110KV线路继电保护课程设计 下载本文

正序阻抗:Z?(1)?(X1.G1?X1.T1X?X1.T3?X1.AB)//(1.G3?X1.BC)

22(16?10)3?8//26 ?(14?24)//? ?负序阻抗:

Z?(2)?Z?(1)?15.44?

零序阻抗:

Z?(0)?(15?72)//20//(48?15)

?11 ?1110.011494?0.05?0.015873??8720631?12.9?3

0.077367 ?其复合序网为三序网串联:

所以故障端口零序电流为:

If(0)?Uf0Z?(1)?Z?(2)?Z?(0)

?115/3?1.516(KA)

15.44?15.44?12.93在零序网络中按照零序导纳进行分配零序电流从而得到此时流过保护1、4的零序电流:

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I0.1?If(0)?0.011494?0.225(KA)

0.0773670.015873?0.311(KA)

0.077367 I0.4?If(0)?(2) B母线两相接地短路时,故障端口各序阻抗和单

相接地短路时相同,即

Z?(2)?Z?(1)?15.44?,Z?(0)?12.93?,

其复合序网为三序网并联:

Z∑(1) Uf|0|Z∑(2)Z∑(0)

Z?(2)//Z?(0)?15.44?12.93?7.04(?),

15.44?12.93

故障端口正序电流为: If(1)?Uf0Z?(1)?Z?(2)//Z?(0)?115/3?2.954(KA)

15.44?7.04 故障端口零序电流为:

If(0)?If(1)?15.44?1.608(KA)

15.44?12.93 同样地,流过保护1、4的零序电流分别为:

I0.1?If(0)?0.011494?0.239(KA)

0.077367 I0.4?If(0)?0.015873?0.330(KA)

0.077367- 11 -

所以I0.max.1?0.239(KA),I0.max.4?0.330(KA)

故零序I段整定值为:

II?KI?3I0.max.1?1.2?3?0.239?0.860(KA)

set.1rel II?KI?3I0.max.4?1.2?3?0.330?1.188(KA)

set.4rel(3) C母线单相接地短路时

Z?(1)?(14?24?16)//10?8.438? Z?(2)?Z?(1)?8.438?

Z?(0)?{[(15?72)//20]?48}//15?64.26//15

?111?64.2615 ?1

0.015562?0.066667 ?1?12.16?

0.082229 故障端口零序电流为: If(0)?Uf0Z?(1)?Z?(2)?Z?(0)?115/3?2.287(KA)

8.438?8.438?12.16 I0.3?If(0)?0.015562?0.433(KA)

0.082229(4) C母线两相接地短路时

Z?(2)//Z?(0)?8.438?12.16?4.981(?)

8.438?12.16If(1)?Uf0Z?(1)?Z?(2)//Z?(0)?115/3?4.948(KA)

8.438?4.981If(0)?If(1)?8.438?2.027(KA)

8.438?12.16I0.3?If(0)?0.015562?0.384(KA)

0.082229- 12 -

所以I0.max.3?0.433(KA)

I II?K?re3I?1.?2?3set.3l0.max.30.?433 59(KA)1.5(5) A母线单相接地短路时 Z?(1)?(10?24?16)//14?10.938?

Z?(2)?Z?(1)?10.938?

Z?(0)?{[(15?48)//20]?72}//15?87.18//15 ?111?87.1815?1

0.011471?0.066667 ?

1?12.798?

0.078138If(0)?Uf0Z?(1)?Z?(2)?Z?(0)?115/3?1.915(KA)

10.938?10.938?12.798I0.2?If(0)?0.011471?0.281(KA)

0.078138(6) A母线两相接地短路时

Z?(2)//Z?(0)?10.938?12.798?5.898(?)

10.938?12.798 If(1)?Uf0Z?(1)?Z?(2)//Z?(0)?115/3?3.944(KA)

10.938?12.798

If(0)?If(1)?10.938?1.817(KA)

10.938?12.79980.011471?0.267(KA)

0.078138 I0.2?If(0)?所以I0.max.2?0.281(KA)

IIset.2?KIrel?3I0.max.2?1.2?3?0.281?1.012(KA)

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