»úеÉè¼Æ»ù´¡£¨³ÂÏþéª-ÑîÅàÁÖ£©¿Îºó´ð°¸È« ÏÂÔر¾ÎÄ

¸÷ÂÝ˨×éÖÐÊÜ×î´ó¼ôÁ¦ÂÝ˨ÉÏËùÊܺÏÁ¦: ͼ(a):ÂÝ˨3 ÊÜÁ¦×î´ó:

a = 30¡ãF = (

FQ

FQ 4 3FQ 32 4 3FQ 12

+F cosa)+(F sina)= (+ )+()=0.612F

2

2

a3 as3 as3

6

ͼ(b):ÂÝ˨4 ÊÜÁ¦×î´ó:

FQ FQ

+=0.5F b4

6 6 3

bs4

Q

F =

FQ

+F =

ͼ(c):ÂÝ˨3¡¢4 ÊÜÁ¦×î´ó: cosb=

6152152 Q

150 2

=

sinb=

75 1

=1502 +752 5

2 2

150+755F =F = (

FQ

+F cosb)2 +(F sinb)2 = (

FQ 2 5FQ 2 2 2 5FQ 1 2

+)+()=0.561F

c3 c4

6

cs3 cs3

6 11 5 11 5

Q

½áÂÛ:±È½ÏÈýÖÖÂÝ˨×é²¼ÖÃÐÎʽÖÐÂÝ˨×éÖÐÊÜ×î

´ó¼ôÁ¦µÄÂÝ˨¿ÉÖª:ͼ(b)²¼ÖÃÐÎʽÂÝ˨ÊÜÁ¦×îС

15-14 ͼ15-49ÊÇÓÉÁ½¿é±ß°åº¸³ÉµÄÁúÃÅʽÆðÖØ»úµ¼¹ìÍмܡ£Á½¿é±ß

°å¸÷ÓÃ4¸öÂÝ˨ÓëÁ¢Öù(¹¤×Ö¸Ö)ÏàÁ¬½Ó,Ö§¼ÜËù³ÐÊܵÄ×î´óÔغÉΪ20000N,ÊÔÉè¼Æ: (1)²ÉÓÃÆÕͨÂÝ˨Áª½Ó(¿¿Ä¦²Á´«Á¦)µÄÂÝ˨ֱ¾¶d; (2)²ÉÓýÂÖÆ¿×ÓÃÂÝ˨Áª½Ó(¿¿¼ôÇд«Á¦)µÄÂÝ˨ֱ¾¶d,ÉèÒÑÖªÂÝ˨µÄ[t ]Ϊ28MPa¡£

ͼ15-49 Ï°Ìâ15-14 ͼ-2-

½âÍâÔغÉÏòÂÝ˨×éÖÐÐļò»¯Ôò:ÂÝ˨×éÊܺáÏòÁ¦FR=20 kN ÂÝ˨×éÊÜÐýתÁ¦¾ØT=20¡Á300=6¡Á103 kNmm ÔÚºáÏòÁ¦×÷ÓÃÏÂ,µ¥¸öÂÝ˨ÊÜÁ¦: F = R =

F20

= 2.5 kN

Tr T 6 103 2 4 8 ÔÚÐýתÁ¦¾ØT×÷ÓÃÏÂ,µ¥¸öÂÝ˨ËùÊÜÁ¦:F =F =F =F = = =

s

22=7.07 kN F = (F +F cos45¡ã)2 +(F sin45¡ã)2 = (2.5+7.07 )2 +(7.07 )2 =9.01 kN

s1 s2 s3 s4

8r2 8r 8 752 +752 ÂÝ˨×éÊÜÁ¦ÈçͼËùʾ,ÆäÖÐÂÝ˨2¡¢3 ËùÊÜÔغÉ×î

´ó,×î´óÔغÉΪ:

smaxss2 s2

22