£©

£¨a£©ÒòA ¡¢BÏ໥×÷ÓÃʱÎÞ»úеÄÜËðʧͬʱ¶¯Á¿Ò²Êغ㣬¹ÊA¡¢BÅöײÊÇÒ»¶¨ÔÚOµã½øÐÐÇÒËٶȻ¥»»¡£ £¨3·Ö£© £®£®£®£®

ҪʹBÎïÌåÇ¡ÄÜÉÏÉýÖÁÔ²»¡×î¸ßµãPµã£¬ÇóAÎïÌåµÄ³õËٶȣ¬¼´ÊÇÇóBÎïÌåÔÚOµãÏòÓÒ³ö·¢µÄËٶȡ£¶ÔBÎïÌå´ÓOµãÖÁPµã£¬Óɶ¯Äܶ¨ÀíµÃ£º

??mgR?mgR?0?12mv0 £¨2·Ö£©

2 ½âÖ®µÃ v0?3gR £¨1·Ö£©

£¨b£©Èôv0²»±ä£¬ÉèBÎïÌåÔÚON¼äÔ˶¯µÄ×Ü·³ÌΪs