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3.11 2.00molÀíÏëÆøÌåÔÚ350KºÍ152kPaÌõ¼þÏ£¬¾ºãѹÀäÈ´ÖÁÌå»ýΪ35.0L£¬´Ë¹ý³Ì·Å³öÁË1260JÈÈÁ¿¡£ÊÔ¼ÆË㣺¢ÙÆðʼÌå»ý£»¢ÚÖÕ̬ζȣ»¢ÛÌåϵ×÷¹¦£»¢ÜÈÈÁ¦Ñ§Äܱ仯£»¢Ýìʱ䡣
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3£®pH = 5.00µÄÇ¿ËáÓëpH = 13.00µÄÇ¿ËáÈÜÒºµÈÌå»ý»ìºÏ£¬Ôò»ìºÏÈÜÒºµÄpHΪ ( ) (A)£®9.00£» (B)£®8.00£» (C)£®12.70£» (D)£®5.00¡£
4£®ÏÂÁÐÈÜÒºµÄŨ¶È¾ùΪ0.100 mol¡¤L-1 £¬ÆäÖÐ[OH-]×î´óµÄÊÇ ( ) (A)£®NaAc£» (B)£®Na2CO3£» (C)£®Na2S£» (D)£®Na3PO4¡£
5£®Ïò1.0L0.10 mol¡¤L-1HAcÈÜÒºÖмÓÈë1.0mL 0.010 mol¡¤L-1HClÈÜÒº£¬ÏÂÁÐÐðÊöÕýÈ·
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7£®ÏÂÁÐÈÜÒºÖУ¬pHÔ¼µÈÓÚ7.0µÄÊÇ ( ) (A)£®HCOONa£» (B)£®NaAc£» (C)£®NH4Ac£» (D)£®(NH4)2SO4¡£
8£®ÏÂÁи÷ÖÖÑÎÔÚË®ÈÜÒºÖÐË®½â²»Éú³É³ÁµíµÄÊÇ ( ) (A)£®SnCl2£» (B)£®SbCl3£» (C)£®Bi(NO3)3£» (D)£®NaNO2¡£
9£®ÅäÖÆpH = 9.00µÄ»º³åÈÜÒº£¬×îºÃӦѡÓà ( ) (A)£®NaHCO3 ¨C Na2CO3£» (B)£®Na2HPO4- Na 2HPO4£» (C)£®HAc ¨CNaAc£» (D)£®NH3¡¤H2O -NH4Cl¡£
10£®Which one of the following ions would give a basic solution upon addition to water?( ) (A)£®NH4+£» (B)£®Na+£» (C)£®C2H3O2-£» (D)£®NO3-. 11£®A certain weak acid is 10% dissociated in 1.0mol¡¤L-1 solution. In 0.10mol¡¤L-1 solution, the percentage of dissociation would be ( )
(A)£®greater than 10£» (B)£®10£» (C)£®less than 10£» (D)£®zero. 12£®When 500mL of 0.10mol¡¤L-1 NaOH is reacted with 500ml of 0.20mol¡¤L-1 HCl the final concentration of H+ is ( )
(A)£®0.10 mol¡¤L-1£» (B)£®0.20 mol¡¤L-1£» (C)£®0.050 mol¡¤L-1£» (D)£®10-7 mol¡¤L-1. 13£®If Kb? for NH3 is 2¡Á10-5£¬Ka? for the NH4+ ion is ( ) (A)£®2¡Á10-5£» (B)£®5¡Á10-10£» (C)£®5¡Á10-5£» (D)£®2¡Á10-19. 14£®A certain buffer contains equal concentrations of X- and HX. The Kb? of X- is 10-10, the pH of the buffer is ( )
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1£®ÔÚpH = 2.0µÄKCNµÄË®ÈÜÒºÖУ¬ÆäÖ÷Òª´æÔÚÐÎʽÊÇʲô£¿pH = 6.86µÄH3PO4ÖУ¬ÆäÖ÷Òª´æÔÚÐÎʽÊÇʲô£¿
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5£®Ä³Ò»ÔªÈõËáÓë36.12mL 0.100 mol¡¤L-1NaOHÕýºÃ×÷ÓÃÍêÈ«¡£È»ºóÔÙ¼ÓÈë18.06mL0.100 mol¡¤L-1HClÈÜÒº£¬²âµÃÈÜÒºpH = 4.92¡£ÊÔ¼ÆËã¸ÃÈõËáµÄ½âÀë³£Êý¡£
6£®NaHCO31.008gÈÜÓÚÊÊÁ¿Ë®ÖУ¬È»ºóÍù´ËÈÜÒºÖмÓÈë´¿¹ÌÌåNaOH 0.3200g£¬×îºó½«ÈÜÒºÒÆÈë250mLÈÝÁ¿Æ¿ÖС£ÒÆÈ¡ÉÏÊöÈÜÒº50.00mL£¬ÒÔ0.100mol¡¤L-1HClÈÜÒºµÎ¶¨¡£¼ÆË㣨1£©ÒÔ·Ó̪Ϊָʾ¼ÁµÎ¶¨ÖÁÖÕµãʱ£¬ÏûºÄHClÈÜÒº¶àÉÙºÁÉý£¿£¨2£©¼ÌÐø¼ÓÈë¼×»ù³Èָʾ¼ÁµÎ¶¨ÖÁÖÕµãʱ£¬ÓÖÏûºÄHClÈÜÒº¶àÉÙºÁÉý£¿
7£®Ä³Ò»ÔªÈõËᣨHA£©ÊÔÑù1.250g£¬¼ÓË®50.00mLʹÆäÈܽ⣬ȻºóÓÃ0.09000 mol.L-1NaOH±ê×¼ÈÜÒºµÎÖÁ»¯Ñ§¼ÆÁ¿µã£¬ÓÃÈ¥NaOHÈÜÒº41.20mL¡£Ôڵζ¨¹ý³ÌÖз¢ÏÖ£¬µ±¼ÓÈë8.24mLNaOH
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8£®Ä³Ñ§Éú±ê¶¨Ò»NaOHÈÜÒº¡£²âµÃÆäŨ¶ÈΪ0.1026 mol¡¤L-1¡£µ«Îó½«Æä±©Â¶ÓÚ¿ÕÆøÖÐ,ÖÂʹÆäÎüÊÕÁËCO2¡£Îª²â¶¨CO2µÄÎüÊÕÁ¿£¬È¡¸Ã¼îÒº25.00mLÓÃ0.1143 mol¡¤L-1HClµÎ¶¨ÖÁ·Ó̪ÖÕµã¼ÆºÄÈ¥HCl 22.31mL¡£¼ÆËãÿÉý¸Ã¼îÒºÎüÊÕÁ˶àÉÙ¿ËCO2£¿
9£®³ÆÈ¡0.7000gµÄÊÔÑù(º¬ÓÐNa3PO4 £¬Na2HPO4»òNaH2PO4¼°²»ÓëËá×÷ÓõÄÔÓÖÊ) £¬ÈÜÓÚË®ºóÓü׻ùºì×öָʾ¼Á£¬ÒÔ0.5000mol¡¤L-1HClÈÜÒºµÎ¶¨£¬ºÄËá14.00mL£¬Í¬ÑùÖÊÁ¿µÄÊÔÑù,Ó÷Ó̪×÷ָʾ¼Á£¬Ðè0.5000mol¡¤L-1HClÈÜÒº5.00mLµÎ¶¨ÖÁÖյ㡣¼ÆËãÊÔÑùÖÐÔÓÖʵĺ¬Á¿¡£
10£®A 0.900g sample containing a weak acid HX (MHX = 75.00) is dissolved in 60.00ml of solution and titration with c(NaOH) = 0.1000mol¡¤L-1 NaOH. When half of the acid is neutralized, the pH is 5.00, at the theory end point the pH is 8.85. Calculate the content of HX in the sample.
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16