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7 8 0.0104 0.0104 0.094 96 96 864 686.304 639.960 2116.224 4906.387 4322.230 4226.230 99.286 14741.612 17722.636 4 1 注:1、I—截面惯性矩,I?bd3/12,b取单位长度; 2、不考虑轴力影响。

用辛普生法近似计算单位位移值如下:

s2?11??0M1?Sds?EhIEhs?I1?1.561867?5?864?4.498?10(6-19) 73.00?10?12??21?s2?0M1M2?Sds?EhIEhy1.561867??I3.00?107?2116.224?1.102?10?4

?22??0M2?Sds?EhIEh?y21.561867?4??14741.612 ?7.675?10 7I3.00?10计算精度校核为:

?11?2?12??22?(4.498?11.02?2?76.75)?10?5?92.268?10?5 ?ss??SEh?(1?y)2I?1.561867?5 ?17722.636?92.267?1073.00?10闭合差:??0

6.3.2 载位移—主动荷载在基本结构中引起的位移

(1)每一楔块上的作用力:

竖向力:Qi?q?bi侧向力:Ei?e?hi自重力:Gi?d??S??h

式中:bi——衬砌外缘相邻两截面之间的水平投影长度,由图6.3中量得;

hi——衬砌外缘相邻两截面之间的竖直投影长度,由图6.3中量得;

d——接缝的衬砌截面厚度。

b1?1.5133,b2?1.3877,b3?1.1856,b4?0.9179,b5?0.5994,b6?0.2475,b7?0.1182B?bi?5.9696??7.31,修正闭合差,每个加上0.1915,则

2b1?1.7048,b2?1.5792,b3?1.3771,b4?1.1094,b5?0.7909,b6?0.4390,b7?0.3097

?bi?7.3101?B2?7.31

h1?0.8905,h2?0.5567,h3?0.8938,h4?1.1829,h5?1.4028,h6?1.5498,h7?1.6096,h8?1.5771

?hi?9.6632?H?9.58m

作用在各楔体上的力均列入表6.4,各集中力均通过相应图形的形心。 (2)外荷载在基本结构中产生的内力

楔块上各集中力对下一接缝的力臂由图6.3中量得,分别记为aq、ae、ag按下式计算:

0弯矩:Mip?Mi0?1,p??xi?(Q?G)??yi?E?Qaq?Gag?Eae(6-20)

i?10轴力:Nip?sin?i?(Q?G)?cos?i?E(6-21)

ii内力

式中:?xi、?yi——相邻两接缝中心点的坐标增值,按下式计算:

?xi?xi?xi?1?yi?yi?yi?1(6-22)

00的计算结果如表6.4和表6.5所示。 Mip、Nip0表6.4载位移Mp计算表

截面 Q G 18.352 18.352 18.352 18.352 18.352 18.352 18.352 18.352 i?1E aq ag 0.771 0.718 0.625 0.488 0.343 0.169 -0.19 ae 0.339 0.5275 0.716 0.743 0.804 0.82 0.792 0.704 i?1?Qaq 371.378 298.025 205.742 112.760 38.236 4.858 -45.909 0 i?1?Gag 14.149 13.177 11.470 8.956 6.295 3.101 -0.264 -3.487 0 Mp1 496.494 2 459.915 3 401.057 4 323.094 5 230.336 6 127.851 7 90.195 8 0 198.629 0.748 124.174 0.648 199.365 0.513 263.849 0.349 312.899 0.166 345.687 0.038 351.777 i?1359.026 -0.509 -0.0144 0 截面 ?Eae 1 67.335 2 65.502 ?(Q?G) ?E 0 556.3732 0 20.944 82.687 181.83 312.851 468.512 640.288 818.686 ?x 1.547 1.462 1.296 1.060 0.762 0.425 0.064 -0.301 ?y 0.183 0.538 0.865 1.144 1.357 1.499 1.557 1.531 ??x?(Q?G) ??y?E 0 -813.418 -1403.638 -1645.105 -1476.949 -944.172 -152.788 +730.612 0 -11.268 -71.524 -208.014 -424.539 -702.299 -996.928 -1253.408 -452.862 -1201.389 -1835.119 -2170.874 -2197.588 -1937.895 -1387.891 -766.960 3 142.745 1083.0538 4 196.040 1551.9858 5 251.570 1938.2528 6 283.464 2221.581 7 284.348 2387.3078 8 247.651 2427.2836 0表6.5载位移Np计算表

截面 0 1 2 3 4 5 6 7 8 sin? 0 0.792 0.965 0.372 -0.508 -0.993 -0.690 0.162 1 cos? 1 0.703 0.570 0.932 0.874 0.546 0.771 0.987 0 ?(Q?G) ?E i?1i?1sin??(Q?G) cos??E N0 i?1i?1p0 556.3732 1083.0538 1551.9858 1938.2528 2221.581 2387.3078 2427.2836 2445.3156 0 20.944 82.687 181.83 312.851 468.512 640.288 818.686 990.231 0 536.738 402.435 -788.494 -1925.618 -1532.762 385.574 2135.995 536.738 0 11.931 77.044 0 524.807 325.391 158.864 -947.357 170.747 -2096.36 361.355 1894.117 631.955 -246.381 521.630 1614.365 11.931 524.807 M80g???Gi(x8?xi?agi)??G1(x8?x1?ag1)?G2(x8?x2?ag2)?G3(x8?x3?ag3)?G4(x8?x4?ag4)?G5(x8?x5?ag5)?G6(x8?x6?ag6)?G7(x8?x7?ag7)?G8ag8

M80q??qB2(x8?B4)M80e??e2H2(6-23)

M80p?M80q?M80e?M80g??758.325(6-24)

0另一方面,从表5.2中得到M8p??766.960

闭合差??766.960?758.325766.960?1.126%

(3)主动荷载位移

表6.6主动荷载位移计算表

截面 0 1 2 3 4 5 6 0 Mp1/I 96 96 96 96 96 96 96 y/I 0 17.664 69.6 152.928 263.04 393.984 538.464 1?y 1 1.184 1.725 2.593 3.74 5.104 6.609 0Mp/I 0Mpy/I 0Mp(y?1)/I 0 -1201.389 -1835.119 -2170.874 -2197.588 -1937.895 -1387.891 0 -43474.752 -115333.323 -176171.451 -208403.902 -210968.487 -186037.905 0 -21221.331 -127724.302 -331987.416 -578053.655 -763499.561 -747329.420 0 -452.862 -1422.444 -3165.581 -5629.076 -8218.981 -9891.015

7 8 -766.960 -452.862 96 96 求和 688.512 835.872 8.172 9.707 -133237.550 -73628.139 -1147255.509 -528061.015 -21221.331 -3097876.700 -9172.573 -6267.595 -44220.127 ?1p??s0M1Mp0Mp?Sds???0.2389(6-25) ?EhIEI?Sds?EhIE0?2p??s0M2Mp0?0yMpI??1.3427(6-26)

计算精度校核:

?1p??2p??1.5816(6-27)

(1?y)Mp?S?sp??I??1.5816(6-28)

Eh闭合差??0

6.3.3 载位移—单位弹性抗力及相应的摩擦力引起的位移

(1)各接缝处的弹性抗力强度

抗力上零点假定在接缝3处,?3?40.462???b; 最大抗力值假定在接缝5 处,?5?67.435???h 最大抗力值以上各截面抗力强度按下式计算:

0cos2?b?cos2?icos2?i?i?(2)?h?(1.341?)?h(6-29)

cos?b?cos2?h0.4317?h;?5??h 带入数据计算出?3?0;?4?0.5388最大抗力值以下各截面抗力强度按下式计算:

yi'2?i?(1?'2)?h(6-30)

yh式中:yi'—所求截面与外轮廓线交点到最大截面抗力截面的垂直距离;

'—墙底外边缘到最大抗力截面的垂直距离。 yh在图6.3中量出:

'''y6?1.5616m;y7?3.1834m;y8?4.7429m

求出:?6?0.8916?h;?7?0.5495?h;?8?0 按比例将所求的抗力绘制在图6.3上。 (2)各楔块上抗力集中力Ri'