¸÷ÂÝ˨×éÖÐÊÜ×î´ó¼ôÁ¦ÂÝ˨ÉÏËùÊܺÏÁ¦: ͼ(a):ÂÝ˨3 ÊÜÁ¦×î´ó:
a = 30¡ãF = (
FQ
FQ 4 3FQ 32 4 3FQ 12
+F cosa)+(F sina)= (+ )+()=0.612F
2
2
a3 as3 as3
6
ͼ(b):ÂÝ˨4 ÊÜÁ¦×î´ó:
FQ FQ
+=0.5F b4
6 6 3
bs4
Q
F =
FQ
+F =
ͼ(c):ÂÝ˨3¡¢4 ÊÜÁ¦×î´ó: cosb=
6152152 Q
150 2
=
sinb=
75 1
=1502 +752 5
2 2
150+755F =F = (
FQ
+F cosb)2 +(F sinb)2 = (
FQ 2 5FQ 2 2 2 5FQ 1 2
+)+()=0.561F
c3 c4
6
cs3 cs3
6 11 5 11 5
Q
½áÂÛ:±È½ÏÈýÖÖÂÝ˨×é²¼ÖÃÐÎʽÖÐÂÝ˨×éÖÐÊÜ×î
´ó¼ôÁ¦µÄÂÝ˨¿ÉÖª:ͼ(b)²¼ÖÃÐÎʽÂÝ˨ÊÜÁ¦×îС
15-14 ͼ15-49ÊÇÓÉÁ½¿é±ß°åº¸³ÉµÄÁúÃÅʽÆðÖØ»úµ¼¹ìÍмܡ£Á½¿é±ß
°å¸÷ÓÃ4¸öÂÝ˨ÓëÁ¢Öù(¹¤×Ö¸Ö)ÏàÁ¬½Ó,Ö§¼ÜËù³ÐÊܵÄ×î´óÔغÉΪ20000N,ÊÔÉè¼Æ: (1)²ÉÓÃÆÕͨÂÝ˨Áª½Ó(¿¿Ä¦²Á´«Á¦)µÄÂÝ˨ֱ¾¶d; (2)²ÉÓýÂÖÆ¿×ÓÃÂÝ˨Áª½Ó(¿¿¼ôÇд«Á¦)µÄÂÝ˨ֱ¾¶d,ÉèÒÑÖªÂÝ˨µÄ[t ]Ϊ28MPa¡£
ͼ15-49 Ï°Ìâ15-14 ͼ-2-
½âÍâÔغÉÏòÂÝ˨×éÖÐÐļò»¯Ôò:ÂÝ˨×éÊܺáÏòÁ¦FR=20 kN ÂÝ˨×éÊÜÐýתÁ¦¾ØT=20¡Á300=6¡Á103 kNmm ÔÚºáÏòÁ¦×÷ÓÃÏÂ,µ¥¸öÂÝ˨ÊÜÁ¦: F = R =
F20
= 2.5 kN
Tr T 6 103 2 4 8 ÔÚÐýתÁ¦¾ØT×÷ÓÃÏÂ,µ¥¸öÂÝ˨ËùÊÜÁ¦:F =F =F =F = = =
s
22=7.07 kN F = (F +F cos45¡ã)2 +(F sin45¡ã)2 = (2.5+7.07 )2 +(7.07 )2 =9.01 kN
s1 s2 s3 s4
8r2 8r 8 752 +752 ÂÝ˨×éÊÜÁ¦ÈçͼËùʾ,ÆäÖÐÂÝ˨2¡¢3 ËùÊÜÔغÉ×î
´ó,×î´óÔغÉΪ:
smaxss2 s2
22